• Nem Talált Eredményt

PETER PAZMANY CATHOLIC UNIVERSITYConsortium members

N/A
N/A
Protected

Academic year: 2022

Ossza meg "PETER PAZMANY CATHOLIC UNIVERSITYConsortium members"

Copied!
62
0
0

Teljes szövegt

(1)

Development of Complex Curricula for Molecular Bionics and Infobionics Programs within a consortial* framework**

Consortium leader

PETER PAZMANY CATHOLIC UNIVERSITY

Consortium members

SEMMELWEIS UNIVERSITY, DIALOG CAMPUS PUBLISHER

The Project has been realised with the support of the European Union and has been co-financed by the European Social Fund ***

PETER PAZMANY CATHOLIC UNIVERSITY

SEMMELWEIS UNIVERSITY

(2)

Peter Pazmany Catholic University Faculty of Information Technology

INTRODUCTION TO BIOPHYSICS

COLLIGATIVE PROPERTIES

www.itk.ppke.hu

(Bevezetés a biofizikába)

(Kolligatív sajátságok)

(3)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Introduction

Colligative properties are properties of a dilute solution that depend only on the number of

particles in the solution but do not depend on the properties of them, like mass or size etc.

Colligative properties are:

Osmotic pressure

Lowering of vapour pressure

(4)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Osmotic pressure

Osmotic pressure is one of the colligative properties of a solution

To formalize it, let us set out from the known fundamental law:

In a heterogenous – consisting of more than one

phase –, closed system at equilibrium, the chemical potential of an uncharged substance is the same in all phases between which it can pass freely

(5)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Consider a closed box containing water in equilibrium with its vapour

Suppose some vapour goes into the liquid phase (or vice versa)

We would like to know what the free energy change of the system is

dG

system

=  G ndn

l

G ndn

v

=

l

dn

l



v

dn

v

(6)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Liquid-vapour system

(7)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Since the system is closed, i.e. only energy

exchange is possible between the system and its environment, we know that

n

l

n

v

= constant

so

dn

l

dn

v

= 0

and

(8)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Thus the free energy change is

dG =

l

dn

l

−

v

dn

v

=

l

−

v

dn

l

based on which

dG

dn

l

=

l

−

v

(9)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Let us plot the free energy, G, as a function of the number of moles in the liquid phase, nl

We can see that there pure liquid or pure vapour are both unstable conditions

Therefore the free energy decreases moving away from either extreme

Somewhere there is a minimum to this function

(10)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

G vs. nl

(11)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Since at equilibrium the slope of the curve is

G n

l

= 0

l

−

v

=0

and

 =

(12)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Now we will apply this fundamental law to osmotic pressure

Let us consider the following figure

In chamber A there are water and some polysaccharide to which the membrane is impermeable

In chamber B there is pure water

(13)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Demonstration of the osmotic pressure

(14)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Water will flow from side B to side A

generating a pressure difference proportional to h, the difference in water levels in the

standpipes at equilibrium

The excess pressure on side A is the osmotic pressure and is signed by π

(15)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

As we know, the pressure is a function of depth

 Pa =h  m ⋅ kg / m

3

⋅ g  m / sec

2

Pa = N / m

2

π can be converted to atm by noting

1 atm = 101325 Pa

(16)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

For our case

H

2O

= 1000 kg / m

3

and

g = 9.80 m / sec

2

(17)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

From the fundamental law discussed earlier, the chemical potential of water must be the same on both sides of the membrane

This is not true for the polysaccharide which can not pass the membrane

(18)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

μ is a function of the temperature, the

pressure and the composition of the solution

1, A

T , p  , x

1, A

=

1,B

T , p , x

1, B

Since temperature is constant on both sides, we can consider μ to be a function of only the pressure and the composition

= fp , x

(19)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Making use of the known relationship, the chemical potentials are

1, A

p  , x

1,A

=

1,0 A

p  RT ln 

1, A

x

1, A

and

1, B

p , x

1, B

=

1,0 B

p  RT ln 

1,B

x

1, B

=

1, B

p

making use of the fact that

(20)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

According to the fundamental law

1,0 A

p  RT ln 

1, A

x

1,A

=

1,0 B

p

so

1,0 A

p −

1,0 B

p =− RT ln x

1, A

RT ln 

1,A

(21)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Now, we wonder how μ changes with p

From basic thermodynamics, let us recall

G p

p , n

=V

and

G

(22)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Since we can do partial differentiation in any order

∂  p= [ p G n

T , p

]

T , n

[ p G n ] = [ n G p ]

(23)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

[ n G p

T , n

]

T , p

= [ n V ]

T , p

[ n V ]

T , p

=  V n

T , p

=V

(24)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

For the standard chemical potential

∂

10

p =V

10

where V0 is the molar volume of the solvent

After rearrangement we get

∂ 

10

=V

10

p

(25)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Let us integrate ∂μ10 from p to p+π assuming that water is incompressible, that is V10 is constant

p p

∂ 

10

= ∫

p p

V

10

p

We get

0

p −

0

p =V

0

⋅  p   − V

0

p

(26)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Finally we get

V

10

=− RT ln x

1,A

RT ln 

1, A

Since

x

1

x

2

=1, x

1

= 1− x

2

and thus

(27)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Let us suppose that the concentration of polysaccharide is

w =10 g / dm

3

and the molecular weight of it is

M = 25000 Da

so the molar concentration of it is

10 g / dm

3

(28)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Thus the mole fraction of the polysaccharide is

x = c cc

H

2O

= 4 ⋅ 10

−4

mol / dm

3

55.5604 mol / dm

3

≈7 ⋅ 10

−6

a very small number

(29)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

For small numbers

ln  1− ≈−

and

ln  1 ≈

if

(30)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Performing this approximation we get

V

10

= RT x

2

RT ln 

1

We know that

x

2

= n

2

n

1

n

2

but since n1 << n2 we can write that

n

(31)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Thus

V

10

= RT n

2

n

1

RT ln 

1

from which

= RT n

2

n V

0

RT ln 

1

V

0

(32)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Further simplifications can be performed

n

1

V

10

≃V

1

and since the polysaccharide takes up only a small portion of the volume of the solution

V

1

V

(33)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Substituting these simplified expressions into the main equation we obtain

= RT n

2

VRT ln 

1

V

10

= RT c

2

RT ln 

1

V

10

(34)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

In the lab, we would weigh out a number of

grams of polysaccharide and report its solution concentration in g/dm3

Let w2 denote the weight of polysaccharide per liter

Thus

c

2

= w

2

M

2

(35)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Substituting this expression of the molar concentration into the expression of the osmotic pressure we get

= RT w

2

M

2

RT

V

10

ln 

1

(36)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Now let us imagine that we are at great dilution

Now

1

≈ 1

and

ln 

1

≈0

thus

RT w

(37)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

We can solve this equation for the molecular weight of the polysaccharide

M

2

= RT w

2

so measuring the osmotic pressure of a solution of some substance its molecular weight can be determined

(38)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Another common form of the equation at infinite dilution

= RT c

2

It can reminds us of the gas law

V = n

2

RT

which holds for ideal solutions

(39)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Let us see more about the nonideality term in the equation for osmotic pressure

= RT w

2

M

2

RT

V

10

ln 

1

Let us recall that if we plot μ1 as a function of x1 we get a straight line with slope R·T for the

ideal case

(40)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Now, let us plot -RT ln γ1 as a function of ln x1

The slope of the curve approaches zero as ln x1 approaches zero

This is because the real and ideal curves coincide at

ln x

1

=0

since

(41)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

-RT ln γ1 vs. ln x1

(42)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

We can change the axes by multiplying the vertical axis by 1/(R·T·V10) and the horizontal axis by 55.56·M2 which converts x2 to w2

x

2

= n

2

n

1

n

2

n

2

n

1

= c

2

c

1

= c

2

55.56 = w

2

55.56 M

2

(43)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

-1/V10 ln γ1 vs. w2

(44)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

We can use a Taylor expansion to express this function relating

− 1

V

10

ln 

1

to

w

2

(45)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

The Taylor expansion is

− 1

V

10

ln 

1

= B

0

B

1

w

2

B

2

w

22

...

where Bi's are constants

This is an infinite series, but Bi gets very small

(46)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Now we should evaluate what B0 and B1 are

When

w

2

=0

then

− 1

V

10

ln 

1

= B

0

so

(47)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

B1 is the initial slope

∂  V 1

10

ln

1

w

2

= B

1

 2 B

2

w

2

which is also zero

B =0

(48)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

The curve starts off as a parabola

− 1

V

10

ln 

1

= B

2

w

22

B

3

w

32

...

so

= RT w

2

M

2

RTB

2

w

22

B

3

w

23

 ... 

(49)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

In general we do not know the values of B's but this is the form of the equation

Now, let us divide through by w2

w

2

= RTM 1

2

B

2

w

2

' higher order terms '

where the higher order terms can be neglected

Now the nonideality term is approximated by a

(50)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

This is the virial expansion

1/M2 is the first virial coefficient B2 is the second virial coefficient

Experimentally we can not measure π at infinite dilution

We must measure π at finite concentration where nonideality is small but still present

(51)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Suppose we collected the following data:

Example 1

w2 (g/dm3) π (atm) π/w2 (atm/g·dm-3)

10 0.011 0.0011

20 0.024 0.0012

30 0.039 0.0013

(52)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Let us plot π/w2 as a function of w2

The extrapolated intercept gives us M2 without the nonideality term

intercept = RT M

2

The slope of the curve is

slope = RT B

2

(53)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

(54)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

The slope gives us the second virial coefficient

The second virial coefficient tells us about forces between molecules

When the slope is positive, the forces are repulsive

A pure protein in a solution, at a pH which is not the isoelectric point, will have the same charge as all the other protein molecules

These protein molecules will repel each other

(55)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

When the slope is negative, the forces are attractive

Such particles will dimerize (polymerize) at higher concentrations

(56)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Two additional rules:

In an osmometer, if side A contains a polysaccharide at one concentration and side B contains a

polysaccharide at a different concentration then

= RTc

If we put more polysaccharides on the same side of an osmometer then

= RTc

(57)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Macromolecules with bound dissociable ions

Let us consider a container consisting of two chambers separated by a semipermeable

membrane, called osmometer

Let us put a protein in side A that dissociates to give one Na+ ion

There will be then the same number of proteins (negatively charged) as Na+ ions

(58)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

According to this if

[ P

]

A

= a

where [P-]A is the molar concentration of the protein in chamber A, then

[ Na

]= a

Therefore, now

= RT 2 a

(59)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Proteins with bound dissociable Na+ ions

(60)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Na+ can diffuse across the membrane but the law of 'electroneutrality' states that there

cannot be a finite (large) charge separation in solution

On microscopic scale, we violate this law all the time (for example battery or the

mitochondrial membrane etc.)

(61)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

If we measured M2 without taking this into account, it will be too small by a factor of 2

If the protein dissociates to give 10 Na+, then the M2 would be off by a factor of 10

(62)

Introduction to biophysics: Colligative properties

www.itk.ppke.hu

Before we understood about polyelectrolytes, people thought proteins had a very small

molecular weight

Also the molecular weight appeared to vary a lot

This leads to the colloidal theory of protein structure

We can solve this problem by dumping a lot of salt into the system

Hivatkozások

KAPCSOLÓDÓ DOKUMENTUMOK

● First of all, let us generalize the problem by considering not Na + and Cl - ions but a general ion with unit positive charge (+ sign in.. subscript) and another one with

● Multiple equilibria occur when small molecules bind to large molecules with multiple binding sites, such as hormones to receptors,.. substrates to enzymes, antigens to antibodies,

 Active transport processes are often distinguished by whether they utilize directly the energy of ATP hydrolysis (primary transport) or utilize the flow of another substance

– Global spatial arrangement of the whole protein – Subunit structure of proteins consisting of two or..

If the current injected into the cable is held constant, the membrane potential settles to a steady-state solution that is independent

• Finally we modeled synaptic conductances, paying extra attention to the NMDA channel: The conductance of this channel depends not only on the binding of the transmitter, but also

Minimum injected current that elicits an action potential as a function of pulse length (the threshold for constant injection is 0.018nA).. Solutions for current clamp

What is the minimal inhibitory weight needed to negate the excitatory input coming from dendrite 2 on the soma (plot the membrane potential of the soma)?. Isolate Dendrite 2