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volume 2, issue 2, article 26, 2001.

Received 6 November, 2000;

accepted 6 March, 2001.

Communicated by:F. Hansen

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Journal of Inequalities in Pure and Applied Mathematics

A PICK FUNCTION RELATED TO AN INEQUALITY FOR THE ENTROPY FUNCTION

CHRISTIAN BERG

Department of Mathematics, University of Copenhagen, Universitetsparken 5

DK-2100 Copenhagen, DENMARK.

EMail:berg@math.ku.dk URL:http://www.math.ku.dk/ berg/

c

2000Victoria University ISSN (electronic): 1443-5756 024-01

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A Pick Function Related to an Inequality for the Entropy

Function Christian Berg

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J. Ineq. Pure and Appl. Math. 2(2) Art. 26, 2001

http://jipam.vu.edu.au

Abstract

The functionψ(z) = 2/(1 +z) + 1/(Log(1−z)/2), holomorphic in the cut plane C\[1,∞[, is shown to be a Pick function. This leads to an integral representation of the coefficients in the power series expansionψ(z) =P

n=0βnzn,|z|< 1.

The representation shows that (βn) decreases to zero as conjectured by F.

Topsøe. Furthermore,(βn)is completely monotone.

2000 Mathematics Subject Classification:30E20, 44A60.

Key words: Pick functions, completely monotone sequences.

Contents

1 Introduction and Statement of Results . . . 3 2 Proofs. . . 5

References

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A Pick Function Related to an Inequality for the Entropy

Function Christian Berg

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1. Introduction and Statement of Results

In the paper [2] about bounds for entropy Topsøe considered the function

(1.1) ψ(x) = 2

1 +x + 1

ln1−x2 , −1< x <1 with the power series expansion

(1.2) ψ(x) =

X

n=0

βnxn

and conjectured from numerical evidence that(βn)decreases to zero.

The purpose of this note is to prove the conjecture by establishing the integral representation

(1.3) βn =

Z 1

dt

tn+12+ ln2 t−12 ), n ≥0.

This formula clearly shows β0 > β1 > · · · > βn → 0. Furthermore, by a change of variable we find

βn = Z 1

0

sn ds

s(π2+ ln2 1−s2s ), n ≥0,

which shows that(βn)is a completely monotone sequence, cf. [3].

The representation (1.3) follows from the observation thatψis the restriction of a Pick function with the following integral representation

(1.4) ψ(z) =

Z 1

dt

(t−z)(π2+ ln2t−12 ), z ∈C\[1,∞[.

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A Pick Function Related to an Inequality for the Entropy

Function Christian Berg

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From (1.4) we immediately get (1.3) sinceβn(n)(0)/n!.

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A Pick Function Related to an Inequality for the Entropy

Function Christian Berg

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2. Proofs

A holomorphic function f : H → C in the upper half-plane is called a Pick function, cf. [1], if Imf(z) ≥ 0for all z ∈ H. Pick functions are also called Nevanlinna functions or Herglotz functions. They have the integral representa- tion

(2.1) f(z) =az+b+ Z

−∞

1

t−z − t 1 +t2

dµ(t),

wherea≥0,b∈Randµis a non-negative Borel measure onRsatisfying Z dµ(t)

1 +t2 <∞. It is known that

(2.2) a= lim

y→∞f(iy)/iy , b =Ref(i), µ = lim

y→0+

1

π Imf(t+iy)dt , where the limit refers to the vague topology. Finally f has a holomorphic ex- tension toC\[1,∞[if and only if supp(µ)⊆[1,∞[.

Let Logz = ln|z|+iArgz denote the principal logarithm in the cut plane C\]− ∞,0], with Argz ∈]−π, π[. Hence Log1−z2 is holomorphic inC\[1,∞[

withz =−1as a simple zero. It is easily seen that

(2.3) ψ(z) = 2

1 +z + 1

Log1−z2 , z ∈C\[1,∞[

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A Pick Function Related to an Inequality for the Entropy

Function Christian Berg

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is a holomorphic extension of (1.1) with a removable singularity for z = −1 whereψ(−1) = 1/2. To see thatV(z) =Imψ(z)≥ 0forz ∈ Hit suffices by the boundary minimum principle for harmonic functions to verify

lim infz→xV(z)≥0forx∈Randlim inf|z|→∞V(z)≥0, where in both cases z ∈H.

We find

z→xlimψ(z) =

ψ(x), x≤1(withψ(1) = 1)

2

1+x + 1

lnx−12 −iπ, x >1 hence

z→xlimV(z) =

0, x≤1

π

π2+ln2x−12 , x >1,

whereas lim|z|→∞ψ(z) = 0. This shows that ψ is a Pick function, and from (2.2) we see thata= 0andµhas the following continuous density with respect to Lebesgue measure

d(x) =

0, x≤1

1

π2+ ln2 x−12

, x >1.

Therefore

ψ(z) = b+ Z

1

1

t−z − t 1 +t2

dt π2+ ln2 t−12 .

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A Pick Function Related to an Inequality for the Entropy

Function Christian Berg

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In this case we can integrate term by term, and since limx→−∞ψ(x) = 0, we find

ψ(z) = Z

1

dt

(t−z)(π2+ ln2 t−12 ) and

b =Reψ(i) = 1− 8 ln 2 π2+ 4 ln2 2 =

Z 1

tdt

(1 +t2)(π2+ ln2t−12 ), which establishes (1.4).

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A Pick Function Related to an Inequality for the Entropy

Function Christian Berg

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References

[1] W.F. DONOGHUE, Monotone Matrix Functions and Analytic Continua- tion, Berlin, Heidelberg, New York, 1974.

[2] F. TOPSØE, Bounds for entropy and divergence for distributions over a two-element set, J. Ineq. Pure And Appl. Math., 2(2) (2001), Article 25.

http://jipam.vu.edu.au/v2n2/044_00.html [3] D.V. WIDDER, The Laplace Transform, Princeton 1941.

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