DE, StudentNumber: 92
Underdamped harmonic oscillator
Let
a= 0.6, b= 0.9, t0 = 0, t1 = 5.9, (1)
ic0 = 1.1, ic1=−0.7, (2)
y00(t) +ay0(t) +by(t) =f(t). (3)
The first order form of (3) is d dt
y v
=A y
v
+B(f(t)) =
0 1
−b −a y v
+
0 1
(f(t)), (4)
wherey0=v. The initial condition (2) is
~ y(0) =
y(0) v(0)
= ic0
ic1
. (5)
1, A
Exercise. Let f(t) = 0, (2) be true. How much isy(t1) ?
Answers. A: 0.132345 B: 0.163314 C: 0.20153 D: 0.248688 E: 0.306881 2, Aa
Exercise. Letf(t) = 0, (2) be true. LetUt1,t0(~z) =~y(t1), where~y(t) is the solution of (4) with the initial condition
~
y(t0) =~z. How much is the first component of
Ut1,t0( ic0
ic1
).
Answers. A: 0.163314 B: 0.20153 C: 0.248688 D: 0.306881 E: 0.378691 3, Ab
Exercise. Letf(t) = 0, (2) be true. LetUt1,t0(~z) =~y(t1), where~y(t) is the solution of (4) with the initial condition
~
y(t0) =~z. Compute Ut1,t0(~z), if~z=n1(0.2,0)T +n2(0,0.2)T, n1,2∈ {0,1,2,3,4,5}. Plot these points!
Answers.
4, Ac
Exercise. f(t) = 0, (2) is true. Solve the following algebro-differential equation!
y0=v, v0 =−spring−f riction, spring=by, f riction=av.
How much isspring(t1) ?
Answers. A: 0.119111 B: 0.146983 C: 0.181377 D: 0.223819 E: 0.276193 5, B
Exercise. f(t) = 0. The general solution of (3) is
y(t) =C1eλ1t+C2eλ2t, =(λ1)>0.
How much is=(C1), if (2) is satisfied?
Answers. A: 0.109392 B: 0.134989 C: 0.166577 D: 0.205556 E: 0.253656 6, Ba
Exercise. f(t) = 0. The general solution of (4) is
~
y(t) =C1eλ1t~v1+C2eλ2t~v2, =(λ1)>0, ~v1 = (1, s21)T, ~v2 = (1, s22)T How much is=(C1), if (10) is satisfied?
Answers. A: 0.109392 B: 0.134989 C: 0.166577 D: 0.205556 E: 0.253656 7, C
Exercise. f(t) = 0. The general solution of (3) is
y(t) =eαt(C1cosωt+C2sinωt).
8, D
Exercise. f(t) = 0, (2), (3) true. Plot y(t) !
Answers.
1 2 3 4 5 6
-0.5 0.5 1.0
1 2 3 4 5 6
-0.5 0.5 1.0
1 2 3 4 5 6
0.5 1.0
1 2 3 4 5 6
-0.5 0.5 1.0
9, E
Exercise. f(t) = 0, (2), (3) is true. Plot y(t), y0(t)-t on a single figure!
Answers.
1 2 3 4 5 6
-0.5 0.5 1.0
1 2 3 4 5 6
-0.5 0.5 1.0
1 2 3 4 5 6
-1.0 -0.5 0.5 1.0
1 2 3 4 5 6
-0.5 0.5 1.0
10, F
Exercise. f(t) = 0, (2), (3) are true. Plot the
γ : [t0, t1]→R2, γ(t) = (y(t), v(t))T parametric curve!
Answers.
-0.5 0.5 1.0
-1.0 -0.5 0.5
0.5 1.0
-0.6 -0.4 -0.2
-0.5 0.5 1.0
-0.8 -0.6 -0.4 -0.2 0.2
-0.5 0.5 1.0
-0.8 -0.6 -0.4 -0.2 0.2 0.4
11, G
Exercise. f(t) = 0, (2), (3) are true. Plot the
γ : [t0, t1]→R3, γ(t) = (t, y(t), v(t))T parametric curve!
0
2
4
6 0.0
0.5 1.0---0.00.60.40.2
0
2
4
6 -0.5
0.0 0.5
1.0--1.00.5 0.0
0.5
0
2
4
6-0.5 0.0 0.5
1.0-0.5
0.0 0
2
4
6-0.5 0.0
0.51.0-0.5 0.0
12, H
Exercise. Plot the (y, v)T →A(y, v)T vector field!
Answers.
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
13, Ha
Exercise. f(t) = 0. Plot the (y, v)T →A(y, v)T vector field and a solution of (4)!
Answers.
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
14, I
Exercise. Compute U = exp(1.4A) ! How much isU11 ?
Answers. A: 0.217904 B: 0.268893 C: 0.331814 D: 0.409459 E: 0.505272 15, J
Exercise. Compute U(t) = exp(tA)-t and plot its first column’s functions!
1 2 3 4 5 6
-0.5 0.5 1.0
1 2 3 4 5 6
-0.5 0.5 1.0
1 2 3 4 5 6
-0.5 0.5 1.0
1 2 3 4 5 6
-0.4 -0.2 0.2 0.4 0.6 0.8 1.0
16, K
Exercise. f(t) = 0, (2) true, y(0) = 1, y0(0) = 0. Plot (y(t), y0(t))T !
Answers.
1 2 3 4 5 6
-0.5 0.5 1.0
1 2 3 4 5 6
-0.5 0.5 1.0
1 2 3 4 5 6
-0.5 0.5 1.0
1 2 3 4 5 6
-0.4 -0.2 0.2 0.4 0.6 0.8 1.0
17, L
Exercise. Compute U(t) = exp(tA)-t and plot its second column’s functions!
Answers.
1 2 3 4 5 6
-0.5 0.5 1.0
1 2 3 4 5 6
-0.5 0.5 1.0
1 2 3 4 5 6
-0.4 -0.2 0.2 0.4 0.6 0.8 1.0
1 2 3 4 5 6
-0.4 -0.2 0.2 0.4 0.6 0.8 1.0
18, M
Exercise. f(t) = 0, (2) true, y(0) = 0, y0(0) = 1. Plot (y(t), y0(t))T !
Answers.
1 2 3 4 5 6
-0.5 0.5 1.0
1 2 3 4 5 6
-0.4 -0.2 0.2 0.4 0.6 0.8 1.0
1 2 3 4 5 6
-0.4 -0.2 0.2 0.4 0.6 0.8 1.0
1 2 3 4 5 6
-0.5 0.5 1.0
Overdamped harmonic oscillator
Let
a= 0, b= 1.84, t0 = 0, t1 = 2.6, (6)
ic0= 0.7, ic1 = 1.4, (7)
y00(t) +ay0(t) +by(t) =f(t). (8)
The first order form of (8) is d dt
y v
=A y
v
+B(f(t)) =
0 1
−b −a y v
+
0 1
(f(t)), (9)
wherey0=v. The initial condition (7) is
~ y(0) =
y(0) v(0)
= ic0
ic1
. (10)
19, A
Exercise. Let f(t) = 0, (2) be true. How much isy(t1) ?
Answers. A: 0.162461 B: 0.200477 C: 0.247389 D: 0.305278 E: 0.376713 20, Aa
Exercise. Letf(t) = 0, (2) be true. LetUt1,t0(~z) =~y(t1), where~y(t) is the solution of (4) with the initial condition
~
y(t0) =~z. How much is the first component of
Ut1,t0( ic0
ic1
).
Answers. A: 0.106689 B: 0.131654 C: 0.162461 D: 0.200477 E: 0.247389
21, Ab
Exercise. Let f(t) = 0, (2) be true. Let Ut1/6,t0(~z) = ~y(t1/6), where ~y(t) is the solution of (4) with the initial condition~y(t0) =~z. ComputeUt1/6,t0(~z), if~z=n1(0.2,0)T+n2(0,0.2)T, n1,2∈ {0,1,2,3,4,5}. Plot these points!
Answers.
22, Ac
Exercise. f(t) = 0, (2) is true. Solve the following algebro-differential equation!
y0=v, v0 =−spring−f riction, spring=by, f riction=av.
How much isspring(t1) ?
Answers. A: 0.298929 B: 0.368878 C: 0.455196 D: 0.561711 E: 0.693152 23, B
Exercise. f(t) = 0. The general solution of (3) is
y(t) =C1eλ1t+C2eλ2t, λ1 > λ2. How much isC1, if (2) is satisfied?
Answers. A: 0. B: 0. C: 0. D: 0. E: 0.
24, Ba
Exercise. f(t) = 0. The general solution of (4) is
~
y(t) =C1eλ1t~v1+C2eλ2t~v2, λ1> λ2, ~v1 = (1, s21)T, ~v2 = (1, s22)T How much is=(C1), if (10) is satisfied?
Answers. A: 1.31779 B: 1.62615 C: 2.00667 D: 2.47623 E: 3.05566
25, D
Exercise. f(t) = 0, (2), (3) true. Plot y(t) !
Answers.
0.5 1.0 1.5 2.0 2.5
0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0 2.5
0.2 0.4 0.6 0.8
0.5 1.0 1.5 2.0 2.5 0.6
0.7 0.8 0.9 1.0 1.1
0.5 1.0 1.5 2.0 2.5
0.3 0.4 0.5 0.6 0.7 0.8 0.9
26, E
Exercise. f(t) = 0, (2), (3) is true. Plot y(t), y0(t)-t on a single figure!
Answers.
0.5 1.0 1.5 2.0 2.5
-0.5 0.5 1.0 1.5
0.5 1.0 1.5 2.0 2.5
0.5 1.0 1.5
0.5 1.0 1.5 2.0 2.5
-0.5 0.5 1.0 1.5
0.5 1.0 1.5 2.0 2.5
-0.5 0.5 1.0 1.5
27, F
Exercise. f(t) = 0, (2), (3) are true. Plot the
γ : [t0, t1]→R2, γ(t) = (y(t), v(t))T parametric curve!
Answers.
0.60.70.80.91.01.1 0.0
0.5 1.0 1.5
0.2 0.4 0.6 0.8
-0.6 -0.4 -0.2 0.2 0.4
0.4 0.5 0.6 0.7 0.8 0.9
-0.4 -0.2 0.2 0.4
0.2 0.4 0.6 0.8 1.0
-0.5 0.5 1.0 1.5
28, G
Exercise. f(t) = 0, (2), (3) are true. Plot the
γ : [t0, t1]→R3, γ(t) = (t, y(t), v(t))T parametric curve!
Answers.
0
1
2
0.4 0.60.8--0.40.2
0.0 0.2 0.4
0
1 0.0 2
0.5 1.0
-0.5 0.0
0.5 1.0
0
1
2 0.60.81.0
0.0 0.5
1.0 0
1
2 0.00.20.40.60.8-0.5 0.0
29, H
Exercise. Plot the (y, v)T →A(y, v)T vector field!
Answers.
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
30, Ha
Exercise. f(t) = 0. Plot the (y, v)T →A(y, v)T vector field and a solution of (4)!
Answers.
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
31, I
Exercise. Compute U = exp(1.4A) ! How much isU11 ?
Answers. A: 0.206568 B: 0.254905 C: 0.314552 D: 0.388157 E: 0.478986 32, J
Exercise. Compute U(t) = exp(tA)-t and plot its first column’s functions!
0.5 1.0 1.5 2.0 2.5
-0.5 0.5 1.0
0.5 1.0 1.5 2.0 2.5
-0.5 0.5 1.0
0.5 1.0 1.5 2.0 2.5
-0.2 0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0 2.5
-0.5 0.5 1.0
33, K
Exercise. f(t) = 0, (2) true, y(0) = 1, y0(0) = 0. Plot (y(t), y0(t))T !
Answers.
0.5 1.0 1.5 2.0 2.5
-0.2 0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0 2.5
-0.5 0.5 1.0
0.5 1.0 1.5 2.0 2.5
-0.5 0.5 1.0
0.5 1.0 1.5 2.0 2.5
-0.5 0.5 1.0
34, L
Exercise. Compute U(t) = exp(tA)-t and plot its second column’s functions!
Answers.
0.5 1.0 1.5 2.0 2.5
-0.2 0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0 2.5
0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0 2.5
-0.1 0.1 0.2 0.3 0.4 0.5
0.5 1.0 1.5 2.0 2.5
0.2 0.4 0.6 0.8 1.0
35, M
Exercise. f(t) = 0, (2) true, y(0) = 0, y0(0) = 1. Plot (y(t), y0(t))T !
Answers.
0.5 1.0 1.5 2.0 2.5
0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0 2.5
0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0 2.5
-0.1 0.1 0.2 0.3 0.4 0.5
0.5 1.0 1.5 2.0 2.5
-0.2 0.2 0.4 0.6 0.8 1.0
Critical damping of a harmonic oscillator
Let
a= 2., b= 0.64, t0 = 2., t1= 2., (11)
ic0= 1., ic1 = 0.7, (12)
y00(t) +ay0(t) +by(t) =f(t). (13)
The first order form of (13) is d dt
y v
=A y
v
+B(f(t)) =
0 1
−b −a y v
+
0 1
(f(t)), (14)
wherey0=v. The initial condition (12) is
~ y(0) =
y(0) v(0)
= ic0
ic1
. (15)
36, A
Exercise. Let f(t) = 0, (2) be true. How much isy(t1) ?
Answers. A: 0.34828 B: 0.429777 C: 0.530345 D: 0.654446 E: 0.807586 37, Aa
Exercise. Letf(t) = 0, (2) be true. LetUt1,t0(~z) =~y(t1), where~y(t) is the solution of (4) with the initial condition
~
y(t0) =~z. How much is the first component of
Ut1,t0( ic0
ic1
).
Answers. A: 0.654446 B: 0.807586 C: 0.996561 D: 1.22976 E: 1.51752
38, Ab
Exercise. Let f(t) = 0, (2) be true. Let Ut1/6,t0(~z) = ~y(t1/6), where ~y(t) is the solution of (4) with the initial condition~y(t0) =~z. ComputeUt1/6,t0(~z), if~z=n1(0.2,0)T+n2(0,0.2)T, n1,2∈ {0,1,2,3,4,5}. Plot these points!
Answers.
39, Ac
Exercise. f(t) = 0, (2) is true. Solve the following algebro-differential equation!
y0=v, v0 =−spring−f riction, spring=by, f riction=av.
How much isspring(t1) ?
Answers. A: 0.275057 B: 0.339421 C: 0.418845 D: 0.516855 E: 0.637799 40, B
Exercise. f(t) = 0. The general solution of (3) is
y(t) =C1eλt+C2teλt. How much isC1, if (2) is satisfied?
Answers. A: -0.0656704 B: -0.0810373 C: -0.1 D: -0.1234 E: -0.152276 41, Ba
Exercise. f(t) = 0. The general solution of (4) is
~
y(t) =C1eλ1t~v1+C2eλ2t~v2, How much isC1(~v2)1, if (10) is satisfied?
Answers. A: -0.0656704 B: -0.0810373 C: -0.1 D: -0.1234 E: -0.152276
42, D
Exercise. f(t) = 0, (2), (3) true. Plot y(t) !
Answers.
0.5 1.0 1.5 2.0
1.05 1.10 1.15 1.20 1.25
0.5 1.0 1.5 2.0
0.9 1.0 1.1
0.5 1.0 1.5 2.0
0.7 0.8 0.9 1.0 1.1
0.5 1.0 1.5 2.0
0.95 1.00 1.05 1.10 1.15 1.20
43, E
Exercise. f(t) = 0, (2), (3) is true. Plot y(t), y0(t)-t on a single figure!
Answers.
0.5 1.0 1.5 2.0
0.5 1.0
0.5 1.0 1.5 2.0
0.5 1.0
0.5 1.0 1.5 2.0
0.5 1.0
0.5 1.0 1.5 2.0
0.5 1.0
44, F
Exercise. f(t) = 0, (2), (3) are true. Plot the
γ : [t0, t1]→R2, γ(t) = (y(t), v(t))T parametric curve!
Answers.
0.80.91.01.1
-0.4 -0.2 0.2 0.4 0.6
0.91.01.1
-0.4 -0.2 0.2 0.4 0.6
1.001.051.101.151.20 -0.2
0.2 0.4 0.6
1.101.151.201.25 -0.2
0.2 0.4 0.6
45, G
Exercise. f(t) = 0, (2), (3) are true. Plot the
γ : [t0, t1]→R3, γ(t) = (t, y(t), v(t))T parametric curve!
Answers.
0.0 0.5
1.0
1.5
2.0
1.01.11.2 0.0
0.5
0.0 0.5
1.0
1.5
2.0
0.8 1.0
0.0 0.5
0.0 0.5
1.0
1.5
2.0
0.80.91.01.1 0.0
0.5 0.0
0.5
1.0
1.5
2.0
1.01.11.2 0.0
0.5
46, H
Exercise. Plot the (y, v)T →A(y, v)T vector field!
Answers.
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
47, Ha
Exercise. f(t) = 0. Plot the (y, v)T →A(y, v)T vector field and a solution of (4)!
Answers.
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
-1.0 -0.5 0.0 0.5 1.0 -1.0
-0.5 0.0 0.5 1.0
48, I
Exercise. Compute U = exp(1.4A) ! How much isU11 ?
Answers. A: 0.454251 B: 0.560546 C: 0.691713 D: 0.853574 E: 1.05331 49, J
Exercise. Compute U(t) = exp(tA)-t and plot its first column’s functions!
0.5 1.0 1.5 2.0
-0.4 -0.2 0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0
-0.2 0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0
-0.2 0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0
-0.2 0.2 0.4 0.6 0.8 1.0
50, K
Exercise. f(t) = 0, (2) true, y(0) = 1, y0(0) = 0. Plot (y(t), y0(t))T !
Answers.
0.5 1.0 1.5 2.0
-0.2 0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0
-0.2 0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0
-0.4 -0.2 0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0
-0.2 0.2 0.4 0.6 0.8 1.0
51, L
Exercise. Compute U(t) = exp(tA)-t and plot its second column’s functions!
Answers.
0.5 1.0 1.5 2.0
0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0
0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0
0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0
0.2 0.4 0.6 0.8 1.0
52, M
Exercise. f(t) = 0, (2) true, y(0) = 0, y0(0) = 1. Plot (y(t), y0(t))T !
Answers.
0.5 1.0 1.5 2.0
0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0
0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0
0.2 0.4 0.6 0.8 1.0
0.5 1.0 1.5 2.0
0.2 0.4 0.6 0.8 1.0
Distributions (δ, δ
0)
LetχA(t) = 1, ift∈A, otherwise χA(t) is zero.
n= 1.15, a= 6, φ(t) =eat, αn(t) =nχ[−1/(2n),1/(2n)](t), βn(t) = 1
√2πσne−t2/(2σn2), σn= 1/(4n),
˜
αn(t) =n2(χ[−1/n,0](t)−χ[0,1/n](t)), β˜n(t) =βn0(t), hf, φi=
Z ∞
−∞
f(t)φ(t)dt 53, A
Exercise. Plot αn(t) and βn(t) !
Answers.
-1.0 -0.5 0.5 1.0
2 4 6 8 10
-1.0 -0.5 0.5 1.0
2 4 6 8
-1.0 -0.5 0.5 1.0
2 4 6 8 10 12
-1.0 -0.5 0.5 1.0
2 4 6 8 10 12 14
54, Aa
Answers.
-0.3 -0.2 -0.1 0.1 0.2 0.3 2
4 6 8 10 12 14
-0.3 -0.2 -0.1 0.1 0.2 0.3 5
10 15 20
-0.3 -0.2 -0.1 0.1 0.2 0.3 5
10 15
-0.3 -0.2 -0.1 0.1 0.2 0.3 5
10 15 20
55, B
Exercise. Plot αen(t) and βen(t)!
Answers.
-1.0 -0.5 0.5 1.0
-200 -100 100 200
-1.0 -0.5 0.5 1.0
-150 -100 -50 50 100 150
-1.0 -0.5 0.5 1.0
-300 -200 -100 100 200 300
-1.0 -0.5 0.5 1.0
-100 -50 50 100
56, C
Exercise. Compute φ(0)− hα, φi ?
Answers. A: -0.00100566 B: -0.00124098 C: -0.00153137 D: -0.00188972 E: -0.00233191 57, D
Exercise. Compute (−φ0(0))− hα,φie ?
Answers. A: 0.00231479 B: 0.00285645 C: 0.00352486 D: 0.00434967 E: 0.0053675 58, E
Exercise. Compute φ(0)− hβ, φi !
Answers. A: -0.000754331 B: -0.000930845 C: -0.00114866 D: -0.00141745 E: -0.00174913
59, F
Exercise. Compute (−φ(0))− hβ, φie !
Answers. A: 0.000702983 B: 0.000867481 C: 0.00107047 D: 0.00132096 E: 0.00163007 60, G
Exercise. Let
n= 2i, i= 0, . . . ,4, errn=|φ(0)− hαn, φi|.
Plot the points [ln(n),ln(errn)] and find the best fitting line by linear regression (i.e. by the method of least squares)!
Answers.
0.5 1.0 1.5 2.0 2.5
-8 -6 -4 -2
0.5 1.0 1.5 2.0 2.5
-8 -6 -4 -2
0.5 1.0 1.5 2.0 2.5
-8 -6 -4 -2
0.5 1.0 1.5 2.0 2.5
-8 -6 -4 -2
61, H Exercise. Let
n= 2i, i= 0, . . . ,4, errn=|φ(0)− hαn, φi|.
Take the points [ln(n),ln(errn)] and find the best fitting line by linear regression (i.e. by the method of least squares)! What is the slope of that line?
Answers. A: -0.86481 B: -1.06718 C: -1.31689 D: -1.62505 E: -2.00531 62, Hb
Exercise. Let
n= 2i, i= 0, . . . ,4, errn=|φ(0)− hγn, φi|, where
γn(t) =χ[0,1/n](t)
Take the points [ln(n),ln(errn)] and find the best fitting line by linear regression (i.e. by the method of least squares)! What is the slope of that line?
Answers. A: -0.921199 B: -1.13676 C: -1.40276 D: -1.73101 E: -2.13606 63, I
Exercise. Let
n= 2i, i= 0, . . . ,4, rr =|(−φ0(0))− hα , φi|.
Answers.
0.5 1.0 1.5 2.0 2.5
-8 -6 -4 -2
0.5 1.0 1.5 2.0 2.5
-8 -6 -4 -2
0.5 1.0 1.5 2.0 2.5
-8 -6 -4 -2
0.5 1.0 1.5 2.0 2.5
-8 -6 -4 -2
64, J
Exercise. Let
n= 2i, i= 2, . . . ,13, errn=|φ(0)− hαn, φi|.
Take the points [ln(n),ln(errn)] and find the best fitting line by linear regression (i.e. by the method of least squares)! What is the slope of that line?
Answers. A: -2.01418 B: -2.4855 C: -3.06711 D: -3.78481 E: -4.67045 65, K
Exercise. y0(t) =δ(t), y(−1) = 0, y0n(t) =αn(t), yn(−1) = 0.Plot y, yn-t!
Answers.
-0.4 -0.2 0.2 0.4 0.2
0.4 0.6 0.8 1.0
-0.4 -0.2 0.2 0.4 0.2
0.4 0.6 0.8 1.0
-0.4 -0.2 0.2 0.4 0.2
0.4 0.6 0.8 1.0
-0.4 -0.2 0.2 0.4 0.2
0.4 0.6 0.8 1.0
66, L
Exercise. y0(t) =δ(t), y(−1) = 0, y0n(t) =βn(t), yn(−1) = 0.Plot y, yn-t!
Answers.
-0.4 -0.2 0.2 0.4 0.2
0.4 0.6 0.8 1.0
-0.4 -0.2 0.2 0.4 0.2
0.4 0.6 0.8 1.0
-0.4 -0.2 0.2 0.4 0.2
0.4 0.6 0.8 1.0
-0.4 -0.2 0.2 0.4 0.2
0.4 0.6 0.8 1.0
67, M
Exercise. y00(t) =δ(t), y(−1) = 0, y0(−1) = 0, y00n(t) =αn(t), yn(−1) = 0, y0(−1) = 0.Plot y, yn-t!
Answers.
-0.2 -0.1 0.1 0.2
0.05 0.10 0.15 0.20
-0.2 -0.1 0.1 0.2
0.05 0.10 0.15 0.20
-0.2 -0.1 0.1 0.2
0.05 0.10 0.15 0.20
-0.2 -0.1 0.1 0.2
0.05 0.10 0.15 0.20
68, N
Exercise. y00(t) =δ(t), y(−1) = 0, y0(−1) = 0, y00n(t) =βn(t), yn(−1) = 0, y0(−1) = 0.Plot y, yn-t!
Answers.
-0.2 -0.1 0.1 0.2
0.05 0.10 0.15 0.20
-0.2 -0.1 0.1 0.2
0.05 0.10 0.15 0.20
-0.2 -0.1 0.1 0.2
0.05 0.10 0.15 0.20
-0.2 -0.1 0.1 0.2
0.05 0.10 0.15 0.20
69, O
Exercise. y00(t) =δ0(t), y(−1) = 0, y0(−1) = 0, y00n(t) =βen(t), yn(−1) = 0, y0(−1) = 0.Plot y, yn-t!
Answers.
-0.2 -0.1 0.1 0.2
0.2 0.4 0.6 0.8 1.0
-0.2 -0.1 0.1 0.2
0.2 0.4 0.6 0.8 1.0
-0.2 -0.1 0.1 0.2
0.2 0.4 0.6 0.8 1.0
-0.2 -0.1 0.1 0.2
0.2 0.4 0.6 0.8 1.0
70, P
Exercise. y00(t) = 0.4δ(t) + 1.6δ0(t), y(−1) = 0, y0(−1) = 0, yn00(t) = 0.4β(t) + 1.6βen(t), yn(−1) = 0, y0(−1) = 0.
Ploty, yn-t!
Answers.
-0.3 -0.2 -0.1 0.1 0.2 0.3 0.5
1.0 1.5
-0.3 -0.2 -0.1 0.1 0.2 0.3 0.5
1.0 1.5
-0.3 -0.2 -0.1 0.1 0.2 0.3 0.5
1.0 1.5
-0.3 -0.2 -0.1 0.1 0.2 0.3 0.5
1.0 1.5
71, Q
Exercise. y00(t) = −3y(t)−y0(t) +δ(t), y(−1) = 0, y0(−1) = 0, yn00(t) = −3yn(t)−yn0(t) +βn(t), yn(−1) = 0, y0n(−1) = 0.Plot y, yn-t!
Answers.
-0.15-0.10-0.05 0.05 0.10 0.15 0.02
0.04 0.06 0.08 0.10 0.12 0.14
-0.15-0.10-0.05 0.05 0.10 0.15 0.02
0.04 0.06 0.08 0.10 0.12 0.14
-0.15-0.10-0.05 0.05 0.10 0.15 0.02
0.04 0.06 0.08 0.10 0.12 0.14
-0.15-0.10-0.05 0.05 0.10 0.15 0.02
0.04 0.06 0.08 0.10 0.12 0.14
72, R
Exercise. y0(t) =−3y(t) +δ(t), y(−1) = 0, yn0(t) =−3yn(t) +βn(t), yn(−1) = 0.Plot y, yn-t!
Answers.
-0.2 -0.1 0.1 0.2 0.2
0.4 0.6 0.8 1.0
-0.2 -0.1 0.1 0.2 0.2
0.4 0.6 0.8 1.0
-0.2 -0.1 0.1 0.2 0.2
0.4 0.6 0.8 1.0
-0.2 -0.1 0.1 0.2 0.2
0.4 0.6 0.8 1.0
73, S
Exercise. y0(t) =−3y(t) +δ(t), y(−1) = 0, yn0(t) =−3yn(t) +βn(t), yn(−1) = 0.Plot y, yn-t!
Answers.
-0.2 -0.1 0.1 0.2 0.2
0.4 0.6 0.8 1.0
-0.2 -0.1 0.1 0.2 0.2
0.4 0.6 0.8 1.0
-0.2 -0.1 0.1 0.2 0.2
0.4 0.6 0.8 1.0
-0.2 -0.1 0.1 0.2 0.2
0.4 0.6 0.8 1.0
StudentNumber: 92
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
B A D B D D E B B C C A C D B A D B C E
21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
D C D C D C C A B C E B D D A E B C D C
41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60
C B B B C C A C C D C C A C B C C C D B
61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80
E B C A A C C D C C D C D