volume 7, issue 3, article 106, 2006.
Received 14 October, 2005;
accepted 07 April, 2006.
Communicated by:L. Pick
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Journal of Inequalities in Pure and Applied Mathematics
ON HARDY’S INEQUALITY INLp(x)(0,∞)
RABIL A. MASHIYEV, BILAL ÇEKIÇ AND SEZAI OGRAS
University of Dicle, Faculty of Sciences and Arts Department of Mathematics
21280- Diyarbakır TURKEY EMail:mrabil@dicle.edu.tr EMail:bilalc@dicle.edu.tr EMail:sezaio@dicle.edu.tr
c
2000Victoria University ISSN (electronic): 1443-5756 310-05
On Hardy’s Inequality in Lp(x)(0,∞)
Rabil A. Mashiyev Bilal Çekiç and Sezai Ogras
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Abstract
Our aim in this paper is to obtain Hardy’s inequality in variable exponent Lebesgue spacesLp(x)(0,∞), where the test functionu(x)vanishes at infinity. We use a local Dini-Lipschitz condition and its the natural analogue at infinity, which play a central role in our proof.
2000 Mathematics Subject Classification:46E35, 26D10.
Key words: Variable exponent, Hardy’s inequality.
The authors are thankful to the referees and Peter Hästö for their helpful suggestions and valuable contributions. This research was supported by DUAPK grant No. 04 FF 40.
Contents
1 Introduction. . . 3 2 Preliminaries . . . 5 3 Main Result . . . 8
References
On Hardy’s Inequality in Lp(x)(0,∞)
Rabil A. Mashiyev Bilal Çekiç and Sezai Ogras
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1. Introduction
Over the last decades the variable exponent Lebesgue space Lp(·)(Ω) and the corresponding Sobolev spaceWm,p(·)(Ω)have been a subject of active research stimulated by development of the studies of problems in elasticity, fluid dy- namics, calculus of variations, and differential equations with p(x)− growth [10,12]. These spaces are a special case of the Musielak-Orlicz spaces [8]. Ifp is the constant, thenLp(·)(Ω)coincides with the classical Lebesgue spaces. We refer to [4, 7] for fundamental properties of these spaces and to [5, 6, 11] for Hardy type inequalities.
The classical Hardy inequality [9] is (1.1)
Z ∞
0
|u(x)|pxβdx ≤ p
β+ 1
pZ ∞
0
|u0(x)|pxβ+pdx,
where 1 < p < ∞,−1 < β < ∞, u is an absolutely continuous function on (0,∞)andu(∞) = lim
x→∞u(x) = 0.
Kokilashvili and Samko [6] gave the boundedness of Hardy operators with fixed singularity in the spacesLp(·)(ρ,Ω)over a bounded open set inRnwith a power weight ρ(x) = |x−x0|β, x0 ∈ Ω¯ and an exponentp(x)satisfying the Dini-Lipschitz condition. The Hardy type inequality can be derived
(1.2)
x
β p(x)u
p(x),(0,`) ≤C(p(x), `) x
β p(x)+1
u0
p(x),(0,`),
where β > −1,1 < p− ≤ p+ < ∞, ` is a positive finite number, and u is an absolutely continuous function on(0, `)in the Lebesgue space with variable exponent for bounded domains from Theorem E in [6].
On Hardy’s Inequality in Lp(x)(0,∞)
Rabil A. Mashiyev Bilal Çekiç and Sezai Ogras
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Recently, Harjulehto, Hästö and Koskenoja [5] have obtained the norm ver- sion of Hardy’s inequality using Diening’s corollaries in the variable exponent Sobolev space. Also they have given a necessary and sufficient condition for Hardy’s inequality to hold.
We consider the problem of the extension of Hardy’s inequality to the case of variablep(x). Such inequalities with variablep(x)are already known for a finite interval (0, `)in the one-dimensional case. Our aim in this paper is to obtain a Hardy type inequality in a one-dimensional Lebesgue space Lp(x)(0,∞)using a distinct method, by considering relevant studies in [1] and [6].
On Hardy’s Inequality in Lp(x)(0,∞)
Rabil A. Mashiyev Bilal Çekiç and Sezai Ogras
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2. Preliminaries
Let Ω ⊂ Rn be an open set, p(·) : Ω → [1,∞) be a measurable bounded function and be denoted as p+ = esssup
x∈Ω
p(x) and p− = essinf
x∈Ω p(x). We de- fine the variable exponent Lebesgue spaceLp(·)(Ω)consisting of all measurable functionsf : Ω→Rsuch that the modular
Ap(f) :=
Z
Ω
|f(x)|p(x)dx
is finite. Ifp+ < ∞then we call pa bounded exponent and we can introduce the norm onLp(·)(Ω)by
(2.1) kfkp(·),Ω := inf
λ >0 :Ap f
λ
≤1
and Lp(·)(Ω) becomes a Banach space. The normkfkp(·),Ω is in close relation with the modularAp(f).
Lemma 2.1 ([4]). Let p(x) be a measurable exponent such that 1 ≤ p− ≤ p(x)≤p+<∞and letΩbe a measurable set inRn. Then,
(i) kfkp(x)=λ6= 0if and only ifAp f λ
= 1;
(ii) kfkp(x)<1(= 1;>1)⇔Ap(f)<1 (= 1;>1);
(iii) For anyp(x), the following inequalities
kfkpp(x)+ ≤Ap(f)≤ kfkpp(x)− , kfkp(x) ≤1
On Hardy’s Inequality in Lp(x)(0,∞)
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and
kfkpp(x)− ≤Ap(f)≤ kfkpp(x)+ , kfkp(x) ≥1 hold.
Lemma 2.2 ([4,7]). The generalization of Hölder’s inequality
Z
Ω
f(x)ϕ(x)dx
≤ckfkp(x)kϕkp0(x)
holds, wherep0(x) = p(x)−1p(x) and the constantc >0depends only onp(x).
We say that the exponentp(·) : Ω →[1,∞)is Dini-Lipschitz if there exists a constantc >0such that
(2.2) |p(x)−p(y)| ≤ c
−log|x−y|,
for everyx, y ∈Ωwith|x−y| ≤ 12.The natural analogue of (2.2) is
(2.3) |p(x)−p(y)| ≤ c
log (e+|x|)
for every x, y ∈ Ω, |y| ≥ |x| at infinity. Under these conditions, most of the properties of the classical Lebesgue space can be readily generalized to the Lebesgue space with variable exponent.
Theorem 2.3 ([5, Theorem 5.2]). LetI = [0, M)forM <∞,p:I →[1,∞) be bounded,p(0) >1and
lim sup
x→0+
(p(x)−p(0)) log 1 x <∞
On Hardy’s Inequality in Lp(x)(0,∞)
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and p−(0,x
0) = p(0) for some x0 ∈ (0,1). If a ∈ h
0,1− p(0)1
, then Hardy’s inequality
(2.4)
u(x) x1−a p(x)
≤Cku0(x)xakp(x)
holds for everyu∈W1,p(x)(I)withu(0) = 0.
Throughout this paper, we will assume that p(x) is a measurable function and use this notation
kfkp(x) :=kfkp(x),(0,∞).
Moreover, we will usecandci as generic constants, i.e. its value may change from line to line.
On Hardy’s Inequality in Lp(x)(0,∞)
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3. Main Result
Theorem 3.1. Letβ > −1 andp : (0,∞) → (1,∞)be such that 1 ≤ p− ≤ p+ <∞and
(3.1) |p(x)−p(y)| ≤ c
−log|x−y|, |x−y| ≤ 1
2, x, y ∈R+. Assume that there exists a numberp(∞)∈[1,∞)anda≥1such that
(3.2) 0≤p(x)−p(∞)≤ c
log(e+x), x≥a.
Then, we have (3.3)
xp(x)β u(x) p(x)
≤c
xp(x)β +1u0(x) p(x)
for every absolutely continuous functionu: (0,∞)→Rwithu(∞) = 0.
Proof. To prove this inequality it suffices to consider the case
xp(x)β +1u0(x) p(x)
= 1
for a monotone decreasing functionu. Using Hölder’s inequality, we obtain u(a) =−
Z ∞
a
u0(t)dt (3.4)
≤c
tp(t)β +1u0(t)
p(t),(a,∞)
t−p(t)β −1
p0(t),(a,∞) ≤c1,
On Hardy’s Inequality in Lp(x)(0,∞)
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where p0(x) = p(x)−1p(x) , and the positive constantc1 depends only on p(x) and β. Sinceu(x) ≤c1 for(0,∞), using Hardy’s inequality for the fixed exponent p(∞)we have
Z ∞
a
xβu(x)p(x)dx≤cp2+ Z ∞
a
xβu(x)p(∞)dx (3.5)
≤c3 Z ∞
a
xβ(−xu0(x))p(∞)dx.
If we divide the interval(a,∞)into three sets such that A={t∈(a,∞) :t|u0(t)|>1},
B ={t∈(a,∞) :t−β−2 < t|u0(t)| ≤1}, C ={t∈(a,∞) :t|u0(t)| ≤t−β−2}, then we can write
Z ∞
a
tβ|tu0(t)|p(∞)dt
= Z
A
tβ|tu0(t)|p(∞)dt+ Z
B
tβ|tu0(t)|p(∞)dt+ Z
C
tβ|tu0(t)|p(∞)dt.
Now, let us estimate each integral. It is easy to see that Z
A
tβ|tu0(t)|p(∞)dt≤ Z ∞
a
tβ|tu0(t)|p(t)dt ≤1
On Hardy’s Inequality in Lp(x)(0,∞)
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and Z
C
tβ|tu0(t)|p(∞)dt ≤ Z
C
tβt−β−2dt≤ Z ∞
a
tβt−β−2dt ≤c.
Since
t(β+2)(p(t)−p(∞))
= (tp(t)−p(∞))β+2
≤
tlog(e+t)1 β+2
≤
elog(e+t)logt β+2
≤eβ+2, we have
Z
B
tβ|tu0(t)|p(∞)dt ≤ Z
B
tβ tβ+2|tu0(t)|p(t)−p(∞)
|tu0(t)|p(∞)dt
≤ Z ∞
a
t(β+2)(p(t)−p(∞))
tβ|tu0(t)|p(t)dt
≤eβ+2 Z ∞
a
tβ|tu0(t)|p(t)dt
≤eβ+2.
Hence, we obtain (3.6)
Z ∞
a
tβ|u(t)|p(t)dt ≤c.
On Hardy’s Inequality in Lp(x)(0,∞)
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On the other hand, by using inequality (1.2) and the assumption (3.1) for the interval(0, a), we can write
(3.7)
Z a
0
tβ|u(t)|p(t)dt ≤c.
Combining inequalities (3.6) and (3.7), we get Z ∞
0
tβ|u(t)|p(t)dt≤c
and hence from the relation between norm and modular we have (3.8)
t
β p(t)u(t)
p(t) ≤c.
Consequently, we have the required result from (3.8) for u(t)
tp(t)β +1u0(t) p(t)
.
On Hardy’s Inequality in Lp(x)(0,∞)
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References
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[8] J. MUSIELAK, Orlicz Spaces and Modular Spaces, Springer-Verlag , Berlin, 1983.
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[9] B. OPIC ANDA. KUFNER, Hardy-type Inequalities, Longman Scientific
& Technical, Harlow, (1990).
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