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Volume 4, Issue 3, Article 62, 2003

GENERALIZATIONS OF THE TRIANGLE INEQUALITY

SABUROU SAITOH DEPARTMENT OFMATHEMATICS,

FACULTY OFENGINEERING

GUNMAUNIVERSITY, KIRYU376-8515, JAPAN.

ssaitoh@math.sci.gunma-u.ac.jp

Received 09 December, 2002; accepted 15 March, 2003 Communicated by T. Ando

ABSTRACT. The triangle inequalitykx+yk ≤(kxk+kyk)is well-known and fundamental.

Since the 8th General Inequalities meeting in Hungary (September 15-21, 2002), the author has been considering an idea that as triangle inequality, the inequalitykx+yk22(kxk2+kyk2) may be more suitable. The triangle inequalitykx+yk2 2(kxk2+kyk2)will be naturally generalized for some natural sum of any two membersfjof any two Hilbert spacesHj. We shall introduce a natural sum Hilbert space for two arbitrary Hilbert spaces.

Key words and phrases: Triangle inequality, Hilbert space, Sum of two Hilbert spaces, various operators among Hilbert spaces, Reproducing kernel, Linear mapping, Norm inequality.

2000 Mathematics Subject Classification. 30C40, 46E32, 44A10, 35A22.

1. A GENERAL CONCEPT

Following [1], we shall introduce a general theory for linear mappings in the framework of Hilbert spaces.

LetH be a Hilbert (possibly finite-dimensional) space. LetE be an abstract set and hbe a HilbertH-valued function onE. Then we shall consider the linear mapping

(1.1) f(p) = (f,h(p))H, f ∈ H

fromHinto the linear spaceF(E)comprising all the complex-valued functions onE. In order to investigate the linear mapping (1.1), we form a positive matrixK(p, q)onEdefined by

(1.2) K(p, q) = (h(q),h(p))HonE ×E.

Then, we obtain the following:

(I) The range of the linear mapping (1.1) byHis characterized as the reproducing kernel Hilbert spaceHK(E)admitting the reproducing kernelK(p, q).

ISSN (electronic): 1443-5756

c 2003 Victoria University. All rights reserved.

140-02

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(II) In general, we have the inequality

kfkHK(E) ≤ kfkH.

Here, for a memberf ofHK(E)there exists a uniquely determinedf ∈ Hsatisfying f(p) = (f,h(p))HonE

and

kfkHK(E) =kfkH.

(III) In general, we have the inversion formula in (1.1) in the form

(1.3) f →f

in (II) by using the reproducing kernel Hilbert spaceHK(E). However, this formula is, in general, involved and intricate. Indeed, we need specific arguments. Here, we assume that the inversion formula (1.3) may be, in general, established.

Now we shall consider two systems

(1.4) fj(p) = (fj,hj(p))Hj, fj ∈ Hj

in the above way by using {Hj, E,hj}2j=1. Here, we assume that E is the same set for both systems in order to have the output functionsf1(p)andf2(p)on the same setE.

For example, we can consider the usual operator f1(p) +f2(p) inF(E). Then, we can consider the following problem:

How do we represent the sumf1(p) +f2(p)onE in terms of their inputsf1 andf2 through one system?

We shall see that by using the theory of reproducing kernels we can give a natural answer to this problem. Following similar ideas, we can consider various operators among Hilbert space (see [2] for the details). In particular, for the product of two Hilbert spaces, the idea gives gen- eralizations of convolutions and the related natural convolution norm inequalities. These norm inequalities gave various generalizations and applications to forward and inverse problems for linear mappings in the framework of Hilbert spaces, see for example, [3, 4, 5]. Furthermore, surprisingly enough, for some very general nonlinear systems, we can consider similar prob- lems. For its importance in general inequalities, we shall refer to natural generalizations of the triangle inequalitykx+yk2 ≤ 2(kxk2 +kyk2)for some natural sum of two arbitrary Hilbert spaces. And then, we may consider this inequality to be more suitable as a triangle inequality than the usual triangle inequality.

2. SUM

By (I),f1 ∈HK1(E)andf2 ∈ HK2(E), and we note that for the reproducing kernel Hilbert spaceHK1+K2(E)admitting the reproducing kernel

K1(p, q) +K2(p, q) onE, HK1+K2(E)is composed of all functions

(2.1) f(p) = f1(p) +f2(p); fj ∈HKj(E) and its normkfkHK

1+K2(E)is given by

(2.2) kfk2H

K1+K2(E)= minn kf1k2H

K1(E)+kf2k2H

K2(E)

o

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where the minimum is taken overfj ∈ HKj(E)satisfying (2.1) forf. Hence, in general, we have the inequality

(2.3) kf1+f2k2HK

1+K2(E) ≤ kf1k2HK

1(E)+kf2k2HK

2(E). In particular, note that for the sameK1 andK2, we have, forK1 =K2 =K

kf1+f2k2H

K(E) ≤2(kf1k2H

K(E)+kf2k2H

K(E)).

Furthermore, the particular inequality (2.3) may be considered as a natural triangle inequality for the sum of reproducing kernel Hilbert spacesHKj(E).

For the positive matrixK1+K2onE, we assume the expression in the form (2.4) K1(p, q) +K2(p, q) = (hS(q),hS(p))HS onE×E with a Hilbert spaceHS-valued function onE and further we assume that (2.5) {hS(p);p∈E}is complete inHS.

Such a representation is, in general, possible ([1, page 36 and see Chapter 1, §5]). Then, we can consider the linear mapping fromHSontoHK1+K2(E)

(2.6) fS(p) = (fS,hS(p))HS, fS ∈ HS and we obtain the isometric identity

(2.7) kfSkHK

1+K2(E) =kfSkHS.

Hence, for such representations (2.4) with (2.5), we obtain the isometric relations among the Hilbert spacesHS.

Now, for the sumf1(p) +f2(p)there exists a uniquely determinedfS ∈ HS satisfying (2.8) f1(p) +f2(p) = (fS,hS(p))HS onE.

Then, fS will be considered as a sum of f1 and f2 through these mappings and so, we shall introduce the notation

(2.9) fS =f1[+]f2.

This sum for the members f1 ∈ H1 and f2 ∈ H2 is introduced through the three mappings induced by{Hj, E, hj}(j = 1,2)and{HS, E, hS}.

The operatorf1[+]f2 is expressible in terms off1andf2by the inversion formula (2.10) (f1,h1(p))H1 + (f2,h2(p))H2 −→f1[+]f2

in the sense (II) fromHK1+K2(E)ontoHS. Then, from (II) and (2.5) we obtain the beautiful triangle inequality

Theorem 2.1. We have the triangle inequality

(2.11) kf1[+]f2k2H

S ≤ kf1k2H

1 +kf2k2H

2.

If{hj(p); p∈ E}are complete in Hj (j = 1,2), thenHj andHKj are isometrical, respec- tively. By using the isometric mappings induced by Hilbert space valued functionshj(j = 1,2) andhS, we can introduce the sum space ofH1 andH2 in the form

(2.12) H1[+]H2

through the mappings. Of course, the sum is a Hilbert space. Furthermore, such spaces are determined in the framework of isometric relations.

For example, if for some positive numberγ

(2.13) K1 γ2K2 onE

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that is, ifγ2K2−K1is a positive matrix onE, then we have

(2.14) HK1(E)⊂HK2(E)

and

(2.15) kf1kHK

2(E)≤γkf1kHK

1(E)forf1 ∈HK1(E)

([1, page 37]). Hence, in this case, we need not to introduce a new Hilbert spaceHS and the linear mapping (2.6) in Theorem 2.1 and we can use the linear mapping

(f2,h2(p))H2, f2 ∈ H2 instead of (2.6) in Theorem 2.1.

3. EXAMPLE

We shall consider two linear transforms

(3.1) fj(p) =

Z

T

Fj(t)h(t, p)ρj(t)dm(t), p∈E whereρj are positive continuous functions onT,

(3.2)

Z

T

|h(t, p)|2ρj(t)dm(t)<∞onp∈E and

(3.3)

Z

T

|Fj(t)|2ρj(t)dm(t)<∞.

We assume that{h(t, p);p∈ E}is complete in the spaces satisfying (3.3). Then, we consider the associated reproducing kernels onE

Kj(p, q) = Z

T

h(t, p)h(t, p)ρj(t)dm(t) and, for example we consider the expression

(3.4) K1(p, q) +K2(p, q) = Z

T

h(t, p)h(t, p)(ρ1(t) +ρ2(t))dm(t).

So, we can consider the linear transform

(3.5) f(p) =

Z

T

F(t)h(t, p)(ρ1(t) +ρ2(t))dm(t) for functionsF satisfying

Z

T

|F(t)|21(t) +ρ2(t))dm(t)<∞.

Hence, through the three transforms (3.1) and (3.5) we have the sum (3.6) (F1[+]F2) (t) = F1(t)ρ1(t) +F2(t)ρ2(t)

ρ1(t) +ρ2(t) .

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4. DISCUSSIONS

• Which is more general the classical one and the second triangle inequality (2.11)? We stated: for two arbitrary Hilbert spaces, we can introduce the natural sum and the second triangle inequality (2.11) is valid in a natural way.

• Which is more beautiful the classical one and the second one (2.11)? The author believes the second one is more beautiful. (Gods love two; and 2 is better than 1/2).

• Which is more widely applicable?

• The author thinks the second triangle inequality (2.11) is superior to the classical one as a triangle inequality. However, for the established long tradition, how will be:

– for the classical one, the triangle inequality of the first kind and

– for the second inequality (2.11), the triangle inequality of the second kind?

REFERENCES

[1] S. SAITOH, Integral Transforms, Reproducing Kernels and their Applications, Pitman Research Notes in Mathematics Series, 369, Addison Wesley Longman, UK (1998). Introduction to the theory of reproducing kernels, Makino-shoten (2002) (in Japanese).

[2] S. SAITOH, Various operators in Hilbert space introduced by transforms, International. J. Appl.

Math., 1 (1999), 111–126.

[3] S. SAITOH, Weighted Lp-norm inequalities in convolutions, Survey on Classical Inequalities, Kluwer Academic Publishers, The Netherlands, (2000), 225–234.

[4] S. SAITOH, V.K. TUANANDM. YAMAMOTO, Reverse weightedLp-norm inequalities in convo- lutions and stability in inverse problems, J. Ineq. Pure and Appl. Math., 1(1) (2000), Art. 7. [ON- LINE:http://jipam.vu.edu.au/v1n1/018_99.html].

[5] S. SAITOH, V.K. TUANANDM. YAMAMOTO, Reverse convolution inequalities and applications to inverse heat source problems, J. Ineq. Pure and Appl. Math., 3(5) (2003), Art. 80. [ONLINE:

http://jipam.vu.edu.au/v3n5/029_02.html].

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