Chapter 1
N . .
s = σ ρ
(1.1.a)Φ σ . n .
s =
(1.1.b)p h
= cν
p mv= (1.2) E h= ν E mv
k = 2
2 (1.3)
( )
[
1 2 1]
2 2 1
1 E ε E hν ν hν
ε + = + − << (1.3)
ε1+E1=E*2 (1.4) hν1+E1*=2hν1+E2 (1.5)
ε1+E1*=ε2+E2 (ε2 >ε1) (1.6a) ε1+E1 =ε2+E2* (ε2 <ε1) (1.6b) ε1a+ε1b+E1=2ε1b+E2* (ε1a >ε1b) (1.7)
E1*=E2+ ε2 (1.8)
ε1a+E1=ε2b+E*2 (1.9) h I m v
I E E
a e e
ν1 2 2 1
= + 2 = * − (1.10) U Qi
i i
=4πε1
∑
R r− (1.11) p=∑
Qi iri
(1.12) F=Q E (1.13) p p= o+αE+1βE +
2
2 ... (1.14)
T p E= × (1.15)
P
p
=
∑
ii
V (1.16)
P= ε χo eE (1.17)
D= εE (1.18)
(
e)
o
o + =ε 1+χ
ε
= E P
D (1.19)
ε ε
ε χ
r ≡ o = +1 e (1.20)
P M
M ≡ r − + ε
ε ρ
1
2 (1.21)
α+
= ε ρ + ε
−
≡ ε
kT 3 3
M N 2 P 1
2
o A r
r M
p (1.22) F=Qv B× (1.23)
T m B= × (1.24)
e
mes= −ms (1.24)
s
Bs mˆ
ˆ=−2h
µ (1.25)
e
B 2m
eh
=
µ (1.26)
m l 2 m
e
e
−
= (1.27)
m
l ˆ
ˆ=−h
µB (1.28)
M Lˆ ˆ
gµB =−h (1.29)
I N
N ˆ ˆ
g µ I=hM (1.30)
p
N 2m
eh
=
µ (1.31)
∆m e r m B
e
= 2 2
4 (1.32) ω µ
γ
=g B Bh = eB (1.33)
ω=gNµB B=γNB
h (1.34)
M=
∫
ψ*i∆mψjdτ (1.35)∑
=
i i
V
M m (1.36)
M= µ χo mH (1.37)
B= µH (1.38)
µ
r= + 1 χ
m (1.39) χm AT B
= + (1.40) ω
≡ ν
=
−
≡
∆E Ei Ej h h (1.41)
( ) ( )
ij 2 t0 2 ij j
i 1 K t i t dt
a
p
ω
=
∫
← exp
h (1.42)
τ ψ ψ
=
∫
K dKij *i ˆ j (1.43)
∆pE
=
V (1.44)
τ ψ
∆ ψ
=
∫
dKij E *i p j (1.45) τ
ψ
∆ ψ
=
∫
dP *i p j (1.46)
− ν
=
−
−
= kT
h kT
E E N
N i j
j
i exp exp (1.47) 1
t a
r+ + = (1.48) δ δE. t≥ hπ
2 (1.49)
δν≥ 1πτ
2 (1.50)
c ν v ν ν
∆ν= − 0 = o (1.51) T I
Io
≡ (1.52)
( )
T I lglg I
A o =−
≡ (1.53)
( )
r I lglg I R
r o=−
≡ (1.54)
c
~≡ν
ν (1.55)
Chapter 2
ψ
=
ψ E
Hˆ (2.1)
(
ϕ θ)
=( ) ( )
ϕ θψ r, , R r Y , (2.2) V
T
Hˆ =ˆ +ˆ (2.3)
V e
o r
= − 1 4
2
πε (2.3)
( )
p p 2 re 2
m T T 2
m T
Tˆ 2 ˆ ˆ ˆ
, h
h + −
−
= ϕθ (2.4)
( )
( )
−( ) [ ( )
ϕθ]
=( ) ( )
ϕ θ
− +
θ
ϕ, ˆ ˆ R r Tˆϕ,θ Y , ER r Y , m
r 2 R V m T
Y 2
e 2 r
e
2 h
h (2.5)
( ) ( ) ( )
T[
Y( ) ]
EY 1 m r 2 R V m T
2 r R
1
e 2 r
e
2 ϕ θ −
θ
= ϕ
− + ˆϕθ ,
, ˆ
ˆ h ,
h (2.6)
En e me hc
o
= −32πε4 h2 2n = − RH2
n (2.7)
( )
( )
ϕ θ
=
ψ , , lm ,
o l n m l,
n, Y
a n
r R 2 r N 1 m l
n (2.8)
ao m eo pm
e
=4πε2h2 =52 9. (2.9) 1
dτ= ψ
∫
ψ* (2.10)( )
2 lmm l
2 1
ˆl Y =l l+ h Y (2.11)
( )
l 1h *hl l
l = + = (2.12)
m l m
l m
ˆY Y
lz = h (2.13) mh
z =
l (2.14)
l*
m=−µB (2.15)
Bm
mz =−µ (2.16)
( ) (
σ = +) ( )
ϕσ ϕ ss 1h ˆ2s (2.17)
(
s 1)
h s*h s + ==
s (2.18)
( )
σ m( )
σsˆzϕ = shϕ (2.19) h
ms z =
s (2.20)
s*
2 B
ms =− µ (2.21)
s B z
ms, =−2µ m (2.22)
j l s= + (2.23)
( )
j 1h j*h j + ==
j ( j=l+s) (2.24) h
j
jz =m
(
−j≤mj ≤+j)
(2.25)( )
ψ=
ψ 2
2 I I+1
ˆ h
I (2.26)
(
I 1)
h I*h I + ==
I for hydrogen 2
I=1 (2.27) h
I
Iz =M
(
-I≤MI ≤+I)
(2.28) I*N p
I g
M = µ (2.29)
I N p z
I g
M , = µ M (2.30) ν
=
−
=
∆E Ei Ej h (2.31) 0
jd
i∆ ψ τ≠
ψ
=
∫
pP * (2.32)
∆p= −e∆r (2.33)
∆px = −e r∆ sin cosθ ϕ (2.34)
∆py = −e r∆ sin sinθ ϕ (2.35) θ
∆
−
=
∆pz e rcos (2.36) dr
d d r
dτ= 2sinθ ϕ θ (2.37)
(
r) (
r)
r r d d dr eP j 2 2
0 0 2
0 i
x =−
∫ ∫ ∫
∞ π πψ* ,ϕ,θψ ,ϕ,θ ∆ sin θcosϕ ϕ θ (2.38)(
r) (
r)
r r d d dr eP j 2 2
0 0 2
0 i
y =−
∫ ∫ ∫
∞ π πψ* ,ϕ,θψ ,ϕ,θ ∆ sin θsinϕ ϕ θ (2.39)(
r) (
r)
r r d d dr eP j 2
0 0 2
0 i
x =−
∫ ∫ ∫
∞ π πψ* ,ϕ,θψ ,ϕ,θ ∆ sinθcosθ ϕ θ (2.40)j 2 i
i 2 j
H n n
n 1 n R 1 hc
E >
−
∆ =
=
ν~ (2.41)
lim 2
n
~ R
j H j
it =T =
ν (2.42)
E z hc
H hc z
n R
n
R
= − 2 2 = − n2 (2.43)
( ) ( )
− −
= −
ν 2
i i 2 j j
z n a
1 a
n R 1
~ (2.44)
∑ ∑ ∑∑
>
+
−
∇
−
=
i i i j i ij
2
i 2 2
e 2
r e r
ze m
Hˆ 2h (2.45)
5 ...
4 3 4 3 3 2 2
1s E s E p E s E p E s E d E p E s
E < < < < < < < < (2.46)
∑
=
i
li
L (2.47)
(
L 1)
h L*hL + =
=
L (2.48)
∑
=
i
si
S 2.49)
(
S 1)
h S*h S + ==
S (2.50)
S L
Jˆ = ˆ + ˆ (2.51)
(
J 1)
J J=L+S,L+S-1,...,L-S J + h= *h=
J (2.52)
S L J J
J
Jz =M h −J≤M ≤+J M =M +M (2.53)
( )
(
L S,veryrarely)
1 L 2
usually S,
L 1
S 2
<
+
= ι
≥ +
=
ι (2.54)
2 1 2
1 2
1 j ,j j 1,..., j j j
J ˆ :
ˆ =
∑
for two electrons = + + − −i
ji
J (2.55)
( )
J g M B2A E 1
E= o + * 2 + µB J (2.56)
( ) ( ) ( ) ( )
* 2* 2
* 2
* 2
J 2
L S
1 J
g = + + − (2.57)
(
M 2M)
B gM M A E
E= o + L S + L + S (2.58)
E Eo gN N IB= − µ M (2.59)
( )
−
+ +
= o 2 2J J 2
3 M 1 b 2 a 2E E 1
E * (2.60)
A e− − =A+ (2.61) A e A
A e A
+ =
+ =
− −
− − 2− (2.62)
( )
O A( )
OI − =− (2.63)
A e+ − =A+ +2e− (2.64) M e+ − =M++2e− (2.65)
ABC e+ − =AB− +C (2.66)
A h+ ν=A++e− (2.67)
A*+ = +B A B++e− (2.68)
A*+BC AC= ++ +B e− (2.69)
A*+ =B A++ +B e− (2.70) A*+ =B A++B− (2.71) A*+ =B AB++e− (2.72)
X++M X M= + + (2.73)
X++M XM= + (2.74)
XH++M X MH= + + (2.75)
F=Q (2.76) E
F=Qv B× (2.77)
Chapter 3 X
E X X
E× = × = (3.1) E
Y
X× = (3.2) Y X= −1 and X Y= −1 (3.3)
(
A×B)
×C=A×(
B×C)
(3.4)1
1 .ie. X Z Y Z
Z X Z
Y= × × − = × × − (3.5)
(3.6)
(3.7) 1
n 2 1 n p
2 p 2
j 1 = −
π +
±
=
χ cos , ,..., (3.8)
∑∑
∑∑
∑∑
∑
α= β>α αβ β α= α= α
α
= >
=
+
− +
∇
−
= N
1
N 2
n
1 i
N
1 i
n 2
1 i
n
i
j ij
n 2
1 i
2 e
2
r e Z Z r
e Z r
e m
Hˆ 2h (3.9)
τ ψ ψ
=
∫
dS12 1* 2 (3.10)
(
I A)
2
X=1 + (3.11)
species molecular orbital Σg+
( ) (
A B)
g 1s 1s
S 1 2
1 +
= +
σ (3.12)
Σu+
( ) (
A B)
u 1s 1s
S 1 2
1 −
= −
σ* (3.13)
( ) ( ) ( ) ( )
[
x y z]
1 2s 2p 2p 2p
2
1 χ +χ +χ +χ
=
ψ (3.14)
( ) ( ) ( ) ( )
[
2s 2px 2py 2pz]
2
2=1 χ +χ −χ −χ
ψ (3.15)
( ) ( ) ( ) ( )
[
2s 2px 2py 2pz]
2
3=1 χ −χ +χ −χ
ψ (3.16)
( ) ( ) ( ) ( )
[
x y z]
4 2s 2p 2p 2p
2
1 χ −χ −χ +χ
=
ψ (3.17)
Sij=0 i≠ j (3.18) Sij=1 i= j (3.19)
τ ψ ψ
=
∫
H dHij i* ˆ j (3.20) Hij= α if i and j belongs to the same atom (Coulomb integral) (3.21)
Hij= β if i and j belong to neighbour atoms (resonance integral) (3.22)
Hij=0 in all other cases (3.23)
H−ES =0 (3.24) α− E β
β α− E = 0
(3.25)
αX = +α hXβ (3.26) βXY =kXYβ (3.27) T I L
r I
=E = 1 = 2 1
2 2 2
ω (3.28)
(
J 1)
J J 0,1,2,3,...J + = * =
= h h
L (3.29)
J M J
MJ − ≤ J ≤
= h
Lz (3.30)
(
J 1)
B J(
J 1)
I J E 2
2
r =h + = ' + (3.31) B I
2
' =h2 (3.32) I m ri
i N
= i
∑
= 12 (3.33)
I= µro2 (3.34) µ = +
m m
m m
1 2
1 2
(3.35)
∆J = ±1 and MJ = ±1 (3.36)
( )( ) ( )
[
J 1 J 2 J J 1]
2B(
J 1)
hc B E - Eri r,j
+
= +
− + +
=
=
ν ,
~ (3.37)
cI h hc
B B 2
=8π
= ′ (3.38)
( ) ( ) ( )
+
− +
=
− +
= kT
J J J B
kT N N
N r ' 1)
exp 1 E 2
exp 1 J
2 ,J 0
0
J (3.39)
∆J = ±2 for identical atoms (3.41)
∆J = ± ±1 2, for different atoms (3.42)
( ) ( )
[
2]
r hcBJ J 1 A B K
E = + + − (3.43)
( ) ( )
[
2]
r hcBJ J 1 C BK
E = + + − (3.44)
( ) ( )
[
J J 1 K2]
Er =hcB + + A−B (3.43)
( ) ( )
[
J J 1 K2]
Er =hcB + + C−B (3.44)
∆J = ±1 ∆K=0 (IR) (3.45)
∆J = ± ±1 2, ∆K=0 (RA) (3.46)
∆J = ±1 (IR) (3.47)
∆J = ±2 (RA) (3.48)
2 2
2 2
2kq 1 dq
d H 2 +
− µ
= h
ˆ (3.49)
,...
2 , 1 , 2 v
v 1 h
Ev =
+ ν
= (3.50)
∆v= ±1 (+: absorption, -: emission) (3.51)
+
−
+ ν
=
2
v 2
v 1 2 x
v 1 h
E (3.52)
∑
∑
−=
−
=
= ν
π
= 3N 6
1 i
2 i 6
N 3
1 i
2 i 2 i 2
2c Q 2T Q
4 V
2 ~ & (3.53)
q g q fq
q 2T & 1&
V
2 = ' = ' − (3.54)
S G S FS
S 2T & 1&
V
2 = ' = ' − (3.55)
GF−λE =0 (3.56)
6 3
,..., 2 ,
~ 1
4 π
2 2ν
2= −
=
λ
ic i N
(3.57)Q L S= −1 (3.58)
j 0 i
2
ij S S
F E
∂
∂
= ∂ or
j 0 i
2
ij q q
f E
∂
∂
= ∂ (3.59)
ρ=
Ι
Ι (3.60)
1 n ,..., 2 , 1 n p
2 p cos 2
j 1 = −
π +
±
=
χ (3.61)
( )
ij ij j
j
i n R r
h
m =1
∑
χ χ − (3.62)2 nc m 2
h hc
kT hc
E
= λ
=
=
ν~ (3.63)
c
A=αl (3.63)
∫
α( )
ν ν=
band
d
A (3.64)
( )
19 3 1 1 12 A
o
e 10 144 10 A dm cm s mol
e N
c m A4
f ε ≈ × − × − − −
= ln . (3.65)
f m ee
=4 3 2
π ν
h P2 (3.66)
( )
<−( )
<− − < −−
<
−
<
−CH3 C2H5 CHCH3 2 C CH3 3 S O (3.67)
− > −F NO2> −OH> −Cl> −NH2−Br> − > − =I C O> −COOH> −CN> −SH> −R N3 + (3.68)
− < −F Cl< −Br< −OH< −OCH3< −NH2< −O− (3.69)
−NO2 > −CHO> −COCH3> −COOH COO> − ≈ −CN> −SO NH2 2 (3.70) I
v 2m
hν= 1 e 2 + (3.71) hν = 1m ve + +I Ev+ Er
2 2 ∆ ∆ (3.72)
v
n= c (3.73)
νλ
=
v (3.74)
r r
n= εrµ ≈ ε (3.75)
− πν
= nz
t 2 i E
E exp (3.76)
−
πν
− π
= c
t nz 2 c i
z 2 n E
E o exp k exp (3.77)
in
kn −
=
n
(3.78)ν α
= lnπ~ 4
10
nk c (3.79)
2 2 o o
p a
ν
−
=ν
∆ (3.80)
R n
n
M ≡ − M +
2 2 1
2 ρ (3.81)
n n
N Ci i
o i i 2
2 2 2
1 2 3
− + =
∑
− ρν Aν
,
(3.82)
λ π −
= ϑ
∆ nL nR
2 l (3.83)
[ ]
lc ϑ= ∆
α (3.84)
[ ]
M =10−3M[ ]
α (3.85)L
R −α
α
= α
∆ (3.86)
zvB mv
= r2 (3.87)
zU= mv2
2 (3.88)
m z B r / = 2 2U
2 (3.89)
m z/ = 5 7. V
4π ν2 2 (3.90)
m z U
s t / = 2
2 2 (3.91)
m m
*≈ m22
1 (3.92)
(
µ B)
2µ B Bµ
∆E=+ B − − B = B (3.93)
hν=2µBB (3.94)
∆ms= ±1 (3.95)
B h
= 2µ νB (3.96)
µ ν
=
−
B
I 2
aM h
B (3.97)
( )
BB'= 1−σ (3.98)
I 1 I 1 I - -I, M M
g
M
I,z=
aµ
N= + ,..., − ,
(3.99)B g
E = − M
IB = −
aµ
NM
(3.100)B g
E =
aµ
N∆ m
(3.101)2 B
a
0
π
= γ
ν
(3.102)( )
a( )
ra B 1
1 2
2 B = −σν
π σ γ
− π =
= γ
ν l (3.103)
( )
a( )
oa B 1
1 2
2 B = −σν
π σ γ
− π =
= γ
ν l (3.104)
δ
−
=
τ 10
(3.105)( )
∑
−σ −∑∑
µ
−
=
i i i i j ij i j
B a
o J M M
2 M h 1
B g E
E (3.106)
n ,..., 2 , 1 i M
1
M
A= ± ∆
Bi= ± =
∆
(3.107)1 M
i
i =±
∆
∑
(3.108)( )
∑
∑
≠ ≠+ ν
= σ +
−
= µ ν
i j
j ij i
j
0 i j ij i
N a
i J M J M
h 1 B
g (3.109)
2
2 J
q qJ 1 2
I= ± + (3.110)
(
+η)
=
γ γ + + + −
= I1
P 2 P P
P 1 P
I I
C H o 41 32
41 32
NOE (3.111)
(
−)
= + − −=2P n n n N N dt
dn
e (3.112)
( )
t = 1−
−
=
−
π
= γ
ϑ 2
t Bi r
(3.114)
(
B Bl)
2 T
1 T
1 a
2 2
π − + γ
* = (3.115)
1 2
*
* 2 2 2
/
1
T T T
T
1 ≤ ≤
= π ν
∆
(3.116)o
o hk
I = (3.120)
k
I=h (3.121)
=λ ν
=~ 1
k (3.122)
sin 2 2
s= ko ϑ (3.123)
( ) ( )
joR sr
k f s expi R
) i
Aexp( j
j =
ψ (3.124)
∑
=ψ
=
Ψ N
1 j
j (3.125)
( ) ( ) ( ) ( )
jk jk k
N
1 j
N
1 k
j sf s f
K s
I sr
sr
∑∑
sin= =
= (3.126)
( ) ( ) ( ) ( )
k j s
f s f K
s I
jk jk k
N
1 j
N
1 k
j
m =
∑∑
≠= = sr
sr
sin (3.127)
( )
s( ) (
' exp isr')
dr'fjϕ =
∫
ρj r − (3.128)( ) [
Z f( )
s]
s s C
fje = 2 j − jϕ (3.129)
( ) ( ) ( )
s Is s I
M
g
= m (3.130)
( )
drr r rp r
0
g =∞
∫
(3.131)
( ) ( )
drr r p
r dr r rp r
0 0 a
∫
∫
∞
∞
= (3.132)
Chapter 4
∑
=−
=
N1 i
ia
E E
E
i (4.1)∑ ∑ ∑ ∑ ∑
= =+ = =+ = +
+ + +
=
Ni N
i j
N i
N i j
N j k
1 1 ij 1 1 1 ijk i,j,k,...,N
ia
E E ... E
E
(4.2)∑ ∑
= =+=
Ni N
i j
1 1
ij
ia
E
E
(4.3)Vˆ Hˆ Vˆ Hˆ Hˆ
Hˆ
ij=
i+
j+ =
0+
(4.4)τ ϕ ϕ ϕ ϕ
=
∫
Vˆ dEij *j *i i j (4.5)
2 ij 1 ij
ij E E
E = + (4.6)
( ) ( ) ( )
ϑ ϕ − ρ ϑ ϕ
+
= π ∑
α α∫
=
α α α i i j j j j j j
N
1 i
i
Z r Y , r r Y , dr
1 2
Q
lm4
j l ml mll
(4.7)10 10 8 8 6 6 4 2 4
R C R C R C R E C
ij ij ij ij
ij =− − − − (4.8) dx Eψ
ψ d 2m 2
2 e
2 =
− h
(4.9)
( )
x exp( )
ikxψk = (4.10)
e 2 2
k
2m
h
E = k
(4.11)= λ
= κ
= h
d h hk N
I (4.12)
+ −
=
kT E 1 E
N 2 N
F F
exp
(4.13)
2dsinα=nλ n= ± ±0 1 2, , ,... (4.14)
( )
s F EE= o (4.15)
( ) ( )
+ +
=
=
∑ ∑
=
= j
3 j 2 j 1 N
1 j
j j
N
1 j
j z
d y l d x k d i h exp f isr
exp f s
F (4.16)
ϑ
=
∆x dsin (4.17) λ ϑ
= π λ π∆
= ϕ
∆ 2 sin
2 x d
(4.18) ,...
3 , 2 , 1 2
4 sin
4 ϑ= π = λ
= π λ π∆
= ϕ
∆ x d n n
(4.19)
( )
N j
i d n
di ij
ij 4 sin 2 1,2,3 1,2,...,
=
= π
= λ ϑ
±
= π ϕ
∆ (4.20)