volume 7, issue 4, article 147, 2006.
Received 19 June, 2006;
accepted 04 September, 2006.
Communicated by:H. Silverman
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Journal of Inequalities in Pure and Applied Mathematics
UNIVALENCE CONDITIONS FOR CERTAIN INTEGRAL OPERATORS
VIRGIL PESCAR
"Transilvania" University of Bra¸sov
Faculty of Mathematics and Computer Science Department of Mathematics
2200 Bra¸sov ROMANIA
EMail:virgilpescar@unitbv.ro
c
2000Victoria University ISSN (electronic): 1443-5756 171-06
Univalence Conditions for Certain Integral Operators
Virgil Pescar
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J. Ineq. Pure and Appl. Math. 7(4) Art. 147, 2006
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Abstract
In this paper we consider some integral operators and we determine conditions for the univalence of these integral operators.
2000 Mathematics Subject Classification:Primary 30C45.
Key words: Univalent function, Integral operator.
Contents
1 Introduction. . . 3 2 Preliminary Results. . . 5 3 Main Results . . . 6
References
Univalence Conditions for Certain Integral Operators
Virgil Pescar
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1. Introduction
Let U = {z ∈C :|z|<1} be the unit disc in the complex plane. The class A and the class S are defined in [2]: let A be the class of functions f(z) = z +a2z2 +· · · , which are analytic in the unit disk normalized with f(0) = f0(0)−1 = 0; letSthe class of the functionsf ∈Awhich are univalent inU.
In [7] is defined the classS(α).For0< α ≤2,letS(α)denote the class of functionsf ∈Awhich satisfy the conditions:
(1.1) f(z)6= 0 for0<|z|<1 and
(1.2)
z f(z)
00
≤α for allz ∈U.
In [7] is proved the next result. For0 < α≤ 2,the functionsf ∈ S(α)are univalent.
In this work, we consider the integral operators
(1.3) Gα(z) =
α
Z z
0
gα−1(u)du α1
and
(1.4) Hα, γ(z) =
α
Z z
0
uα−1
h(u) u
γ
du α1
Univalence Conditions for Certain Integral Operators
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forg(z)∈S, h(z)∈Sand for someα, γ ∈C.
Kim - Merkes [1] studied the integral operator
(1.5) Fγ(z) =
Z z
0
h(u) u
γ
du
and obtained the following result
Theorem 1.1. If the functionh(z)belongs to the classS, then for any complex numberγ, |γ| ≤ 14,the functionFγ(z)defined by (1.5) is in the classS.
Univalence Conditions for Certain Integral Operators
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2. Preliminary Results
In order to prove our main results we will use the lemma due to N.N. Pascu [4]
presented in this section.
Lemma 2.1. Let the functionf ∈Aandαa complex number,Reα >0. If
(2.1) 1− |z|2 Reα
Reα
zf00(z) f0(z)
≤1,
for allz ∈U, then for all complex numbersβ, Reβ ≥Reαthe function
(2.2) Fβ(z) =
β
Z z
0
uβ−1f0(u)du β1
is regular and univalent inU.
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3. Main Results
Theorem 3.1. Let α be a complex number, Re α ≥ 0 and the function g ∈ S, g(z) =z+a2z2+· · · .If
(j1) |α−1| ≤ Re α
4 for Re α∈(0,1) or
(j2) |α−1| ≤ 1
4 for Re α∈[1,∞), then the function
(3.1) Gα(z) =
α
Z z
0
gα−1(u)du α1
is in the classS.
Proof. From (3.1) we have
(3.2) Gα(z) =
"
α Z z
0
uα−1
g(u) u
α−1
du
#α1 .
The function g(z) is regular and univalent, hence g(z)z 6= 0 for allz ∈ U. We can choose the regular branch of the function h
g(z) z
iα−1
to be equal to 1 at the origin.
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Let us consider the regular function inU, given by
(3.3) p(z) =
Z z
0
g(u) u
α−1
du.
Becauseg ∈S, we obtain (3.4)
z g0(z) g(z)
≤ 1 +|z|
1− |z|
for allz ∈U.
We have
1− |z|2 Reα Re α
z p00(z) p0(z)
= 1− |z|2 Reα Re α
z g0(z) g(z) −1
(3.5)
≤ 1− |z|2 Reα
Reα |α−1|
zg0(z) g(z)
+ 1
.
From (3.5) and (3.4) we obtain (3.6) 1− |z|2 Reα
Re α
z p00(z) p0(z)
≤ 1− |z|2 Reα
Reα |α−1| 2 1− |z|. Now, we consider the cases
i1) 0<Reα <1.
The function
s: (0,1)→ <, s(x) = 1−a2x (0 < a < 1)
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is a increasing function and fora =|z|, z ∈U,we obtain
(3.7) 1− |z|2 Reα ≤ 1− |z|2
for allz ∈U.
From (3.6) and (3.7), we have
(3.8) 1− |z|2 Reα
Re α
zp00(z) p0(z)
≤ 4|α−1|
Re α for allz ∈U.
Using the condition (j1) and (3.8) we get
(3.9) 1− |z|2 Reα
Re α
zp00(z) p0(z)
≤1 for allz ∈U.
i2) Re α ≥1.
We observe that the function
q : [1,∞)→ <, q(x) = 1−a2x
x (0< a < 1)
is a decreasing function, and that, if we takea =|z|, z ∈U,then
(3.10) 1− |z|2 Reα
Reα ≤1− |z|2 for allz ∈U.
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From (3.6) and (3.10) we obtain
(3.11) 1− |z|2 Reα
Re α
zp00(z) p0(z)
≤4|α−1|.
From (3.11) and (j2), we have
(3.12) 1− |z|2 Reα
Re α
zp00(z) p0(z)
≤1 for allz ∈U.
Using (3.9), (3.12) and because p0(z) =
g(z) z
α−1
, from Lemma 2.1 for α =β it results that the functionGα(z)is in the classS.
Theorem 3.2. If α is a real number, α ∈ 4
5, 54
and the function g ∈ S(α), then the function
(3.13) Gα(z) =
α
Z z
0
gα−1(u)du α1
is in the classS.
Proof. Ifg ∈S(α),theng ∈ Sand by Theorem3.1forα ∈4
5, 54
,we obtain the functionGα(z)in the classS.
Theorem 3.3. Letα, γ be a complex numbers and the functionh∈S, h(z) = z+a2z2+· · · .
If
(p1) |γ| ≤ Reα
4 for Reα∈(0,1)
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or
(p2) |γ| ≤ 1
4 for Reα∈[1,∞) then the function
(3.14) Hα, γ(z) =
α Z z
0
uα−1
h(u) u
γ
du α1
is regular and univalent inU.
Proof. Let us consider the regular function inU,defined by
(3.15) f(z) =
Z z
0
h(u) u
γ
du.
For the functionh∈S, we obtain (3.16)
z h0(z) h(z)
≤ 1 +|z|
1− |z|
for allz ∈U.
We obtain
(3.17) 1− |z|2 Reα Re α
z f00(z) f0(z)
≤ 1− |z|2 Reα Reα |γ|
zh0(z) h(z)
+ 1
.
From (3.17) and (3.16), we have (3.18) 1− |z|2 Reα
Reα
z f00(z) f0(z)
≤ 1− |z|2 Reα
Re α |γ| 2 1− |z|
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We consider the cases j1) 0<Re α <1.
In this case we obtain
(3.19) 1− |z|2 Reα ≤ 1− |z|2 for allz ∈U.
From (3.18) and (3.19), we get
(3.20) 1− |z|2 Reα
Re α
zf00(z) f0(z)
≤ 4|γ|
Re α for allz ∈U.
By (3.20) and (p1) we have
(3.21) 1− |z|2 Reα
Re α
zf00(z) f0(z)
≤1 for allz ∈U.
j2) Reα ≥1.
For this case we obtain
(3.22) 1− |z|2 Reα
Reα ≤1− |z|2 for allz ∈U.
From (3.18) and (3.22) we have
(3.23) 1− |z|2 Reα
Re α
zf00(z) f0(z)
≤4|γ|.
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From (3.23) and (p2), we get
(3.24) 1− |z|2 Reα
Re α
zf00(z) f0(z)
≤1 for allz ∈U.
From (3.21), (3.24) and becausef0(z) =
h(z) z
γ
, from Lemma2.1forα = β it results that the functionHα,γ(z)is in the classS.
Remark 1. Forα = 1,from Theorem3.3we obtain Theorem1.1, the result due to Kim-Merkes.
Theorem 3.4. Letγ be a complex number and the functionh∈S(a).
If
(3.25) |γ| ≤ α
4 for α∈(0,1) or
(3.26) |γ| ≤ 1
4 for α∈[1,2]
then the functionHα, γ(z)defined by (3.14) is in the classS.
Proof. Because h(z) ∈S(α), 0 < α≤2,thenh(z)∈ Sand by Theorem3.3 the functionHα, γ(z)belongs to the classS.
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References
[1] Y.J. KIMANDE.P. MERKES, On an integral of powers of a spirallike func- tion, Kyungpook Math. J., 12(2) (1972), 249–253.
[2] P.T. MOCANU, T. BULBOAC ˘A ANDG.St. S ˘AL ˘AGEAN, The Geometric Theory of Univalent Functions, Cluj, 1999.
[3] Z. NEHARI, Conformal Mapping, Mc Graw-Hill Book Comp., New York, 1952 (Dover. Publ. Inc., 1975).
[4] N.N. PASCU, An improvement of Becker’s univalence criterion, Proceed- ings of the Commemorative Session Simion Stoilov, Bra¸sov, (1987), 43–48.
[5] V. PESCAR, New univalence criteria, "Transilvania" University of Bra¸sov, Bra¸sov, 2002.
[6] C. POMMERENKE, Univalent Functions, Vanderhoeck Ruprecht, G˝ottin- gen, 1975.
[7] D. YANG AND J. LIU, On a class of univalent functions, IJMMS, 22(3) (1999), 605–610.