Modulus ofU-Convexity and Modulus ofW∗-Convexity
Zhanfei Zuo and Yunan Cui vol. 9, iss. 4, art. 107, 2008
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A NOTE ON THE MODULUS OF U -CONVEXITY AND MODULUS OF W
∗-CONVEXITY
ZHANFEI ZUO AND YUNAN CUI
Department of Mathematics
Harbin University of Science and Technology Harbin, Heilongjiang 150080, P.R. China
EMail:zuozhanfei0@163.com yunan_cui@yahoo.com.cn
Received: 29 July, 2008
Accepted: 13 November, 2008
Communicated by: S.S. Dragomir 2000 AMS Sub. Class.: 46B20.
Key words: Modulus of U-convexity; Modulus of W*-convexity; Coefficient of weak orthog- onality; Uniform normal structure; Fixed point.
Abstract: We present some sufficient conditions for which a Banach spaceXhas normal structure in term of the modulus of U-convexity, modulus of W*-convexity and the coefficient of weak orthogonality. Some known results are improved.
Modulus ofU-Convexity and Modulus ofW∗-Convexity
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Contents
1 Introduction 3
2 Uniform Normal Structure 6
Modulus ofU-Convexity and Modulus ofW∗-Convexity
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1. Introduction
We assume thatXandX∗stand for a Banach space and its dual space, respectively.
By SX andBX we denote the unit sphere and the unit ball of a Banach spaceX, respectively. LetCbe a nonempty bounded closed convex subset of a Banach space X. A mappingT :C →Cis said to be nonexpansive provided the inequality
kT x−T yk ≤ kx−yk
holds for everyx, y ∈C. A Banach spaceX is said to have the fixed point property if every nonexpansive mappingT :C →Chas a fixed point, whereCis a nonempty bounded closed convex subset of a Banach spaceX.
Recall that a Banach space X is said to be uniformly non-square if there exists δ > 0such that kx+yk/2 ≤ 1−δ or kx−yk/2 ≤ 1−δ wheneverx, y ∈ SX. A bounded convex subsetK of a Banach spaceX is said to have normal structure if for every convex subsetH ofK that contains more than one point, there exists a pointx0 ∈H such that
sup{kx0−yk:y∈H}<sup{kx−yk:x, y ∈H}.
A Banach space X is said to have weak normal structure if every weakly compact convex subset of X that contains more than one point has normal structure. In re- flexive spaces, both notions coincide. A Banach space X is said to have uniform normal structure if there exists0< c < 1such that for any closed bounded convex subsetK ofX that contains more than one point, there existsx0 ∈Ksuch that
sup{kx0−yk:y∈K}< csup{kx−yk:x, y ∈K}.
It was proved by W.A. Kirk that every reflexive Banach space with normal structure has the fixed point property (see [9]).
Modulus ofU-Convexity and Modulus ofW∗-Convexity
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The WORTH property was introduced by B. Sims in [15] as follows: a Banach spaceX has the WORTH property if
n→∞lim
kxn+xk − kxn−xk = 0
for all x ∈ X and all weakly null sequences {xn}. In [16], Sims introduced the following geometric constant
ω(X) = supn
λ >0 :λ·lim inf
n→∞ kxn+xk ≤lim inf
n→∞ kxn−xko ,
where the supremum is taken over all the weakly null sequences{xn}inX and all elementsx of X. It was proved that 13 ≤ ω(X) ≤ 1. It is known thatX has the WORTH property if and only ifω(X) = 1. We also note here thatω(X) = ω(X∗) in a reflexive Banach space (see [7]).
In [1] and [2], Gao introduced the modulus ofU-convexity and modulus of W∗- convexity of a Banach spaceX, respectively, as follows:
UX() := inf
1−1
2kx+yk:x, y ∈SX, f(x−y)≥for somef ∈ ∇x
,
WX∗() := inf 1
2f(x−y) :x, y ∈SX,kx−yk ≥for somef ∈ ∇x
. Here∇x :={f ∈SX∗ :f(x) =kxk}. S. Saejung (see [11], [12]) studied the above modulus extensively, and obtained some useful results as follows :
(1) If UX() > 0or W∗() > 0 for some ∈ (0,2), then X is uniformly non- square.
(2) IfUX() > 12 max{0, −1}for some ∈ (0,2), thenX has uniform normal structure. Further, ifUX() >max{0, −1}for some ∈(0,2), then X and X∗ has uniform normal structure.
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(3) IfWX∗()> 12max{0, −1}for some ∈(0,2), thenXandX∗ has uniform normal structure.
In a recent paper [4], Gao introduced the following quadratic parameter, which is defined as
E(X) = sup
kx+yk2+kx−yk2 :x, y ∈SX .
The constant is also a significant tool in the geometric theory of Banach spaces.
Furthermore, Gao obtained the values ofE(X) for some classical Banach spaces.
In terms of the constant, he obtained some sufficient conditions for a Banach space X to have uniform normal structure, which plays an important role in fixed point theory.
In this paper, we will show that a Banach spaceX has uniform normal structure whenever
UX(1 +ω(X))> 1−ω(X)
2 or WX∗(1 +ω(X))> 1−ω(X)
2 .
These results improve S. Saejung’s and Gao’s results. Furthermore, sufficient condi- tions for uniform normal structure in terms ofE(X)andω(X)have been obtained which improve the results in [3].
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2. Uniform Normal Structure
As our proof uses the ultraproduct technique, we start by making some basic defini- tions. LetU be a filter onI. Then,{xi}is said to be convergent toxwith respect to U, denoted bylimUxi =x, if for each neighborhoodV ofx,{i∈I :xi ∈V} ∈ U. A filterU onIis called an ultrafilter if it is maximal with respect to the ordering of set inclusion. An ultrafilter is called trivial if it is of the form{A : A ⊆ I, i0 ∈ A}
for somei0 ∈I. We will use the fact that ifU is an ultrafilter, then (1) for anyA⊆I, eitherA∈ U orI A∈ U;
(2) if{xi}has a cluster pointx, thenlimUxi exists and equalsx.
Let{Xi}be a family of Banach spaces andl∞(I, Xi)denote the subspace of the product space equipped with the norm k(xi)k = supi∈Ikxik < ∞. Let U be an ultrafilter onI and NU = {(xi) ∈ l∞(I, Xi) : limUkxik = 0}. The ultraproduct of {Xi}i∈I is the quotient space l∞(I, Xi)/NU equipped with the quotient norm.
We will use (xgi)U to denote the element of the ultraproduct. In the following, we will restrict our set I to be N (the set of U natural numbers), and let Xi = X, i ∈ N, for some Banach space X. For an ultrafilter U on N, we useXeU to denote the ultraproduct. Note that if U is nontrivial, then X can be embedded into XeU
isometrically.
Lemma 2.1 (see [5]). LetXbe a Banach space without weak normal structure, then there exists a weakly null sequence{xn}∞n=1 ⊆SX such that
limn kxn−xk= 1 for all x∈co{xn}∞n=1
Theorem 2.2. IfUX(1 +ω(X))> 1−ω(X)2 , thenX has uniform normal structure.
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Proof. It suffices to prove thatX has weak normal structure whenever UX(1 +ω(X))> 1−ω(X)
2 .
In fact, since 13 ≤ω(X)≤1, we have
UX()> 1−ω(X)
2 ≥0
for some∈(0,2). This implies thatXis super-reflexive, and thenUX() = UXe() (see [11]). Now suppose thatX fails to have weak normal structure. Then, by the Lemma2.1, there exists a weakly null sequence{xn}∞n=1 inSX such that
limn kxn−xk= 1 for all x∈co{xn}∞n=1.
Take {fn} ⊂ SX∗ such that fn ∈ ∇xn for all n ∈ N. By the reflexivity of X∗, without loss of generality we may assume thatfn+ f for somef ∈BX∗(where+ denotes weak star convergence). We now choose a subsequence of{xn}∞n=1, denoted again by{xn}∞n=1, such that
limn kxn+1−xnk= 1, |(fn+1−f)(xn)|< 1
n, fn(xn+1)< 1 n for alln∈N. It follows that
limn fn+1(xn) = lim
n (fn+1−f)(xn) +f(xn) = 0.
Putx˜= (xn+1−xn)U,y˜= [ω(X)(xn+1+xn)]U, andf˜= (−fn)U. By the definition ofω(X)and Lemma2.1, then
kf˜k= ˜f(˜x) =k˜xk= 1
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and
k˜yk=k[ω(X)(xn+1+xn)]Uk ≤ kxn+1−xnk= 1.
Furthermore, we have f(˜˜x−y) = lim˜
U (−fn)
(1−ω(X))xn+1−(1 +ω(X))xn
= 1 +ω(X), k˜x+ ˜yk= lim
U k(1 +ω(X))xn+1−(1−ω(X))xnk
≥lim
U (fn+1)
(1 +ω(X))xn+1−(1−ω(X))xn
= 1 +ω(X).
From the definition ofUX(), we have
UX(1 +ω(X)) =UXe(1 +ω(X))≤ 1−ω(X)
2 ,
which is a contradiction. Therefore
UX(1 +ω(X))> 1−ω(X) 2 implies thatX has uniform normal structure.
Remark 1. Compare to the result of S. Saejung (2). Let = 1 + ω(X). Then UX() > 2−2 implies thatX has uniform normal structure from Theorem2.2. It is well known that13 ≤ω(X)≤1, therefore −12 > 2−2 wheneverω(X)> 12, therefore Theorem2.2strengthens the result of S. Saejung (2).
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The modulus of convexity ofXis the functionδX() : [0,2]→[0,1]defined by δX() = inf
1− kx+yk
2 :x, y ∈SX,kx−yk=
= inf
1− kx+yk
2 :kxk ≤1,kyk ≤1,kx−yk ≥
.
The function δX() is strictly increasing on [0(X),2]. Here 0(X) = sup{ : δX() = 0} is the characteristic of convexity of X. Also, X is uniformly non- square provided0(X)<2. Some sufficient conditions for which a Banach spaceX has uniform normal structure in terms of the modulus of convexity have been widely studied in [3], [5], [13], [18]. It is easy to prove thatUX() ≥ δX(), therefore we have the following corollary which strengthens Theorem 6 of Gao [3].
Corollary 2.3. IfδX((1 +ω(X))> 1−ω(X2 ), thenXhas uniform normal structure.
Remark 2. In fact, it is well known thatJ(X)< if and only ifδX()>1− 2 (see [6]). Therefore Corollary2.3is equivalent toJ(X)<1 +ω(X)implies thatX has uniform normal structure (see [7, Theorem 2]). Moreover, ifX is the Bynum space b2,∞, thenX does not have normal structure andδX((1 +ω(X)) = 1−ω(X)2 . Hence Theorem2.2and Corollary2.3are sharp.
It is well known that0(X) = 2ρ0X∗(0). Here,ρ0X(0) = limt→0 ρXt(t), whereρX(t) is the modulus of smoothness defined as
ρX(t) = sup
kx+tyk+kx−tyk
2 −1 :x, y ∈SX
.
Therefore we have the following corollary.
Corollary 2.4. IfδX(2ω(X))> 1−ω(X2 ), thenXandX∗ have uniform normal struc- ture.
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Proof. From2ω(X)≤1 +ω(X)and the monotonicity ofδX(), we have thatXhas uniform normal structure from Corollary2.3. It is well known thatω(X) = ω(X∗) in a reflexive Banach space. So the inequality ρ0X∗(0) < ω(X), or, equivalently, 0(X) < 2ω(X) imply X∗ has uniform normal structure (see [10], [13]). From the definition of0(X), obviously the conditionδX(2ω(X)) > 1−ω(X2 ) implies that 0(X)<2ω(X). SoX∗have uniform normal structure.
Theorem 2.5. IfWX∗(1 +ω(X))> 1−ω(X2 ), thenXhas uniform normal structure.
Proof. It suffices to prove that X has weak normal structure whenever WX∗(1 + ω(X))> 1−ω(X2 ). In fact, since 13 ≤ω(X)≤1, we haveWX∗(2)> 1−ω(X)2 ≥0for some ∈ (0,2). This implies that X is super-reflexive, and WX∗() = W∗
Xe()(see [12]). Repeating the arguments in the proof of Theorem2.2, andx˜= (xn−xn+1)U,
˜
y= [ω(X)(xn+1+xn)]U, andf˜= (fn)U. Then
f(˜x) =k˜xk= 1 and k˜yk ≤1.
Furthermore, we have k˜x−yk˜ = lim
U k(1 +ω(X))xn+1−(1−ω(X))xnk
≥lim
U (fn+1)
(1 +ω(X))xn+1−(1−ω(X))xn
= 1 +ω(X),
1 2
f˜(˜x−y) =˜ 1 2lim
U (fn)
(1−ω(X))xn−(1 +ω(X))xn+1
= 1−ω(X)
2 .
However, this implies
WX∗(1 +ω(X)) =W∗
Xe(1 +ω(X))≤ 1−ω(X) 2
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which is a contradiction. Therefore
WX∗(1 +ω(X))> 1−ω(X) 2 implies thatX has uniform normal structure.
Remark 3. Similarly, the above theorem strengthens the result of S. Saejung (3), wheneverω(X)> 12. SinceWX∗()≥δX(), therefore we also obtain Corollary2.3 from Theorem2.5.
The following theorem can be found in [14].
Theorem 2.6. LetX be a Banach space, we have
E(X) = sup{2+ 4(1−δX())2 :∈(0,2]}
Remark 4. Letting→2−in Theorem2.6, we obtain the following inequality E(X)≥4 + [0(X)]2.
Corollary 2.7. If E(X) < 2(1 + ω(X))2, then X and X∗ have uniform normal structure.
Proof. From Theorem2.6, E(X) < 2(1 +ω(X))2 implies thatδX((1 +ω(X)) >
1−ω(X)
2 , soXhas uniform normal structure from Corollary2.3. It is well known that 0(X) < 2ω(X) implies thatX∗ have uniform normal structure. Therefore, from Remark4, E(X) <4(1 +ω(X)2)implies thatX∗ have uniform normal structure.
Obviously
E(X)<2(1 +ω(X))2 ≤4(1 +ω(X)2) impliesX∗ have uniform normal structure.
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Remark 5. In [3], Gao obtained that ifE(X)<1 + 2ω(X) + 5(ω(X))2, thenXhas uniform normal structure. Comparing the result of Gao and Corollary2.7, we have the following equality
2(1 +ω(X))2−1−2ω(X)−5(ω(X))2 = (1−ω(X))(3ω(X) + 1).
It is well known that 13 ≤ω(X)≤1, so whenω(X)<1, we have (1−ω(X))(3ω(X) + 1)>0.
Therefore Corollary2.7is strict generalization of Gao’s result. Moreover this is ex- tended to conclude uniform normal structure forX∗. In fact repeating the arguments in [7], we have thatE(b2,∞) = 3+2√
2, whereb2,∞is the Bynum space which does not have normal structure andE(X) = 2(1 +ω(X))2 (note that ω(b2,∞) =
√2 2 ).
Therefore Corollary2.7is sharp.
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