(2010) pp. 95–100
http://ami.ektf.hu
Some inequalities for q-polygamma function and ζ q -Riemann zeta functions
Valmir Krasniqi
a, Toufik Mansour
bArmend Sh. Shabani
aaDepartment of Mathematics, University of Prishtina, Prishtinë 10000, Republic of Kosova
bDepartment of Mathematics, University of Haifa, 31905 Haifa, Israel Submitted 26 February 2010; Accepted 10 June 2010
Abstract
In this paper, we present some inequalities forq-polygamma functions and ζq-Riemann Zeta functions, using aq-analogue of Holder type inequality.
Keywords:q-polygamma functions,q-zeta function.
MSC:33D05, 11S40, 26D15.
1. Introduction and preliminaries
In this section, we provide a summary of notations and definitions used in this paper. For details, one may refer to [3, 5].
Forn= 1,2, . . .we denote byψn(x) =ψ(n)(x)the polygamma functions as the n-th derivative of the psi function ψ(x) = Γ
′(x)
Γ(x), x > 0, where Γ(x) denotes the usual gamma function.
Throughout this paper we will fixq∈(0,1). Letabe a complex number. The q-shifted factorials are defined by
(a;q)n =
n−1Y
k=0
(1−aqk), n= 1,2, . . . ,
(a;q)∞= lim
n→∞(a;q)n =Y
k>0
(1−aqk).
95
Jackson [4] defined theq-gamma function as Γq(x) = (q;q)∞
(qx;q)∞(1−q)1−x, x6= 0,−1, . . . (1.1) It satisfies the functional equation
Γq(x+ 1) = [x]qΓq(x), Γq(1) = 1, (1.2) where forxcomplex[x]q = 1−q1−qx.
Theq-gamma function has the following integral representation (see [2]) Γq(x) =
Z 1−1q
0
tx−1Eq−qtdqt= Z 1−∞q
0
tx−1Eq−qtdqt, x >0.
where Exq = P∞
j=0qj(j2−1)[j]xj
q! = (1 + (1−q)x)∞q , which is the q-analogue of the classical exponential function.
Theq-analogue of theψfunction is defined as the logarithmic derivative of the q-gamma function
ψq(x) =Γ′q(x)
Γq(x), x >0. (1.3)
Theq-Jackson integral from0to ais defined by (see [4, 5]) Z a
0
f(x)dqx= (1−q)a X∞
n=0
f(aqn)qn. (1.4)
Fora=∞theq-Jackson integral is defined by (see [4, 5]) Z ∞
0
f(x)dqx= (1−q) X∞
n=−∞
f(qn)qn (1.5)
provided that sums in (1.4) and (1.5) converge absolutely.
In [2] theq-Riemman zeta function is defined as follows (see Section 2.3 for the definitions)
ζq(s) = X∞
n=1
1 {n}sq =
X∞
n=1
q(n+α([n]q))s
[n]sq . (1.6)
In relation to (1.3) and (1.6), K. Brahim [1], using aq-analogue of the generalized Schwarz inequality, proved the following Theorems.
Theorem 1.1. Forn= 1,2. . .,
ψq,n(x)ψq,m(x)>ψq,2m+n 2 (x),
whereψq,n=ψq(n) isn-th derivative ofψq and m+n2 is an integer.
Theorem 1.2. For all s >1, [s+ 1]q
ζq(s)
ζq(s+ 1) >q[s]q
ζq(s+ 1) ζq(s+ 2).
The aim of this paper is to present some inequalities forq-polygamma functions and q-zeta functions by using a q-analogue of Holder type inequality, similar to those in [1].
2. Main results
2.1. A lemma
In order to prove our main results, we need the following lemma.
Lemma 2.1. Let a∈R+∪ {∞}, letf andg be two nonnegative functions and let p, t >1 such thatp−1+t−1= 1. The following inequality holds
Z a 0
f(x)g(x)dqx6 Z a
0
fp(x)dqx1p Z a
0
gt(x)dqx1t . Proof. Leta >0. By (1.4) we have that
Z a 0
f(x)g(x)dqx= (1−q)a X∞
n=0
f(aqn)g(aqn)qn. (2.1) By the use of the Holder’s inequality for infinite sums, we obtain
X∞
n=0
f(aqn)g(aqn)qn 6
X∞
n=0
fp(aqn)qnp1
·X∞
n=0
gt(aqn)qn1t
. (2.2)
Hence
(1−q)aX∞
n=0
f(aqn)g(aqn)qn
6((1−q)a)1pX∞
n=0
fp(aqn)qn1p
·((1−q)a)1tX∞
n=0
gt(aqn)qn1t
. (2.3) The result then follows from (2.1), (2.2) and (2.3).
2.2. The q-polygamma function
From (1.1) one can derive the following series representation for the function ψq(x) =Γ
′ q(x) Γq(x):
ψq(x) =−log(1−q) + logqX
n>1
qnx
1−qn, x >0, (2.4)
which implies that
ψq(x) =−log(1−q) + logq 1−q
Z q 0
tx−1
1−tdqt. (2.5)
Theorem 2.2. For n= 2,4,6. . . setψq,n(x) =ψq(n)(x)the n-th derivative of the function ψq. Then for p, t >1 such that 1p +1t = 1 the following inequality holds
ψq,n
x p+y
t
6ψq,n(x)1p·ψq,n(y)1t. (2.6) Proof. From (2.5) we deduce that
ψq,n(x) = logq 1−q
Z q 0
(logu)nux−1
1−u dqu, (2.7)
hence
ψq,n
x p+y
t
= logq 1−q
Z q 0
(logu)nuxp+yt−1 1−u dqu.
By Lemma 2.1 witha=qwe have ψq,n
x p+y
t
= logq 1−q
Z q 0
h(logu)n 1−u
i1p ux
−1 p
h(logu)n 1−u
i1t uy
−1 q dqu
6logq 1−q
Z q 0
(logu)nux−1
1−u dqu1plogq 1−q
Z q 0
(logu)nuy−1 1−u dqu1t
= (ψq,n(x))1p(ψq,n(y))1t wheref(u) =
(logu)n 1−u
p
ux
−1
p andg(u) =
(logu)n 1−u
t
uy−t1.
Forp=t= 2 in (2.6) one has the following result.
Corollary 2.3. We have ψq,n
x+y 2
6
q
ψq,n(x)·ψq,n(y).
2.3. q-zeta function
Forx >0 we setα(x) = loglogxq −E
logx logq
and{x}q = qx+α([x][x]q q), whereE
logx logq
is the integer part of loglogxq.
In [2] theq-zeta function is defined as follows ζq(s) =
X∞
n=1
1 {n}sq =
X∞
n=1
q(n+α([n]q))s [n]sq .
There ([2]) it is proved that ζq is a q-analogue of the classical Riemman Zeta function, and for all s∈Csuch thatR(s)>1, and for allu >0one has
ζq(s) = 1 Γeq(s)
Z ∞ 0
us−1Zq(u)dqu, whereZq(t) =P∞
n=1e−{n}q qt,Γeq(t) = KΓq(t)
q(t), and Kq(t) = (1−q)−s
1 + (1−q)−1 · (−(1−q);q)∞(−(1−q)−1;q)∞
(−(1−q)qs;q)∞(−(1−q)−1q1−s;q)∞
.
Theorem 2.4. For 1p+1t = 1 and xp+yt >1, eΓq
x p+yt Γfq
1 p(x)·fΓq
1 t(y)
6ζ
1
qp(x)·ζq1t(y) ζq
x
p+yt . Proof. From Lemma 2.1 we have that
Z ∞ 0
uxp+yt−1Zq(u)dqu= Z ∞
0
ux−1p ·(Zq(u))1puy−1t ·(Zq(u))1tdqu.
6 Z ∞
0
ux−1·(Zq(u))dqup1
· Z ∞
0
uy−1·(Zq(u))dqu1t .
Forf(u) =ux−1p ·(Zq(u))1p andg(u) =uy−1t ·(Zq(u))1t we obtain that Γeq
x p+y
t ·ζq
x p+y
t
6eΓ
1
qp(x)·eΓq1t(y)·ζ
1
qp(x)·ζ
1
qt(y),
which completes the proof.
Acknowledgements. The authors would like to thank the anonymous referees for their comments and suggestions.
References
[1] Brahim, K., Turán-Type Inequalities for someq-special functions,J. Ineq. Pure Appl.
Math., 10(2) (2009) Art. 50.
[2] Fitouhi, A., Bettaibi, N., Brahim, K., The Mellin transform in quantum calculus, Constructive Approximation, 23(3) (2006) 305–323.
[3] Gasper, G., Rahman, M., Basic Hypergeometric Series, 2nd Edition, (2004), En- cyclopedia of Mathematics and Applications, 96, Cambridge University Press, Cam- bridge.
[4] Jackson, F.H., On aq-definite integrals,Quart. J. Pure and Appl. Math., 41 (1910) 193–203.
[5] Kac, V.G., Cheung, P., Quantum Calculus, Universitext, Springer-Verlag, New York, (2002).
Valmir Krasniqi
Department of Mathematics University of Prishtina
Prishtinë 10000, Republic of Kosova e-mail: vali.99@hotmail.com Toufik Mansour
Department of Mathematics University of Haifa
31905 Haifa, Israel
e-mail: toufik@math.haifa.ac.il Armend Sh. Shabani
Department of Mathematics University of Prishtina
Prishtinë 10000, Republic of Kosova e-mail: armend_shabani@hotmail.com