OCTOGON MATHEMATICAL MAGAZINE Vol. 17, No.1, April 2009, pp 288-290
ISSN 1222-5657, ISBN 978-973-88255-5-0, www.hetfalu.ro/octogon
288
Improvement of one of S´ andor‘s inequalities
Nicu¸sor Minculete32
ABSTRACT.The objective of this paper is to present an improvement of S´andor‘s inequality
√σk(n)·σ1(n) σk−1
2 (n) ≤n−(k4−l) ·n
k+l2 +1
2 , for anyn, k, l∈N∗, whereσk(n)is the sum ofkth powers of divisors of n, so σk(n) =P
d|n
dk.
INTRODUCTION
Letn be a positive integer,n≥1. We note with σk(n) the sum ofkth powers of divisors ofn, so, σk(n) =P
d|n
dk, whence we obtain the following equalities: σ1(n) =σ(n) and σ0(n) =τ(n)−the number of divisors of n.
In [1], J. S´andor shows that pσk(n)·σl(n)
σk−l
2 (n) ≤n−(k4−l) ·nk+l2 + 1
2 , for anyn, k, l∈N∗ (1) In [2] an inequality which is due to J.B. Diaz and F.T. Metcalf is proved, namely:
Lemma 1.1 Letn be a positive integer,n≥2. For every
a1, a2, ..., an∈R and for everyb1, b2, ..., bn∈R∗ with m≤ abii ≤M and m, M ∈R, we have the following inequality:
Xn i=1
a2i +mM Xn i=1
b2i ≤(m+M) Xn
i=1
aibi. (2)
32Received: 25.03.2009
2000Mathematics Subject Classification. 11A25
Key words and phrases. The sum of the natural divisors of n, the sum of kth powers of divisors ofn
Improvement of one of S´andor‘s inequalities 289 1. MAIN RESULT
Theorem 1.2. For everyn, k, l∈N withn≥2 and k−2l ∈N the following relation
pσk(n)·σl(n) σk−l
2 (n) ≤ nl−4kσk(n) +nk−4lσl(n) 2σk−l
2 (n) ≤n−(k4−l) ·nk+l2 + 1
2 , is true. (3) Proof. In the Lemma 1.1, making the substitutionai =q
dki and bi = √1
dli, wheredi is the divisor of n, for anyi= 1, τ(n). Since
1≤ abii = q
dk+li ≤nk+l2 and aibi =d
k−l
i2 , we take m= 1 and M =nk+l2 . Therefore, inequality (2) becomes
τ(n)X
i=1
dki +nk+l2
τ(n)X
i=1
1 dli ≤
1 +nk+l2 τ(n)X
i=1
d
k−l
i2
which is equivalent to
σk(n) +nk+l2 σl(n) nl ≤
1 +nk+l2 σk−l
2 (n) so that
σk(n) +nk−2lσl(n)≤
1 +nk+l2 σk−l
2 (n), (4)
for everyn, k, l∈N with n≥2.
The arithmetical mean is greater than the geometrical mean or they are equal, so for everyn, k, l∈N withn≥2, we have
q
nk−2lσk(n)σl(n)≤ σk(n) +nk−2lσl(n)
2 . (5)
Consequently, from the relations (4) and (5), we deduce the inequality pσk(n)σl(n)
σk−l
2 (n) ≤ nl−4kσk(n) +nk−4lσl(n) 2σk−l
2 (n) ≤n−(k4−l) ·nk+l2 +l
2 .
Remark Fork→k+ 2 andl→k we obtain the relation pσk+2(n)·σk(n)
σ(n) ≤
√1
nσk+2(n) +√
nσk(n)
2σ(n) ≤ 1
√n ·nk+1+ 1
2 , (6)
290 Nicu¸sor Minculete for everyn, k∈N with n≥2.
Fork=l, we deduce another inequality which is due to S´andor, namely, σk(n)
τ(n) ≤ nk+ 1
2 , (7)
for everyn, k∈N withn≥2.
REFERENCES
[1] S´andor, J., On Jordan’s Arithmetical Function, Gazeta Matematic˘a nr.
2-3/1993.
[2] Drimbe, M.O.,Inegalit˘at¸i. Idei ¸si metode, Editura GIL, Zal˘au, 2003.
“Dimitrie Cantemir” University of Bra¸sov E-mail: minculeten@yahoo.com