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2014, No. 35, 1–22;

http://www.math.u-szeged.hu/ejqtde/

Insensitizing controls for the Cahn–Hilliard type equation

Peng Gao

B

Institute of Mathematics, Jilin University, 2699 Qianjin Street, Changchun, 130012, P. R. China Received 30 December 2013, appeared 29 July 2014

Communicated by Vilmos Komornik

Abstract. This paper is addressed to showing the existence of insensitizing controls for the one-dimensional Cahn–Hilliard type equation with a superlinear nonlinearity. We solve this problem by reducing the original problem to a controllability problem. The crucial point in this paper is an observability estimate for a linearized cascade system of the Cahn–Hilliard type equation. In order to obtain this observability estimate, we establish a global Carleman estimate for a fourth order parabolic operator.

Keywords: Cahn–Hilliard type equation, insensitizing control, controllability, observ- ability, superlinear nonlinearity, global Carleman estimate.

2010 Mathematics Subject Classification: 35K35, 93B05, 93B07.

1 Introduction

Set I = (0, 1), T > 0, and Q = I ×(0,T). Let ω and O be nonempty open subsets of I. We consider the Cahn–Hilliard type equation posed on the finite interval I satisfying some homogeneous boundary conditions and an initial condition, namely









yt+yxxxx+ f(y) =ξ+hχω inQ, y(0,t) =0=y(1,t) in(0,T), yx(0,t) =0=yx(1,t) in(0,T), y(x, 0) =y0(x) +τz0(x) in I,

(1.1)

where f is aC1 function defined onRverifying f00 ∈ Lloc(R), f(0) =0 and

|slim|→

f0(s)

log(1+|s|) =0, (1.2)

ξ ∈ L2(Q)and y0 ∈ L2(I) are given, z0 ∈ L2(I) is unknown with kz0kL2(I) = 1, τ is a small unknown real number, andh∈L2(Q)is a control function to be determined. Hereχωdenotes the characteristic function ofω.

BCorresponding author. Email: gaopengjilindaxue@126.com

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The Cahn–Hilliard equation is an equation of mathematical physics which describes the process of phase separation, by which the two components of a binary fluid spontaneously separate and form domains pure in each component. It arises as a phenomenological model for isothermal phase separation in a binary alloy, see Cahn [7, 8] and Hilliard [20] for a derivation, [15,23,27] for general analysis, and the reviews given in [16].

Let us define

Φ(y(·,·,τ,h)) = 1 2

Z T

0

Z

O |y(x,t,τ,h)|2 dx dt, wherey(·,·,τ,h)is the solution of (1.1) associated toτ.

The following control problem is addressed: Does there exist a control h ∈ L2(Q) such

that dΦ(y(·,·,τ,h))

τ=0

=0

holds? The problem is interesting, and attracts many authors’ attention. We call it insensitiz- ing control problem. Next, we investigate the existence of insensitizing controls forΦ about the system (1.1), their definitions are as follows.

Definition 1.1. The control h is said to insensitize the functional Φ if for every z0 satisfying kz0kL2(I) =1, the corresponding solutionyof (1.1) satisfies

d

dτΦ(y(·,·,τ,h)) τ=0

=0.

The insensitizing control problem consists in finding a control function such that some functional of the state is locally insensitive to the perturbations of these initial and boundary data. The concept of insensitizing control was introduced by J. L. Lions [21]. Later on, Bodart and Fabre proposed the weakened notion of ε−insensitizing control in [2]. A similar result was proved by Teresa [12] in unbounded domains. The first results on the existence and non- existence of insensitizing controls were proved in [13]. For more general nonlinearities, see [3,4,5]. A similar result for wave equations was obtained in [11,26].

The main purpose in our paper is to study the existence of insensitizing controls for the Cahn–Hilliard equation. As far as we know, there is no insensitivity result for this equation.

In this sense, this is the first attempt to consider insensitizing controls problem for the Cahn–

Hilliard equation. In order to solve this problem, we establish a new observability estimate (see Theorem1.2).

Following the methods introduced in [21] and developed in [2,11,13,26], one gets that the existence of a controlhinsensitizing the functionalΦalong the solutions of (1.1) is equivalent to the existence of a controlhsuch that the solution(y,q)of the cascade system (1.3)–(1.4)









yt+yxxxx+ f(y) =ξ+hχω in Q, y(0,t) =0=y(1,t) in (0,T), yx(0,t) =0= yx(1,t) in (0,T), y(x, 0) =y0(x) in I

(1.3)









−qt+qxxxx+ f0(y)q=yχO inQ, q(0,t) =0=q(1,t) in(0,T), qx(0,t) =0=qx(1,t) in(0,T),

q(x,T) =0 in I

(1.4)

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satisfies

q(x, 0) =0.

Namely, system (1.3)–(1.4) is null controllable. The null controllability has been widely in- vestigated for the heat equation and there has been a great number of results (see for in- stance [6, 22] and the references therein for a detailed account). To our best knowledge, there have been limited publications on the controllability of higher order parabolic equations.

Among them, Díaz [14] considered the approximate controllability and non-approximate con- trollability of higher order parabolic equations. The null boundary controllability for a one- dimensional fourth order parabolic equation was studied in [6,10]. Cerpa [9] considered the local boundary controllability for an especial one-dimensional fourth order parabolic equation (Kuramoto–Sivashinsky equation). Recently, Zhou [28] considered the null controllability for one-dimensional semilinear fourth order parabolic equations.

In order to investigate system (1.3)–(1.4), we firstly consider the linearized system of (1.3)–

(1.4)









yt+yxxxx+ay=ξ+hχω in Q, y(0,t) =0= y(1,t) in (0,T), yx(0,t) =0=yx(1,t) in (0,T), y(x, 0) =y0(x) in I

(1.5)









−qt+qxxxx+bq=yχO inQ, q(0,t) =0=q(1,t) in(0,T), qx(0,t) =0=qx(1,t) in(0,T),

q(x,T) =0 in I

(1.6)

where a,b∈ L(Q).

The adjoint system of (1.5)–(1.6) is









pt+pxxxx+b(x,t)p=0 inQ, p(0,t) =0= p(1,t) in(0,T), px(0,t) =0= px(1,t) in(0,T), p(x, 0) = p0(x) in I

(1.7)









−zt+zxxxx+a(x,t)z = pχO in Q, z(0,t) =0=z(1,t) in (0,T), zx(0,t) =0=zx(1,t) in (0,T),

z(x,T) =0 in I.

(1.8)

According to the duality argument, the observability estimate of (1.7)–(1.8) is important for the insensitizing control problem.

Theorem 1.2. For every p0 ∈ L2(I), if (p,z)is the solution to (1.7)–(1.8), there exist M > 0 and C(T)>0,such that

Z

Q

eMt z2dx dt ≤eC(T)(kakL∞(Q)+kbkL∞(Q)+1)Z

ω×(0,T)

z2dx dt. (1.9)

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The following duality identity for the solutions of (1.5)–(1.6) and (1.7)–(1.8) holds Z

Q

(ξ+hχω)z dx dt=

Z

I q(x, 0)p0(x)−z(x, 0)y0(x)dx (1.10) for everyh ∈ L2(Q),y0 ∈ L2(), p0 ∈ L2(). Indeed, multiplying (1.5) by z and integrating by parts in account of the boundary and initial (final) conditions in (1.5)–(1.6) and (1.7)–(1.8), we can get (1.10).

By the observability estimate (1.9) of the linearized system (1.5)–(1.6) and the fixed point theorem, we have the following result:

Theorem 1.3. LetOandωbe nonempty open subsets of I satisfyingω∩ O 6= and y0 =0.Then for anyξ ∈ L2(Q)verifying eM2tξ ∈ L2(Q),one can find a control function h ∈ L2(Q)insensitizing the functionalΦalong the solution of (1.1), where M is same as in Theorem1.2.

Remark 1.4. In view of Theorem1.3, we can obtain the null controllability of (1.3)–(1.4) with the nonlinearities f(s) =o(s(log(|s|)))for |s| → ∞. For the scalar Cahn–Hilliard type equa-

tion 









yt+yxxxx+F(y) =hχω in Q, y(0,t) =0=y(1,t) in (0,T), yx(0,t) =0=yx(1,t) in (0,T), y(x, 0) =y0(x) in I

(1.11)

with nonlinearities such that F(s) = o(s(log72(|s|)))for |s| → ∞, it seems possible to obtain the null controllability of (1.11). Indeed, following the same idea as in [18], we can choose a small timeT< Tand find a controlhthat drives the solution to zero atT, then extendhby zero to the rest interval[T,T].

However, for the system (1.3)–(1.4), since the existence of the nonhomogeneous termξ, the above method does not work. More precisely, even though we can obtain the null control- lability of (1.3)–(1.4) at a small time T, the zero control in [T,T]cannot guarantee the null controllability of (1.3)–(1.4) atTowing toξ. According to the existent methods, the best result for the nonlinearities in (1.3)–(1.4) we can obtain is f(s) = o(s(log(|s|))) for |s| → ∞. The key point is the estimate (4.7) in Section 4. The same reason can also be found in [3] which considers the insensitizing controls for a heat equation.

The paper is organized as follows. In Section 2, we present some well-posedness results by the classical semigroup theory, multipliers method and suitable energy estimates. Then, we establish a Carleman estimate for the fourth order parabolic operator. The observability estimate is established in Section 3. In Section 4, by means of the variational approach, the observability estimate in the above section and Kakutani’s fixed point theorem, we establish the existence of insensitizing controls for the Cahn–Hilliard equation.

2 Some preliminaries

In order to prove Theorem 1.2, we should establish a global Carleman estimate for a fourth order parabolic operator.

Letψ∈ C()satisfy thatψ>0 in Ω,ψ(0) = ψ(1) =0,kψkC() =1,|ψx |>0 in Ω\ω0, ψx(0)>0 andψx(1)<0. For any given positive constantsλandµ, we setd(x,t) = eµ(ψ(x)+3)e

t(Tt) ,

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θ(x,t) =eλd(x,t)and ϕ(x,t) = eµt((ψT(x)+t)3),∀(x,t)∈ Q. LetPbe an operator Py:=yt+yxxxx,

defined on U := y ∈ L2(0,T;H4(I)) | y(t, 0) = y(t, 1) = yx(t, 0) = yx(t, 1) = 0, t ∈ (0,T), Py∈ L2(0,T;L2(I)) .

Proposition 2.1. There exist four constantsµ0>1, C0 >0,C1 >0and C2 >0such that forµ=µ0

and for everyλ≥C0(T+T2)and y ∈ U,we have Z

Q

1

λϕθ2(y2t+y2xxxx) +λϕθ2y2xxx+λ3ϕ3θ2y2xx+λ5ϕ5θ2y2x+λ7ϕ7θ2y2 dx dt

≤C1 Z

Qθ2|Py|2dx dt+

Z

Qωλ7ϕ7θ2y2dx dt

.

(2.1)

Moreover, Z

Q

λ1t(T−t)θ2(y2t +y2xxxx) +λt1(T−t)1θ2y2xxx+λ3t3(T−t)3θ2y2xx +λ5t5(T−t)5θ2y2x+λ7t7(T−t)7θ2y2

dx dt

≤C2 Z

ω×(0,T)λ7θ2t7(T−t)7y2dxdt+

Z

Qθ2|Py|2dx dt

.

(2.2)

Remark 2.2. A Carleman estimate for the fourth order parabolic operator was previously ob- tained in [28]. Our Carleman estimate is a generalization to the result in [28]. More precisely, we can also obtain the estimate forR

Q 1

λϕθ2(y2t +y2xxxx) +λϕθ2y2xxx

dx dt. We only sketch the proof in the Appendix.

Now, we present a regularity result for the following system









yt+yxxxx+ay= g inQ, y(0,t) =0=y(1,t) in(0,T), yx(0,t) =0=yx(1,t) in(0,T), y(x, 0) =y0(x) in I.

(2.3)

Proposition 2.3.

(i) If g∈ L2(0,T;L2(I)),a∈ L(Q)and y0∈ L2(I),system(2.3)has a unique mild solution y in C([0,T];L2(I))∩L2(0,T;H02(I)).Moreover, there exists a constant C=C(T),such that

kykC([0,T];L2(I))∩L2(0,T;H20(I)) ≤CeC(kakL(Q)+1)

kgkL2(0,T;L2(I))+ky0kL2(I)

.

(ii) If g ∈L2(0,T;L2(I)),a ∈L(Q)and y0 ∈H02(I),system(2.3)has a unique mild solution y in C([0,T];H20(I))∩L2(0,T;H4(I)).Moreover, there exists a constant C=C(T),such that

kykC([0,T];H2

0(I))∩L2(0,T;H4(I)) ≤CeC(kakL(Q)+1)

kgkL2(0,T;L2(I))+ky0kH2 0(I)

.

Remark 2.4. By the classical semigroup theory, multipliers method and suitable energy esti- mates [19,24], we can obtain Proposition2.3.

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3 Proof of Theorem 1.2

Applying the classical estimates for the parabolic equation to the system (1.7)–(1.8), we can obtain the following lemma.

Lemma 3.1. System(1.7)–(1.8)has the following energy estimates (i)

Z

Ip2(t2)dx≤e2kbkL(Q)(t2t1) Z

Ip2(t1)dx, ∀t1 <t2; (ii)

kz(t)k2L2(I)

Z T

t e(2kakL(Q)+1)(st)kp(s)kL2(O)ds, ∀t ∈[0,T]. In particular, we have

Z

Ip2

t+ T 4

dx ≤ekbkL(Q)T2 Z

Ip2(t)dx, ∀t ∈ T

4,3T 4

, and hence,

Z

I×(T2,T)p2dx dt≤ekbkL(Q)T2 Z

I×(T4,3T4 )p2dx dt. (3.1) On the other hand,

Z T

t

kz(s)k2L2(I)ds≤ (T−t)e(2kakL(Q)+1)T2 Z T

t

kp(s)kL2(O)ds, ∀t ∈ T

2,T

,

thus Z

I×(T2,T)z2dxds≤ e(kakL(Q)+1)T Z

O×(T2,T)p2dxds. (3.2) By the same method as in [5, Lemma 2.4], a simple calculation yields

Lemma 3.2. Set m0 =min

x

e−eµ(ψ(x)+3)

and M0 =max

x

e−eµ(ψ(x)+3) . (i) Whenλ> 2M7T2

0,the function e

2λM0

T(Tt)(T−t)7 is decreasing in(0,T). (ii) Whenλ> 15T8m2

0,we haveλ8θ2t15(T−t)15≤230T14m08e8. In particular, we have that for anyt∈ (0, T2),

e

2λM0

t(Tt)t7(T−t)7 =e2λMTt0t7·e

2λM0

T(Tt)(T−t)7

≥e2λMTt0 T

2 7

·e

2λM0 T T2

T 2

7

=e2λMTt0 ·C(T). Proof of Theorem1.2

We first assume that p0 ∈ H02(I).

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According to Proposition 2.1, we obtain that there exists a positive λ0, such that when λλ0

Z

Qλ7θ2t7(T−t)7p2dxdt+

Z

Qλ5θ2t5(T−t)5p2xdx dt +

Z

Qλ3θ2t3(T−t)3p2xxdx dt+

Z

Qλ1θ2t1(T−t)1p2xxxdx dt

≤C Z

ω×(0,T)λ7θ2t7(T−t)7p2dx dt+

Z

Qθ2|bp|2dx dt

≤C Z

ω×(0,T)λ7θ2t7(T−t)7p2dx dt+1 2

Z

Qλ7θ2t7(T−t)7p2dx dt

and Z

Qλ7θ2t7(T−t)7z2dx dt+

Z

Qλ5θ2t5(T−t)5z2xdxdt +

Z

Q

λ3θ2t3(T−t)3z2xxdx dt+

Z

Q

λθ2t1(T−t)1z2xxxdx dt

≤C Z

ω×(0,T)

λ7θ2t7(T−t)7z2dx dt+

Z

Q

θ2|pχO−az|2dx dt

≤C Z

ω×(0,T)λ7θ2t7(T−t)7z2dx dt+1 2

Z

Qλ7θ2t7(T−t)7z2dx dt+

Z

Qθ2p2χOdx dt

.

Then we have Z

Qλ7θ2t7(T−t)7p2dx dt+

Z

Qλ5θ2t5(T−t)5p2xdx dt +

Z

Qλ3θ2t3(T−t)3p2xxdx dt+

Z

Qλθ2t1(T−t)1p2xxxdx dt

≤C Z

ω×(0,T)λ7θ2t7(T−t)7p2dx dt

(3.3)

and

Z

Qλ7θ2t7(T−t)7z2dx dt+

Z

Qλ5θ2t5(T−t)5z2xdx dt +

Z

Qλ3θ2t3(T−t)3z2xxdx dtdt+

Z

Qλθ2t1(T−t)1z2xxxdx dt

≤C Z

ω×(0,T)λ7θ2t7(T−t)7z2dx dt+

Z

Qθ2p2χOdx dt

.

(3.4)

Let us consider two open sets B1 and B2 such that B1 ⊂ B2ω∩ O, and let us set u=λ7θ2t7(T−t)7. Consider a functionξ1 ∈C0(I)such that 0≤ξ1 ≤1 in I,ξ1 =1 in B1, suppξ1⊂ B2ω∩ O, |ξ1x|

ξ1/21 ,|ξ1xx|

ξ1/21 ,|ξ1xxx|

ξ11/2 ,|ξ1xxxx|

ξ1/21 ∈ L(Q).

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From (3.3), we can deduce that Z

Qλ7θ2t7(T−t)7p2dx dt+

Z

Qλ5θ2t5(T−t)5p2xdx dt +

Z

Qλ3θ2t3(T−t)3p2xxdx dt+

Z

Qλθ2t1(T−t)1p2xxxdx dt

≤ C Z

B1×(0,T)λ7θ2t7(T−t)7p2dx dt

≤ C Z

O×(0,T)λ7θ2t7(T−t)7p2dx dt

≤ C Z

Q

ξ1up·pχOdx dt

= C Z

Qξ1up·(−zt+zxxxx+a(x,t)z)dx dt

= C Z

Q

zp·(ξ1u)t+ (a−b)zp·ξ1u+4zpxxx·(ξ1u)x+6zpxx·(ξ1u)xx +4zpx·(ξ1u)xxx+zp·(ξ1u)xxxxdx dt

=:C(I1+I2+I3+I4+I5+I6). Since

|ξ1u|=λ7e2λat7(T−t)7ξ1

|(ξ1u)t| ≤Cλ8e2λat9(T−t)9ξ1

|(ξ1u)x| ≤Cλ7e2λat7(T−t)7|ξ1x|+Cλ8e2λat8(T−t)8ξ1

|(ξ1u)xx| ≤Cλ7e2λat7(T−t)7|ξ1xx|+Cλ8e2λat8(T−t)8|ξ1x| +Cλ8e2λat8(T−t)8ξ1+Cλ9e2λat9(T−t)9ξ1

|(ξ1u)xxx| ≤Cλ7e2λat7(T−t)7(|ξ1xxx|+λt1(T−t)1|ξ1xx|

+λ2t2(T−t)2|ξ1x|+λ2t2(T−t)2|ξ1|+λt1(T−t)1|ξ1x| +λ3t3(T−t)3|ξ1|+λt1(T−t)1|ξ1|)

|(ξ1u)xxxx| ≤Ce2λa(λ9t9(T−t)9|ξ1xx|+λ10t10(T−t)10|ξ1x|

+λ11t11(T−t)11|ξ1|+λ8t8(T−t)8|ξ1xxx|+|ξ1xxxx|),

by the Cauchy–Schwartz inequality and following the ideas in [5], it holds that for sufficiently largeλ0

|I1|= Z

Qzp·(ξ1u)tdx dt

δ Z

Q

λ7θ2t7(T−t)7p2ξ1dx dt+C(δ)

Z

Q

λ9θ2t11(T−t)11z2ξ1dx dt,

|I2|= Z

Q

(a−b)zp·ξ1u dx dt

δ Z

Qλ7θ2t7(T−t)7p2ξ1dx dt+C(δ)

Z

Qλ7θ2t7(T−t)7z2ξ1dx dt,

|I3|= Z

Qzpxxx·(ξ1u)xdx dt

δ Z

Qλθ2t1(T−t)1p2xxxξ1dx dt+C(δ)

Z

Qλ15θ2t15(T−t)15z2χB2dx dt,

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|I4|= Z

Qzpxx·(ξ1u)xxdx dt

δ Z

Qλ3θ2t3(T−t)3p2xxξ1dx dt+C(δ)

Z

Qλ15θ2t15(T−t)15z2χB2dx dt,

|I5|= Z

Qzpx·(ξ1u)xxxdx dt

δ Z

Qλ5θ2t5(T−t)5p2xξ1dx dt+C(δ)

Z

Qλ15θ2t15(T−t)15z2χB2dx dt,

|I6|= Z

Qzp·(ξ1u)xxxxdx dt

δ Z

Qλ7θ2t7(T−t)7p2ξ1dx dt+C(δ)

Z

Qλ13θ2t13(T−t)13z2χB2dx dt with λλ0. Thus

Z

Qλ7θ2t7(T−t)7p2dx dt+

Z

Qλ5θ2t5(T−t)5p2xdx dt +

Z

Qλ3θ2t3(T−t)3p2xxdx dt+

Z

Qλ1θ2t1(T−t)1p2xxxdx dt

≤ C(I1+I2+I3+I4+I5+I6)

δ Z

Qλ7θ2t7(T−t)7p2ξ1dx dt+λ5θ2t5(T−t)5p2xξ1dx dt +

Z

Qλ3θ2t3(T−t)3p2xxξ1dx dt+

Z

Qλθ2t1(T−t)1p2xxxξ1dx dt

+C(δ)

Z

Q

λ15θ2t15(T−t)15z2χB2dx dt.

Then we have Z

Q

λ7θ2t7(T−t)7p2dx dt+

Z

Q

λ5θ2t5(T−t)5p2xdx dt +

Z

Qλ3θ2t3(T−t)3p2xxdx dt+

Z

Qλθ2t1(T−t)1p2xxxdx dt

≤C Z

Qλ15θ2t15(T−t)15z2χB2dx dt, namely,

Z

Qθ2t7(T−t)7p2dx dt ≤C Z

Qλ8θ2t15(T−t)15z2χB2dx dt. (3.5) From (3.4) and (3.5), we can deduce that for sufficient large λ0

Z

Qλ7θ2t7(T−t)7z2dx dt

≤C Z

B2×(0,T)λ7θ2t7(T−t)7z2dx dt+

Z

Qθ22Odx dt

≤C Z

B2×(0,T)λ7θ2t7(T−t)7z2dx dt+λ7 Z

Qθ2t7(T−t)72Odx dt

≤C Z

B2×(0,T)λ7θ2t7(T−t)7z2dx dt+

Z

Qλ15θ2t15(T−t)15z2χB2dx dt

≤C(T)

Z

Qλ15θ2t15(T−t)15z2χB2dx dt

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withλλ0. Namely Z

Qθ2t7(T−t)7z2dx dt≤ C(T)

Z

Qλ8θ2t15(T−t)15z2χB2dx dt. (3.6) Setλλ1:=max7T2

2M0,15T8m2

0,λ0 andMλ = 2λMT 0. On the one hand, according to Lemma 3.2, (3.6) and the definition ofθ, we have

Z

I×(0,T2)eMtλz2dx dt

≤C(T)

Z

I×(0,T2)θ2t7(T−t)7z2dx dt

≤C(T)

Z

Qθ2t7(T−t)7z2dx dt

≤C(T)

Z

B2×(0,T)λ8θ2t15(T−t)15z2dx dt.

On the other hand, from (3.1), (3.2) and (3.5), it holds that Z

I×(T2,T)

eMtλz2dx dt

Z

I×(T2,T)z2dx dt

≤eC(T)(kakL(Q)+1) Z

O×(T2,T)p2dx dt

≤eC(T)(kakL∞(Q)+1) Z

I×(T2,T)p2dx dt

≤eC(T)(kakL(Q)+kbkL(Q)+1) Z

I×(T4,3T4 )p2dx dt

≤eC(T)(kakL∞(Q)+kbkL∞(Q)+1) Z

I×(T4,3T4 )θ2t7(T−t)7p2dx dt

≤eC(T)(kakL(Q)+kbkL(Q)+1) Z

I×(0,T)θ2t7(T−t)7p2dx dt

≤eC(T)(kakL(Q)+kbkL(Q)+1) Z

B2×(0,T)λ8θ2t15(T−t)15z2dx dt.

Thus, in view of Lemma3.2, we have Z

QeMtλz2dx dt

=

Z

I×(0,T2)eMtλz2dx dt+

Z

I×(T2,T)eMtλz2dx dt

≤eC(T)(kakL(Q)+kbkL(Q)+1) Z

B2×(0,T)λ8θ2t15(T−t)15z2dx dt

≤eC(T)(kakL∞(Q)+kbkL∞(Q)+1) Z

B2×(0,T)z2dx dt.

(3.7)

Finally, settingλ= λ1in (3.7) and we define M = Mλ1.

By a density argument, (3.7) holds for the solution (p,z) of (1.7)–(1.8) if the initial data p0 ∈ L2(I). Indeed, we can choose a sequence {p0n} ⊂ H02(I)such that p0n → p0 in L2(I). By i) of Proposotion2.3, we obtain that R

QeMt z2ndx dt → R

QeMt z2dx dt and R

ω×(0,T)z2ndx dt →

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