Alpha Convexity Khalida Inayat Noor vol. 8, iss. 1, art. 16, 2007
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ON A GENERALIZATION OF ALPHA CONVEXITY
KHALIDA INAYAT NOOR
Mathematics Department,
COMSATS Institute of Information Technology, Islamabad, Pakistan.
EMail:khalidanoor@hotmail.com
Received: 28 November, 2006
Accepted: 06 February, 2007
Communicated by: N.E. Cho 2000 AMS Sub. Class.: 30C45, 30C50.
Key words: Starlike, Convex, Strongly alpha-convex, Bounded boundary rotation.
Abstract: In this paper, we introduce and study a classM˜k(α, β, γ), k ≥ 2of analytic functions defined in the unit disc. This class generalizes the concept of alpha- convexity and include several other known classes of analytic functions. Inclu- sion results, an integral representation and a radius problem is discussed for this class.
Acknowledgements: This research is supported by the Higher Education Commission, Pakistan, through research grant No: 1-28/HEC/HRD/2005/90.
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Contents
1 Introduction 3
2 Main Results 5
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1. Introduction
LetP˜denote the class of functions of the form
(1.1) p(z) = 1 +c1z+c2z2+· · · ,
which are analytic in the unit discE ={z :|z|<1}.LetP˜(γ)be the subclass ofP˜ consisting of functionspwhich satisfy the condition
(1.2) |argp(z)| ≤ πγ
2 , for some γ(γ >0), z ∈E.
We note thatP˜(1) = P is the class of analytic functions with positive real part. We introduce the classP˜k(γ)as follows:
An analytic functionpgiven by (1.1) belongs toP˜k(γ),forz ∈E,if and only if there existp1, p2 ∈P˜(γ)such that
(1.3) p(z) =
k 4 + 1
2
p1(z)− k
4 −1 2
p2(z), k ≥2.
We now define the classM˜k(α, β, γ)as follows:
Definition 1.1. Let α ≥ 0, β ≥ 0 (α+β 6= 0) and let f be analytic in E with f(0) = 0, f0(0) = 1and f0(z)fz (z) 6= 0.Then f ∈ M˜k(α, β, γ)if and only if , for z ∈E,
α α+β
zf0(z)
f(z) + β α+β
(zf0(z))0 f0(z)
∈P˜k(γ).
We note that, fork = 2, β = (1−α),we have the classM˜2(α,1−α, γ) = ˜Mα(γ) of strongly alpha-convex functions introduced and studied in [4].
We also have the following special cases.
Alpha Convexity Khalida Inayat Noor vol. 8, iss. 1, art. 16, 2007
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(i) M˜2(α,0,1) = S?, M˜2(0, β,1) = C, where S? and C are respectively the well-known classes of starlike and convex functions. It is known [3] that M˜α(γ)⊂S?andM˜2(α,0, γ)coincides with the class of strongly starlike func- tions of orderγ,see [1,7,8].
(ii) M˜k(α,0,1) = Rk, M˜k(0, β,1) = Vk,whereRk is the class of functions of bounded radius rotation and Vk is the class of functions of bounded boundary rotation.
AlsoM˜k(0, β, γ) = ˜Vk(γ)⊂VkandM˜k(α,0, γ) = ˜Rk(γ)⊂Rk.
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2. Main Results
Theorem 2.1. A functionf ∈ M˜k(α, β, γ), α, β >0,if and only if, there exists a functionF ∈R˜k(γ)such that
(2.1) f(z) =
"
α+β α
Z z
0
(F(t))α+ββ t dt
#α+ββ .
Proof. A simple calculation yields α
α+β
zf0(z)
f(z) + β α+β
(zf0(z))0
f0(z) = zF0(z) F(z) .
If the right hand side belongs toP˜k(γ)so does the left and conversely, and the result follows.
Theorem 2.2. Letf ∈M˜k(α, β, γ).Then the function
(2.2) g(z) =f(z)
zf0(z) f(z)
α+ββ
belongs toR˜k(γ)forz ∈E.
Proof. Differentiating (2.2) logarithmically, we have zg0(z)
g(z) = α α+β
zf0(z)
f(z) + β α+β
(zf0(z))0 f0(z) , and, sincef ∈M˜k(α, β, γ),we obtain the required result.
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Theorem 2.3. Let f ∈ M˜k(α, β, γ), β > 0,0 < γ ≤ 1. Then f ∈ R˜k(γ) for z ∈E.
Proof. Let zff(z)0(z) =p(z).Then (zf0(z))0
f0(z) =p(z) + zp0(z) p(z) . Therefore, forz ∈E,
(2.3) α
α+β
zf0(z)
f(z) + β α+β
(zf0(z))0 f0(z) =
p(z) + β α+β
zp0(z) p(z)
∈P˜k(γ).
Let
(2.4) φ(α, β) = α
α+β z
1−z + β α+β
z (1−z)2. Then, using (1.3) and (2.4), we have
p ? φ(α, β) z
= k
4 +1
2 p1? φ(α, β) z
− k
4 − 1
2 p2?φ(α, β) z
,
where?denotes the convolution (Hadamard product). This gives us p(z) + β
α+β zp0(z)
p(z) = k
4 + 1
2 p1(z) + β α+β
zp01(z) p1(z)
− k
4 − 1
2 p2(z) + β α+β
zp02(z) p2(z)
.
From (2.3), it follows that
pi+ β α+β
zp0i pi
∈P˜(γ), i= 1,2,
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and, using a result due to Nunokawa and Owa [6], we conclude thatpi ∈ P˜(γ) in E, i= 1,2.Consequentlyp∈P˜k(γ)and hencef ∈R˜k(γ)forz ∈E.
Theorem 2.4. Let, for(α1 +β1)6= 0, α1
α1+β1 < α
α+β, β1
α1+β1 < β
α+β and 0≤γ <1.
Then
M˜k(α, β, γ)⊂M˜K(α1, β1, γ), z ∈E.
Proof. We can write α1 α1 +β1
zf0(z)
f(z) + β1 α1+β1
(zf0(z))0 f0(z)
=
1− β1(α+β) β(α1+β1)
zf0(z) f(z) +
β1(α+β) β(α1+β1)
α α+β
zf0(z)
f(z) + β α+β
(zf0(z))0 f0(z)
=
1− β1(α+β) β(α1+β1)
H1(z) + β1(α+β)
β(α1+β1)H2(z),
whereH1, H2 ∈P˜k(γ)by using Definition1.1and Theorem2.3. Since0< γ ≤1, the classP˜(γ)is a convex set and consequently, by (1.3), the classP˜k(γ)is a convex set. This impliesH ∈ P˜k(γ)and thereforef ∈ M˜k(α1, β1, γ). This completes the proof.
Theorem 2.5. Letf ∈M˜k(α, β, γ).Then
(2.5) h(z) = Z z
0
(f0(t))
β α+β
f(t) t
α+βα
dt belongs to V˜k(γ) for z ∈E.
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Proof. From (2.5), we have
h0(z) = (f0(z))
β α+β
f(z) z
α+βα .
Now the proof is immediate when we differentiate both sides logarithmically and use the fact thatf ∈M˜k(α, β, γ).
In the following we study the converse case of Theorem2.3withγ = 1.
Theorem 2.6. Let f ∈ R˜k(1). Then f ∈ M˜k(α, β,1), β > 0 for |z| < r(α, β), where
(2.6) r(α, β) = 1−ρ212
−ρ, with ρ= β α+β. This result is best possible.
Proof. Sincef ∈R˜k(1), zff(z)0(z) ∈P˜k(1) =Pk,and α
α+β
zf0(z)
f(z) + β α+β
(zf0(z))0
f0(z) =p(z) + β α+β
zp0(z) p(z) .
Letφ(α, β) be as given by (2.4). Now using (1.3) and convolution techniques, we have
p(z) + β α+β
zp0(z)
p(z) =p(z)? φ(α, β) z
= k
4 +1
2 p1(z)? φ(α, β) z
− k
4 −1
2 p2(z)?φ(α, β) z
.
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Sincepi ∈P˜2(1) =P and it is known [2] thatRen
φ(α,β) z
o
> 12 for|z|< r(α, β),it follows from a well known result, see [5] thath
pi? φ(α,β)z i
∈P for|z|< r(α, β), i= 1,2.withr(α, β)given by (2.6). The functionφ(α, β)given by (2.4) shows that the radiusr(α, β)is best possible.
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References
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[3] S.S. MILLER, P.T. MOCANUAND M.O. READE, Allα-convex functions are univalent and starlike, Proc. Amer. Math. Soc., 37 (1973), 552–554.
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[5] K. INAYAT NOOR, Some properties of certain analytic functions, J. Natural Geometry, 7 (1995), 11–20.
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