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Volume 7, Issue 2, Article 58, 2006

ON ˇCEBYŠEV TYPE INEQUALITIES INVOLVING FUNCTIONS WHOSE DERIVATIVES BELONG TO Lp SPACES

B.G. PACHPATTE 57 SHRINIKETANCOLONY

NEARABHINAYTALKIES

AURANGABAD431 001 (MAHARASHTRA) INDIA

bgpachpatte@gmail.com

Received 10 November, 2005; accepted 16 November, 2005 Communicated by I. Gavrea

ABSTRACT. In this note we establish new ˇCebyšev type integral inequalities involving functions whose derivatives belong toLpspaces via certain integral identities.

Key words and phrases: ˇCebyšev type inequalities,Lpspaces, Integral identities, Absolutely continuous functions, Hölder’s integral inequality.

2000 Mathematics Subject Classification. 26D15, 26D20.

1. INTRODUCTION

One of the classical and important inequalities discovered by P.L. ˇCebyšev [1] is the following integral inequality (see also [10, p. 207]):

(1.1) |T (f, g)| ≤ 1

12(b−a)2kf0kkg0k,

wheref, g : [a, b]→Rare absolutely continuous functions whose derivativesf0, g0 ∈L[a, b]

and

(1.2) T (f, g) = 1 b−a

Z b

a

f(x)g(x)dx−

1 b−a

Z b

a

f(x)dx 1 b−a

Z b

a

g(x)dx

, which is called the ˇCebyšev functional, provided the integrals in (1.2) exist.

Because of fundamental importance of (1.1) in analysis and applications, many researchers have given considerable attention to it and a number of extensions, generalizations and variants have appeared in the literature, see [5], [6], [8] – [10] and the references given therein. The main purpose of the present note is to establish new inequalities similar to the inequality (1.1) involving functions whose derivatives belong toLp spaces. The analysis used in the proofs is based on the integral identities proved in [3] and [2] and our results provide new estimates on these types of inequalities.

ISSN (electronic): 1443-5756 c

2006 Victoria University. All rights reserved.

340-05

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2. STATEMENT OFRESULTS

In what followsRand0 denote the set of real numbers and the derivative of a function. Let [a, b] ⊂ R, a < b; and as usual for any function h ∈ Lp[a, b], p > 1 we define khkp = Rb

a |h(t)|pdt1p

. We use the following notations to simplify the details of presentation. For suitable functionsf, g : [a, b]→Rwe set

F = 1 3

f(a) +f(b)

2 + 2f

a+b 2

, G= 1

3

g(a) +g(b)

2 + 2g

a+b 2

,

S(f, g) =F G− 1 b−a

F

Z b

a

g(x)dx+G Z b

a

f(x)dx

+ 1

b−a Z b

a

f(x)dx 1 b−a

Z b

a

g(x)dx

,

H(f, g) = 1 b−a

Z b

a

[F g(x) +Gf(x)]dx

−2 1

b−a Z b

a

f(x)dx 1 b−a

Z b

a

g(x)dx

. Now, we state our main results as follows.

Theorem 2.1. Let f, g : [a, b] → R be absolutely continuous functions whose derivatives f0, g0 ∈Lp[a, b],p > 1. Then we have the inequalities

(2.1) |T (f, g)| ≤ 1

(b−a)3 kf0kpkg0kp Z b

a

(B(x))2q dx,

(2.2) |T (f, g)| ≤ 1 2 (b−a)2

Z b

a

h|g(x)| kf0kp+|f(x)| kg0kpi

(B(x))1q dx, where

(2.3) B(x) = (x−a)q+1+ (b−x)q+1

q+ 1 ,

forx∈[a, b]and 1p + 1q = 1.

The following variants of the inequalities in (2.1) and (2.2) hold.

Theorem 2.2. Let f, g : [a, b] → R be absolutely continuous functions whose derivatives f0, g0 ∈Lp[a, b],p > 1. Then we have the inequalities

(2.4) |S(f, g)| ≤ 1

(b−a)2M

2q

kf0kpkg0kp,

(2.5) |H(f, g)| ≤ 1

(b−a)2M

1 q

Z b

a

h|g(x)| kf0kp +|f(x)| kg0kpi dx,

(3)

where

(2.6) M = (2q+1+ 1) (b−a)q+1

3 (q+ 1) 6q , and 1p + 1q = 1.

3. PROOF OFTHEOREM2.1 From the hypotheses we have the following identities (see [3, 7]):

(3.1) f(x)− 1

b−a Z b

a

f(t)dt = 1 b−a

Z b

a

k(x, t)f0(t)dt,

(3.2) g(x)− 1

b−a Z b

a

g(t)dt = 1 b−a

Z b

a

k(x, t)g0(t)dt, forx∈[a, b],where

(3.3) k(x, t) =

( t−a if t∈[a, x]

t−b if t∈(x, b] . Multiplying the left sides and right sides of (3.1) and (3.2) we have (3.4) f(x)g(x)−f(x)

1 b−a

Z b

a

g(t)dt

−g(x) 1

b−a Z b

a

f(t)dt

+ 1

b−a Z b

a

f(t)dt 1 b−a

Z b

a

g(t)dt

= 1

(b−a)2 Z b

a

k(x, t)f0(t)dt

Z b

a

k(x, t)g0(t)dt

. Integrating both sides of (3.4) with respect toxover[a, b]and dividing both sides of the resulting identity by(b−a)we get

(3.5) T (f, g) = 1 (b−a)3

Z b

a

Z b

a

k(x, t)f0(t)dt

Z b

a

k(x, t)g0(t)dt

dx.

From (3.5) and using the properties of modulus and Hölder’s integral inequality we have

|T(f, g)| ≤ 1 (b−a)3

Z b

a

Z b

a

|k(x, t)| |f0(t)|dt

Z b

a

|k(x, t)| |g0(t)|dt

dx

≤ 1

(b−a)3 Z b

a

Z b

a

|k(x, t)|q

1

q Z b

a

|f0(t)|pdt

1 p!

×

Z b

a

|k(x, t)|qdt

1

q Z b

a

|g0(t)|pdt

1 p!

dx

= 1

(b−a)3 kf0kpkg0kp Z b

a

Z b

a

|k(x, t)|q

1 q!2 (3.6) dx.

(4)

A simple calculation shows that (see [4]) Z b

a

|k(x, t)|qdt= Z x

a

|t−a|qdt+ Z b

x

|t−b|qdt

= Z x

a

(t−a)qdt+ Z b

x

(b−t)qdt

= (x−a)q+1+ (b−x)q+1

q+ 1 =B(x). (3.7)

Using (3.7) in (3.6) we get (2.1).

Multiplying both sides of (3.1) and (3.2) byg(x)andf(x)respectively and adding the result- ing identities we get

(3.8) 2f(x)g(x)−

g(x) 1

b−a Z b

a

f(t)dt

+f(x) 1

b−a Z b

a

g(t)dt

=g(x) 1

b−a Z b

a

k(x, t)f0(t)dt

+f(x) 1

b−a Z b

a

k(x, t)g0(t)dt

. Integrating both sides of (3.8) with respect toxover[a, b]and rewriting we obtain

(3.9) T (f, g) = 1 2 (b−a)2

Z b

a

g(x)

Z b

a

k(x, t)f0(t)dt+f(x) Z b

a

k(x, t)g0(t)dt

dx.

From (3.9) and using the properties of modulus, Hölder’s integral inequality and (3.7) we have

|T(f, g)| ≤ 1 2 (b−a)2

Z b

a

|g(x)|

Z b

a

|k(x, t)| |f0(t)|dt+|f(x)|

Z b

a

|k(x, t)| |g0(t)|dt

dx

≤ 1

2 (b−a)2 Z b

a

"

|g(x)|

Z b

a

|k(x, t)|qdt

1

q Z b

a

|f0(t)|pdt

1 p

+|f(x)|

Z b

a

|k(x, t)|qdt

1

q Z b

a

|g0(t)|pdt

1 p#

dx

= 1

2 (b−a)2 Z b

a

h|g(x)| kf0kp+|f(x)| kg0kpiZ b a

|k(x, t)|qdt

1 q

dx

= 1

2 (b−a)2 Z b

a

h|g(x)| kf0kp+|f(x)| kg0kpi

(B(x))1q dx.

This is the required inequality in (2.2). The proof is complete.

4. PROOF OFTHEOREM2.2 From the hypotheses we have the following identities (see [2]):

(4.1) F − 1

b−a Z b

a

f(x)dx= 1 b−a

Z b

a

m(x)f0(x)dx,

(4.2) G− 1

b−a Z b

a

g(x)dx= 1 b−a

Z b

a

m(x)g0(x)dx,

(5)

where

(4.3) m(x) =

( x− 5a+b6 if x∈

a,a+b2 x− a+5b6 if x∈a+b

2 , b . Multiplying the left sides and right sides of (4.1) and (4.2) we get

(4.4) S(f, g) = 1

(b−a)2 Z b

a

m(x)f0(x)dx

Z b

a

m(x)g0(x)dx

.

From (4.4) and using the properties of modulus and Hölder’s integral inequality, we have

|S(f, g)| ≤ 1 (b−a)2

Z b

a

|m(x)| |f0(x)|dx

Z b

a

|m(x)| |g0(x)|dx

≤ 1

(b−a)2

Z b

a

|m(x)|qdx

1q Z b

a

|f0(x)|pdx 1p!

×

Z b

a

|m(x)|qdx

1q Z b

a

|g0(x)|pdx 1p!

= 1

(b−a)2

Z b

a

|m(x)|qdx 1q!2

kf0kpkg0kp. (4.5)

A simple computation gives (see [2]) Z b

a

|m(x)|qdx = Z a+b2

a

x−5a+b 6

q

dx+ Z b

a+b 2

x−a+ 5b 6

q

dx

= Z 5a+b6

a

5a+b 6 −x

q

dx+ Z a+b2

5a+b 6

x−5a+b 6

q

dx +

Z a+5b6

a+b 2

a+ 5b 6 −x

q

dx+ Z b

a+5b 6

x− a+ 5b 6

q

dx

= 1

q+ 1

"

5a+b 6 −a

q+1

+

a+b

2 − 5a+b 6

q+1

+

a+ 5b

6 −a+b 2

q+1

+

b− a+ 5b 6

q+1#

= (2q+1+ 1) (b−a)q+1 3 (q+ 1) 6q =M.

(4.6)

Using (4.6) in (4.5) we get the required inequality in (2.4).

Multiplying both sides of (4.1) and (4.2) byg(x)andf(x)respectively and adding the result- ing identities we get

(4.7) F g(x) +Gf(x)−

g(x) 1

b−a Z b

a

f(x)dx

+f(x) 1

b−a Z b

a

g(x)dx

=g(x) 1

b−a Z b

a

m(x)f0(x)dx

+f(x) 1

b−a Z b

a

m(x)g0(x)dx

.

(6)

Integrating both sides of (4.7) with respect toxover[a, b]and dividing both sides of the resulting identity by(b−a)we get

(4.8) H(f, g) = 1 (b−a)2

Z b

a

g(x)

Z b

a

m(x)f0(x)dx+f(x) Z b

a

m(x)g0(x)dx

dx.

From (4.8) and using the properties of modulus, Hölder’s integral inequality and (4.6) we have

|H(f, g)| ≤ 1 (b−a)2

Z b

a

|g(x)|

Z b

a

|m(x)| |f0(x)|dx+|f(x)|

Z b

a

|m(x)| |g0(x)|dx

dx

≤ 1

(b−a)2 Z b

a

"

|g(x)|

Z b

a

|m(x)|qdx

1q Z b

a

|f0(x)|pdx p1

+|f(x)|

Z b

a

|m(x)|qdx

1q Z b

a

|g0(x)|pdx 1p#

dx

= 1

(b−a)2 Z b

a

h|g(x)| kf0kp+|f(x)| kg0kpiZ b a

|m(x)|qdx 1q

= 1

(b−a)2M1q Z b

a

h|g(x)| kf0kp +|f(x)| kg0kpi dx.

This is the desired inequality in (2.5). The proof is complete.

REFERENCES

[1] P.L. ˇCEBYŠEV, Sur les expressions approximatives des intégrales par les auters prises entre les mêmes limites, Proc.Math.Soc. Charkov, 2 (1882), 93–98.

[2] S.S. DRAGOMIR, On Simpson’s quadrature formula for differentiable mappings whose derivatives belong toLpspaces and applications, RGMIA Res. Rep. Coll., 1(2) (1998), 89–96.

[3] S.S. DRAGOMIRANDN.S. BARNETT, An Ostrowski type inequality for mappings whose second derivatives are bounded and applications, RGMIA Res. Rep. Coll., 1(2) (1998), 69–77.

[4] S.S. DRAGOMIR AND S. WANG, A new inequality of Ostrowski’s type inLp norm, Indian J.

Math., 40(3) (1998), 299–304.

[5] H.P. HEINIG AND L. MALIGRANDA, Chebyshev inequality in function spaces, Real Analysis Exchange, 17 (1991-92), 211–247.

[6] D.S. MITRINOVI ´C, J.E. PE ˇCARI ´CANDA.M. FINK, Classical and New Inequalities in Analysis, Kluwer Academic Publishers, Dordrecht, 1993.

[7] D.S. MITRINOVI ´C, J.E. PE ˇCARI ´CANDA.M. FINK, Inequalities Involving Functions and Their Integrals and Derivatives, Kluwer Academic Publishers, Dordrecht, 1994.

[8] B.G. PACHPATTE, On Trapezoid and Grüss like integral inequalities, Tamkang J. Math., 34(4) (2003), 365–369.

[9] B.G. PACHPATTE, On Ostrowski-Grüss- ˇCebyšev type inequalities for functions whose modulus of derivatives are convex, J. Inequal. Pure and Appl. Math., 6(4) (2005), Art. 128. [ONLINE:

http://jipam.vu.edu.au/article.php?sid=602].

[10] J.E. PE ˇCARI ´C, F. PORCHANANDY. TONG, Convex Functions, Partial Orderings and Statistical Applications, Academic Press, San Diego, 1992.

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