volume 3, issue 3, article 34, 2002.
Received 15 February, 2002;
accepted 22 February, 2002.
Communicated by:Th. M. Rassias
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Journal of Inequalities in Pure and Applied Mathematics
PROJECTION ITERATIVE SCHEMES FOR GENERAL VARIATIONAL INEQUALITIES
MUHAMMAD ASLAM NOOR, YI JU WANG AND NAIHUA XIU
Etisalat College of Engineering, Sharjah,
United Arab Emirates EMail:noor@ece.ac.ae
School of Mathematics and Computer Science, Nanjing Normal University
Nanjing, Jiangsu, 210097, The People’s Republic of China.
AND
Institute of Operations Research, Qufu Normal University, Qufu Shandong, 273165, The People’s Republic of China.
Department of Applied Mathematics, Northern Jiaotong University, Beijing, 100044,
The People’s Republic of China.
EMail:nhxiu@center.njtu.edu.cn
c
2000Victoria University ISSN (electronic): 1443-5756 010-02
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Abstract
In this paper, we propose some modified projection methods for general varia- tional inequalities. The convergence of these methods requires the monotonic- ity of the underlying mapping. Preliminary computational experience is also reported.
2000 Mathematics Subject Classification:90C30
Key words: General variational inequalities, Projection method, Monotonicity.
The research of Yiju Wang and Naihua Xiu is partially supported by N.S.F. of China (Grants No. Q99A11 and 19971002,10171055).
Contents
1 Introduction. . . 3
2 Preliminaries . . . 5
3 Algorithms and Convergence. . . 7
4 Preliminary Computational Experience . . . 13 References
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1. Introduction
Let K be a nonempty closed convex set in Euclidean space Rn. For given nonlinear operators T, g : Rn → Rn, consider the problem of finding vector u∗ ∈Rnsuch thatg(u∗)∈Kand
(1.1) hT(u∗), g(u)−g(u∗)i ≥0, ∀g(u)∈K.
This problem is called general variational inequality (GVI) which was intro- duced by Noor in [10]. General variational inequalities have important appli- cations in many fields including economics, operations research and nonlinear analysis, see, e.g., [5], [10] – [15] and the references therein.
Ifg(u) ≡ u, then the general variational inequality (1.1) reduces to finding vectoru∗ ∈K such that
(1.2) hT (u∗), u−u∗i ≥0, ∀u∈K,
which is known as the classical variational inequality and was introduced and studied by Stampacchia [18] in 1964. For the recent state-of-the-art, see e.g., [1] – [22].
IfK∗∗ = {u∈ Rn| hu, vi ≥ 0, ∀v ∈ K}is a polar cone of a convex cone K inRn, then problem (1.1) is equivalent to findingu∗ ∈Rnsuch that
(1.3) g(u)∈K, T(u)∈K∗∗, hg(u), T(u)i= 0,
which is known as the general complementarity problem. Ifg(u) =u−m(u), wheremis a point-to-set mapping, then problem (1.3) is called quasi (implicit)
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complementarity problem. Forg(u) =u,problem (1.3) is known as the gener- alized complementarity problem.
For general variational inequality, Noor [10] gave a fixed point equation re- formulation, Pang and Yao [15] established some sufficient conditions for the existence of the solutions and investigated their stability, and He [5] proposed an inexact implicit method. In this paper, we consider a projection method for solving GVI under the assumptions that the solution set is nonempty and the underlying mapping is monotone in a generalized sense.
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2. Preliminaries
For nonempty closed convex setK ⊂Rnand any vectoru∈Rn, the orthogonal projection ofuontoK, i.e.,arg min{||v−u|| |v ∈K}, is denoted byPK(u). In the following, we state some well known properties of the projection operator.
Lemma 2.1. [23]. Let K be a closed convex subset of Rn, for any u ∈ Rn, v ∈K, then
hPK(u)−u, v−PK(u)i ≥0.
From Lemma2.1, it follows that the projection operatorPK is nonexpansive.
Invoking Lemma 2.1, one can prove that the general variational inequality (1.1) is equivalent to the fixed-point problem For GVI, this result is due to Noor [10].
Lemma 2.2. [10]. A vector u∗ ∈ Rn withg(u∗) ∈ K is a solution of GVI if and only ifg(u∗) =PK(g(u∗)−ρT (u∗))for someρ >0.
Based on this fixed-point formulation, various projection type iterative meth- ods for solving general variational inequalities have been suggested and ana- lyzed, see [5], [10] – [15].
In this paper, we suggest another projection method which needs two projec- tions at each iteration and its convergence requires the following assumptions.
Assumption 1.
(i) The solution set of GVI, denoted byK∗, is nonempty.
(ii) MappingT :Rn→Rnisg-monotone, i.e.,
hT(u)−T(v), g(u)−g(v)i ≥0, ∀u, v∈Rn.
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(iii) Mappingg :Rn →Rnis nonsingular, i.e., there exists a positive constant µsuch that
||g(u)−g(v)|| ≥µ||u−v||, ∀u, v ∈Rn.
Note that for g ≡ I, g-monotonicity of mapping T reduces to the usual definition of monotone. Furthermore, every solvable monotone variational in- equality of form (1.2) satisfies the above assumptions.
Throughout this paper, we define the residue vectorRρ(u)by the following relation
Rρ(u) :=g(u)−PK(g(u)−ρT(u)).
Invoking Lemma 2.2, one can easily conclude that vector u∗ is a solution of GVI if and only ifu∗ is a root of the following equation:
Rρ(u) = 0, for someρ≥0.
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3. Algorithms and Convergence
The basic idea of our method is as follows. First, take an initial pointu0 ∈ Rn such thatg(u0)∈ K and compute the projection residue. If it is a zero vector, then stop; otherwise, take the negative projection residue as a direction and per- form a line search along this direction to get a new point; after constructing a
“descent direction” related to the current point and the new point, the next iter- ative point can be obtained by using a projection. Repeat this process until the projection residue is a zero vector. So the algorithm needs only two projections at each iteration.
Now, we formally describe our method for solving the GVI problem.
Algorithm 1.
Initial step: Chooseu0 ∈Rnsuch thatg(u0)∈K, select anyσ, γ ∈(0,1), ρ∈(0,+∞), letk := 0.
Iterative step: Forg uk
∈K,takewk∈Rnsuch that g wk
:=PK g uk
−ρT uk . If
Rρ uk
= 0, then stop. Otherwise, computevk∈Rnsuch thatg vk
:=g uk
−ηkRρ uk
,whereηk =γmk
withmkbeing the smallest nonnegative integermsatisfying
(3.1) ρ
T uk
−T vk
, Rρ uk
≤σ
Rρ uk
2.
Computeuk+1 by solving the following equation g uk+1
=PK g uk
+αkdk , wheredk=− ηkRρ uk
+ηkT uk
+ρT vk , αk = (1−σ)ηkkRρ(uk)k2
kdkk2 .
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Remark 3.1. We analyze the step-size rule given in (3.1). If Algorithm1 ter- minates with Rρ uk
= 0, then uk is a solution of GVI. Otherwise, by non- singularity ofg and continuity ofT andg,ηksatisfying (3.1) exists.
Remark 3.2. In Algorithm1, several implicit equations ofg must be solved at each iteration. Ifg ≡I,thenvk = (1−ηk)uk+ηkwk.
Remark 3.3. We recall the searching directions appear in existing projection- type methods for solving VI of form (1.2). They are
(i) the direction−T(¯uk)by Korpelevich [9], whereu¯k=PK uk−αkT uk
; (ii) the direction−
uk−u¯k−αk
T uk
−T u¯k by Solodov and Tseng [17], Tseng [20], Sun [19] and He [6].
(iii) the direction−
uk−u¯k+T u¯k by Noor [13].
(iv) the direction−T vk
by Iusem and Svaiter [7] and Solodov and Svaiter [16].
(v) the direction− ηkr uk
+T vk
by Wang, Xiu and Wang [22].
In our algorithm, wheng ≡I, the searching direction reduces to
− ηkr uk
+ηkT uk
+ρT vk .
It is a combination of the projection residue and T, and differs from the above five types of directions.
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Now, we discuss the convergence of Algorithm1. From the iterative proce- dure, we know thatg uk
, g vk
, g wk
∈Kfor allk. For anyg(u∗)∈K∗, by Assumption(ii), we have
(3.2)
ρT uk
, g uk
−g(u∗)
≥0.
From Lemma2.1, we know that g uk
−ρT uk
−g wk
, g wk
−g(u∗)
≥0,
which can be written as g uk
−ρT uk
−g wk
, g wk
−g uk +
g uk
−g wk
−ρT uk
, g uk
−g(u∗)
≥0.
Combining with inequality (3.2), we obtain (3.3)
Rρ uk
, g uk
−g(u∗)
≥
Rρ uk
2−ρ T uk
, Rρ uk .
So
g uk
−g(u∗),−dk
= g uk
−g(u∗), ηkRρ uk
+ηkT uk
+ρT vk
= g uk
−g(u∗), ηkRρ uk +
g uk
−g(u∗), ηkT uk +
g uk
−g(u∗), ρT vk
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≥ηk
Rρ uk
2−ρηk
T uk
, Rρ uk +
g uk
−g vk
, ρT vk
=ηk
Rρ uk
2−ρηk T uk
, Rρ uk +ηk
Rρ uk
, ρT vk
=ηk
Rρ uk
2−ρηk T uk
−T vk
, Rρ uk
≥ηk
Rρ uk
2−σηk
Rρ uk
2
= (1−σ)ηk
Rρ uk
2,
where the first inequality uses (3.3) and the g-monotonicity of T, the second inequality follows from inequality (3.1).
For anyα >0, one has PK g uk
+αdk
−g(u∗)
2
≤ g uk
−g(u∗) +αdk
2
= g uk
−g(u∗)
2+α2kdkk2+ 2α
dk, g uk
−g(u∗)
≤ g uk
−g(u∗)
2+α2kdkk2−2α(1−σ)ηk
Rρ uk
2,
where the first inequality uses non-expansiveness of projection operator.
Based on the above analysis, we show that Algorithm 1 converges under Assumptions(i)–(iii).
Theorem 3.1. Under Assumptions(i)–(iii), if Algorithm1generates an infinite sequence{uk}, then{uk}globally converges to a solutionu∗of GVI.
Proof. Letα := α = (1−σ)ηk||Rρ(uk)||2
in the aforementioned inequalities, we
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obtain
g(uk+1)−g(u∗) ≤
g uk
−g(u∗)
2− (1−σ)2η2k
Rρ uk
4
||dk||2 .
So
g uk
−g(u∗)
is a non-increasing sequence, and
g uk is a bounded sequence. Sincegis nonsingular, we conclude that{uk}is a bounded sequence.
Short discussion leads to that{dk}is bounded. So, there exists an infinite subset N1 such that
k∈Nlim1,k→∞
Rρ uk = 0 or an infinite subsetN2such that
k∈Nlim2,k→∞ηk = 0.
If lim
k∈N1,k→∞
Rρ uk
= 0, we know that any cluster u˜ of {uk : k ∈ N1} is a solution of GVI. Since
g uk
−g(u∗)
is non-increasing, if we take u∗ = ˜u, then we know that{g uk
}globally converges tog(˜u)and thus{uk} globally converges tou˜from Assumption(iii).
If lim
k∈N2,k→∞ηk = 0, letv¯k ∈Rnsuch thatg vk
=g uk
− ηk
γRρ(uk). From the linear searching procedure ofηk, we have
ρ T uk
−T(¯vk), Rρ uk
> σ
Rρ uk
2, for sufficiently largek∈N2. Therefore,
ρ T uk
−T(¯vk) > σ
Rρ uk
, for sufficiently largek ∈N2.
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This, plus lim
k∈N2,k→∞
ηk
γ = 0, yields lim
k∈N2,k→∞
Rρ uk
= 0. Similar discus- sion leads to that any cluster of
uk :k ∈N2 is a solution to GVI. Replacing u∗ by this cluster point yields the desired result.
If we replace ρ with ρk in Algorithm 1, then we obtain the following im- proved algorithm to GVI.
Algorithm 2.
Initial step: Chooseu0 ∈Rnsuch thatg(u0)∈K, select anyσ, γ ∈(0,1), η−1 = 1,θ >0.
Letk= 0.
Iterative step: Forg uk
∈K,defineρk= min{θηk−1,1}, and takewk∈Rn such thatg wk
=PK(g uk
−ρkT uk ).
IfRρk uk
= 0, then stop. Otherwise, takevk∈Rnin the following way: g vk
= (1−ηk)g uk
+ηkg wk , whereηk =γmk, withmk being the smallest
nonnegative integermsatisfying ρkhT uk
−T vk
, Rρk uk
i ≤σ
Rρk uk
2. Computeuk+1 by solving the following equation:
g(uk+1) =PK(g uk
+αkdk) wheredk =− ηkRρk uk
+ηkT uk
+ρkT vk , αk = (1−σ)ηkkRρk(uk)k2
kdkk2 .
The convergence of Algorithm2can be proved similarly.
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4. Preliminary Computational Experience
In the following, we present some numerical experiments for Algorithms1and 2. For these algorithms, we used
r xk, ρk
≤10−8as stopping criteria.
Throughout the computational experiments, the parameters used were set as σ = 0.5, γ = 0.8. All computational results were undertaken on a PC-II by MATLAB.
Example 4.1. This example is a quadratic subproblem of the trust region ap- proach for solving medium-size nonlinear programming problem:
min 1
2x>Hx+c>x|x∈C
.
This problem is equivalent to VI(F, C) withF(x) =Hx+c. the data is chosen as: H = V W V, where V = I −2||v||vv>2 is a Householder matrix and W = diag(σi)withσi = cosn+1iπ + 1000. The vectorsvandccontain pseudo-random numbers:
v1 = 13846, vi = (42108vi−1+ 13846)mod46273, i= 2, . . . , n;
c1 = 13846, ci = (45287ci−1 + 13846)mod46219, i= 2, . . . , n.
For this test problems, the domain set C = {x∈Rn| ||x|| ≤105}. Ta- ble 1 gives the numerical results for this example with starting point x0 = (0,0, . . . ,0)T for different dimensionsn.
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Dimension Algorithm1(ρ= 1) Algorithm2(θ = 400)
n= 10 73 56
n= 20 75 58
n= 50 78 58
n= 80 81 60
n = 100 84 60
n = 200 97 60
Table 1: Numbers of iterations for Example4.1
Example 4.2. This example is a general variational inequality with g(x) = Ax+qandF(x) = x, where
A=
4 −2 0 · · · 0 1 4 −2 · · · 0 0 1 4 · · · 0 ... ... ... ... ... 0 0 0 · · · −2 0 0 0 · · · 4
, q =
1 1 1 ... 1 1
.
For this test problems, the domain setC = {x ∈ Rn|0 ≤ xi ≤ 1, fori = 1,2,· · ·n}. Table2gives the results for this example with starting pointx0 =
−A−1qfor different dimensionsn.
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Dimension Algorithm1(ρ= 1) Algorithm2(100 ≤θ≤400)
n= 10 492 492
n= 20 489 489
n= 50 484 484
n= 80 481 481
n = 100 480 480
n = 200 476 476
Table 2: Numbers of iterations for Example4.2
From Table1and Table2, one observes that Algorithms1and2work quite well for these examples, respectively, and there is not much difference to the choice of parameterρk in the second algorithm, especially for Example4.2.
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