· PERIOD!CA POLYTECHNICA SER. CIVIL ENG. VOL. 36, NO. 4, PP. 455-450 (1992)
AN INVERSE MARKOV-CHEBYSHEV INEQUALITY
V. K. ROHATGI* and Gabor J. SZEKELyl
"Department of Mathematics and Statistics, BGSU, USA Department of Mathematics,
Faculty of Civil Engineering Technical University, H-1521 Budapest
e-mail: H3361SZE@ELLA.HU Received: December 1, 1992
Suppose that X is an arbitrary non negative random variable with three given moments E(X). E(X2) and Lower bounds will be given for the tail probabilities
PU::
> al·Keywords: : .\larkov-Chebyshev inequality, moment problem.
One of the most classical and most investigated class of probability in- equalities gives bounds on the expected value EJ(X) given Egi(X)
=
Ci,i
=
1,2, ... ,m where X is a real valued random variable, Ci E R,f
and gi ER -+ R such that the expectations above exist. In case gi (x) xi this is a modification of the moment problem (see SHOHAT and T.A.IIIARKIN,(1943) Ch.HI). The best known special case for X ~ 0 is P(X ~ a) ::; Eg(X)/g(a}
(m
=
1, f(x) = Ia.(x), the indicator function of [a, 00)) which is Ivfarkov's inequality for g( x) = x and Chebyshev's inequality for g( x) = x2• These in- equalities can be found in most introductory texts (for more information on their history and recent advances see the References). On the other hand it is hard to find in the literature lower bounds on P(X ~ a). LOEVE (1977, p. 159) gives one for bounded random variables: if P(OS
XS
c)=
1 thenP(X ~ a) ~ [Eg(X) - g(a}J/c. If only a
>
E(X)>
0 is given then clearly the best lower bound is trivial (=0). The same holds if both a>
E(X)>
0 and E(X2) (or VarX) are given. In case a<
E(X) = 1 FELLER (1966, p.152) provides the inequality P(X
>
a)S
(1-a )2/ E(X2). To get nontrivial bounds in general case suppose that E(X), E(X2) and E(X3) are given and we seek a Markov-Chebyshev type lower bound in the formI Research supported by Hungarian National Foundation for Scientific Research.
Grant Ni<. 1.J0.j. 190.5
4.56 V. k'. ROHATGI and G. J. SZEI,ELY
THEOREM. If X ~ 0 and E(X3) is finite then
P(X
>
a) ~(20: - 30:2)E(X)ja
+
(30:2 - 1)E(X2)ja'2+
(1 - 20:)E(X3)ja3 (2) sup a> 1 0: 2( 1 - 0: -)?and if there exists a random variable X supported on {O, a, b} for some
b
>
a with prescribed first, second and third moments then for this randomvariable X (2) is an equality (thus in many cases (2) cannot be improved).
RE:VIARKS. Observe that on the right-hand side of (2) the sum of the coef- ficients is O.
The explicit value of the best 0: is not simple, it is a solution of a cubic equation, and depends on E(Xt i = 1,2,3 and a. However, we need not use the best value. E.g. if we choose 0:
=
2 we get a simple nontrivial (but not necessarily best) boundTHE PROOF OF THE THEOREM If (1) holds for all X ~ 0 with finite E(X3) then it surely holds fOT all random variables degenerate at x ~ O. Thus for the indicator function Ia(x) of [a, (0) we have
(4)
Since p(x) ::; 0 on (0, ,bounded from above on (a,co), there exists an
Xo
<
0 such that p(xo)=
O. p(x)<
0 on [a, then (4) does notgive any nontrivial bound. Therefore there must exist an Xl ~ a such that p(Xl)
=
O. Denote by b E (a, co) the unique number where p(x) takes its maximum in (a, co). To get the best possible lower bounds we may suppose that p(b) = 1. For simplicity put Xo = 0 and Xl = a. Then we have the following conditionsp(O) = p(a) = 0, p(b) = 1, p'(b) = 0.
Using the notation 0: = bja we get
· AN IN FER SE }.fARKOF-CHEBI·SHEF INEQ(:ALITY ·1.5,
therefore Ia(X) ~ p~(X) for every 0::
>
1. Taking expectations on both sides and then supremum for 0::>
1 on the right hand side we get (2). We get equality in (2) if X is supported on {O, a, b}.REMARK. The restriction X ~ 0 is essential. If X may take any x E R then (4) cannot hold since on R the right hand side of (4) is not bounded.
Therefore noniriviallower bounds on P(IXI
>
a) require at least four mo- ments E(Xti = 1,2,3,4.1. X is a random variable having the same m o m e n i s i = 1,2,3 as the uniform random variable on (0,1) then E(Xi) = (i
+
1)-1 and thus (3) gives P(X>
1/2) ~ 1/6. This bound is shaTp and is achieved for the random variable P(X 0)=
1/6, P(X=
1/2)=
2/3 andP(X
=
1/6)=
1/6. Loeve's bound with g(x)=
x3 and c=
1 is 1/8.2. If X is a random variable having the same moments as the exponential distribution with mean 1/)", then EX2
=
2/)..2 and EX3=
6/)..3.Thus the lower bound (2) for P(X
~
c\) is 1/12 for c = 1, 27/120 for c=
2, and 125/688 for c=
3. For the exponentially distributed X, the corresponding exact p1'Obabilities aTe e-I .3679, e-I/2=
.6065,and e-I/3 = .7165. Loeve's inequality does not cover this case.
References
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177-184 (186/)).
DIIARMADIIIKARI, S. vV. - JOAG-DEv, K. (1983): The Gauss-Tcheb~'shev Ineqtlalit~· for U nimodal Distributions. TeoT. VCTOjutn.i P7-i71Lcn .. pp. 817-820.
FELLER, W. (1966): An Introduction to Probability Thpory and Its Application. Wiley.
New York.
HEYDE, C. C. - SENETA. E. (1977): BienaYllle: Statistical Theory Anticipatpd. Springer.
New York.
](ARLIN, S. SIIAPLEY, L. S. (19.53): Geometry of !llotllPnt Spaces. fidem. Amc7·. Math.
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LO~;VE, M. (19,/): Probability Theory (4th edition). Springer, Npw York.
MARKOV, A. A. (191:3): The Calculus of Probabilitios (in Russian). !lloscow, Co~izdat.
458 V. K. ROHATGI and G. J. SZEJ.:ELY
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