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Critical point result of Schechter type in a Banach space

Hannelore Lisei

B

and Orsolya Vas

Babes,–Bolyai University, Faculty of Mathematics and Computer Science, Kog˘alniceanu Str. 1, Cluj-Napoca, RO – 400084 , Romania

Received 11 June 2015, appeared 22 March 2016 Communicated by Gennaro Infante

Abstract. Using Ekeland’s variational principle we give a critical point theorem of Schechter type for extrema on a sublevel set in a Banach space. This result can be applied to localize the solutions of PDEs which contain nonlinear homogeneous opera- tors.

Keywords: critical point, Ekeland’s variational principle, Palais–Smale type compact- ness condition,p-Laplacian.

2010 Mathematics Subject Classification: 47J30, 47J05, 58E05, 34B15.

1 Introduction

Finding the set of solutions of certain PDEs is closely related to the investigation of the critical points of a certain functional defined on an appropriate Hilbert or Banach space. Mountain pass theorems, saddle point theorems, linking theorems, mountain cliff theorems give suffi- cient conditions for the existence of a minimizer for a certain differentiable functional defined on the whole space or on a bounded region (for example, see [3,16–19,21]).

In [13–15] R. Precup studies critical point theorems of Schechter type forC1functionals on a closed ball and also on a closed conical shell in a Hilbert space by using Palais–Smale type compactness conditions and also Leray–Schauder conditions on the boundary. These results can be used successfully to localize the solutions of PDEs involving the Laplace operator.

In our paper we improve the above mentioned Schechter type results (on a ball) for sub- level sets in locally uniformly convex Banach spaces and then apply our result for localizing the solutions for p-Laplace type equations on bounded, and also on unbounded domains.

The paper is structured as follows: Section 2 contains certain preliminaries concerning duality mappings on Banach spaces and the assumptions for the critical point problem which we are investigating. Section 3 states the main result of our paper. Section 4 presents two examples of localizing the solutions for problems containing the p-Laplacian.

BCorresponding author. Email: hanne@math.ubbcluj.ro

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2 Preliminaries

Let X be a real Banach space, X its dual, h·,·idenotes the duality between X and X. The norm onXand onX is denoted by k · k.

A continuous function ϕ : R+R+ is called a normalization function if it is strictly increasing, ϕ(0) =0 andϕ(r)→forr→∞.

The duality mapping corresponding to the normalization function ϕis the set valued operator Jϕ: X→ P(X)defined by

Jϕx =nx ∈ X :hx,xi= ϕ(kxk)kxk,kxk= ϕ(kxk)o, x ∈X.

Assumption (A1): XandX are locally uniformly convex reflexive Banach spaces.

Observe that X is strictly convex, because a locally uniformly convex Banach space is also strictly convex, see [5, Theorem 3, p. 31]. Then it follows that card(Jϕx) = 1 by [6, Proposition 1, p. 342]. Hence, Jϕ :X→X

hJϕx,xi= ϕ(kxk)kxk and kJϕxk= ϕ(kxk). The following result holds.

Theorem 2.1. [6, Theorem 5, p. 345]Let X be a reflexive, locally uniformly convex Banach space and Jϕ: X→X. Then Jϕis bijective and its inverse Jϕ1is bounded, continuous and monotone. Moreover, it holds Jϕ1 = χ1Jϕ1, whereχ : X → X∗∗ is the canonical isomorphism between X and X∗∗ and J

ϕ1 :X →X∗∗is the duality mapping on X corresponding to the normalization function ϕ1. We consider ¯J : X → Xdefined by ¯J = Jϕ1. By Theorem2.1 it follows that ¯J is bounded, continuous and monotone. Forw∈ Xdenote v= Jϕ1wand compute

hw, ¯Jwi=hJϕv,vi= ϕ(kvk)kvk=kJϕvkkvk=kwkkJϕ1wk and

kJw¯ k=kJϕ1wk=kχ1Jϕ1wk=kJϕ1wkX∗∗ = ϕ1(kwk). We conclude

hw, ¯Jwi= ϕ1(kwk)kwk and kJw¯ k= ϕ1(kwk) for eachw∈ X. (2.1) Fix 0<R.

Assumption (A2): Let H:X →Rbe of classC1 such that the level set NR={u∈ X: H(u) =R}is non-void and bounded ,

uinfNRhH0(u),ui>0, and the operatorH0 maps bounded sets into bounded sets.

We denote

XR= {u∈X: H(u)≤R}.

Assumption (A3): Let F:XRRbe of classC1 such thatFis bounded by below onXR.

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We introduce some auxiliary mappings:

D: NR →X, D(u) =F0(u)− hF0(u),ui hH0(u),uiH

0(u), E: NR →X, E(u) = JD¯ (u)− hH0(u), ¯JDui

hH0(u),ui u.

Lemma 2.2. Assume that (A1)holds, and that F : XRRand H : X → Rare C1functions. For all u∈ NRthe following properties hold:

(1) hH0(u),E(u)i=0,

(2) hF0(u),E(u)i= ϕ1(kD(u)k)kD(u)k. Proof. Letu∈ NR be arbitrary. We compute

hH0(u),E(u)i=

H0(u), ¯JD(u)−hH0(u), ¯JDui hH0(u),ui u

=0.

Observe that

hD(u),ui=

F0(u)− hF0(u),ui hH0(u),uiH

0(u),u

=0. (2.2)

By using the statement (1) of this lemma, by (2.2) and (2.1) we have hF0(u),E(u)i=

F0(u)− hF0(u),ui hH0(u),uiH

0(u),E(u)

=hD(u),E(u)i

=

D(u), ¯JD(u)i − hH0(u), ¯JDui

hH0(u),ui hD(u),u

= hD(u), ¯JD(u)i= ϕ1(kD(u)k)kD(u)k.

3 Main result

Theorem 3.1. Assume that(A1),(A2)and(A3)are satisfied. Then, there exists a sequence(xn)n ⊂ XRsuch that F(xn)→infF(XR)and one of the following statements hold

(a) F0(xn)→0as n→∞;

(b) for each n∈Nwe have H(xn) =R,hH0(xn), ¯JF0(xn)i ≤0and F0(xn)− hF0(xn),xni

hH0(xn),xniH

0(xn)→0 as n→. If, in addition, there exists a∈R+such that

hH0(x), ¯JF0(x)i ≥ −a for each x∈ NR,

and F satisfies a Palais–Smale type compactness condition (i.e. any sequence satisfying(a)or(b)has a convergent subsequence) and the following boundary condition holds

F0(x) +µH0(x)6=0 for anyµ>0, x∈ NR, (3.1) then there exists x ∈XR such that

F(x) =infF(XR) and F0(x) =0.

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Proof. By Ekeland’s variational principle, see [8, Theorem 1, p. 444], applied for XR (we use here thatHis continuous, henceXRis a closed set), the distanced(x,y) =kx−yk, the function F(which is continuous and bounded by below, see (A3)),ε= n1 and foru∈ XRsuch that

F(u)≤infF(XR) + 1 n, it follows that there exists a sequence(xn)nin XRsuch that

F(xn)≤F(u)≤infF(XR) + 1 n, and

F(xn)<F(y) + 1

nkxn−yk for eachy ∈XR\ {xn}. (3.2) This yieldsF(xn)→infF(XR).

Since(xn)nbelongs toXR, we distinguish two cases:

(1) there exists a subsequence of(xn)n, still denoted by(xn)n, such that H(xn)< Rfor each n∈N;

(2) there exists a subsequence of(xn)n, still denoted by(xn)n, such that H(xn) =Rfor each n∈N.

Case (1)Fix n∈ N. Lett >0 and z∈ X such thatkzk=1. Since His a continuous function and H(xn)< R, we have that there exits δ > 0 (small enough) such that H(xn−tz) < Rfor eacht ∈(0,δ). Hencexn−tz ∈XR\ {xn}for eacht∈ (0,δ)and by (3.2) it holds

F(xn)−F(xn−tz)< t n. By takingt &0 it follows

hF0(xn),zi ≤ 1 n.

Butz ∈ X with kzk = 1 was arbitrary chosen, hence kF0(xn)k ≤ n1, which yields F0(xn) → 0 as n → ∞. Hence we constructed a sequence (xn)n which satisfies the statement (a) of this theorem.

Case (2)Fix n∈ N. We have H(xn) = R. Letz ∈ Xsuch that kzk= 1. We use the definition of the Fréchet derivative of H: for eachε >0 there exists δε >0 such that for eacht ∈ (0,δε) we have

εt< H(xn−tz)−H(xn) +hH0(xn),tzi<εt.

Hence,

R−εt−thH0(xn),zi< H(xn−tz)<R+εt−thH0(xn),zi for eacht ∈(0,δε). (3.3)

IfhH0(xn),zi>0: by takingε=hH0(xn),ziin (3.3) we get H(xn−tz)< R for each t∈(0,δε).

Hencexn−tz∈ XR\ {xn}fort ∈(0,δε). By (3.2) it follows that fort ∈(0,δε) F(xn)−F(xn−tz)< t

n,

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then byt&0 we get hF0(xn),zi ≤ 1

n for eachz∈ Xwithkzk=1 and hH0(xn),zi>0. (3.4)

• If hH0(xn),zi = 0: we approximate z by a sequence (zk)k such that kzkk = 1 and hH0(xn),zki > 0 for each k ∈ N, while kz−zkk → 0 as k → ∞. Since hH0(xn),·i is con- tinuous, we havehH0(xn),zki → hH0(xn),zi=0 ask→.

Let k ∈ N be fixed. By considering (3.3) for zk instead of z and ε = hH0(xn),zki for t∈(0,δε)we get

H(xn−tzk)< R.

Then, xn−tzk ∈ XR\ {xn}fort ∈(0,δε). By (3.2) we obtain fortsufficiently small F(xn)−F(xn−tzk)< t

n, which yields

hF0(xn),zki ≤ 1 n. Butkz−zkk →0 as k→∞, hence

hF0(xn),zi ≤ 1 n. This inequality and (3.4) imply

hF0(xn),zi ≤ 1

n for eachz∈ Xwithkzk=1 and hH0(xn),zi ≥0. (3.5) Further we have two possible cases.

Case (2a) There exists a subsequence of (xn)n, which we still denote by (xn)n, such that hH0(xn), ¯JF0(xn)i>0: by takingz = k 1

JF0(xn)kJF¯ 0(xn)in (3.5) we get hF0(xn), ¯JF0(xn)i ≤ 1

nkJF0(xn)k. By the property (2.1) of ¯J it follows that

hF0(xn), ¯JF0(xn)i= ϕ1(kF0(xn)k)kF0(xn)k and kJF¯ 0(xn)k= ϕ1(kF0(xn)k) which yields

kF0(xn)k ≤ 1 n,

hence F0(xn)→ 0 asn → and we obtained a sequence(xn)n which satisfies the statement (a) of this theorem.

Case (2b) There exists a subsequence of (xn)n, which we still denote by (xn)n, such that hH0(xn), ¯JF0(xn)i ≤0: by takingz= kE(1x

n)kE(xn)in (3.5) (ifkE(xn)k=0, then by Lemma2.2(2) we getkD(xn)k=0) and by Lemma2.2(2) we get

ϕ1(kD(xn)k)kD(xn)k=hF0(xn),E(xn)i ≤ 1

nkE(xn)k. Hence,

ϕ1(kD(xn)k)kD(xn)k ≤ 1

nkE(xn)k. (3.6)

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Denote the kernel ofH0(xn)byKn={x ∈X:hH0(xn),xi=0}and the projection mapping Pn: X→ Kn by Pnv=v− hH0(xn),vi

hH0(xn),xnixn.

Since v ∈ X 7→ hH0(xn),vi is linear and continuous, it follows that Pn is also linear and continuous.

Since (xn)n ⊂ NR and the level set NR is bounded, it follows that (xn)n is a bounded sequence. By the assumption onH0 it follows that(H0(xn))nis also bounded and there exists

0< βR := inf

uNR

hH0(u),ui ≤ hH0(xn),xni for eachn∈N. We write

kPnvk ≤ kvk+ kH0(xn)kkvk

infnNhH0(xn),xnikxnk ≤

1+ kH0(xn)kkxnk βR

kvk for eachv ∈X.

Hence there existsαR>0 (independent ofn) such that

kPnvk ≤αRkvk for eachv∈ X.

We takev = JD¯ (xn)to get PnJD¯ (xn) =E(xn)and

kE(xn)k ≤αRkJD¯ (xn)k=αRϕ1(kD(xn)k) for each n∈N.

Then by (3.6) we have

ϕ1(kD(xn)k)kD(xn)k ≤ αR

n ϕ1(kD(xn)k) for each n∈N.

This yields D(xn) → 0 as n → ∞. Hence we constructed a sequence (xn)n which satisfies statement (b) of this theorem.

If, in addition, Fsatisfies the (PS) type compactness condition.

Case (a) F0(xn) → 0 as n → and there exist x ∈ XR and a subsequence (xnk)k such that kxnk−xk →0 ask→∞. Since Fis aC1function, we get F0(x) =0 and by the construction of (xn)n we haveF(xn)→infF(XR), henceF(x) =infF(XR).

Case (b)We haveD(xn)→ 0 asn → ∞, H(xn) = R andhH0(xn), ¯JF0(xn)i ≤ 0 for all n ∈ N and there exist x ∈ XR (XR is a closed set, since H is continuous) and a subsequence (xnk)k such that kxnk −xk → 0 as k → ∞. Hence F(x) = limkF(xnk) = infF(XR), F0(x) = limkF0(xnk)andx∈ NR, i.e. H(x) = R. ButD(xnk)→0 ask →∞, which implies

F0(x)− hF0(x),xi hH0(x),xiH

0(x) =0. (3.7)

Applying the operator ¯J we get

JF¯ 0(x)− hF0(x),xi hH0(x),xiJH¯

0(x) =0, which yields

hH0(x), ¯JF0(x)i − hF0(x),xi

hH0(x),xihH0(x), ¯JH0(x)i=0,

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hH0(x), ¯JF0(x)i − hF0(x),xi hH0(x),xiϕ

1(kH0(x)k)kH0(x)k=0. (3.8) Since we are investigating Case (b), it follows that(hH0(xn), ¯JF0(xn)i)n is a bounded sequence inR, hence there existb∈R,b≤0, and a subsequence, denoted again by(xnk)k, such that

hH0(xnk), ¯JF0(xnk)i →b.

Butkxnk−xk →0 ask →∞, hence

hH0(x), ¯JF0(x)i=b≤0.

Using (3.8) it follows

hF0(x),xi hH0(x),xiϕ

1(kH0(x)k)kH0(x)k= b≤0.

Since hH0(x),xi > 0 (assumption on H0 and the fact that x ∈ NR as the limit of (xnk)k), we obtain

hF0(x),xi ≤0.

•IfhF0(x),xi=0, then (3.7) impliesF0(x) =0.

•IfhF0(x),xi<0, then (3.7) implies

F0(x) +µH0(x) =0 whereµ=−hF0(x),xi

hH0(x),xi >0 andx∈ NR, which contradicts the assumption (3.1) from the statement of this theorem.

4 Applications

4.1 Example 1

Consider the Sobolev space W01,p(), where is a bounded domain in Rk with Lipschitz continuous boundary and 1 < p<∞, equipped with the norm

kuk1,p = Z

|∇u(x)|pdx 1p

, where

∇u= ∂u

∂x1, . . . , ∂u

∂xk

, |∇u|=

k i=1

∂u

∂xi 2!12

.

The Banach space (W01,p(),k · k1,p)is uniformly convex, see [1, Theorem 3.6]. Moreover, it is also uniformly smooth (which is proved by using Clarkson’s inequalities [1, 2.38 Theorem, p. 44] and [4, Definition 2.4., p. 13]). The dual space(W01,p()) will be denoted byW1,p0(), where 1p+ p10 =1, and by [4, Theorem 2.10] it follows that it is uniformly convex.

The Rellich–Kondrachov Theorem states that the embeddingW01,p(),→Lq()is compact for q∈ (1,p)(where p = kkpp if p < k and p = ∞, if p ≥ k) and there existsCq > 0 such that

kukLq()≤Cqkuk1,p for eachu∈W01,p(). (4.1)

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In the context of our paper we choose (X,k · k) = (W01,p(),k · k1,p), ¯J = Jϕ1, where ϕ(t) =tp1fort ∈R+and let H :W01,p()→Rbe given byH(u) = 1pkuk1,pp .

We consider the p-Laplacian operator−p :W01,p()→W1,p0()defined by h−p(u),vi=

Z

|∇u(x)|p2∇u(x)∇v(x)dxfor all u,v∈W01,p().

It is known that the functional H is continuously Fréchet differentiable on W01,p() and H0 = −p. The operator −p is in fact the duality mapping Jϕ : W01,p() → W1,p0() corresponding to the normalization function ϕ(t) = tp1 fort ∈ R+, i.e. H0 = Jϕ, for details consult [6, Theorem 7 and Theorem 9]. In our example we have

NR =

v∈W01,p(): 1

pkvk1,pp = R

and

XR =

v∈W01,p(): 1

pkvk1,pp ≤ R

.

Assume that f : Ω×RR is a Carathéodory function such that f(x, 0) 6= 0 for a.e.

x∈ and

|f(x,s)| ≤a(x)|s|q1+b(x) forx ∈Ω, s∈R,

where a ∈ L(),b ∈ Lqq1()are positive functions and q ∈ (1,p). Define the Nemytskii operatorNf :W01,p()→W1,p0()by

Nf (u) (x) = f(x,u(x)).

We have Nf(W01,p()) ,→ Nf(Lq()) ⊂ Lqq1() = (Lq()) ,→ W1,p0() and Nf is a continuous function which maps bounded sets into bounded sets (see [9]).

Consider the following Dirichlet problem involving the p-Laplacian:

pu= f(x,u) a.e. x ∈ and u

=0. (4.2)

We callu∈W01,p()aweak solutionof (4.2) if for eachv∈W01,p()it holds Z

|∇u(x)|p2∇u(x)∇v(x)dx=

Z

f(x,u(x))v(x)dx. (4.3) We introduceF:W01,p()→Rdefined by

F(u) = 1

pkuk1,pp

Z

h(x,u)dx, whereh:Ω×RRish(x,t) =

Z t

0 f(x,s)ds. We have (see [9, Theorem 7]) F0(u) =H0(u)−Nf (u).

The critical points ofFare the solutions of (4.3).

(A4) Assumptions for R: denote by C an upper bound for Cq and suppose that one of the following three assumptions is satisfied.

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(1) If p>q: letR>0 be a solution of the inequality inR Rp

1

p >Cqpq

p

p kakL()Rq

1

p +Cp1

p p kbk

L

q q1(). (2) If p=q: assume 1>CpkakL() and let Rbe such that

R>

 Cp1

p p kbk

L

p p1()

1−CpkakL()

p p1

.

(3) If q> p: assume that 1> CqpqppkakL()+Cp1ppkbk

L

q

q1() and letR > 0 to be a solution of the inequality inR

Rp

1

p −Cqpq

p

p kakL()Rq

1

p >Cp1

p p kbk

L

q q1(). Proposition 4.1. The following relation holds

F0(u) +µH0(u)6=0 for anyµ>0, u∈ NR, where R satisfies one of the three conditions mentioned in(A4).

Proof. We reason by contradiction: assume that there exist u ∈ NR and µ > 0 such that F0(u) +µH0(u) =0, which implies

(1+µ)hJϕ(u),ui=hNf(u),ui. (4.4) By our assumptions

hNf(u),ui=

Z

f(x,u(x))u(x)dx

Z

a(x)|u(x)|q+b(x)|u(x)|dx≤ kakL()kukq

Lq()+kbk

L

q q1()

kukLq(). Using (4.1) and (4.4) we get

kuk1,pp ≤(1+µ)kuk1,pp ≤ kakL()kukq

Lq()+kbk

L

q q1()

kukLq()

≤CqkakL()kukq1,p+Ckbk

L

q q1()

kuk1,p.

Butu ∈NR implieskuk1,p= (pR)1p, and we obtain pR≤CqkakL()(pR)qp +Ckbk

L

q q1()

(pR)1p, which yields

Rp

1

p ≤Cqpq

p

p kakL()Rq

1

p +Cp1

p p kbk

L

q

q1(). (4.5) The assumptions in (A4) imply that (4.5) cannot be satisfied.

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Proposition 4.2. Suppose that R satisfies one of the three conditions mentioned in (A4). Then F satisfies the following Palais–Smale type compactness condition: if(un)n is a sequence from XR such that one of the following statements hold

(a) F0(un)→0as n→;

(b) for each n∈Nwe have H(un) =R,hH0(un), ¯JF0(un)i ≤0and F0(un)− hF0(un),uni

hH0(un),uniH

0(un)→0 as n→∞,

then(un)nadmits a convergent subsequence.

Proof. Since the sequence(un)nis bounded inW01,p()(it belongs toXR) and since the embed- dingW01,p(),→ Lq()is compact forq∈(1,p), there existu∈W01,p()and a subsequence of (un)n, which we denote again by (un)n, which converges weakly in W01,p() to u and strongly inLq()tou. Then by Hölder’s inequality we have

hNf(un),un−ui ≤ kf(·,un)k

L

q

q1()kun−ukLq()→0. (4.6) Case (a): F0(un)→0 asn→∞. Then,

hH0(un),un−ui=hF0(un),un−ui+hNf(un),un−ui →0.

The(S+)property ofH0 = Jϕ (see [6, Theorem 10]) implies(un)nconverges strongly tou.

Case (b): For eachn∈Nwe haveH(un) =R,hH0(un), ¯JF0(un)i ≤0 and F0(un)− hF0(un),uni

hH0(un),uniH

0(un)→0 asn→∞.

We denote

µ= lim

n

hF0(un),uni hH0(un),uni ∈R.

Therefore,

F0(un)−µH0(un)→0 asn→. (4.7) Ifµ=0, the above convergence implies

F0(un)→0 asn→∞.

As in Case (a) it follows that there existu∈W01,p() and a subsequence of(un)n, which we denote again by(un)n, which converges strongly inW01,p()tou. Since F0 is continuous, we haveF0(u) =0, which implieshH0(u),ui= hNf(u),ui. Butu∈ NR(since(un)nbelongs to the closed setNR), which yields

pR=hNf(u),ui ≤CqkakL()(pR)qp +Ckbk

L

q

q1()(pR)1p.

This contradicts the assumption onRfrom (A4). Hence, the caseµ=0 is not possible.

Forµ6=0 we have by (4.7)

hF0(un)−µH0(un),un−ui →0 asn→∞.

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(1−µ)hH0(un),un−ui+hNf(un),un−ui →0 asn→∞.

Ifµ6=1 we get by (4.6)

(1µ)hH0(un),un−ui →0 asn→∞.

The (S+) property of H0 = Jϕ implies (un)n converges strongly to u. The convergence (4.7) and the strong convergenceun →uimplies F0(u)−µH0(u) =0.

hF0(u), ¯JF0(u)i=µhH0(u), ¯JF0(u)i.

But hH0(u), ¯JF0(u)i ≤ 0 and hF0(u), ¯JF0(u)i ≥ 0, therefore µ < 0 and the relation F0(u)− µH0(u) =0 contradicts the statement of Proposition4.1. Hence, the caseµ6=1 is not possible.

Forµ=1: by (4.7) it follows that

hF0(un), ¯JF0(un)i − hH0(un), ¯JF0(un)i →0 asn→∞.

Using (2.1) we have

hF0(un), ¯JF0(un)i= ϕ1(kF0(un)k)kF0(un)k ≥0 and by the assumptions of Case (b) we have

−hH0(un), ¯JF0(un)i ≥0

Then F0(un) → 0 asn → ∞. As in Case (a) it follows that there exist u∈W01,p() and a subsequence of (un)n, which we denote again by(un)n, which converges strongly inW01,p() to u. This yields u ∈ NR, because (un)n belongs to the closed set NR. Since F0 and H0 are continuous, we have by the convergence (4.7) thatF0(u)−H0(u) =0,

hF0(u), ¯JF0(u)i=hH0(u), ¯JF0(u)i.

ButhH0(u), ¯JF0(u)i ≤0 (by the assumption of Case (b) and by the strong convergenceun→u) and hF0(u), ¯JF0(u)i ≥ 0, hence F0(u) = 0, which implies H0(u) = 0 and then u = 0. But 0 /∈ NR, contradictsu∈ NR. Hence the caseµ=1 is not possible.

We apply Theorem3.1 in order to localize the solution of (4.3).

Theorem 4.3. Suppose that R satisfies one of the three conditions mentioned in(A4). Then, equation (4.3)admits a weak solution u∈XR, which minimizes F on XR.

In what follows we discuss situations when the best Sobolev constantCqadmits an upper estimate which can be computed:

Denote the first eigenvalue of thep-Laplace operator by λp() = min

vW01,p()\{0}

R

|∇v(x)|pdx R

|v(x)|pdx . Then,

kukLpp()1

λp()kuk1,pp for allu∈W01,p(). Hence the best embedding constant of W01,p(),→ Lp() is Cp = 1

λp()

1/p

, while for q < p the best embedding constant of W01,p(),→ Lq() verifies (via Hölder’s inequality)

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Cq≤ ||ppqq 1

λp()

1/p

(here || denotes the Lebesgue measure, i.e. the k-dimensional vol- ume, of the setΩ). In order to obtain upper bounds forCq(q≤ p) we need lower bounds for λp().

By using the Faber–Krahn inequality [2, Theorem 1] it holds λp()≥ λp(),

whereΩ is thek-dimensional ball centered at the origin having the same volume asΩ. So it has the radiusr = 1

π ||Γ(2k +1)1/k.

By [10] we have for the ballΩ = BrRk of radiusrthe inequality λp(Br)≥

k rp

p

.

Then the best Sobolev constant has the following upper estimate, which can be computed:

Cpp k√

π

||Γ k

2+1 1k

, and for 1<q< p

Cqp k√ π

||k(ppqq)+1Γ k

2+1 1k

.

Fork =1 andΩ= (0,T)⊂Rthe value of the first eigenvalue is known (see [7])

λp() = (p−1) T psin(πp)

!p

, hence

Cp = T psin(πp) 2π(p−1)1p .

For the casek=1 andΩ= (0,T)the sharp Poincaré inequality is known (see [20], p. 357):

for each p>1,q>1 andu∈W01,p(0,T)it holds

kukLq() ≤Cqkuk1,p, where the embedding constant is given by

Cq= T

1 q+1

p0

2B(1q,p10) p

01q

qp10 p0+q1p1q

,

p0 = pp1 andBis the Beta function.

4.2 Example 2

For 1< p<we define the following subspace of radially symmetric functions ofW1,p(Rk) Wr1,p(Rk) =u∈W1,p(Rk):u(x) =u(x0)∀ x,x0Rk,|x|=|x0| ,

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endowed with the norm induced fromW1,p(Rk) kukp =

Z

Rk

|∇u(z)|p+|u(z)|pdz.

The spaceW1,p(Rk) is a separable, reflexive and uniformly convex Banach space [1, 3.6 The- orem, p. 61]; moreover, it is also uniformly smooth (which is proved by using Clarkson’s inequalities [1, 2.38 Theorem, p. 44] and [4, Definition 2.4., p. 13]).

In the context of Section 2 and Section 3 we consider X = Wr1,p(Rk) endowed with the above normk · k, Xis a closed subspace ofW1,p(Rk). Hence it is also uniformly smooth and by [4, Theorem 2.10] it follows that its dualX is uniformly convex.

LetJϕ :X→ X be the duality mapping corresponding to the weight functionϕ(t) =tp1, t ∈ R+ where p ∈ (1,+) (see [3, Proposition 2.2.4]). It is well known that the duality mapping Jϕ satisfies the following conditions:

kJϕuk= ϕ(kuk) and hJϕu,ui=kJϕukkuk for all u∈X.

Moreover, the functional H : X →R defined by H(u) = 1pkukp is convex and Fréchet differ- entiable with H0 = Jϕ. We take ¯J = Jϕ1.

It is known [11, Théorème II. 1] that the embedding Wr1,p(Rn) ,→ Lq(Rn)is compact for q∈ (p,p)(wherek ≥2, p = kkpp if p <kand p =∞, if p ≥k) there existsCq>0 (the best embedding constant) such that

kukLq(Rk) ≤Cqkuk for eachu∈Wr1,p(Rk). (4.8) Let f :R×RkRbe a Carathéodory function such that f(x, 0)6=0 for a.e.x∈Rwhich satisfies

|f(x,s)| ≤a(x)|s|q1+b(x) for(x,s)∈Rk×R,

where a ∈ L(Rk),b ∈ Lqq1(Rk)are positive functions and q ∈ (p,p)and f(x,·) = f(x0,·) for all x,x0Rn,|x|= |x0|(f is radially symmetric in the first variable).

Consider the following problem involving the p-Laplacian:

pu+|u|p2u= f(x,u) a.e.x ∈Rk. (4.9) We call u∈W1,p(Rk)aweak solutionof (4.9) if for eachv ∈W1,p(Rk)it holds

Z

|∇u(x)|p2∇u(x)∇v(x) +|u(x)|p2u(x)v(x)dx=

Z

f(x,u(x))v(x)dx. (4.10) Define the Nemytskii operatorNf :X→ X byNf (u) (x) = f(x,u(x))andF: X→Rby

F(u) = 1

pkuk1,pp

Z

Rnh(x,u)dx, where h:Ω×RRish(x,t) =Rt

0 f(x,s)ds. We have F0(u) = H0(u)−Nf(u).

Let G= O(Rk)be the set of all rotations onRk. Observe that the elements of GleaveRk invariant, i.e.g(Rk) =Rk for allg∈G. Ginduces an isometric linear action overW1,p(Rk)by

(gu)(z) =u(g1z), g ∈G, u∈W1,p(Rk), a.e. z∈Rk.

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A functionφdefined onW1,p(Rk)is said to beG-invariant if

φ(gu) =φ(u) for allg ∈G, u∈W1,p(Rk). In factWr1,p(Rk)is the fixed point set ofW1,p(Rk)underGand the norm

kuk= Z

Rk(|∇u(z)|p+|u(z)|p)dz 1p

isG-invariant onW1,p(Rk).

Observe that by the assumption on f and the above remark, the functionalFisG-invariant and then by the principle of symmetric criticality [12] every critical point ofFis also a solution of (4.10).

Consider

XR=

v∈Wr1,p(Rk): 1

pkvkp ≤R

. Reasoning as in Section4.1 one has the following result.

Theorem 4.4. Suppose that R satisfies one of the three conditions mentioned in(A4). Then, F admits a critical point u∈XR, which minimizes F on XR. Moreover, this critical point is also a weak solution of (4.10).

We discuss situations when the Sobolev constant Cq admits an upper estimate which can be computed: by [20] we have that for 1< p<kand p= kkpp it holds for allu ∈W1,p(Rk)

kukLp

(Rk) ≤CR Z

Rk|∇u(x)|pdx 1p

, where

CR= √1 πk1p

p−1 k−p

11p Γ(1+2k)Γ(k) Γ(kp)Γ(1+k− kp)

!1k . Obviously this implies

kukLp

(Rk)≤CRkukfor eachu∈W1,p(Rk).

For any q ∈ (p,p) there exists θ ∈ (0, 1) such that q = θp+ (1−θ)p, then by Hölder’s inequality

kukq

Lq(Rk)≤ kukθp

Lp(Rk)kuk(1θ)p

Lp(Rk) ≤Ckq

1 p1q R kukq,

for eachu ∈ W1,p(Rk). Then the Sobolev constant has the following upper estimate, which can be computed:

Cq≤Ck

1 p1q

R forq∈

p, kp k−p

and 1< p<k.

Acknowledgement

The authors would like to express their special thanks to Prof. Cs. Varga from Babes,-Bolyai University in Cluj-Napoca for his constructive discussions.

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[2] T. Bhattacharya, A Proof of the Faber–Krahn inequality for the first eigenvalue of the p-Laplacian,Ann. Mat. Pura Appl. (4)177(1999), 225–240.MR1747632;url

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MR1467724;url

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