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volume 4, issue 4, article 74, 2003.

Received 01 May, 2003;

accepted 27 September, 2003.

Communicated by:S.S. Dragomir

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Journal of Inequalities in Pure and Applied Mathematics

THE SPREAD OF THE SHAPE OPERATOR AS CONFORMAL INVARIANT

BOGDAN D. SUCEAV˘A

Department of Mathematics California State University, Fullerton CA 92834-6850, U.S.A.

EMail:bsuceava@fullerton.edu URL:http://math.fullerton.edu/bsuceava

c

2000Victoria University ISSN (electronic): 1443-5756 060-03

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The Spread of the Shape Operator as Conformal Invariant

Bogdan D. Suceav ˘a

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Abstract

The notion the spread of a matrix was first introduced fifty years ago in algebra.

In this article, we define the spread of the shape operator by applying the same idea to submanifolds of Riemannian manifolds. We prove that the spread of shape operator is a conformal invariant for any submanifold in a Riemannian manifold. Then, we prove that, for a compact submanifold of a Riemannian manifold, the spread of the shape operator is bounded above by a geometric quantity proportional to the Willmore-Chen functional. For a complete non- compact submanifold, we establish a relationship between the spread of the shape operator and the Willmore-Chen functional. In the last section, we ob- tain a necessary and sufficient condition for a surface of rotation to have finite integral of the spread of the shape operator.

2000 Mathematics Subject Classification:53B25, 53B20, 53A30.

Key words: Principal curvatures, Shape operator, Extrinsic scalar curvature, Sur- faces of rotation

Contents

1 Introduction. . . 3 2 Geometric Inequalities on Compact Submanifolds . . . 7 3 The Noncompact Case . . . 11

References

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The Spread of the Shape Operator as Conformal Invariant

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1. Introduction

In the classic matrix theory spread of a matrix has been defined by Mirsky in [7]

and then mentioned in various references, as for example [6]. LetA∈Mn(C), n ≥ 3,and letλ1, . . . , λn be the characteristic roots ofA. The spread ofAis defined to bes(A) = maxi,ji−λj|.Let us denote by||A||the Euclidean norm of the matrix A,i.e.: ||A||2 = Pm,n

i,j=1|aij|2. We use also the classical notation E2 for the sum of all 2-square principal subdeterminants ofA.IfA ∈ Mn(C) then we have the following inequalities (see [6]):

(1.1) s(A)≤

2||A||2 − 2 n|trA|2

12 ,

(1.2) s(A)≤√

2||A||.

IfA∈Mn(R),then:

(1.3) s(A)≤

2

1− 1

n

(trA)2−4E2(A) 12

,

with equality if and only ifn−2of the characteristic roots ofAare equal to the arithmetic mean of the remaining two.

Consider now an isometrically immersed submanifold Mn of dimension n ≥ 2 in a Riemannian manifold ( ¯Mn+s,¯g). Then the Gauss and Weingarten formulae are given by

∇¯XY =∇XY +h(X, Y),

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∇¯Xξ=−AξX+DXξ,

for everyX, Y ∈ Γ(T M)andξ ∈ Γ(νM).Take a vector η ∈ νpM and con- sider the linear mapping Aη : TpM → TpM. Let us consider the eigenvalues λ1η, . . . , λnη ofAη.We put

(1.4) Lη(p) = sup

i=1,...,n

iη)− inf

i=1,...,niη).

Lη is the spread of the shape operator in the directionη.We define the spread of the shape operator at the pointpby

(1.5) L(p) = sup

η∈νpM

Lη(p).

SupposeM is a compact submanifold ofM .¯

Let us remark that whenM2 is a surface we have

L2ν(p) = (λ1ν(p)−λ2ν(p))2 = 4(|H(p)|2−K(p)),

whereνis the normal vector atp, His the mean curvature, andKis the Gaus- sian curvature. In [1] it is proved that for a surface M2 inE2+s the geometric quantity(|H|2−K)dV is a conformal invariant. As a corollary, one obtains for an orientable surface inE2+sthatL2νdV is a conformal invariant.

Letξn+1, . . . , ξn+s be an orthonormal frame in the normal fibre bundleνM.

Let us recall the definition of the extrinsic scalar curvature from [2]:

ext= 2 n(n−1)

s

X

r=1

X

i<j

λin+rλjn+r.

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In [2] it is proved that for a submanifoldMnof a Riemannian manifold( ¯M ,¯g), the geometric quantity(|H|2−ext)g is invariant under any conformal change of metric. If M is compact (see also [2]), this result implies that for M, a n-dimensional compact submanifold of a Riemannian manifold( ¯M ,g),¯ the ge- ometric quantityR

(|H|2−ext)n2dV is a conformal invariant.

Let us prove the following fact.

Proposition 1.1. LetMnbe a submanifold of the Riemannian manifold( ¯M ,¯g).

Then the spread of the shape operator is a conformal invariant.

Proof. The context and the idea of the proof are similar to the one given in [3, pp. 204-205]. Let us considerρ a nowhere vanishing positive function onM .¯ We have the conformal change of metric in the ambient spaceM¯ given by

¯

g2g.¯

Let us denote by hand h the second fundamental forms of M in ( ¯M ,g)¯ and ( ¯M ,g¯),respectively. Then we have (see [3]):

g(AξX, Y) =g(AξX, Y) +g(X, Y)¯g(U, ξ),

whereU is the vector field defined byU = (dρ)#.Lete1, . . . , enbe the princi- pal normal directions ofAξ with respect tog.Thenρ−1e1, . . . , ρ−1en,form an orthonormal frame ofM with respect tog,and they are the principal directions ofAξ.Therefore

L(p) = sup

ξ∈νpM;||ξ||=1

Lξ

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= sup

ξ∈νpM;||ξ||=1

sup

i=1,...,n

iξ)− inf

j=1,...,njξ)

= sup

ξ∈νpM;||ξ||=1

sup

i=1,...,n

λiξ+ ¯g(U, ξ)

− inf

j=1,...,n λjξ+ ¯g(U, ξ)

= sup

ξ∈νpM;||ξ||=1

sup

i=1,...,n

λiξ

− inf

j=1,...,n λjξ

=L(p).

This proves the proposition.

WhenM is a surface, bothLandL2dV are conformal invariants.

The shape discriminant of the submanifoldM inM¯ w.r.t. a normal direction ηwas discussed in [9]. LetAη be the shape operator associated with an arbitrary normal vectorηatp.The shape discriminant ofηis defined by

(1.6) Dη = 2||Aη||2 − 2

n(trace Aη)2,

where||Aη||2 = (λ1η)2 +· · ·+ (λnη)2,at every pointp∈M ⊂M .¯ The following pointwise double inequality was proved in [9]:

(1.7) Dη

n 2

≤L2η ≤Dη,

We will use this inequality later on. The proof of this fact is algebraically related to the proof of Chen’s fundamental inequality with classical curvature invariants (see [4]). The alternate proof of this result is presented in [10].

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The Spread of the Shape Operator as Conformal Invariant

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2. Geometric Inequalities on Compact Submanifolds

In this section, we study the relationship between the spread of the shape oper- ator’s spectrum and the conformal invariant from [2]. The main result is Propo- sition2.1. For its proof we need a few preliminary steps.

Proposition 2.1. LetMnbe a compact submanifold of a Riemannian manifoldn+s.Then the following inequality holds:

(2.1) Z

M

LdV 2

(vol(M))2n−2n ≤2n(n−1) Z

M

(|H|2−ext)n2dV n2

. The equality holds if and only if either n = 2 or M is a totally umbilical submanifold of dimensionn ≥3.

Before presenting the proof, let us see what this inequality means. For any conformal diffeomorphismφof the ambient spaceM¯, the quantity

Z

φ(M)

LdVφ 2

(vol(φ(M))2n−2n

is bounded above by the conformal invariant geometric quantity expressed in (2.1).

First, let us prove the following.

Lemma 2.2. Let Mn ⊂ M¯n+s be a compact submanifold and pan arbitrary point inM. Consider an orthonormal normal frameξ1, . . . , ξs atpand letDα

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be the shape discriminant corresponding to ξα, where α = 1, . . . , s. Then we have

(2.2) 1

2n(n−1)

s

X

α=1

Dα=|H|2−ext.

Proof. Since

H = 1 n

s

X

α=1 n

X

i=1

λiα

! ξα,

ext = 2 n(n−1)

s

X

α=1

X

i<j

λiαλjα, we have

(2.3) |H|2−ext= 1 n2

s

X

α=1 n

X

i=1

iα)2− 2 n2(n−1)

s

X

α=1

X

i<j

λiαλjα. A direct computation yields

(2.4) Dα = 2(n−1)

n

n

X

i=1

iα)2− 4 n

X

i<j

λiαλjα.

Summing fromα= 1toα=sin (2.4) and comparing the result with (2.3) one may get (2.2).

From the cited result in [2] and the previous lemma, we have:

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Corollary 2.3. IfM is a compact submanifold in the ambient space, then Z

M s

X

α=1

Dα

!n2 dV is a conformal invariant.

Let us remark that forn= 2this is a well-known fact.

Lemma 2.4. Let M be a submanifold in the arbitrary ambient spaceM .¯ With the previous notations we have

4(|H|2−ext)≤

s

X

α

L2α(p)≤2n(n−1)(|H|2−ext)

at each pointp∈M. The equalities holds if and only if p is an umbilical point.

Proof. This is a direct consequence of Lemma2.2and (1.7).

Proof. We may prove now Proposition2.1. Letpbe an arbitrary point ofM and letη0 be a normal direction such thatL(p) = Lη0(p).Consider the completion ofη0 up to a orthonormal normal baseη01, . . . , ηs.Then we have

(2.5) L2(p) = L2η

0(p)≤

s

X

α=1

L2α(p)≤2n(n−1)(|H|2−ext).

By applying Hölder’s inequality, one has:

Z

M

LdV 2

≤ Z

M

L2dV

(vol(M)).

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Applying Hölder’s inequality one more time yields Z

M

|H|2−ext dV ≤

Z

M

|H|2−extn2 dV

n2

(vol(M))n−2n . Therefore, by using the inequality established in Lemma2.4, we have

Z

M

LdV 2

≤ Z

M

L2dV

(vol(M))

≤2n(n−1)vol(M) Z

M

|H|2−ext dV

≤2n(n−1) (vol(M))2n−2n Z

M

|H|2 −extn2 dV

2n . Let us discuss when the equality case may occur. We have seen that we get an identity ifn= 2.

Now, let us assume n ≥ 3. The first inequality in (2.5) is equality at p if there exist s−1umbilical directions (i.e. Lα(p) = 0 for s = 2, . . . , n). The second inequality in (2.5) is equality if and only ifpis an umbilical point (see [9]). Finally, the two Hölder inequalities are indeed equalities if and only if there exist real numbers θ and µsatisfying L(p) = θ and|H|2 −ext = µat every p∈ M.The first equality conditions impose pointwiseL(p) = 0, which yieldsθ=µ= 0.This means thatM is totally umbilical.

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3. The Noncompact Case

LetM be ann-dimensional noncompact submanifold of an(n+d)-dimensional Riemannian manifold( ¯M , g).

Proposition 3.1. LetMn⊂M¯n+dbe a complete noncompact submanifold and η1, . . . , ηdan orthonormal basis of the normal bundle. Suppose thatP

λiαλjα≥ 0andLα ∈L2(M). Then

Z

M

(|H|2−ext)dV <∞.

Proof. We use the inequality (1.7). It is sufficient to prove locally the inequality:

|H|2−ext≤

d

X

i=1

Di

This is true since, elementary, the following inequality holds:

1α)2+· · ·+(λdα)2− 2n n−1

X

i<j

λiαλjα≤2[(λ1α)2+· · ·+(λdα)2]−2 n

( d X

i=1

iα) )2

. This is equivalent to

n(n−1)

d

X

i=1

iα)2−2n2X

i<j

λiαλjα≤2(n−1)2

d

X

i=1

iα)2−4(n−1)X

i<j

λiαλjα or

(n2 −3n+ 2) ( d

X

i=1

iα)2 )

+ 2(n2−2n+ 2)X

i<j

λiαλjα ≥0,

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which holds by using the hypothesis and thatn ≥2.

The inequality is theα-component of the invariant inequality we are going to prove. By adding up d such inequalities and by considering the improper integral onM of the appropriate functions, the conclusion follows. This is due to

Z

M

(|H|2−ext)dV ≤ Z

M d

X

i=1

DidV ≤ n

2 d

X

i=1

Z

M

L2idV by the first inequality in1.7.

In the next proposition we establish a relation betweenR

M[L(p)]2dV and the Willmore-Chen integralR

M(|H| −ext)dV,studied in [2].

Proposition 3.2. Let Mn ⊂ M¯n+dbe a complete noncompact orientable sub- manifold. IfL(p)∈L2(M),thenR

M(|H|2−ext)dV <∞.

Proof. By direct computation, we have:

Z

M

(|H|2−ext)dV = 1 n2(n−1)

Z

M d

X

α=1

X

i<j

1α−λjα)2dV (3.1)

≤ 1

n2(n−1) Z

M d

X

α=1

X

i<j

L2(p)dV

= d 2n

Z

M

L2(p)dV.

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Let us discuss now two examples. First, let us consider the catenoid defined by

fc(u, v) =

ccosu coshv

c, c sinu coshv c, v

. Using the classical formulas for example from [8] one finds:

λ1 =−λ2 = 1

ccosh−2 v c. Therefore, we have

Z

−∞

L(p)dv= Z

−∞

2

ccosh−2v

cdv = 4 Z

−∞

etdt

e2t+ 1 = 4π <∞.

Let us consider the pseudosphere whose profile functions are given by (see, for example [5]):

c1(v) = ae−v/a c2(v) =

Z v

0

p1−e−2t/adt

for 0 ≤ v < ∞. For simplicity, let us consider just the “upper” part of the pseudosphere. We have

λ1 = ev/a a

p1−e−2v/a,

λ2 =−

aev/ap

1−e−2v/a−1

.

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Remark that:

Z

M

LdV = Z

0

et/a a√

1−e−2t/adt= 1 2

Z

1

√dy

y−1 =∞.

A natural question is to find a characterization for surfaces of rotation that have finite integral of the spread of shape operator.

Consider surfaces of revolution whose profile curves are described asc(s) = (y(s), s)(see, for example, [8]). Then we have the following.

Proposition 3.3. Let M be a surface of rotation in Euclidean 3-space defined by

f(s, t) = (y(s) cost, y(s) sint, s).

Then the integral of the spread of the shape operator onM is finite if and only if there exists an integrableC(R)functionf >0which satisfies the following second order differential equation:

−yy00 = 1 + (y0)2±f(s)y(1 + (y0)2)32.

Proof. For the proof, we use the classical formulas from [5, p. 228]. We have forλ1 =kmeridian, and respectively forλ2 =kparallel:

λ1 = −y00 [1 + (y0)2]32, λ2 = 1

y[1 + (y0)2]12.

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Then, the condition that the integral is finite means that there exists an integrable functionf >0such that

Z

R

1−λ2|ds = Z

R

f(s)ds.

If we assume that f ∈ C, then the equality between the function under the integral holds everywhere and a straightforward computation yields the claimed equality.

For example, for the catenoidf(s) = 0.

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References

[1] B.Y. CHEN, An invariant of conformal mappings, Proc. Amer. Math. Soc., 40 (1973), 563–564.

[2] B.Y. CHEN, Some conformal invariants of submanifolds and their appli- cations, Boll. Un. Mat. Ital., (4) 10 (1974) 380–385.

[3] B.Y. CHEN, Total Mean Curvature and Submanifolds of Finite Type, World Scientific, 1984.

[4] B.Y. CHEN, Mean curvature and shape operator of isometric immersions in real-space-forms, Glasgow Math.J., 38 (1996) 87–97.

[5] A. GRAY, Modern Differential Geometry of Curves and Surfaces with Matematica, CRC Press, Second edition, 1998.

[6] M. MARCUS AND H. MINC, A survey of matrix theory and matrix in- equalities, Prindle, Weber & Schmidt, 1969.

[7] L. MIRSKY, The spread of a matrix, Mathematika, 3(1956), 127–130.

[8] M. SPIVAK, A Comprehensive Introduction to Differential Geometry, Vol- ume three, Publish or Perish, Inc., Second edition, 1979.

[9] B. SUCEAV˘A, Some theorems on austere submanifolds, Balkan. J. Geom.

Appl., 2 (1997), 109–115.

[10] B. SUCEAV˘A, Remarks on B.Y. Chen’s inequality involving classical in- variants, Anal. ¸Sti. Univ. Al. I. Cuza Ia¸si, Matematicˇa, XLV (1999), 405–

412.

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