volume 7, issue 3, article 97, 2006.
Received 21 March, 2006;
accepted 12 July, 2006.
Communicated by:F. Zhang
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Journal of Inequalities in Pure and Applied Mathematics
NORM INEQUALITIES FOR SEQUENCES OF OPERATORS RELATED TO THE SCHWARZ INEQUALITY
SEVER S. DRAGOMIR
School of Computer Science and Mathematics Victoria University
PO Box 14428, MCMC 8001 VIC, Australia.
EMail:sever@csm.vu.edu.au URL:http://rgmia.vu.edu.au/dragomir
c
2000Victoria University ISSN (electronic): 1443-5756 088-06
Norm Inequalities for Sequences of Operators
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Abstract
Some norm inequalities for sequences of linear operators defined on Hilbert spaces that are related to the classical Schwarz inequality are given. Applica- tions for vector inequalities are also provided.
2000 Mathematics Subject Classification:Primary 47A05, 47A12.
Key words: Bounded linear operators, Hilbert spaces, Schwarz inequality, Cartesian decomposition of operators.
Contents
1 Introduction. . . 3
2 Some General Results. . . 7
3 Other Results. . . 14
4 Vector Inequalities. . . 19 References
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1. Introduction
Let(H;h·,·i)be a real or complex Hilbert space andB(H)the Banach algebra of all bounded linear operators that mapHintoH.
In many estimates one needs to use upper bounds for the norm of the linear combination of bounded linear operatorsA1, . . . , Anwith the scalarsα1, . . . , αn, where separate information for scalars and operators are provided. In this situ- ation, the classical approach is to use a Hölder type inequality as stated below
n
X
i=1
αiAi
≤
n
X
i=1
|αi| kAik
!
≤
1≤i≤nmax {|αi|}Pn
i=1kAik; (Pn
i=1|αi|p)p1 (Pn
i=1kAikq)1q ifp >1, 1p + 1q = 1;
1≤i≤nmax {kAik}Pn i=1|αi|.
Notice that, the case whenp=q= 2, which provides the Cauchy-Bunyakovsky- Schwarz inequality
(1.1)
n
X
i=1
αiAi
≤
n
X
i=1
|αi|2
!12 n X
i=1
kAik2
!12
is of special interest and of larger utility.
In the previous paper [1], in order to improve (1.1), we have established the following norm inequality for the operators A1, . . . , An ∈ B(H) and scalars
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α1, . . . , αn ∈K:
(1.2)
n
X
i=1
αiAi
2
≤
1≤i≤nmax |αi|2Pn
i=1kAik2; Pn
i=1|αi|2p1p Pn
i=1kAik2q1q ifp > 1, 1p +1q = 1;
Pn
i=1|αi|2 max
1≤i≤nkAik2
+
1≤i6=j≤nmax {|αi| |αj|}P
1≤i6=j≤n
AiA∗j ; h
(Pn
i=1|αi|r)2 −Pn
i=1|αi|2ri1r P
1≤i6=j≤n
AiA∗j
s1s
ifr >1, 1r + 1s = 1;
h (Pn
i=1|αi|)2−Pn
i=1|αi|2i
1≤i6=j≤nmax
AiA∗j ,
where (1.2) should be seen as all the9possible configurations.
Some particular inequalities of interest that can be obtained from (1.2) and provide alternative bounds for the classical Cauchy-Bunyakovsky-Schwarz (CBS) inequality are the following [1]:
(1.3)
n
X
i=1
αiAi
≤ max
1≤i≤n|αi|
n
X
i,j=1
AiA∗j
!12 ,
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(1.4)
n
X
i=1
αiAi
2
≤
n
X
i=1
|αi|2
1≤i≤nmaxkAik2+ (n−1) max
1≤i6=j≤n
AiA∗j
,
(1.5)
n
X
i=1
αiAi
2
≤
n
X
i=1
|αi|2
max
1≤i≤nkAik2+ X
1≤i6=j≤n
AiA∗j
2
!12
and
(1.6)
n
X
i=1
αiAi
2
≤
n
X
i=1
|αi|2p
!1p
n
X
i=1
kAik2q
!1q
+ (n−1)1p X
1≤i6=j≤n
AiA∗j
q
!1q
,
wherep >1, 1p + 1q = 1.In particular, forp=q= 2,we have from (1.6)
(1.7)
n
X
i=1
αiAi
2
≤
n
X
i=1
|αi|4
!12
n
X
i=1
kAik4
!12
+ (n−1)12 X
1≤i6=j≤n
AiA∗j
2
!12
.
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The aim of the present paper is to establish other upper bounds of interest for the quantitykPn
i=1αiAik,where, as above,α1, . . . , αnare real or complex numbers, while A1, . . . , An are bounded linear operators on the Hilbert space (H;h·,·i).These are compared with the (CBS) inequality (1.1) and shown that some times they are better. Applications for vector inequalities are also given.
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2. Some General Results
The following result containing 9 different inequalities may be stated:
Theorem 2.1. Letα1, . . . , αn∈KandA1, . . . , An∈B(H).Then (2.1)
n
X
i=1
αiAi
2
≤
A B C where
A:=
1≤k≤nmax |αk|2Pn i,j=1
AiA∗j ,
1≤k≤nmax |αk|(Pn
i=1|αi|r)1r Pn
i=1
Pn j=1
AiA∗j
s1s , wherer >1, 1r +1s = 1;
1≤k≤nmax |αk|Pn
i=1|αi| max
1≤i≤n
Pn j=1
AiA∗j
,
(2.2) B :=
1≤i≤nmax |αi|(Pn
k=1|αk|p)1pPn i=1
Pn j=1
AiA∗j
q1q
Pn
i=1|αi|t1t (Pn
k=1|αk|p)1p
Pn i=1
Pn j=1
AiA∗j
ququ1
wheret >1, 1t +u1 = 1;
Pn
i=1|αi|(Pn
k=1|αk|p)1p max
1≤i≤n
Pn
j=1
AiA∗j
q1q ,
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forp >1, 1p + 1q = 1and
C :=
1≤i≤nmax|αi|Pn
k=1|αk|Pn
i=1 max
1≤j≤n
AiA∗j ,
(Pn
i=1|αi|m)m1 Pn k=1|αk|
"
Pn i=1
1≤j≤nmax
AiA∗j
l#1l ,
wherem, l >1, m1 +1l = 1;
(Pn
k=1|αk|)2 max
1≤i,j≤n
AiA∗j .
Proof. We observe, in the operator partial order ofB(H), we have that
0≤
n
X
i=1
αiAi
! n X
i=1
αiAi
!∗
(2.3)
=
n
X
i=1
αiAi
n
X
j=1
αjA∗j =
n
X
i=1 n
X
j=1
αiαjAiA∗j.
Taking the norm in (2.3) and noticing thatkU U∗k=kUk2for anyU ∈B(H), we have:
n
X
i=1
αiAi
2
=
n
X
i=1 n
X
j=1
αiαjAiA∗j
≤
n
X
i=1 n
X
j=1
|αi| |αj| AiA∗j
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=
n
X
i=1
|αi|
n
X
j=1
|αj| AiA∗j
!
=:M.
Utilising Hölder’s discrete inequality we have that
n
X
j=1
|αj| AiA∗j
≤
1≤k≤nmax |αk|Pn j=1
AiA∗j ,
(Pn
k=1|αk|p)1p Pn
j=1
AiA∗j
q1q
wherep >1, 1p + 1q = 1;
Pn
k=1|αk| max
1≤j≤n
AiA∗j ,
for anyi∈ {1, . . . , n}.
This provides the following inequalities:
M ≤
1≤k≤nmax |αk|Pn
i=1|αi| Pn
j=1
AiA∗j
=:M1 (Pn
k=1|αk|p)1pPn
i=1|αi| Pn
j=1
AiA∗j
q1q
:=Mp wherep > 1, 1p +1q = 1;
Pn
k=1|αk|Pn i=1|αi|
1≤j≤nmax
AiA∗j
:=M∞.
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Utilising Hölder’s inequality forr, s >1, 1r +1s = 1,we have:
n
X
i=1
|αi|
n
X
j=1
AiA∗j
!
≤
1≤i≤nmax |αi|Pn i,j=1
AiA∗j
(Pn
i=1|αi|r)1r h Pn
i=1
Pn j=1
AiA∗j
si1s , wherer >1, 1r + 1s = 1;
Pn
i=1|αi| max
1≤i≤n
Pn j=1
AiA∗j
, and thus we can state that
M1 ≤
1≤k≤nmax |αk|2Pn i,j=1
AiA∗j ;
1≤k≤nmax |αk|(Pn
i=1|αi|r)1r Pn
i=1
Pn j=1
AiA∗j
s1s , wherer >1, 1r +1s = 1;
1≤k≤nmax |αk|Pn
i=1|αi| max
1≤i≤n
Pn j=1
AiA∗j
, and the first part of the theorem is proved.
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By Hölder’s inequality we can also have that (forp > 1, 1p +1q = 1)
Mp ≤
n
X
k=1
|αk|p
!1p
×
1≤i≤nmax|αi|Pn i=1
Pn j=1
AiA∗j
q1q
; Pn
i=1|αi|t1t
Pn i=1
Pn j=1
AiA∗j
ququ1 ,
wheret >1, 1t + 1u = 1;
Pn
i=1|αi| max
1≤i≤n
Pn
j=1
AiA∗j
q1q ,
and the second part of (2.1) is proved.
Finally, we may state that
M∞≤
n
X
k=1
|αk| ×
1≤i≤nmax|αi|Pn
i=1 max
1≤j≤n
AiA∗j
(Pn
i=1|αi|m)m1
"
Pn i=1
1≤j≤nmax
AiA∗j
l#1l
wherem, l >1, m1 +1l = 1;
Pn
i=1|αi| max
1≤i,j≤n
AiA∗j ,
giving the last part of (2.1).
Remark 1. It is obvious that out of (2.1) one can obtain various particular inequalities. For instance, the choicet= 2, p= 2(thereforeu=q = 2) in the
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B−branch of (2.2) gives:
n
X
i=1
αiAi
2
≤
n
X
i=1
|αi|2
n
X
i,j=1
AiA∗j
2
!12 (2.4)
=
n
X
i=1
|αi|2
n
X
i=1
kAik4+ X
1≤i6=j≤n
AiA∗j
!12 .
If we consider now the usual Cauchy-Bunyakovsky-Schwarz (CBS) inequality
(2.5)
n
X
i=1
αiAi
2
≤
n
X
i=1
|αi|2
n
X
i=1
kAik2,
and observe that
n
X
i,j=1
AiA∗j
2
!12
≤
n
X
i,j=1
kAik2 A∗j
2
!12
=
n
X
i=1
kAik2,
then we can conclude that (2.4) is a refinement of the (CBS) inequality (2.5).
Corollary 2.2. Letα1, . . . , αn∈KandA1, . . . , An ∈B(H)so thatAiA∗j = 0 withi6=j.Then
(2.6)
n
X
i=1
αiAi
2
≤
A˜ B˜ C˜
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where
A˜:=
1≤k≤nmax |αk|2Pn
i=1kAik2;
1≤k≤nmax |αk|(Pn
i=1|αi|r)1r Pn
i=1kAik2s1s , wherer >1, 1r + 1s = 1;
1≤k≤nmax |αk|Pn
i=1|αi| max
1≤i≤n
kAik2 ,
B˜ :=
1≤i≤nmax|αi|(Pn
k=1|αk|p)1pPn
i=1kAik2; v Pn
i=1|αi|t1t (Pn
k=1|αk|p)1pPn
i=1kAik2uu1 , wheret >1, 1t +u1 = 1;
Pn
i=1|αi|(Pn
k=1|αk|p)1p max
1≤i≤n
kAik2 ,
wherep >1and
C˜ :=
1≤i≤nmax |αi|Pn
k=1|αk|Pn
i=1kAik2; (Pn
i=1|αi|m)m1 Pn
k=1|αk| Pn
i=1kAik2l1l , wherem, l >1, m1 +1l = 1;
(Pn
k=1|αk|)2 max
1≤i,j≤n
kAik2 .
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3. Other Results
A different approach is embodied in the following theorem:
Theorem 3.1. Ifα1, . . . , αn∈KandA1, . . . , An∈B(H),then
n
X
i=1
αiAi
2
≤
n
X
i=1
|αi|2
n
X
j=1
AiA∗j (3.1)
≤
Pn
i=1|αi|2 max
1≤i≤n
hPn j=1
AiA∗j i
; Pn
i=1|αi|2p1ph Pn
i=1
Pn j=1
AiA∗j
qi1q wherep >1, 1p + 1q = 1;
1≤i≤nmax |αi|2Pn i,j=1
AiA∗j . Proof. From the proof of Theorem2.1we have that
n
X
i=1
αiAi
2
≤
n
X
i=1 n
X
j=1
|αi| |αj| AiA∗j
.
Using the simple observation that
|αi| |αj| ≤ 1
2 |αi|2+|αj|2
, i, j ∈ {1, . . . , n},
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we have
n
X
i=1 n
X
j=1
|αi| |αj| AiA∗j
≤ 1 2
n
X
i=1 n
X
j=1
|αi|2+|αj|2 AiA∗j
= 1 2
n
X
i=1 n
X
j=1
|αi|2 AiA∗j
+|αj|2 AiA∗j
=
n
X
i=1 n
X
j=1
|αi|2 AiA∗j
,
which proves the first inequality in (3.1).
The second part follows by Hölder’s inequality and the details are omitted.
Remark 2. If in (3.1) we chooseα1 =· · ·=αn = 1,then we get
n
X
i=1
Ai
≤
n
X
i=1
kAik2+
n
X
1≤i6=j≤n
AiA∗j
!12
≤
n
X
i=1
kAik,
which is a refinement for the generalised triangle inequality.
The following corollary may be stated:
Corollary 3.2. If A1, . . . , An ∈ B(H) are such that AiA∗j = 0 for i 6= j,
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i, j ∈ {1, . . . , n},then
n
X
i=1
αiAi
2
≤
n
X
i=1
|αi|2kAik2 (3.2)
≤
Pn
i=1|αi|2 max
1≤i≤nkAik2; Pn
i=1|αi|2p1ph Pn
j=1kAik2qi1q wherep > 1, 1p +1q = 1;
1≤i≤nmax |αi|2Pn
i=1kAik2. Finally, the following result may be stated as well:
Theorem 3.3. Ifα1, . . . , αn∈KandA1, . . . , An∈B(H),then
(3.3)
n
X
i=1
αiAi
2
≤
1≤i≤nmax|αi|2Pn i,j=1
AiA∗j ; (Pn
i=1|αi|p)2p Pn
i,j=1
AiA∗j
q1q wherep >1, 1p + 1q = 1;
(Pn
i=1|αi|)2 max
1≤i,j≤n
AiA∗j . Proof. We know that
n
X
i=1
αiAi
2
≤
n
X
i=1 n
X
j=1
|αi| |αj| AiA∗j
=:P.
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Firstly, we obviously have that P ≤ max
1≤i,j≤n{|αi| |αj|}
n
X
i,j=1
AiA∗j
= max
1≤i≤n|αi|2
n
X
i,j=1
AiA∗j .
Secondly, by the Hölder inequality for double sums, we obtain
P ≤
" n X
i,j=1
(|αi| |αj|)p
#1p n X
i,j=1
AiA∗j
q
!1q
=
n
X
i=1
|αi|p
n
X
j=1
|αj|p
!1p n X
i,j=1
AiA∗j
q
!1q
=
n
X
i=1
|αi|p
!2p n X
i,j=1
AiA∗j
q
!1q ,
wherep >1, 1p + 1q = 1.
Finally, we have
P ≤ max
1≤i,j≤n
AiA∗j
n
X
i,j=1
|αi| |αj|
=
n
X
i=1
|αi|
!2
1≤i,j≤nmax
AiA∗j
and the theorem is proved.
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Corollary 3.4. If α1, . . . , αn ∈ K and A1, . . . , An ∈ B(H) are such that AiA∗j = 0fori, j ∈ {1, . . . , n}withi6=j,then
(3.4)
n
X
i=1
αiAi
2
≤
1≤i≤nmax|αi|2Pn
i=1kAik2; (Pn
i=1|αi|p)2p Pn
i=1kAik2q1q , wherep >1, 1p + 1q = 1;
(Pn
i=1|αi|)2 max
1≤i≤n
kAik2 .
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4. Vector Inequalities
As pointed out in our previous paper [1], the operator inequalities obtained above may provide various vector inequalities of interest.
If byM(α,A)we denote any of the bounds provided by (2.1), (2.4), (3.1) or (3.3) for the quantitykPn
i=1αiAik2, then we may state the following general fact:
Under the assumptions of Theorem2.1, we have:
(4.1)
n
X
i=1
αiAix
2
≤ kxk2M(α,A). for anyx∈H and
(4.2)
n
X
i=1
αihAix, yi
2
≤ kxk2kyk2M(α,A).
for anyx, y ∈H,respectively.
The proof follows by the Schwarz inequality in the Hilbert space(H,h·,·i), see for instance [1], and the details are omitted.
Now, we consider the non zero vectorsy1, . . . , yn∈H.Define the operators [1]
Ai :H →H, Aix= hx, yii
kyik ·yi, i∈ {1, . . . , n}.
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J. Ineq. Pure and Appl. Math. 7(3) Art. 97, 2006
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Since
kAik=kyik, i∈ {1, . . . , n}
thenAiare bounded linear operators inH.Also, since hAix, xi= |hx, yii|2
kyik ≥0, x∈H, i∈ {1, . . . , n}
and
hAix, zi= hx, yii hyi, zi kyik , hx, Aizi= hx, yii hyi, zi
kyik ,
giving
hAix, zi=hx, Aizi, x, z ∈H, i∈ {1, . . . , n},
we may conclude that Ai (i= 1, . . . , n)are positive self-adjoint operators on H.
Since, for anyx∈H,one has
k(AiAj) (x)k= |hx, yji| |hyj, yii|
kyjk , i, j ∈ {1, . . . , n}, then we deduce that
kAiAjk=|(yi, yj)|; i, j ∈ {1, . . . , n}.
Norm Inequalities for Sequences of Operators
Related to the Schwarz Inequality Sever S. Dragomir
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J. Ineq. Pure and Appl. Math. 7(3) Art. 97, 2006
If (yi)i=1,n is an orthonormal family on H,then kAik = 1 andAiAj = 0for i, j ∈ {1, . . . , n}, i6=j.
Now, utilising, for instance, the inequalities in Theorem 3.1 we may state that:
n
X
i=1
αihx, yii kyik yi
2
(4.3)
≤ kxk2
n
X
i=1
|αi|2
n
X
j=1
|hyi, yji|
≤ kxk2×
Pn
i=1|αi|2 max
1≤i≤n
hPn
j=1|hyi, yji|i
; Pn
i=1|αi|2p1ph Pn
i=1
Pn
j=1|(yi, yj)|qi1q wherep >1, 1p + 1q = 1;
v max
1≤i≤n|αi|2Pn
i,j=1|hyi, yji|.
for anyx, y1, . . . , yn ∈Handαn, . . . , αn∈K. The proof follows on choosingAi = h·,ykyii
ikyi in Theorem3.1and taking into account thatkAik=kyik,
AiA∗j
=|hyi, yji|, i, j ∈ {1, . . . , n}. We omit the details.
Norm Inequalities for Sequences of Operators
Related to the Schwarz Inequality Sever S. Dragomir
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J. Ineq. Pure and Appl. Math. 7(3) Art. 97, 2006
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The choiceαi = kyik(i= 1, . . . , n)will produce some interesting bounds for the norm of the Fourier series
n
X
i=1
hx, yiiyi
.
Notice that the vectorsyi (i= 1, . . . , n)are not necessarily orthonormal.
Similar inequalities may be stated if one uses the other two main theorems.
For the sake of brevity, they will not be stated here.
Norm Inequalities for Sequences of Operators
Related to the Schwarz Inequality Sever S. Dragomir
Title Page Contents
JJ II
J I
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J. Ineq. Pure and Appl. Math. 7(3) Art. 97, 2006
References
[1] S.S. DRAGOMIR, Some Schwarz type inequalities for sequences of opera- tors in Hilbert spaces, Bull. Austral. Math. Soc., 73 (2006), 17–26.