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Key words and phrases: Differential inequalities,n-fold symmetric functions, analytic functions of Koebe type, starlike func- tions, strongly starlike functions, Jack’s Lemma

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Volume 5, Issue 3, Article 57, 2004

A SUFFICIENT CONDITION FOR STARLIKENESS OF ANALYTIC FUNCTIONS OF KOEBE TYPE

MUHAMMET KAMALI AND H.M. SRIVASTAVA MATEMATIKBÖLÜMÜ

FEN-EDEBIYATFAKÜLTESI

ATATÜRKÜNIVERSITESI, TR-25240 ERZURUM

TURKEY

mkamali@atauni.edu.tr

DEPARTMENT OFMATHEMATICS ANDSTATISTICS

UNIVERSITY OFVICTORIA

VICTORIA, BRITISHCOLUMBIAV8W 3P4 CANADA

harimsri@math.uvic.ca

Received 18 April, 2004; accepted 25 May, 2004 Communicated by Th.M. Rassias

ABSTRACT. By making use of Jack’s Lemma as well as several differential and other inequal- ities (and parametric constraints), the authors derive sufficient conditions for starlikeness of a certain class ofn-fold symmetric analytic functions of Koebe type. Relevant connections of the results presented here with those given in earlier works are also indicated.

Key words and phrases: Differential inequalities,n-fold symmetric functions, analytic functions of Koebe type, starlike func- tions, strongly starlike functions, Jack’s Lemma.

2000 Mathematics Subject Classification. Primary 30C45; Secondary 30A10, 30C80.

1. INTRODUCTION, DEFINITIONS ANDPRELIMINARIES

LetAdenote the class of functionsf which are analytic in the open unit disk U={z :z ∈C and |z|<1}

and normalized by

f(0) =f0(0)−1 = 0.

Also, as usual, let

(1.1) S =

f :f ∈ A and R

zf0(z) f(z)

>0 (z ∈U)

ISSN (electronic): 1443-5756 c

2004 Victoria University. All rights reserved.

The present investigation was supported, in part, by the Natural Sciences and Engineering Research Council of Canada under Grant OGP0007353.

102-04

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and

(1.2) S˜(α) =

f :f ∈ A and

arg

zf0(z) f(z)

< απ

2 (z ∈U; 0< α51)

be the familiar classes of starlike functions inUand strongly starlike functions of orderαinU (0< α51),respectively. We note that

(α)⊂ S (0< α <1) and S˜(1)≡ S. We denote byH(α)the class of functionsf ∈ Adefined by

(1.3) H(α) :=

f :f ∈ A and R

αz2 f00(z)

f(z) +z f0(z) f(z)

>0

f(z)

z 6= 0; z ∈U; α=0

, so that, as already observed by Ramesha et al. [6], we have the following inclusion relationships (cf. [6]):

(1.4) H(α)⊂ S and H(1) ⊂S˜

1 2

.

In fact, a sharper inclusion relationship than the second one in (1.4) was given subsequently by Nunokawa et al. [4] as follows:

(1.5) H(1) ⊂S˜(β)

β < 1

2

.

Obradovi´c and Joshi [5], on the other hand, made use of the method of differential inequalities in order to derive several other related results for classes of strongly starlike functions inU.

Motivated essentially by the aforementioned earlier works, we aim here at deriving sufficient conditions for starlikeness of ann-fold symmetric functionfb(z)of Koebe type, defined by

(1.6) fb(z) := z

(1−zn)b (b=0; n ∈N:={1,2,3, . . .}), which obviously corresponds to the familiar Koebe function when

n= 1 and b= 2.

The following result (popularly known as Jack’s Lemma) will also be required in the deriva- tion of our main result (Theorem 1 below).

Lemma 1 (Jack [2]). Let the(nonconstant)functionw(z)be analytic in|z|< ρwithw(0) = 0.

If|w(z)|attains its maximum value on the circle|z|=r < ρat a pointz0,then z0w0(z0) =kw(z0),

wherekis a real number andk =1.

2. THEMAINRESULT AND ITS CONSEQUENCES

We begin by proving a stronger result than what we indicated in the preceding section.

Theorem 1. Let then-fold symmetric functionfb(z), defined by(1.6), be analytic inUwith fb(z)

z 6= 0 (z ∈U).

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(i) Iffb(z)satisfies the inequality:

(2.1) R

αz2fb00(z)

fb(z) +zfb0(z) fb(z)

>− αnb 4 +

1− nb

2 1− αnb 2

(z ∈U),

thenfb(z)is starlike inUfor

α >0 and 3α+ 2−√

2α 5nb5 3α+ 2 +√

∆ 2α

∆ := 9α2−4α+ 4 .

(ii) Iffb(z)satisfies the inequality(2.1)withα= 0, that is, if

(2.2) R

zfb0(z) fb(z)

>1− nb

2 (z ∈U),

thenfb(z)is starlike inUfor05nb52.

Proof. (i) Letα >0andfb(z)satisfy the hypotheses of Theorem 1. We put zfb0(z)

fb(z) = 1 + (nb−1)w(z) 1−w(z) , wherew(z)is analytic inUwith

w(0) = 0 and w(z)6= 1 (z ∈U). Then we have

{fb0(z) +zfb00(z)}fb(z)−z{fb0(z)}2 {fb(z)}2

= (nb−1)w0(z){1−w(z)}+w0(z){1 + (nb−1)w(z)}

{1−w(z)}2 ,

which implies that

(2.3) z fb00(z)

fb(z) +fb0(z) fb(z)−z

fb0(z) fb(z)

2

= nbw0(z) {1−w(z)}2. On the other hand, we can write

z2 fb00(z)

fb(z) = nbzw0(z)

{1−w(z)}2 −1 + (nb−1)w(z) 1−w(z) +

1 + (nb−1)w(z) 1−w(z)

2

,

that is,

αz2 fb00(z) fb(z) =α

"

nbzw0(z) {1−w(z)}2 +

1 + (nb−1)w(z) 1−w(z)

2#

−α· 1 + (nb−1)w(z) 1−w(z) ,

which, in turn, implies that (2.4) αz2 fb00(z)

fb(z) +z fb0(z) fb(z) = α

"

nbzw0(z) {1−w(z)}2 +

1 + (nb−1)w(z) 1−w(z)

2#

+ (1−α)1 + (nb−1)w(z) 1−w(z) .

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Now we claim that|w(z)|<1 (z ∈U). If there exists az0 inUsuch that |w(z0)|= 1,then (by Jack’s Lemma) we have

z0w0(z0) =kw(z0) (k =1). By setting

w(z0) = e (05θ <2π), we thus find that

R

αz02 fb00(z0)

fb(z0) +z0 fb0(z0) fb(z0)

=R α

"

nbz0w0(z0) (1−w(z0))2 +

1 + (nb−1)w(z0) 1−w(z0)

2#

+ (1−α)1 + (nb−1)w(z0) 1−w(z0)

!

=R α

"

nbke (1−e)2 +

1 + (nb−1)e 1−e

2#

+ (1−α)1 + (nb−1)e 1−e

!

−nbk 4 sin2

θ 2

+

1− nb 2

2

−n2b2 4

1 + cosθ 1−cosθ

+ (1−α)

1− nb 2

=−αnb 4

k+nbcos2 θ

2

sin2 θ

2

 +

1− nb

2 1− αnb 2

5−αnb 4 +

1− nb

2 1−αnb 2

(z ∈U), sincek =1.

If we let R

αz02 fb00(z0)

fb(z0) +z0 fb0(z0) fb(z0)

5−αnb 4 +

1− nb

2 1− αnb 2

(2.5)

= 1 4

α(nb)2−(3α+ 2)(nb) + 4

=:ϑ(nb) (z ∈U), then

ϑ(nb)50 3α+ 2−√

2α 5nb5 3α+ 2 +√

2α ; ∆ := 9α2−4α+ 4

! .

Thus we have

(2.6) R

αz20 fb00(z0)

fb(z0) +z0 fb0(z0) fb(z0)

50 (z∈U) 3α+ 2−√

2α 5nb5 3α+ 2 +√

2α ; ∆ := 9α2−4α+ 4

! , which is a contradiction to the hypotheses of Theorem 2.

Therefore, |w(z)| < 1 for all z in U. Hence fb(z) is starlike in U, thereby proving the assertion (i) of Theorem 1.

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(ii) The proof of the assertion (ii) of Theorem 1 was given by Fukui et al. [1], and so we omit

the details here.

Corollary 1. The following inclusion relationship holds true:

Hb(α) :=

(

fb :fb ∈ A and R

αz2 fb00(z)

fb(z) +z fb0(z) fb(z)

>0

fb(z)

z 6= 0; z ∈U; α=0 )

⊂ S

for then-fold symmetric functionfb(z)defined by(1.6).

3. APPLICATIONS OF DIFFERENTIAL INEQUALITIES

In this section, we apply the following known result involving differential inequalities with a view to deriving several further sufficient conditions for starlikeness of then-fold symmetric functionfb(z)defined by (1.6).

Lemma 2 (Miller and Mocanu [3]). LetΘ (u, v)be a complex-valued function such that Θ :D→C (D⊂C×C),

Cbeing(as usual)the complex plane,and let

u=u1+iu2 and v =v1+iv2.

Suppose that the functionΘ (u, v)satisfies each of the following conditions:

(i) Θ (u, v)is continuous inD; (ii) (1,0)∈DandR(Θ (1,0))>0;

(iii) R(Θ (iu2, v1))50for all(iu2, v1)∈Dsuch that v1 5− 1

2 1 +u22 . Let

p(z) = 1 +p1z+p2z2+· · · be analytic(regular)inUsuch that

p(z), zp0(z)

∈D (z ∈U). If

R Θ (p(z), zp0(z))

>0 (z ∈U), then

R p(z)

>0 (z ∈U). Let us now consider the following implication:

R

αz2 fb00(z)

fb(z) +z fb0(z) fb(z)

>− αnb 4 +

1− nb

2 1−αnb 2

⇒R

z fb0(z) fb(z)

µ!

>0 (3.1)

z∈U; −αnb 4 +

1− nb

2 1−αnb 2

<1; α =0; µ=1

! .

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If we put

p(z) =

z fb0(z) fb(z)

µ

,

then (3.1) is equivalent to (3.2) R α

µ{p(z)}(1−µ)/µ zp0(z) +α{p(z)}2/µ

+ (1−α){p(z)}1/µ+ αnb 4 −

1− nb

2 1− αnb 2

!

>0

⇒R p(z)

>0 (z ∈U). By setting

p(z) =u and zp0(z) =v, and letting

Θ(u, v) = α

µu(1−µ)/µv +αu2/µ+ (1−α)u1/µ+αnb 4 −

1− nb

2 1− αnb 2

, it is easy to show that, for

α=0 and µ=1, we have

(i) Θ(u, v)is continuous inD= (C\ {0})×C; (ii) (1,0)∈Dand

R Θ(1,0)

= 3αnb 4 + nb

2 − αn2b2 4 >0, since

− αnb 4 +

1− nb

2 1− αnb 2

<1.

Thus the conditions (i) and (ii) of Lemma 2 are satisfied. Moreover, for (iu2, v1)∈D such that v1 5− 1

2 1 +u22 ,

we obtain

R θ(iu2, v1)

= α

µ|u2|(1−µ)/µ v1cos

(1−µ)π 2µ

+α|u2|2/µcos π

µ

+ (1−α)|u2|1/µ cos π

+ αnb 4 −

1−nb

2 1− αnb 2

5− α

2µ(1 +u22)|u2|(1−µ)/µ sin π

+α|u2|2/µ cos π

µ

+ (1−α)|u2|1/µ cos π

+ αnb 4 −

1−nb

2 1− αnb 2

,

which, upon putting|u2|=s(s >0), yields

(3.3) R Θ (iu2, v1)

5Φ(s),

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where

(3.4) Φ(s) :=− α

2µ(1 +s2)s(1−µ)/µ sin π

+αs2/µ cos π

µ

+ (1−α)s1/µ cos π

+αnb 4 −

1− nb

2 1−αnb 2

.

Remark. If, for some choices of the parametersα, µ,andnb,we find that Φ (s)50 (s >0),

then we can conclude from(3.3)and Lemma2that the corresponding implication(3.1)holds true.

First of all, for the choice:

µ= 1 and nb= 2, we obtain

Theorem 2. If then-fold symmetric functionfb(z),defined by(1.6)and analytic inUwith fb(z)

z 6= 0 (z ∈U), satisfies the following inequality:

(3.5) R

αz2 fb00(z)

fb(z) +z fb0(z) fb(z)

>− α

2 (z ∈U), thenfb ∈ S for any realα =0.

Proof. Forµ= 1andnb= 2,we find from (3.4) that Φ(s) =− 3

2αs2 50 (s∈R),

which implies Theorem 2 in view of the above remark.

Next, for

α= 2

3, nb= 3±√

3, and µ= 2, we get

Theorem 3. If then-fold symmetric functionfb(z),defined by(1.6)and analytic inUwith fb(z)

z 6= 0 (z ∈U), satisfies the following inequality:

(3.6) R

2

3 z2 fb00(z)

fb(z) +z fb0(z) fb(z)

>0 (z∈U),

then

arg

zfb0(z) fb(z)

< π

4 (z ∈U) or,equivalently,

Hb 2

3

⊂S˜ 1

2

.

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Proof. By setting

α= 2

3, nb= 3±√

3, and µ= 2 in (3.4), we have

Φ(s) =− (1−s)2 6√

2s 50 (s >0),

which leads us to Theorem 3 just as in the proof of Theorem 2.

REFERENCES

[1] S. FUKUI, S. OWAANDK. SAKAGUCHI, Some properties of analytic functions of Koebe type, in Current Topics in Analytic Function Theory (H.M. Srivastava and S. Owa, Editors), World Scientific Publishing Company, Singapore, New Jersey, London and Hong Kong, 1992, pp. 106–117.

[2] I.S. JACK, Functions starlike and convex of orderα, J. London Math. Soc. (Ser. 2), 3 (1971), 469–

474.

[3] S.S. MILLERAND P.T. MOCANU, Second order differential inequalities in the complex plane, J.

Math. Anal. Appl., 65 (1978), 289–305.

[4] M. NUNOKAWA, S. OWA, S.K. LEE, M. OBRADOVI ´C, M.K. AOUF, H. SAITOH, A. IKEDA

ANDN. KOIKE, Sufficient conditions for starlikeness, Chinese J. Math., 24 (1996), 265–271.

[5] M. OBRADOVI ´CANDS.B. JOSHI, On certain classes of strongly starlike functions, Taiwanese J.

Math., 2 (1998), 297–302.

[6] C. RAMESHA, S. KUMAR ANDK.S. PADMANABHAN, A sufficient condition for starlikeness, Chinese J. Math., 23 (1995), 167–171.

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