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Volume 7, Issue 4, Article 140, 2006

PARTIAL SUMS OF SOME MEROMORPHIC FUNCTIONS

S. LATHA AND L. SHIVARUDRAPPA DEPARTMENT OFMATHEMATICS

MAHARAJASCOLLEGE

UNIVERSITY OFMYSORE

MYSORE- 570005, INDIA.

drlatha@gmail.com

DEPARTMENT OFMATHEMATICS, S.J.C.E VISWESHWARAYAHTECHNOLOGICALUNIVERSITY

BELGAM, INDIA.

shivarudrappa@lycos.com

Received 05 July, 2005; accepted 18 October, 2006 Communicated by G. Kohr

ABSTRACT. In the present paper we give some results concerning partial sums of certain mero- morphic functions.We also consider the partial sums of certain integral operator.

Key words and phrases: Partial sums, Meromorphic functions, Integral operators, Meromorphic starlike functions, Meromor- phic convex functions, Meromorphic close to convex functions.

2000 Mathematics Subject Classification. 30C45.

1. INTRODUCTION

LetΣbe the class consisting of functions of the form

(1.1) f(z) = 1

z +

X

k=1

akzk

which are regular in the punctured discE ={z : 0<|z| <1}with a simple pole at the origin and residue1there.

Let fn(z) = 1z +Pn

k=1akzk be thenth partial sum of the series expansion for f(z) ∈ Σ.

Let Σ(A, B), ΣK(A, B), Σc(A, B),−1 ≤ A < B ≤ 1be the subclasses of functions in Σ satisfying

(1.2) −

zf0(z) f(z)

≺ 1 +Az

1 +Bz, z ∈ U =E∪ {0}

ISSN (electronic): 1443-5756

c 2006 Victoria University. All rights reserved.

203-05

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(1.3) −

zf00(z) f0(z) + 1

≺ 1 +Az

1 +Bz, z ∈ U.

(1.4) −z2f0(z)≺ 1 +Az

1 +Bz, z ∈ U

respectively [5]. The classesΣ(2α−1,1)andΣK(2α−1,1)are respectively the well known subclasses ofΣconsisting of functions meromorphic starlike of orderαand meromorphic con- vex of orderαand meromorphically close to convex of orderα denoted byΣ(α),ΣK(α)and Σc(α)respectively.

If f(z) = 1z +P

k=1akzk and g(z) = 1z +P

k=1bkzk, then their Hadamard product (or convolution), denoted byf(z)∗g(z)is the function defined by the power series

f(z)∗g(z) = 1 z +

X

k=1

akbkzk.

In the present paper, we give sufficient conditions for f(z)to be in Σ(A, B),ΣK(A, B)and further investigate the ratio of a function of the form (1.1) to its sequence of partial sums when the coefficients are sufficiently small to satisfy conditions

X

k=1

k{k(1 +B) + (1 +A)}|ak| ≤B−A,

X

k=1

{k(1 +B) + (1 +A)}|ak| ≤B−A.

More precisely, we will determine sharp lower bounds for<n

f(z) fn(z)

o , <n

fn(z) f(z)

o , <n

f0(z) fn0(z)

o

and<nf0 n(z) f0(z)

o

.Further, we give a property for the partial sums of certain integral operators in connection with functions belonging to the classΣc(A, B).

2. SOMEPRELIMINARY RESULTS

Theorem 2.1. Letf(z) = 1z +P

k=1akzk, z ∈E.If (2.1)

X

k=1

k{k(1 +B) + (1 +A)}|ak| ≤B −A, then f(z)∈ΣK(A, B).

Proof. It suffices to show that

1 + zff(z)00(z) + 1 B

1 + zff000(z)(z)

+A

<1,

that is,

zf00(z) + 2f0(z) Bzf00(z) + (A+B)f0(z)

<1.

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Consider

zf00(z) + 2f0(z) Bzf00(z) + (A+B)f0(z)

(2.2)

=

P

k=1k(k+ 1)akzk+1 (B −A) +BP

k=1k(k+ 1)akzk+1−(2B−A)P

k=1kakzk+1

≤ Σk(k+ 1)|ak| (B−A)−P

k=1k(kB+A)|ak|. (2.2) is bounded by1if

X

k=1

k(k+ 1)|ak| ≤(B−A)

X

k=1

k(kB+A)|ak|

which reduces to (2.1)

Similarly we can prove the following theorem.

Theorem 2.2. Letf(z) = 1z +P

k=1akzk, z ∈E.If (2.3)

X

k=1

{k(1 +B) + (1 +A)}|ak| ≤B−A, then f(z)∈Σ(A, B).

3. MAINRESULTS

Theorem 3.1. Iff(z)of the form (1.1) satisfies (2.3), then

<

f(z) fn(z)

≥ 2(n+ 1 +A)

2n+ 2 +A+B, z ∈ U.

The result is sharp for everyn,with extremal function

(3.1) f(z) = 1

z + B−A

2n+ 2 +A+Bzn+1, n ≥0.

Proof. Consider

2n+ 2 +A+B B −A

f(z)

fn(z) − 2n+A+B 2n+ 2 +A+B

= 1 +Pn

k=1akzk+1+ 2n+2+A+BB−A P

k=n+1akzk+1 1 +Pn

k=1akzk+1

= 1 +w(z) 1−w(z), where

w(z) =

2n+2+A+B B−A

P

k=n+1akzk+1 2 + 2Pn

k=1akzk+12n+2+A+BB−A P

k=n+1akzk+1 and

|w(z)| ≤

2n+2+A+B B−A

P k=1|ak| 2−2Pn

k=1|ak| − 2n+2+A+BB−A P

k=n+1|ak|. Now

|w(z)| ≤1

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if and only if

2

2n+ 2 +A+B B−A

X

k=n+1

|ak| ≤2−2

n

X

k=1

|ak|,

which is equivalent to (3.2)

n

X

k=1

|ak|+2n+ 2 +A+B B−A

X

k=n+1

|ak| ≤1.

It suffices to show that the left hand side of (3.2) bounded above by

X

k=1

2k+A+B (B−A) |ak|, which is equivalent to

n

X

k=1

2(k+A) B−A

|ak|+

X

k=n+1

2(k−n−1) B −A

|ak| ≥0.

To see that the functionf(z)given by (3.1) gives the sharp result, we observe for z =ren+2πi

that

f(z)

fn(z) = 1 + B −A

2n+ 2 +A+Bzn+2 →1− B−A

2n+ 2 +A+B = 2(n+ 1 +A) 2(n+ 1) +A+B whenr →1.

Therefore we complete the proof of Theorem 3.1.

Corollary 3.2. ForA= 2α−1, B = 1,we get Theorem2.1in [3] which states as follows:

Iff(z)of the form (1.1) satisfies condition

X

1

(k+α)|ak| ≤1−α,

then

<

f(z) fn(z)

≥ n+ 2α

n+ 1 +α, z ∈ U. The result is sharp for everyn, with extremal function

f(z) = 1

z + 1−α

n+ 1 +αzn+1, n≥0.

Theorem 3.3. Iff(z)of the form (1.1) satisfies (2.1), then

<

f(z) fn(z)

≥ (n+ 2)(2n+A+B)

(n+ 1)(2n+ 2 +A+B), z ∈ U. The result is sharp for everyn,with extremal function

(3.3) f(z) = 1

z + B−A

(n+ 1)(2n+ 2 +A+B)zn+1, n ≥0.

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Proof. Consider

(n+ 1)(2n+ 2 +B +A) B −A

f(z)

fn(z) − (n+ 2)(2n+A+B) (n+ 1)(2n+ 2 +A+B)

= 1 +Pn

k=1akzk+1+ (n+1)(2n+2+A+B) B−A

P

k=n+1akzk+1 1 +Pn

k=1akzk+1 := 1 +w(z)

1−w(z), where

w(z) =

(n+1)(2n+2+A+B) B−A

P

k=n+1akzk+1 2 + 2Pn

k=1akzk+1+(n+1)(2n+2+B+A) B−A

P

k=n+1akzk+1. Now

|w(z)| ≤

(n+1)(2n+2+A+B) B−A

P

k=n+1|ak| 2−2Pn

k=1|ak| − (n+1)(2n+2+A+B) B−A

P

k=n+1|ak| ≤1 if

(3.4)

n

X

k=1

|ak|+(n+ 1)(2n+ 2 +A+B) B−A

X

k=n+1

|ak| ≤1.

The left hand side of (3.4) is bounded above by

X

k=1

k(2k+A+B) B−A |ak| if

1 B−A

( n X

k=1

(k(2k+A+B)−(B −A))|ak|

+

X

k=n+1

(k(2k+A+B)−(n+ 1)(2n+ 2 +A+B))|ak| )

≥0,

and the proof is completed.

Corollary 3.4. ForA= 2α−1, B = 1,we get Theorem2.2in [3] which reads:

Iff(z)of the form (1.1) satisfies condition

X

1

k(k+α)|ak| ≤1−α,

then

<

f(z) fn(z)

≥ (n+ 2)(n+α)

(n+ 1)(n+ 1 +α), z∈ U. The result is sharp for everyn, with extremal function

f(z) = 1

z + 1−α

(n+ 1)(n+ 1 +α)zn+1, n ≥0.

We next determine bounds for<n

fn(z) f(z)

o . Theorem 3.5.

(a) Iff(z)of the form (1.1) satisfies the condition (2.3), then

<

fn(z) f(z)

≥ 2n+ 2 +A+B

n+ 2 , z ∈ U.

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(b) Iff(z)of the form (1.1) satisfies condition (2.1), then

<

fn(z) f(z)

≥ 2(n+ 1)(2n+ 2 +A+B)

2(n+ 1)(n+ 2)−n(B−A), z ∈ U.

Equalities hold in(a)and(b)for the functions given by (3.1) and (3.3) respectively.

Proof. We prove(a).The proof of(b)is similar to(a)and will be omitted.

Consider 2(n+ 2)

B−A

fn(z)

f(z) −2n+ 2 +A+B 2(n+ 2)

= 1 +Pn

k=1akzk+1+ 2n+2+A+BB−A P

k=n+1akzk+1 1 +Pn

k=1akzk+1 := 1 +w(z) 1−w(z), where

|w(z)| ≤

n+2 B−A

P

k=n+1|ak| 1−Pn

k=1|ak| − n+A+BB−A P

k=n+1|ak| ≤1.

This last inequality is equivalent to (3.5)

n

X

k=1

|ak|+2n+ 2 +A+B B−A

X

k=n+1

|ak| ≤1.

Since the left hand side of (3.5) is bounded above by

X

k=1

2k+A+B B−A |ak|,

the proof is completed.

Corollary 3.6. ForA= 2α−1, B = 1,we get Theorem2.3in [3] which reads:

(a) Iff(z)of the form (1.1) satisfies condition

X

1

(k+α)|ak| ≤1−α,

then

<

fn(z) f(z)

≥ (n+ 1 +α)

(n+ 2) , z ∈ U. (b) Iff(z)of the form (1.1) satisfies condition

X

1

k(k+α)|ak| ≤1−α,

then

<

fn(z) f(z)

≥ (n+ 1)(n+ 1 +α)

(n+ 1)(n+ 2)−n(1−α), z ∈ U. Equalities hold in (a) and (b) for the functions given by

f(z) = 1

z + 1−α

(n+ 1 +α)zn+1, n≥0, f(z) = 1

z + 1−α

(n+ 1)(n+ 1 +α)zn+1, n≥0 respectively.

(7)

We turn to ratios involving derivatives. The proof of Theorem 3.7 is similar to that in Theo- rem 3.1 and(a)of Theorem 3.5 and so the details may be omitted.

Theorem 3.7. Iff(z)of form (1.1) satisfies condition (2.3) withA=−B,then

<

f0(z) fn0(z)

≥0, z ∈ U, (a)

<

fn0(z) f0(z)

≥ 1

2, z ∈ U. (b)

In both the cases, the extremal function is given by (3.1) withA=−B.

Theorem 3.8. Iff(z)of form (1.1) satisfies condition (2.1) then,

<

f0(z) fn0(z)

≥ 2(n+A+B)

2n+ 2 +A+B, z ∈ U, (a)

<

fn0(z) f0(z)

≥ 2n+ 2 +A+B

2(n+ 2) , z ∈ U. (b)

In both the cases, the extremal function is given by (3.3)

Proof. It is well known that f(z)∈ΣK(A, B)if and only if−zf0(z)∈Σ(A, B).In particular, f(z) satisfies condition (2.1)if and only if −zf0(z) satisfies condition (2.3).Thus (a)is an immediate consequence of Theorem 3.1 and(b)follows directly from(a)of Theorem 3.5.

For a functionf(z)∈Σ,we define the integral operatorF(z)as follows F(z) = 1

z2 Z z

0

tf(t)dt = 1 z +

X

k=1

1

k+ 2akzk, z ∈E.

Thenthpartial sumFn(z)of the integral operatorF(z)is given by Fn(z) = 1

z +

n

X

k=1

1

k+ 2akzk, z ∈E.

The following lemmas will be required for the proof of Theorem 3.11 below.

Lemma 3.9. For0≤θ≤π, 12 +Pm k=1

cos(kθ) k+1 ≥0

Lemma 3.10. LetP be analytic inU withP(0) = 1 and<{P(z)} > 12 inU.For any function Qanalytic inU the functionP ∗Qtakes values in the convex hull of the image onU underQ.

Lemma 3.9 is due to Rogosinski and Szego [4] and Lemma 3.10 is a well known result ([2]

and [6]) that can be derived from the Herglotz representation forP.Finally we derive Theorem 3.11. Iff(z)∈Σc(A, B),thenFn(z)∈Σc(A, B).

Proof. Letf(z)be the form (1.1) and belong to the classΣc(A, B).

We have,

(3.6) <

(

1− 1 B−A

X

k=1

kakzk+1 )

> 1

2, z ∈ U.

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Applying the convolution properties of power series toFn0(z)we may write

−z2Fn0(z) = 1−

n

X

k=1

k

k+ 2akzk+1 (3.7)

= 1− 1

B−A

X

k=1

kakzk+1

!

∗ 1 + (B−A)

X

k=n+1

1 k+ 1zk

! . Puttingz = re, 0 ≤ r < 1, 0 ≤ |θ| ≤ π, and making use of the minimum principle for harmonic functions along with Lemma 3.9, we obtain

<

(

1 + (B−A)

n+1

X

k=1

1 k+ 1zk

)

= 1 + (B−A)

n+1

X

k=1

rkcos(kθ) k+ 1 (3.8)

>1 + (B−A)

n+1

X

k=1

coskθ k+ 1

1−

B−A 2

. In view of (3.6), (3.7), (3.8) and Lemma 3.10 we deduce that

−<{z2Fn0(z)}>

1−

B−A 2

, 0≤A+B <2, z ∈ U,

which completes the proof of Theorem 3.11

Corollary 3.12. ForA= 2α−1, B = 1,we obtain Theorem2.8in [3] which reads:

Iff(z)∈Σc(α),thenFn(z)∈Σc(α).

REFERENCES

[1] S. RUSCHWEYH, Convolutions in Geometric Function Theory, Les Presses de l’Universite de Montreal, 1982.

[2] A.W. GOODMAN, Univalent Functions, Vol. I, Mariner Publ. Co., Tampa, Fl., (1983).

[3] NAK EUN CHO AND S. OWA, On partial sums of certain meromorphic functions, J. Inequal.

in Pure and Appl. Math., 5(2) (2004), Art. 30. [ONLINE: http://jipam.vu.edu.au/

article.php?sid=377].

[4] W. ROGOSINSKIAND G. SZEGO, Uber die abschimlte von potenzreihen die in ernein kreise be schranket bleiben, Math. Z., 28 (1928), 73–94.

[5] S. LATHA, Some studies in the theory of univalent and multivalent functions, PhD Thesis, (1994).

[6] R. SINGHANDS. SINGH, Convolution properties of a class of starlike fuctions, Proc. Amer. Math.

Soc., 106 (1989), 145–152.

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