volume 7, issue 4, article 153, 2006.
Received 07 February, 2006;
accepted 13 April, 2006.
Communicated by:B. Yang
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Journal of Inequalities in Pure and Applied Mathematics
BEST GENERALIZATION OF HARDY-HILBERT’S INEQUALITY WITH MULTI-PARAMETERS
DONGMEI XIN
Department of Mathematics Guangdong Education College Guangzhou, Guangdong 510303 People’s Republic Of China.
EMail:xdm77108@gdei.edu.cn
c
2000Victoria University ISSN (electronic): 1443-5756 034-06
Best Generalization of Hardy-Hilbert’s Inequality With
Multi-Parameters Dongmei Xin
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Abstract
By introducing some parameters and theβfunction and improving the weight function, we obtain a generalization of Hilbert’s integral inequality with the best constant factor. As its applications, we build its equivalent form and some par- ticular results.
2000 Mathematics Subject Classification:26D15.
Key words: Hardy-Hilbert’s inequality, Hölder’s inequality, weight function, βfunc- tion.
Contents
1 Introduction. . . 3 2 Some Lemmas. . . 7 3 Main Results and Applications . . . 9
References
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1. Introduction
Ifp > 1, 1p+1q = 1, f, gare non-negative functions such that0<R∞
0 fp(t)dt <
∞and0<R∞
0 gq(t)dt <∞, then we have (1.1)
Z ∞ 0
Z ∞ 0
f(x)g(y)
x+y dxdy < π sin(πp)
Z ∞ 0
fp(t)dt
1pZ ∞ 0
gq(t)dt 1q
;
(1.2)
Z ∞ 0
Z ∞ 0
f(x) x+ydx
p
dy <
"
π sin(πp)
#p
Z ∞ 0
fp(t)dt, where the constant factors sin(π/p)π and
h π sin(π/p)
ip
are the best possible (see [1]).
Inequality (1.1) is well known as Hardy-Hilbert’s integral inequality, which is important in analysis and applications (see [2]). Inequality (1.1) is equivalent to (1.2).
In 2002, Yang [3] gave some generalizations of (1.1) and (1.2) by introducing a parameterλ >0as:
(1.3) Z ∞
0
Z ∞ 0
f(x)g(y) xλ+yλ dxdy
< π λsin(πp)
Z ∞ 0
t(p−1)(1−λ)fp(t)dt p1
× Z ∞
0
t(q−1)(1−λ)gq(t)dt 1q
;
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(1.4)
Z ∞ 0
yλ−1 Z ∞
0
f(x) xλ+yλdx
p
dy
<
"
π λsin(πp)
#p
Z ∞ 0
t(p−1)(1−λ)fp(t)dt,
where the constant factors λsin(π/p)π andh
π λsin(π/p)
ip
are the best possible. In- equality (1.3) is equivalent to (1.4).
Whenλ = 1, both (1.3) and (1.4) change to (1.1) and (1.2). Yang [4] gave another generalization of (1.1) by introducing a parameterλand aβfunction.
In 2004, by introducing some parameters and estimating the weight function, Yang [5] gave some extensions of (1.1) and (1.2) with the best constant factors as:
(1.5) Z ∞
0
Z ∞ 0
f(x)g(y) xλ+yλ dxdy
< π λsin(πr)
Z ∞ 0
xp(1−λr)−1fp(x)dx
1p Z ∞ 0
xq(1−λs)−1gq(x)dx 1q
;
(1.6)
Z ∞ 0
ypλs−1 Z ∞
0
f(x) xλ+yλdx
p
dy
<
π λsin(πr)
pZ ∞ 0
xp(1−λr)−1fp(x)dx,
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where the constant factors λsin(π/r)π andh
π λsin(π/r)
ip
are the best possible. In- equality (1.5) is equivalent to (1.6). Recently, [6, 7, 8, 9] considered some multiple extensions of (1.1).
Under the same conditions with (1.1), we still have (see [1, Th. 342]):
(1.7) Z ∞
0
Z ∞ 0
ln
x y
f(x)g(y) x−y dxdy
<
"
π sin(πp)
#2
Z ∞ 0
fp(t)dt
1pZ ∞ 0
gq(t)dt 1q
;
(1.8)
Z ∞ 0
ln
x y
f(x) x−y dx
p
dy <
"
π sin(πp)
#2p
Z ∞ 0
fp(t)dt,
where the constant factorsh
π sin(π/p)
i2
andh
π sin(π/p)
i2p
are the best possible. In- equality (1.7) is equivalent to (1.8). In recent years, by introducing a parameter λ, Kuang [10] gave an new extension of (1.7).
In 2003, by introducing a parameterλ > 0and the weight function, Yang [11] gave another generalisation of (1.7) and the extended equivalent form as:
(1.9) Z ∞
0
Z ∞ 0
ln
x y
f(x)g(y) xλ−yλ dxdy
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<
"
π λsin(πp)
#2
Z ∞ 0
t(p−1)(1−λ)fp(t)dt
1pZ ∞ 0
t(q−1)(1−λ)gq(t)dt 1q
;
(1.10)
Z ∞ 0
yλ−1
ln
x y
f(x) xλ−yλ dx
p
dy
<
"
π λsin(πp)
#2p
Z ∞ 0
t(p−1)(1−λ)fp(t)dt,
where the constant factors h
π λsin(π/p)
i2
and h
π λsin(π/p)
i2p
are the best possible.
Inequality (1.9) is equivalent to (1.10).
In this paper, by using the β function and obtaining the expression of the weight function, we give a new extension of (1.7) with some parameters as (1.5). As applications, we also consider the equivalent form and some other particular results.
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2. Some Lemmas
Lemma 2.1. If p > 1, 1p + 1q = 1, r > 1, 1s + 1r = 1, λ > 0,define the weight functionωλ(s, p, x)as
(2.1) ωλ(s, p, x) = Z ∞
0
ln
x y
xλ−yλ ·x(p−1)(1−λr)
y1−λs dy, x∈(0,∞).
Then we have
(2.2) ωλ(s, p, x) = xp(1−λr)−1 π
λsin(πr) 2
.
Proof. For fixedx, settingu= (yx)λ in the integral (2.1) and by [1] (see [1, Th.
342 Remark]), we have ωλ(s, p, x) = 1
λ2 Z ∞
0
lnu
xλ(u−1)· x(p−1)(1−λr)
(u1λx)1−λs xuλ1−1du (2.3)
= 1
λ2xp(1−λr)−1 Z ∞
0
lnu
u−1·u−1rdu
= π
λsin(πr) 2
xp(1−λr)−1. Hence, (2.2) is valid and the lemma is proved.
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Note. By (2.3), we still have
ωλ(r, q, y) = Z ∞
0
ln
x y
xλ −yλ ·x(q−1)(1−λs) y1−λr dx (2.4)
=yq(1−λs)−1 π
λsin(πs) 2
.
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3. Main Results and Applications
Theorem 3.1. Ifp > 1, 1p+1q = 1, r > 1, 1s+1r = 1, λ >0, f, g ≥0such that 0<R∞
0 xp(1−λr)−1fp(x)dx <∞,and0<R∞
0 xq(1−λs)−1gq(x)dx <∞,then we have
(3.1) Z ∞
0
Z ∞ 0
ln
x y
f(x)g(y) xλ−yλ dxdy
<
π λsin(πr)
2Z ∞ 0
xp(1−λr)−1fp(x)dx 1p
× Z ∞
0
xq(1−λs)−1gq(x)dx 1q
, where the constant factorh
π λsin(π/r)
i2
is the best possible. In particular, (a) forr =s= 2,we have
(3.2) Z ∞
0
Z ∞ 0
ln
x y
f(x)g(y) xλ−yλ dxdy
<
π λ
2Z ∞ 0
xp(1−λ2)−1fp(x)dx 1p
× Z ∞
0
xq(1−λ2)−1gq(x)dx 1q
,
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(b) forλ= 1, we have (3.3)
Z ∞ 0
Z ∞ 0
ln
x y
f(x)g(y) x−y dxdy
<
π sin(πr)
2Z ∞ 0
xps−1fp(x)dx
1pZ ∞ 0
xqr−1gq(x)dx 1q
. Proof. By Hölder’s inequality and Lemma2.1, we have
Z ∞ 0
Z ∞ 0
ln
x y
f(x)g(y) xλ−yλ dxdy (3.4)
= Z ∞
0
Z ∞ 0
ln
x y
xλ−yλ
1 p
· x(1−λr)/q y(1−λs)/pf(x)
×
ln
x y
xλ−yλ
1 q
· y(1−λs)/p x(1−λr)/qg(y)
dxdy
≤
Z ∞
0
Z ∞
0
ln x
y
xλ−yλ · x(p−1)(1−λr) y(1−λs) dy
fp(x)dx
1 p
×
Z ∞
Z ∞ ln x
y
xλ−yλ · y(q−1)(1−λs)
(1−λ) dx
gq(y)dy
1 q
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= Z ∞
0
ωλ(s, p, x)fp(x)dx
1pZ ∞ 0
ωλ(r, q, y)gq(y)dy 1q
.
If (3.4) takes the form of equality, then there exist constantsAandB, such that they are not all zero and (see [12])
A ln
x y
xλ−yλ ·x(p−1)(1−λr)
y1−λs fp(x) = B ln
x y
xλ−yλ · y(q−1)(1−λs) x1−λr gq(y), a.e. in (0,∞)×(0,∞).
We find thatAx·xp(1−λr)−1fp(x) =By·yq(1−λs)−1gq(y),a.e. in(0,∞)×(0,∞).
Hence there exists a constantC, such that
Ax·xp(1−λr)−1fp(x) = C=By·yq(1−λs)−1gq(y), a.e. in (0,∞).
Without loss of generality, suppose A 6= 0, we may get xp(1−λr)−1fp(x) = C/(Ax), a.e. in (0,∞), which contradicts 0 < R∞
0 xp(1−λr)−1fp(x)dx < ∞.
Hence (3.4) takes strict inequality as follows:
(3.5) Z ∞
0
Z ∞ 0
ln
x y
f(x)g(y) xλ−yλ dxdy
<
Z ∞ 0
ωλ(s, p, x)fp(x)dx
1pZ ∞ 0
ωλ(r, q, y)gq(y)dy 1q
. In view of (2.2) and (2.4), we have (3.1).
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If the constant factor h π
λsin(π/r)
i2
in (3.1) is not the best possible, then there exists a positive constantK
withK <h
π λsin(π/r)
i2
and ana >0. We have
(3.6) Z ∞
a
Z ∞ 0
ln
x y
f(x)g(y) xλ−yλ dxdy
< K Z ∞
a
xp(1−λr)−1fp(x)dx
1p Z ∞ a
xq(1−λs)−1gq(x)dx 1q
. Forε >0small enough ε < pλr
and0< b < a,settingfεandgεas:
fε(x) =gε(x) = 0, x∈(0, b);
fε=x−1−εp+λr, gε=x−1−εq+λs, x∈[b,∞), then we find
(3.7) Z ∞
a
Z ∞ b
ln x
y
fε(x)·gε(y) xλ−yλ dxdy
= Z ∞
a
Z ∞ b
ln
x y
x−1−εp+λr ·y−1−εq+λs xλ−yλ dxdy.
In (3.7), forb→0+,by (3.6), we have 1 Z ∞
lnu
u−1+1s−qλε du=ε
Z ∞Z ∞ln
x y
fε(x)gε(y)
dxdy≤ K .
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Forε+→0,by [1] (see [1, Th. 342 Remark]), it follows that h π
λsin(π/r)
i2
≤K, which contradicts the fact that K < h
π λsin(π/r)
i2
. Hence the constant factor h π
λsin(π/r)
i2
in (3.1) is the best possible. The theorem is proved.
Theorem 3.2. Ifp > 1, 1p + 1q = 1, r > 1, 1s + 1r = 1, λ >0, f ≥ 0such that 0<R∞
0 xp(1−λr)−1fp(x)dx <∞, then we have (3.8)
Z ∞ 0
ypλs−1
Z ∞
0
ln
x y
f(x) xλ−yλ dx
p
dy
<
π λsin(πr)
2pZ ∞ 0
xp(1−λr)−1fp(x)dx,
where the constant h π
λsin(π/r)
i2p
is the best possible. Inequality (3.8) is equiva- lent to (3.1). In particular,
(a) forr =s= 2, we have
(3.9)
Z ∞ 0
ypλ2 −1
Z ∞
0
ln
x y
f(x) xλ−yλ dx
p
dy
<π λ
2pZ ∞ 0
xp(1−λ2)−1fp(x)dx,
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(b) forλ= 1, we have
(3.10)
Z ∞ 0
yps−1
Z ∞
0
ln x
y
f(x) x−y dx
p
dy
<
π sin(πr)
2pZ ∞ 0
xps−1fp(x)dx.
Proof. Setting a real functiong(y)as
g(y) = ypλs −1
Z ∞
0
ln
x y
f(x) xλ−yλ dx
p−1
, y∈(0,∞), then by (3.1), we find
Z ∞ 0
yq(1−λs)−1gq(y)dy p
(3.11)
=
Z ∞
0
ypλs −1
Z ∞
0
ln x
y
f(x) xλ−yλ dx
p
dy
p
=
Z ∞
0
Z ∞ 0
ln
x y
f(x)g(y) xλ −yλ dxdy
p
≤
π 2pZ ∞
xp(1−λr)−1fp(x)dx
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× Z ∞
0
xq(1−λs)−1gq(x)dx p−1
. Hence we obtain
(3.12) 0<
Z ∞ 0
yq(1−λs)−1gq(y)dy
≤
π λsin(πr)
2pZ ∞ 0
xp(1−λr)−1fp(x)dx <∞.
By (3.1), both (3.11) and (3.12) take the form of strict inequality, and we have (3.8).
On the other hand, suppose that (3.8) is valid. By Hölder’s inequality, we find
Z ∞ 0
Z ∞ 0
ln
x y
f(x)g(y) xλ−yλ dxdy (3.13)
= Z ∞
0
yλs−1p Z ∞
0
ln
x y
f(x) xλ−yλ dx
h
y−λs+1pg(y)i dy
≤
Z ∞
0
ypλs −1
Z ∞
0
ln
x y
f(x) xλ−yλ dx
p
dy
1 p
× Z ∞
0
yq(1−λs)−1gq(y)dy 1q
.
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Then by (3.8), we have (3.1). Hence (3.1) and (3.8) are equivalent.
If the constant h π
λsin(π/r)
i2p
in (3.8) is not the best possible, by using (3.13), we may get a contradiction that the constant factor in (3.1) is not the best possi- ble. Thus we complete the proof of the theorem.
Remark 1.
(a) For r = q, s = p,Inequality (3.1) reduces to (1.9) and (3.8) reduces to (1.10).
(b) Inequality (3.1) is an extension of (1.7) with parameters(λ, r, s).
(c) It is interesting that inequalities (1.9) and (3.2) are different, although they have the same parameters and possess a best constant factor.
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[9] M. KRNI ´CANDJ. PE ˇCARI ´C, General Hilbert’s and Hardy’s inequalities, Math. Inequal. & Applics., 8(1) (2005), 29–51.
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[10] JICHANG KUANG AND L. DEBNATH, On new generalizations of Hilbert’s inequality and their applications, J. Math. Anal. Appl., 245 (2000), 248–265.
[11] BICHENG YANG, On a generalization of a Hilbert’s type integral inequal- ity and its applications, Mathematics Applications, 16(2) (2003), 82–86.
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