http://jipam.vu.edu.au/
Volume 7, Issue 4, Article 139, 2006
A MULTIPLE HARDY-HILBERT INTEGRAL INEQUALITY WITH THE BEST CONSTANT FACTOR
HONG YONG
DEPARTMENT OFMATHEMATICS
GUANGDONGUNIVERSITY OFBUSINESSSTUDY
GUANGZHOU510320 PEOPLE’SREPUBLIC OFCHINA.
hongyong59@sohu.com
Received 14 September, 2005; accepted 14 December, 2005 Communicated by B. Yang
ABSTRACT. In this paper, by introducing the normkxkα(x∈Rn), we give a multiple Hardy- Hilbert’s integral inequality with a best constant factor and two parametersα,λ.
Key words and phrases: Multiple Hardy-Hilbert integral inequality, theΓ-function, Best constant factor.
2000 Mathematics Subject Classification. 26D15.
1. INTRODUCTION
Ifp >1, 1p + 1q = 1, f ≥0,g ≥0,0<R∞
0 fp(x)dx < +∞, 0<R∞
0 gq(x)dx < +∞, then the well known Hardy-Hilbert integral inequality is given by (see [3]):
(1.1)
Z ∞ 0
Z ∞ 0
f(x)g(x)
x+y dxdy < π sin
π p
Z ∞
0
fp(x)dx
1pZ ∞ 0
gq(x)dx 1q
,
where the constant factor π
sin(πp) is the best possible. Its equivalent form is:
(1.2)
Z ∞ 0
Z ∞ 0
f(x) x+ydx
p
dy <
π sin
π p
p
Z ∞ 0
fp(x)dx,
where the constant factor
π sin(πp)
p
is also the best possible.
Hardy-Hilbert’s inequality is valuable in harmonic analysis, real analysis and operator the- ory. In recent years, many valuable results (see [4] – [10]) have been obtained in the form of
ISSN (electronic): 1443-5756
c 2006 Victoria University. All rights reserved.
273-05
generalizations and improvements of Hardy-Hilbert’s inequality. In 1999, Kuang [5] gave a generalization with a parameterλof (1.1) as follows:
(1.3)
Z ∞ 0
Z ∞ 0
f(x)g(y)
xλ+yλ dxdy < hλ(p) Z ∞
0
x1−λfp(x)dx
1p Z ∞ 0
x1−λgq(x)dx 1q
,
wheremaxn
1 p,1qo
< λ ≤ 1, hλ(p) = πh
λsinp1
π pλ
sin1q
π qλ
i−1
. Because of the constant factorhλ(p)being not the best possible, Yang [8] gave a new generalization of (1.1) in 2002 as follows:
(1.4) Z ∞
0
Z ∞ 0
f(x)g(y) xλ+yλ dxdy
< π λsin
π p
Z ∞
0
x(1−λ)(p−1)fp(x)dx
1pZ ∞ 0
x(1−λ)(q−1)gq(x)dx 1q
,
its equivalent form is:
(1.5)
Z ∞ 0
yλ−1 Z ∞
0
f(x) xλ+yλdx
p
dy <
π λsin
π p
p
Z ∞ 0
x(1−λ)(p−1)fp(x)dx,
where the constant factors π
λsin(πp) in (1.4) and
π λsin(πp)
p
in (1.5) are all the best possible.
At present, because of the requirement of higher-dimensional harmonic analysis and higher- dimensional operator theory, multiple Hardy-Hilbert integral inequalities have been studied.
Hong [11] obtained: If a > 0, Pn i=1
1
pi = 1, pi > 1, fi ≥ 0, ri = p1
i
Qn
j=1pj, λ >
1 a
n−1− r1
i
,i= 1,2, . . . , n, then
(1.6) Z ∞
α
· · · Z ∞
α
1 [Pn
i=1(xi−αi)a]λ
n
Y
i=1
fi(x)dx1· · ·dxn ≤ Γn−2 α1 αn−1Γ(λ)
×
n
Y
i=1
Γ
1 a
1− 1
ri
Γ
λ− 1 a
n−1− 1 ri
Z ∞ α
(t−α)n−1−αλfipidt pi1
.
Afterwards, Bicheng Yang and Kuang Jichang etc. obtained some multiple Hardy-Hilbert integral inequalities (see [9, 6]).
In this paper, by introducing the Γ-function, we generalize (1.3) and (1.4) into multiple Hardy-Hilbert integral inequalities with the best constant factors.
2. SOME LEMMAS
First of all, we introduce the signs as:
Rn+ ={x= (x1, . . . , xn) :x1, . . . , xn>0},
kxkα = (xα1 +· · ·+xαn)α1, α >0.
Lemma 2.1 (see [1]). Ifpi >0,ai >0,αi >0,i= 1,2, . . . , n,Ψ(u)is a measurable function, then
(2.1) Z
. . . Z
x1,...,xn>0;
x
1 a1
α1
+···+(xnan)αn≤1 Ψ
x1 a1
α1
+· · ·+ xn
an αn
×xp11−1· · ·xpnn−1dx1· · ·dxn
=
ap11· · ·apnnΓ
p1
α1
· · ·Γ
pn
αn
α1· · ·αnΓ
p1
α1 +· · ·+ αpn
n
Z 1
0
Ψ(u)u
p1
α1+···+pnαn−1
du.
whereΓ(·)is theΓ-function.
Lemma 2.2. Ifp > 1, 1p+1q = 1,n∈Z+,α >0,λ >0, setting the weight functionωα,λ(x, p, q) as:
ωα,λ(x, p, q) = Z
Rn+
1 kxkλα+kykλα
kxk
1 q
α
kyk
1
αp
(n−λ)p
kxkα kykα
λq dy,
then
(2.2) ωα,λ(x, p, q) =kxk(n−λ)(p−1)α πΓn α1 sin
π p
λαn−1Γ αn.
Proof. By Lemma 2.1, we have
ωα,λ(x, p, q) =kxk(n−λ)(p−1)+λq α
Z
Rn+
1
kxkλα+kykλαkyk−(n−λ+λq)
α dy
=kxk(n−λ)(p−1)+λ
α q lim
r→+∞
Z
· · · Z
y1,...,yn>0;yα1+···+yαn<rα
× h
r yr1α
+· · ·+ yrnαα1i−(n−λ+λq)
kxkλα+h
r yr1α
+· · ·+ yrnαα1iλy11−1· · ·yn1−1dy1· · ·dyn
=kxk(n−λ)(p−1)+λq
α lim
r→+∞
rnΓn α1 αnΓ nα
Z 1 0
ruα1−(n−λ+λq)
kxkλα+
ruα1λunα−1du
=kxk(n−λ)(p−1)+λq α
Γn α1
αn−1Γ nα lim
r→+∞
Z r 0
1
kxkλα+uλuλ−λq−1du
=kxk(n−λ)(p−1)+λq α
Γn α1 αn−1Γ nα
Z ∞ 0
1
kxkλα+uλuλ−λq−1du
=kxk(n−λ)(p−1)α Γn α1 λαn−1Γ nα
Z ∞ 0
1
1 +uu1p−1du
=kxk(n−λ)(p−1)α Γn α1 λαn−1Γ nαΓ
1 p
Γ
1− 1
p
=kxk(n−λ)(p−1)α πΓn α1 sin
π p
λαn−1Γ αn,
hence (2.2) is valid.
Lemma 2.3. Ifp >1, 1p+1q = 1,n ∈Z+,α >0,λ >0,0< ε < λ(q−1), settingω˜α,λ(x, q, ε) as:
˜
ωα,λ(x, q, ε) = Z
Rn+
1
kxkλα+kykλαkyk−
(n−λ)(q−1)+n+ε
α q dy,
then we have
(2.3) ω˜α,λ(x, q, ε) =kxk−
λ q−εq α
Γn α1 λαn−1Γ nαΓ
1 p− ε
λq
Γ 1
q + ε λq
.
Proof. Lemma 2.3 can be proved in the same manner as Lemma 2.2.
3. MAINRESULTS
Theorem 3.1. Ifp >1, 1p +1q = 1,n∈Z+,α >0,λ >0,f ≥0,g ≥0, and
(3.1) 0<
Z
Rn+
kxk(n−λ)(p−1)α fp(x)dx <∞, 0<
Z
Rn+
kxk(n−λ)(q−1)α gq(x)dx <∞,
then
(3.2) Z
Rn+
Z
Rn+
f(x)g(y)
kxkλα+kykλαdxdy < πΓn α1 sin
π p
λαn−1Γ nα
× Z
Rn+
kxk(n−λ)(p−1)α fp(x)dx
!1p Z
Rn+
kxk(n−λ)(q−1)α gq(x)dx
!1q
;
(3.3)
Z
Rn+
kykλ−nα Z
Rn+
f(x)
kxkλα+kykλαdx
!p
dy
<
πΓn α1 sin
π p
λαn−1Γ nα
p
Z
Rn+
kxk(n−λ)(p−1)α fp(x)dx,
where the constant factors πΓ
n(α1)
sin(πp)λαn−1Γ(nα) and
πΓn(α1)
sin(πp)λαn−1Γ(nα) p
are all the best possible.
Proof. By Hölder’s inequality, we have
A:=
Z
Rn+
Z
Rn+
f(x)g(y)
kxkλα+kykλαdxdy
= Z
Rn+
Z
Rn+
f(x) (kxkλα+kykλα)p1
kxk
1 q
α
kyk
1
αp
n−λ
kxkα kykα
pqλ
× g(y)
(kxkλα+kykλα)1q
kyk
1 p
α
kxk
1
αq
n−λ
kykα kxkα
pqλ dxdy
≤
Z
Rn+
Z
Rn+
fp(x) kxkλα+kykλα
kxk
1
αq
kyk
1 p
α
(n−λ)p
kxkα kykα
λq dxdy
1 p
×
Z
Rn+
Z
Rn+
gq(x) kxkλα+kykλα
kyk
1
αp
kxk
1 q
α
(n−λ)q
kykα kxkα
λp dxdy
1 q
=
Z
Rn+
fp(x)
Z
Rn+
1 kxkλα+kykλα
kxk
1
αq
kyk
1 p
α
(n−λ)p
kxkα kykα
λq dy
dx
1 p
×
Z
Rn+
gq(y)
Z
Rn+
1 kxkλα+kykλα
kyk
1
αp
kxk
1 q
α
(n−λ)q
kykα kxkα
λp dx
dy
1 q
= Z
Rn+
fp(x)ωα,λ(x, p, q)dx
!1p Z
Rn+
gq(y)ωα,λ(y, q, p)dy
!1q ,
according to the condition of taking equality in Hölder’s inequality, if this inequality takes the form of an equality, then there exist constantsC1 andC2, such that they are not all zero, and
C1fp(x) kxkλα+kykλα
kxk
1 q
α
kyk
1 p
α
(n−λ)p
kxkα
kykα λq
= C2gq(y) kxkλα+kykλα
kyk
1 p
α
kxk
1 q
α
(n−λ)q
kykα kxkα
λp
, a.e. inRn+×Rn+, it follows that
C1kxk(n−λ)(p−1)+n
α fp(x) = C2kyk(n−λ)(q−1)+n
α gq(y) =C (constant), a.e. in Rn+×Rn+, which contradicts (3.1), hence we have
A <
Z
Rn+
fp(x)ωα,λ(x, p, q)dx
!1p Z
Rn+
gq(y)ωα,λ(y, q, p)dy
!1q .
By Lemma 2.2 andsin
π p
= sin(πq), we have
A <
πΓn α1 sin
π p
λαn−1Γ αn
1 p
Z
Rn+
kxk(n−λ)(p−1)α fp(x)dx
!1p
×
"
πΓn α1 sin(πq)λαn−1Γ nα
#1q Z
Rn+
kyk(n−λ)(q−1)α gq(y)dy
!1q
= πΓn α1 sin
π p
λαn−1Γ nα Z
Rn+
kxk(n−λ)(p−1)α fp(x)dx
!1p Z
Rn+
kxk(n−λ)(q−1)α gq(x)dx
!1q .
Hence (3.2) is valid.
For0< a < b <∞, setting
ga,b(y) =
kykλ−nα R
Rn+
f(x)
kxkλα+kykλαdxp−1
, a <kykα < b,
0, 0<kykα ≤a or kykα ≥b,
˜
g(y) = kykλ−nα Z
Rn+
f(x)
kxkλα+kykλαdx
!p−1
, y∈Rn+,
by (3.1), for sufficiently smalla >0and sufficiently largeb > 0, we have
0<
Z
a<kykα<b
kyk(n−λ)(q−1)α gqa,b(y)dy <∞.
Hence by (3.2), we have Z
a<kykα<b
kyk(n−λ)(q−1)α g˜q(y)dy
= Z
a<kykα<b
kykλ−nα Z
Rn+
f(x) kxkλα+kykλαdx
!p
dy
= Z
a<kykα<b
kykλ−nα Z
Rn+
f(x) kxkλα+kykλαdx
!p−1
Z
Rn+
f(x)
kxkλα+kykλαdx
! dy
= Z
Rn+
Z
Rn+
f(x)ga,b(y) kxkλα+kykλαdxdy
< πΓn α1 sin
π p
λαn−1Γ nα Z
Rn+
kxk(n−λ)(p−1)α fp(x)dx
!1p
× Z
Rn+
kyk(n−λ)(q−1)α gqa,b(y)dy
!1q
= πΓn α1 sin
π p
λαn−1Γ nα Z
Rn+
kxk(n−λ)(p−1)α fp(x)dx
!1p
× Z
a<kykα<b
kyk(n−λ)(q−1)α ˜gq(y)dy 1q
,
it follows that
Z
a<kykα<b
kyk(n−λ)(q−1)α g˜q(y)dy <
πΓn α1 sin
π p
λαn−1Γ nα
p
Z
Rn+
kxk(n−λ)(p−1)α fp(x)dx.
Fora→0+,b→+∞, by (3.1), we obtain
0<
Z
Rn+
kyk(n−λ)(q−1)α g˜q(y)dy
≤
πΓn α1 sin
π p
λαn−1Γ αn
p
Z
Rn+
kxk(n−λ)(p−1)α fp(x)dx <∞,
hence by (3.2), we have
Z
Rn+
kykλ−nα Z
Rn+
f(x)
kxkλα+kykλαdx
!p
dy
= Z
Rn+
Z
Rn+
f(x)˜g(y)
kxkλα+kykλαdxdy
< πΓn α1 sin
π p
λαn−1Γ nα Z
Rn+
kxk(n−λ)(p−1)α fp(x)dx
!1p Z
Rn+
kyk(n−λ)(q−1)α g˜q(y)dy
!1q
= πΓn α1 sin
π p
λαn−1Γ nα Z
Rn+
kxk(n−λ)(p−1)α fp(x)dx
!1p
×
"
Z
Rn+
kykλ−nα Z
Rn+
f(x) kxkλα+kykλαdx
!p
dy
#1q ,
it follows that Z
Rn+
kykλ−nα Z
Rn+
f(x)
kxkλα+kykλαdx
!p
dy
<
πΓn α1 sin
π p
λαn−1Γ nα
p
Z
Rn+
kxk(n−λ)(p−1)α fp(x)dx.
Hence (3.3) is valid.
Remark 3.2. By (3.3), we can also obtain (3.2), hence (3.3) and (3.2) are equivalent.
If the constant factor Cn,α(λ, p) := πΓ
n(α1)
sin(πp)λαn−1Γ(nα) in (3.2) is not the best possible, then there exists a positive constantK < Cn,α(λ, p), such that
(3.4) Z
Rn+
Z
Rn+
f(x)g(y)
kxkλα+kykλαdxdy
< K Z
Rn+
kxk(n−λ)(p−1)α fp(x)dx
!p1 Z
Rn+
kyk(n−λ)(q−1)α gq(y)dy
!1q .
In particular, setting f(x) = kxk−
(n−λ)(p−1)+n+ε p
α , g(y) =kyk−
(n−λ)(q−1)+n+ε q
α , 0< ε < λ(q−1), (3.4) is still true. By the properties of limit, there exists a sufficiently smalla >0, such that
Z
kxkα>a
Z
Rn+
1
kxkλα+kykλαkxk−
(n−λ)(p−1)+n+ε p
α kyk−
(n−λ)(q−1)+n+ε q
α dxdy
< K Z
kxkα>a
kxk(n−λ)(p−1)α kxk−(n−λ)(p−1)−n−ε
α dx
1p
× Z
kykα>a
kyk(n−λ)(q−1)α kyk−(n−λ)(q−1)−n−ε
α dy
1q
=K Z
kxkα>a
kxk−n−εα dx.
On the other hand, by Lemma 2.3, we have Z
kxkα>a
Z
Rn+
1
kxkλα+kykλαkxk−
(n−λ)(p−1)+n+ε p
α kyk−
(n−λ)(q−1)+n+ε q
α dxdy
= Z
kxkα>a
kxk−n+
λ q−pε α
Z
Rn+
1
kxkλα+kykλαkyk−
(n−λ)(q−1)+n+ε q
α dydx
= Z
kxkα>a
kxk−n+
λ q−ε
α pω˜α,λ(x, q, ε)dx
= Γn α1 λαn−1Γ nαΓ
1 p− ε
λq
Γ 1
q + ε λq
Z
kxkα>a
kxk−n−εα dx,
hence we obtain
Γn α1 λαn−1Γ nαΓ
1 p − ε
λq
Γ 1
q + ε λq
< K.
Forε→0+, we have
Cn,α(λ, p) = πΓn α1 sin
π p
λαn−1Γ nα ≤K,
this contradicts the fact that K < Cn,α(λ, p).Hence the constant factor in (3.2) is the best possible.
Since (3.3) and (3.2) are equivalent, the constant factor in (3.3) is also the best possible.
Corollary 3.3. Ifp >1, 1p +1q = 1,n∈Z+,α >0,f ≥0,g ≥0, and
(3.5) 0<
Z
Rn+
fp(x)dx <∞, 0<
Z
Rn+
gq(x)dx <∞,
then
(3.6)
Z
Rn+
Z
Rn+
f(x)g(y)
kxknα+kyknαdxdy
< πΓn α1 sin
π p
nαn−1Γ nα Z
Rn+
fp(x)dx
!1p Z
Rn+
gq(x)dx
!1q
;
(3.7)
Z
Rn+
Z
Rn+
f(x)
kxknα+kyknαdx
!p
dy <
πΓn 1α sin
π p
nαn−1Γ αn
p
Z
Rn+
fp(x)dx,
where the constant factors in (3.6) and (3.7) are all the best possible.
Proof. By takingλ =nin Theorem 3.1, (3.6) and (3.7) can be obtained.
Corollary 3.4. Ifp >1, 1p +1q = 1,n∈Z+,f ≥0,g ≥0, and
(3.8) 0<
Z
Rn+
fp(x)dx <∞, 0<
Z
Rn+
gq(x)dx <∞,
then
(3.9)
Z
Rn+
Z
Rn+
f(x)g(y) (Pn
i=1xi)n+ (Pn
i=1yi)ndxdy
< π n! sin
π p
Z
Rn+
fp(x)dx
!1p Z
Rn+
gq(x)dx
!1q
;
(3.10) Z
Rn+
Z
Rn+
f(x) (Pn
i=1xi)n+ (Pn
i=1yi)ndx
!p
dy <
π n! sin
π p
p
Z
Rn+
fp(x)dx,
where the constant factors in (3.9) and (3.10) are all the best possible.
Proof. By takingα = 1in Corollary 3.3, (3.9) and (3.10) can be obtained.
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