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volume 5, issue 3, article 81, 2004.

Received 27 August, 2003;

accepted 28 April, 2004.

Communicated by:S.S. Dragomir

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Journal of Inequalities in Pure and Applied Mathematics

CORRIGENDUM TO “ON SHORT SUMS OF CERTAIN MULTIPLICATIVE FUNCTIONS”

OLIVIER BORDELLÈS

2 Allée de la Combe 43000 AIGUILHE FRANCE.

EMail:borde43@wanadoo.fr

c

2000Victoria University ISSN (electronic): 1443-5756 118-03

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Corrigendum to “On Short Sums of Certain Multiplicative

Functions”

Olivier Bordellès

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J. Ineq. Pure and Appl. Math. 5(3) Art. 81, 2004

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Abstract

This note is a corrigendum of the main result of the paper ”On short sums of certain multiplicative functions” (J. Ineq. Pure & Appl. Math., 3(5), Art. 70 (2002)).

2000 Mathematics Subject Classification:11N37, 11P21 Key words: Corrigendum, Short sums, Integer points

The author is indebted to the referee for insightful comments.

The purpose of this note is both to give a corrected statement of the main result in [1] and to provide the necessary changes to the arguments in that paper to justify this corrected statement. The result we now assert is the following : Theorem 1. Let ε, c0 > 0 and2 6 y 6 c0x1/2 be real numbers. Let f be a multiplicative function satisfying0 6 f(n)6 1for any positive integern and f(p) = 1for any prime numberp.We have asx→+∞:

X

x<n6x+y

f(n) =yP(f) +Oε x1/15+εy2/3 ,

where

P(f) :=Y

p

1− 1

p

1 +

X

l=1

f pl pl

! .

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Corrigendum to “On Short Sums of Certain Multiplicative

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Olivier Bordellès

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Before giving the proof, we note that ify < x1/5,thenx1/15 > y1/3 so that the expression x1/15+εy2/3 in the error term exceeds the main term (as well as the trivial bound ofy+ 1on the sum).

Proof. On page 5 of [1], the sum

S1 := X

y<d6x+y dsquarefull

|g(d)|

x+y d

−hx d

i

has been bounded by the sum

S2 := X

b6(x+y)1/3

X (by3)1/2<a6(x+yb3 )1/2

(x+y)b−3 a2

− xb−3

a2

by usingd=a2b3withµ2(b) = 1,andS2 has been bounded by

εxε max

16B6(x+y)1/3

Rx

b3, B, y B3

for any (small) positive real number ε,where we definedR(f, N, δ)to be the number of integer points (n, m) verifying n ∈ ]N; 2N]and |f(n)−m| 6 δ.

Unfortunately, the partP

b6y1/3 ofS2 cannot be estimated by

max

16B6(x+y)1/3

Rx

b3, B, y B3

,

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Corrigendum to “On Short Sums of Certain Multiplicative

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Olivier Bordellès

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hence we have to proceed differently: for any positive integerr,we set

τ(r)(n) :=X

dr|n

1

and recall that

τ(r)(n)εnε/r for any positive integersn, r.

InS1,d=a2b3 > yimpliesa > y1/5 orb > y1/5.Since

X

y1/5<a6(x+y)1/2

X (ay2)1/3<b6(x+ya2 )1/3

(x+y)a−2 b3

− xa−2

b3

6 X

y1/5<a6(x+y)1/2

X

x

a2<n6x+ya2

τ(3)(n)

and we have the same ifb > y1/5,then

S1 6 X

y1/5<b6(x+y)1/3

X

x

b3<n6x+y

b3

τ(2)(n) + X

y1/5<a6(x+y)1/2

X

x

a2<n6x+y

a2

τ(3)(n)

= X

y1/5<b6(2y)1/3

X

x

b3<n6x+yb3

τ(2)(n) + X

(2y)1/3<b6(x+y)1/3

X

x

b3<n6x+yb3

τ(2)(n)

+ X

y1/5<a6(2y)1/2

X

x

a2<n6x+ya2

τ(3)(n) + X

(2y)1/2<a6(x+y)1/2

X

x

a2<n6x+ya2

τ(3)(n)

:= Σ1+ Σ2+ Σ3+ Σ4.

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Corrigendum to “On Short Sums of Certain Multiplicative

Functions”

Olivier Bordellès

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• ForΣ1andΣ3 we use the trivial bound:

Σ1+ Σ3 ε xε/2 X

y1/5<b6(2y)1/3

x+y b3

−hx b3

i

+xε/3 X

y1/5<a6(2y)1/2

x+y a2

−h x a2

i

ε xε/2y

 X

b>y1/5

1

b3 + X

a>y1/5

1 a2

ε y4/5xε/2.

• ForΣ2,we use the method of [1] to get

Σ2 ε xε x1/6+y1/3 .

• ForΣ4,if we supposey 6c0x1/2(wherec0 >0is sufficiently small),we have using Lemmas 2.1 and 2.2 of [1]:

Σ4 ε xε (

max

(2y)1/2<A6c−10 y

Rx a2, A, y

A2

+ max

c−10 y<A6x1/2

Rx

a2, A, y A2

)

ε xε

(xy)1/6+x1/5+x1/15y2/3 .

Hence we finally have S1 ε xε

x1/15y2/3+y4/5+ (xy)1/6+x1/5 +x1/6+y1/3 ε xε x1/15y2/3+y4/5

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ify>x1/5.Note thaty4/5 x1/15y2/3ify6c0x1/2 and that

X

x<n6x+y

f(n)−yP(f)

y x1/15y2/3

ify < x1/5.This concludes the proof of the theorem.

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Corrigendum to “On Short Sums of Certain Multiplicative

Functions”

Olivier Bordellès

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References

[1] O. BORDELLÈS, On short sums of certain multiplicative functions, J.

Inequal. Pure and Appl. Math., 3(5) (2002), Art. 70. [ONLINE: http:

//jipam.vu.edu.au/article.php?sid=222]

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