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volume 7, issue 1, article 17, 2006.

Received 19 September, 2005;

accepted 09 January, 2006.

Communicated by:S. Puntanen

Abstract Contents

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Journal of Inequalities in Pure and Applied Mathematics

ON THE STAR PARTIAL ORDERING OF NORMAL MATRICES

JORMA K. MERIKOSKI AND XIAOJI LIU

Department of Mathematics, Statistics and Philosophy FI-33014 University of Tampere, Finland

EMail:jorma.merikoski@uta.fi

College of Computer and Information Science Guangxi University for Nationalities

Nanning 530006, China.

EMail:xiaojiliu72@yahoo.com.cn

c

2000Victoria University ISSN (electronic): 1443-5756 278-05

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On the Star Partial Ordering of Normal Matrices Jorma K. Merikoski and Xiaoji Liu

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Abstract

We order the space of complexn×nmatrices by the star partial ordering≤. So A ≤ B means thatAA = ABand AA = BA. We find several characterizations forA≤Bin the case of normal matrices. As an application, we study howA≤ Brelates toA2 B2. The results can be extended to study howA≤Brelates toAkBk, wherek≥2is an integer.

2000 Mathematics Subject Classification:15A45, 15A18.

Key words: Star partial ordering, Normal matrices, Eigenvalues.

We thank the referee for various suggestions that improved the presentation of this paper. The second author thanks Guangxi Science Foundation (0575032) for the support.

Contents

1 Introduction. . . 3

2 Characterizations ofA≤B . . . 4

3 Relationship betweenA≤ BandA2 B2 . . . 11

4 Remarks. . . 15 References

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On the Star Partial Ordering of Normal Matrices Jorma K. Merikoski and Xiaoji Liu

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1. Introduction

Throughout this paper, we consider the space of complexn×nmatrices (n≥2).

We order it by the star partial ordering≤. SoA≤ Bmeans thatAA=AB andAA =BA. Our motivation rises from the following

Theorem 1.1 (Baksalary and Pukelsheim [1, Theorem 3]). LetAandBbe Hermitian and nonnegative definite. ThenA2 B2 if and only ifA≤ B.

We cannot drop out the assumption on nonnegative definiteness.

Example 1.1. Let

A = 1 0

0 1

, B=

1 0 0 −1

.

ThenA2 B2, but notA≤ B.

We will study how A ≤ B relates to A2 B2 in the case of normal matrices. We will see (Theorem 3.1) that the “if” part of Theorem1.1 remains valid. However, it is not valid for all matrices.

Example 1.2. Let

A = 1 1

0 0

, B=

1 1 2 −2

.

ThenA≤ B, but notA2 B2.

In Section2, we will give several characterizations ofA ≤ B. Thereafter, in Section3, we will apply some of them in discussing our problem. Finally, in Section4, we will complete our paper with some remarks.

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On the Star Partial Ordering of Normal Matrices Jorma K. Merikoski and Xiaoji Liu

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2. Characterizations of A ≤

B

Hartwig and Styan ([2, Theorem 2]) presented eleven characterizations ofA≤ Bfor general matrices. One of them uses singular value decompositions. In the case of normal matrices, spectral decompositions are more accessible.

Theorem 2.1. Let Aand Bbe normal matrices with 1 ≤ rankA < rankB.

Then the following conditions are equivalent:

(a) A≤ B.

(b) There is a unitary matrixUsuch that UAU=

D O O O

, UBU=

D O O E

,

whereDis a nonsingular diagonal matrix andE 6= Ois a diagonal ma- trix.

(c) There is a unitary matrixUsuch that UAU=

F O O O

, UBU=

F O O G

,

whereFis a nonsingular square matrix andG6=O.

(d) If a unitary matrixUsatisfies UAU=

F O O O

, UBU=

F0 O O G

,

whereFis a nonsingular square matrix,F0 is a square matrix of the same dimension, andG6=O, thenF=F0.

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On the Star Partial Ordering of Normal Matrices Jorma K. Merikoski and Xiaoji Liu

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(e) If a unitary matrixUsatisfies

UAU=

D O O O

, UBU=

D0 O O E

,

whereDis a nonsingular diagonal matrix,D0 is a diagonal matrix of the same dimension, andE6=Ois a diagonal matrix, thenD=D0.

(f) If a unitary matrixUsatisfies

UAU=

D O O O

,

whereDis a nonsingular diagonal matrix, then

UBU=

D O O G

,

whereG6=O.

(g) All eigenvectors corresponding to nonzero eigenvalues ofAare eigenvec- tors ofBcorresponding to the same eigenvalues.

The reason to assume 1 ≤ rankA < rankB is to omit the trivial cases A =OandA=B.

Proof. We prove this theorem in four parts.

Part 1. (a)⇒(b)⇒(c)⇒(a).

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(a) ⇒ (b). Assume (a). Then, by normality, A and B commute and are therefore simultaneously diagonalizable (see, e.g., [3, Theorem 1.3.19]). Since A and A have the same eigenvectors (see, e.g., [3, Problem 2.5.20]), also A andB are simultaneously diagonalizable. Hence (recall the assumption on the ranks) there exists a unitary matrixUsuch that

UAU=

D O O O

, UBU=

D0 O O E

,

whereDis a nonsingular diagonal matrix,D0 is a diagonal matrix of the same dimension, and E 6= O is a diagonal matrix. Now AA = AB implies DD=DD0 and furtherD =D0. Hence (b) is valid.

(b)⇒(c). Trivial.

(c)⇒(a). Direct calculation.

Part 2. (a)⇒(d)⇒(e)⇒(a).

This is a trivial modification of Part 1.

Part 3. (b)⇔(f).

(b)⇒(f). Assume (b). LetUbe a unitary matrix satisfying

UAU =

D O O O

.

By (b), there exists a unitary matrixVsuch that

VAV=

D0 O O O

, VBV=

D0 O O E

,

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On the Star Partial Ordering of Normal Matrices Jorma K. Merikoski and Xiaoji Liu

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where D0 is a nonsingular diagonal matrix and E 6= O is a diagonal matrix.

Interchanging the columns ofVif necessary, we can assumeD0 =D.

LetU= U1 U2

be such a partition that

UAU= U1

U2

A U1 U2

=

U1AU1 U1AU2

U2AU1 U2AU2

=

D O O O

. Then, for the corresponding partitionV = V1 V2

, we have

VAV= V1

V2

A V1 V2

=

V1AV1 V1AV2 V2AV1 V2AV2

=

D O O O

and

VBV= V1

V2

B V1 V2

=

V1BV1 V1BV2 V2BV1 V2BV2

=

D O O E

.

Noting that

A= V1 V2

D O O O

V1 V2

= V1 V2

DV1 O

=V1DV1,

we therefore have

UBU= U1

U2

V1 V2

D O O E

V1 V2

U1 U2

= U1

U2

V1 V2

DV1 EV2

U1 U2

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On the Star Partial Ordering of Normal Matrices Jorma K. Merikoski and Xiaoji Liu

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=

U1V1 U1V2 U2V1 U2V2

DV1U1 DV1U2 EV2U1 EV2U2

=

U1V1 O O U2V2

DV1U1 O O EV2U2

=

U1V1DV1U1 O O U2V2EV2U2

=

U1AU1 O O U2V2EV2U2

=

D O O U2V2EV2U2

,

and so (f) follows.

(f)⇒(b). Assume (f). LetUbe a unitary matrix such that

UAU =

D O O O

,

whereDis a nonsingular diagonal matrix. Then, by (f),

UBU=

D O O G

,

where G 6= O. SinceG is normal, there exists a unitary matrix Wsuch that E =WGWis a diagonal matrix. Let

V =U

I O O W

.

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On the Star Partial Ordering of Normal Matrices Jorma K. Merikoski and Xiaoji Liu

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Then

VAV =

I O O W

UAU

I O O W

=

I O O W

D O O O

I O O W

=

D O O O

and

VBV=

I O O W

UBU

I O O W

=

I O O W

D O O G

I O O W

=

D O O E

.

Thus (b) follows.

Part 4. (b)⇔(g).

This is an elementary fact.

Corollary 2.2. LetAandBbe normal matrices. IfA ≤ B, thenAB=BA.

Proof. Apply (b).

The converse does not hold (even assumingrankA < rankB), see Exam- ple2.1. The normality assumption cannot be dropped out, see Example2.2.

Example 2.1. Let

A = 2 0

0 0

, B=

1 0 0 1

.

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On the Star Partial Ordering of Normal Matrices Jorma K. Merikoski and Xiaoji Liu

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ThenAB=BAandrankA <rankB, butA≤ Bdoes not hold. However,

1

2A ≤ B, which makes us look for a counterexample such thatcA≤ Bdoes not hold for anyc6= 0. It is easy to see that we must haven ≥3. The matrices

A=

2 0 0 0 3 0 0 0 0

, B=

3 0 0 0 4 0 0 0 1

obviously have the required properties.

Example 2.2. Let

A = 0 1

0 0

, B=

0 1 1 0

. ThenA≤ B, butAB6=BA.

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On the Star Partial Ordering of Normal Matrices Jorma K. Merikoski and Xiaoji Liu

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3. Relationship between A ≤

B and A

2

B

2

We will see thatA ≤ B ⇒ A2 B2 for normal matrices, but the converse needs an extra condition, which we first present using eigenvalues.

Theorem 3.1. Let Aand Bbe normal matrices with 1 ≤ rankA < rankB.

Then

(a) A≤ B

is equivalent to the following:

(b) A2 B2

and if A and B have nonzero eigenvalues α and respectively β such that α2 andβ2 are eigenvalues ofA2 and respectivelyB2 with a common eigenvector x, thenα =β andxis a common eigenvector ofAandB.

Proof. Assuming (a), we have

UAU=

D O O O

, UBU=

D O O E

as in (b) of Theorem2.1, and so

UA2U=

D2 O O O

, UB2U=

D2 O O E2

.

Hence, by Theorem2.1, the first part of (b) follows. The second part is trivial.

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On the Star Partial Ordering of Normal Matrices Jorma K. Merikoski and Xiaoji Liu

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Conversely, assume (b). Then

UA2U=

∆ O O O

, UB2U=

∆ O O Γ

,

whereU,∆, andΓare matrices obtained by applying (b) of Theorem2.1toA2 andB2. Letu1, . . . ,unbe the column vectors ofUand denoter= rankA.

Fori = 1, . . . , r, we haveA2ui = B2ui = δiui, where(δi) = diag∆. So, by the second part of (b), there exist complex numbersd1, . . . , drsuch that, for alli= 1, . . . , r, we haved2iiandAui =Buiiui. LetDbe the diagonal matrix with(di) = diagD.

Fori = r+ 1, . . . , n, we have B2ui = γi−rui, where(γj) = diagΓ. Take complex numberse1, . . . , en−rsatisfyinge2iifori= 1, . . . , n−r. LetEbe the diagonal matrix with(ei) = diagE. Then

UAU=

D O O O

, UBU=

D O O E

,

and (a) follows from Theorem2.1.

As an immediate corollary, we obtain a generalization of Theorem1.1.

Corollary 3.2. Let A and B be normal matrices whose all eigenvalues have nonnegative real parts. ThenA2 B2 if and only ifA≤ B.

Next, we present the extra condition using diagonalization.

Theorem 3.3. Let Aand Bbe normal matrices with 1 ≤ rankA < rankB.

Then

(a) A≤ B

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is equivalent to the following:

(b) A2 B2

and if

UAU=

D O O O

, UBU=

DH O O E

,

whereUis a unitary matrix,Dis a nonsingular diagonal matrix,His a unitary diagonal matrix, andE6=Ois a diagonal matrix, thenH=I.

(Note that the second part of (b) is weaker than (e) of Theorem2.1. Other- wise Theorem3.3would be nonsense.)

Proof. For (a) ⇒the first part of (b), see the proof of Theorem3.1. For (a)⇒ the second part of (b), see (e) of Theorem2.1.

Conversely, assume (b). As in the proof of Theorem3.1, we have

UA2U=

∆ O O O

, UB2U=

∆ O O Γ

.

Hence

UAU=

D O O O

, UBU=

D0 O O E

,

whereDandD0 are diagonal matrices satisfyingD2 = (D0)2 = ∆andE is a diagonal matrix satisfyingE2 =Γ.

Denoting(di) = diagD, (d0i) = diagD0, r = rankA, we therefore have d2i = (d0i)2 for all i = 1, . . . , r. Hence there are complex numbersh1, . . . , hr

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such that|h1|=· · ·=|hr|= 1andd0i =dihi for alli= 1, . . . , r. LetHbe the diagonal matrix with(hi) = diagH. ThenD0 = DH, and soD0 = Dby the second part of (b). Thus (b) of Theorem2.1is satisfied, and so (a) follows.

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4. Remarks

We complete our paper with four remarks.

Remark 1. Letk ≥ 2be an integer. A natural further question is whether our discussion can be extended to describe how A ≤ B relates to Ak Bk. As noted by Baksalary and Pukelsheim [1], Theorem 1.1 can be generalized in a similar way. In other words, for Hermitian nonnegative definite matrices, Ak Bkif and only ifA≤ B. It can be seen also that Theorems3.1and3.3 can be, with minor modifications, extended correspondingly.

Remark 2. LetA andB be arbitraryn×n matrices withrankA < rankB.

Hartwig and Styan ([2, Theorem 2]) proved thatA ≤ B if and only if there are unitary matricesUandVsuch that

UAV=

Σ O O O

, UBV=

Σ O O Θ

,

whereΣis a positive definite diagonal matrix andΘ6=Ois a nonnegative def- inite diagonal matrix. This is analogous to (a)(b) of Theorem2.1. Actually it can be seen that all the characterizations of A ≤ Blisted in Theorem 2.1 have singular value analogies in the general case.

Remark 3. The singular values of a normal matrix are absolute values of its eigenvalues (see e.g., [3, p. 417]). Hence it is relatively easy to see that if (and only if)AandBare normal, thenUandVabove can be chosen so thatUV is a diagonal matrix.

Remark 4. For normal matrices, it can be shown that Theorems 3.1 and 3.3 have singular value analogies. In the proof, it is crucial thatUVis a diagonal matrix. So these results do not remain valid without the normality assumption.

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References

[1] J.K. BAKSALARYANDF. PUKELSHEIM, On the Löwner, minus and star partial orderings of nonnegative definite matrices and their squares, Linear Algebra Appl., 151 (1991), 135–141.

[2] R.E. HARTWIG AND G.P.H. STYAN, On some characterizations on the

“star” partial ordering for matrices and rank subtractivity, Linear Algebra Appl., 82 (1986), 145–161.

[3] R.A. HORNANDC.R. JOHNSON, Matrix Analysis, Cambridge University Press, 1985.

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