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Infinitely many weak solutions for a fourth-order equation on the whole space

Mohammad Reza Heidari Tavani

B1

and Mehdi Khodabakhshi

2

1Department of Mathematics, Ramhormoz branch, Islamic Azad University, Ramhormoz, Iran

2Department of Mathematics and Computer Sciences, Amir Kabir University of Technology, Tehran, Iran

Received 30 June 2020, appeared 20 May 2021 Communicated by Gabriele Bonanno

Abstract. The existence of infinitely many weak solutions for a fourth-order equation on the whole space with a perturbed nonlinear term is investigated. Our approach is based on variational methods and critical point theory.

Keywords:weak solution, fourth-order equation, critical point theory, variational meth- ods.

2020 Mathematics Subject Classification: 34B40, 34B15, 47H14.

1 Introduction

In this paper we consider the following problem

u(x)−(q(x)u0(x))0+s(x)u(x) =λf(x,u(x)), a.e.x∈ R, (1.1) where λ is a positive parameter and q,s ∈ L(R) with q0 = ess infRq > 0 and s0 = ess infRs>0. Here the function f :R2Ris an L1-Carathéodory function.

As we know, differential equations have many applications in engineering and mechanical science. Many important engineering topics eventually lead to a differential equation. One of the most important and widely used types of such equations is the fourth-order differen- tial equation. These equations play an essential role in describing the large number of elastic deflections in beams. Due to the importance of these equations in applied sciences, many authors have studied different types of these equations and obtained important results. Re- search on the existence and multiplicity of solutions for different types of these equations can be seen in the work of many authors. For example, to study fourth-order two-point boundary value problems we refer the reader to references [3–5,8,10–12].

For instance in [3], the authors researched the following problem:

(u+Au00+Bu= λf(t,u), t ∈[0, 1],

u(0) =u(1) =u00(0) =u00(1) =0 (1.2)

BCorresponding author. Email: m.reza.h56@gmail.com

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where A and B are real constants and they achieved multiplicity results using variational methods and critical point theory. It should be noted that in the study of many important problems such as mathematical models of beam deflection, the differential equation is consid- ered at infinite interval. Also, because the operators used to solve equations such as (1.1) onR are not compact, so the study of such problems is very important. That is why some authors have turned their attention to the whole space. For example in [9], applying the critical point theory the author has studied the existence and multiplicity of solutions for the following problem:

u(x) +Au00(x) +Bu(x) =λα(x).f(u(x)), a.e.x ∈ R, (1.3) whereAis a real negative constant andBis a real positive constant,λis a positive parameter andα, f :RRare two functions such that α∈ L1(R), α(x)≥0, for a.e. x ∈R,α6≡0 and also f is continuous and non-negative.

In this work, using a critical point theorem obtained in [2] which we recall in the next section (Theorem 2.7), we establish the existence of infinitely many weak solutions for the problem (1.1).

2 Preliminaries

Let us recall some basic concepts.

Definition 2.1. A function f :R2Ris said to be an L1-Carathéodory function, if (C1) the functionx7→ f(x,t)is measurable for everyt ∈R,

(C2) the functiont7→ f(x,t)is continuous for almost everyx ∈R, (C3) for everyρ>0 there exists a functionlρ(x)∈ L1(R)such that

sup

|t|≤ρ

|f(x,t)| ≤lρ(x), for a.e.x∈R.

DenoteW02,2(R)is the closure ofC0(R)inW2,2(R)and according to the properties of the Sobolev spaces, we know thatW02,2(R) =W2,2(R), [1, Corollary 3.19].

We denote by| · |t the usual norm onLt(R), for allt ∈ [1,+]and it is well known that W2,2(R)is continuously embedded inL(R), [6, Corollary 9.13].

The Sobolev spaceW2,2(R)is equipped with the following norm kukW2,2(R)=

Z

R(|u00(x)|2+|u0(x)|2+|u(x)|2)dx 1/2

, for allu∈W2,2(R). Also, we considerW2,2(R)with the norm

kuk= Z

R(|u00(x)|2+q(x)|u0(x)|2+s(x)|u(x)|2)dx 1/2

, for allu∈W2,2(R). According to

(min{1,q0,s0})12kukW2,2(R)≤ kuk ≤(max{1,|q|,|s|})12kukW2,2(R), (2.1)

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the norm k · kis equivalent to the k · kW2,2(R) norm. Since the embeddingW2,2(R)→ L(R) is continuous hence there exists a constantCq,s(depending on the functions q and s) such that

|u|≤ Cq,skuk, ∀u∈W2,2(R).

In the following proposition, we provide an approximation for this constant.

Proposition 2.2. We have

|u| ≤ Cq,skuk (2.2)

where Cq,s = 1

4|q||s|

14 max{1,|q|,|s|}

min{1,q0,s0}

12 .

Proof. Letv∈W1,1(R), then from [7, p. 138, formula 4.64], one has

|v(x)| ≤ 1 2 Z

R|v0(t)|dt. (2.3)

Now if u ∈ W2,2(R) then v(x) = (|q||s|)12|u(x)|2 ∈ W1,1(R) and thus from (2.3) and Hölder’s inequality one has,

(|q||s|)12|u(x)|2

Z

R(|q||s|)12|u0(t)||u(t)|dt≤((|q|)12|u0|2)(|s|12|u|2) that is ,

|u(x)| ≤

1

|q||s| 14

((|q|)12|u0|2)12(|s|12|u|2)12. (2.4) Now according to xay1a ≤ aa(1−a)1a(x+y), x,y ≥ 0, 0 < a < 1 [7, p. 130, formula 4.47], and classical inequalitya1p +b1p ≤2

(p1)

p (a+b)1p, from (2.1) and (2.4) one has

|u(x)| ≤

1

|q||s| 14

1 2

12 1 2

12Z

R|q||u0(t)|2dt 12

+ Z

R|s||u(t)|2dt 12

1

|q||s| 14

1 2

12 1 2

12 (2)12

Z

R(|q||u0(t)|2+|s||u(t)|2)dt 12

1 4|q||s|

14Z

R(|u00(t)|2+|q||u0(t)|2+|s||u(t)|2)dt 12

1 4|q||s|

14

max{1,|q|,|s|} min{1,q0,s0}

12 Z

R(|u00(t)|2+|u0(t)|2+|u(t)|2)dt 12

which means that|u|≤ Cq,skuk.

LetΦ, Ψ:W2,2(R)→Rbe defined by Φ(u) = 1

2kuk2 = 1 2 Z

R(|u00(x)|2+q(x)|u0(x)|2+s(x)|u(x)|2)dx (2.5) and

Ψ(u) =

Z

RF(x,u(x))dx (2.6)

for everyu∈W2,2(R)where F(x,ξ) =Rξ

0 f(x,t)dtfor all (x,ξ)∈R2. It is well known thatΨ is a sequentially weakly upper semicontinuous whose differential at the pointu∈W2,2(R)is

Ψ0(u)(v) =

Z

Rf(x,u(x))v(x)dx.

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It is clear that Φ is a strongly continuous and coercive functional. Also since the norm k · k on Hilbert space W2,2(R)is a weakly sequentially lower semi-continuous functional in W2,2(R) therefore Φ is a sequentially weakly lower semicontinuous functional on W2,2(R). Moreover,Φis continuously Gâteaux differentiable functional whose differential at the point u∈W2,2(R)is

Φ0(u)(v) =

Z

R(u00(x)v00(x) +q(x)u0(x)v0(x) +s(x)u(x)v(x))dx for everyv∈W2,2(R).

Definition 2.3. Let Φ and Ψ be defined as above. Put Iλ = ΦλΨ, λ > 0. We say that u ∈ W2,2(R) is a critical point of Iλ when Iλ0(u) = 0{W2,2(R)}, that is, Iλ0(u)(v) = 0 for all v∈W2,2(R).

Definition 2.4. A functionu :RR is a weak solution to the problem (1.1) if u ∈ W2,2(R)

and Z

R u00(x)v00(x) +q(x)u0(x)v0(x) +s(x)u(x)v(x)−λf(x,u(x))v(x)dx=0, for allv∈W2,2(R).

Remark 2.5. We clearly observe that the weak solutions of the problem (1.1) are exactly the solutions of the equationIλ0(u)(v) =Φ0(u)(v)−λΨ0(u)(v) =0.

Lemma 2.6. Suppose that f : R2R is a non-negative L1-Carathéodory function. If u0 6≡ 0is a weak solution for problem(1.1)then u0is non-negative.

Proof. From Remark2.5, one has Φ0(u0)(v)−λΨ0(u0)(v) = 0 for allv ∈W2,2(R). Let v(x) =

¯

u0 =max{−u0(x), 0}and we assume that E={x ∈R:u0(x)<0}. Then we have Z

EEc

(u000(x)u¯000(x) +q(x)u00(x)u¯00(x) +s(x)u0(x)u¯0(x))dx=

Z

Rλf(x,u0(x))u¯0(x)dx,

that is Z

E

(−|u¯000(x)|2−q(x)|u¯00(x)|2−s(x)|u¯0(x)|2)dx≥0 which means thatku¯0k=0 and henceu0 ≥0 and the proof is complete .

Our main tool is the following critical point theorem.

Theorem 2.7([2, Theorem 2.1]). Let X be a reflexive real Banach space, letΦ,Ψ : X → Rbe two Gâteaux differentiable functionals such that Φis sequentially weakly lower semicontinuous, strongly continuous, and coercive andΨ is sequentially weakly upper semicontinuous. For every r > infXΦ, let us put

ϕ(r):= inf

uΦ1(]−∞,r[)

supvΦ1(]−∞,r[)Ψ(v)−Ψ(u) r−Φ(u)

and

γ:=lim inf

r→+ ϕ(r), δ := lim inf

r→(infXΦ)+ϕ(r). Then, one has

(a) for every r> infXΦand everyλ0, ϕ1(r)

, the restriction of the functional Iλ = ΦλΨto Φ1(]−∞,r[)admits a global minimum, which is a critical point (local minimum) of Iλin X.

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(b) Ifγ<+then, for eachλ0,γ1

, the following alternative holds:

either

(b1) Iλpossesses a global minimum, or

(b2) there is a sequence{un}of critical points (local minima) of Iλ such that

n→+limΦ(un) = +. (c) Ifδ< +then, for eachλ0,1δ

, the following alternative holds:

either

(c1) there is a global minimum ofΦwhich is a local minimum of Iλ, or

(c2) there is a sequence of pairwise distinct critical points (local minima) of Iλ, with limn→+Φ(un) =infXΦ, which weakly converges to a global minimum ofΦ.

3 Main results

Let

τ:= 540

86111(max{1,|q|,|s|})Cq,s2, (3.1) A:=lim inf

ρ→+

R

Rsup|t|≤ρF(x,t)dx

ρ2 , (3.2)

and

B:=lim sup

ρ→+

R58

3 8

F(x,ρ)dx

ρ2 . (3.3)

Now we formulate our main result as follows.

Theorem 3.1. Let f :R2Rbe an L1-Carathéodory function, and assume that (i) F(x,t)≥0for every(x,t)∈R×]0,38[∪]58, 1[,

(ii) A<τB, whereτ,A and B are given by(3.1),(3.2)and(3.3)respectively.

Then for every

λ

#(max{1,|q|,|s|}) B

86111 1080, 1

2A Cq,s2

"

the problem(1.1)admits a sequence of many weak solutions which is unbounded in W2,2(R).

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Proof. Fixλas in our conclusion. Our aim is to apply Theorem2.7, part(b)withX =W2,2(R), andΦ,Ψ are the functionals introduced in section 2. As shown in the previous section, the functionalsΦ and Ψ satisfy all regularity assumptions requested in Theorem 2.7. Now, we look on the existence of critical points of the functional Iλ in W2,2(R). To this end, we take {ρn}be a sequence of positive numbers such that limnρn= +and

nlim

R

Rsup|t|≤ρnF(x,t)dx ρ2n = A.

Setrn := 12 Cρn

q,s

2

, for everyn∈N.

For eachu∈W2,2(R)and bearing (2.2) in mind, we see that Φ1(]−∞,rn[) ={u∈W2,2(R);Φ(u)<rn}

=

u∈W2,2(R); 1

2kuk2 < 1 2

ρn

Cq,s 2

=u∈ X; Cq,skuk<ρnu∈W2,2(R); |u|ρn . Now, since 0∈Φ1(]−,rn[)then we have the following inequalities:

ϕ(rn) = inf

uΦ1(]−∞,rn[)

supvΦ1(]−∞,rn[)

R

RF(x,v(x))dx−R

RF(x,u(x))dx rnku2k2

≤ R

Rsup|t|≤ρnF(x,t)dx

rn =

R

Rsup|t|≤ρnF(x,t)dx

1 2

ρn

Cq,s

2

=2Cq,s2 R

Rsup|t|≤ρnF(x,t)dx ρn2 , for everyn∈N. Hence, it follows that

γ≤lim inf

n Φ(rn)≤2Cq,s2A< +,

because condition (ii)shows A < +∞. Now, we prove that the functional Iλ is unbounded from below. For our goal, let{ηn}be a sequence of positive numbers such that limnηn = +and

n→+lim R 58

3 8

F(x,ηn)dx

ηn2 = B. (3.4)

Let{vn}be a sequence inW2,2(R)which is defined by

vn(x):=









649ηn x234x

, if x∈0,38 , ηn, if x∈38,58

,

649ηn x254x+14, if x∈58, 1 ,

0, otherwise.

(3.5)

One can compute that

kvnkW2,2(R)

2 = 86111 540 ηn2, and so from (2.1) we have

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(min{1,q0,s0})86111

1080 ηn2Φ(vn)≤(max{1,|q|,|s|})86111

1080 ηn2. (3.6) Also, by using condition(i), we infer

Z

RF(x,vn(x))dx≥

Z 5

8 3 8

F(x,ηn)dx, for every n∈N. Therefore, we have

Iλ(vn) =Φ(vn)−λΨ(vn)≤(max{1,|q|,|s|})86111

1080 ηn2λ Z 58

3 8

F(x,ηn)dx, for every n∈N. IfB<+∞, let

e

(max{1,|q|,|s|}) λB

86111 1080, 1

. By (3.4) there isNe such that

Z 5

8 3 8

F(x,ηn)dx>eBηn2, (∀n> Ne). Consequently, one has

Iλ(vn)≤ (max{1,|q|,|s|})86111

1080 ηn2λeBηn2

= ηn2

(max{1,|q|,|s|})86111

1080 −λeB

, for every n> Ne. Thus, it follows that

nlimIλ(vn) =−∞.

If B= +∞, then consider

M > (max{1,|q|,|s|}) λ

86111 1080. By (3.4) there isN(M)such that

Z 5

8 3 8

F(x,ηn)dx> Mηn2, (∀n> N(M)). So, we have

Iλ(vn)≤ (max{1,|q|,|s|})86111

1080 ηn2λMηn2

= ηn2

(max{1,|q|,|s|})86111 1080 −λM

,

for every n> N(M). Taking into account the choice of M, also in this case, one has

nlimIλ(vn) =−∞.

Therefore according to Theorem2.7, the functional Iλ admits an unbounded sequence{un} ⊂ W2,2(R) of critical points. It means that, problem (1.1) admits a sequence of many weak solutions which is unbounded inW2,2(R).

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Now we present the following example to illustrate Theorem3.1.

Example 3.2. LetF :R2Rbe the function defined as F(x,t):=

t5 1cos(ln|t|)

1+x2 , if(x,t)∈R×R− {0} 0, if(x,t)∈R× {0} and therefore we have

f(x,t):=

5t4 1cos(ln|t|)

+t4sin(ln|t|)

1+x2 , if (x,t)∈R×R− {0}

0, if (x,t)∈R× {0}.

We observe that

A:=lim inf

ρ→+

R

Rsup|t|≤ρF(x,t)dx

ρ2 =0 (3.7)

and

B:=lim sup

ρ→+

R58

3 8

F(x,ρ)dx

ρ2 = +∞. (3.8)

So, by Theorem3.1, for everyλ∈(0,+)the problem

u(x)− (1+ex2)u0(x)0+ (π+tan1x)u(x)

=λ5u

(x)4 1cos(ln|u(x)|)

+u(x)4sin(ln|u(x)|)

1+x2 , a.e.x ∈ R,

(3.9)

has a sequence of weak solutions which is unbounded inW2,2(R).

Note that, as in the previous example, under appropriate conditions, the existence of infinitely many weak solutions for problem (1.1) will be guaranteed for anyλR+. For this case, the following result is a consequence of Theorem3.1.

Corollary 3.3. Suppose that f : R2R is an L1-Carathéodory function. Also, assume that the assumption (i)in Theorem 3.1 holds and A = and B = 0 where A and B are given by(3.2)and (3.3)respectively. Then, for everyλ>0,the problem(1.1)possesses a sequence of many weak solutions which is unbounded in W2,2(R).

A special case of Theorem3.1is given in the following corollary.

Corollary 3.4. Suppose that f : R2R is an L1-Carathéodory function. Also, assume that the assumption(i)in Theorem3.1holds and

(i1) (max{1,|q|,|s|})861111080 < B, (i2) A< 1

2Cq,s2. Then, the problem

u(x)−(q(x)u0(x))0+s(x)u(x) = f(x,u(x)), a.e. x ∈ R, (3.10) possesses a sequence of many weak solutions which is unbounded in W2,2(R).

Proof. The corollary is an immediate consequence of Theorem3.1whenλ=1.

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Remark 3.5. In Theorem 3.1, we can consider f(x,t) = β(x)g(t) where β,g : RR are two functions such that β ∈ L1(R), β ≥ 0 , for a.e. x ∈ R, β 6≡ 0 and also g is continuous and non-negative. We set G(t) = Rt

0g(ξ)dξ for all t ∈ R. Since G0(t) = g(t) ≥ 0 then G is non-decreasing function. Therefore (3.2) and (3.3) become the following simpler forms:

A:=lim inf

ρ→+

R

Rsup|t|≤ρF(x,t)dx

ρ2 =lim inf

ρ→+

G(ρ)|β|1

ρ2 (3.11)

and

B:=lim sup

ρ→+

R58

3 8

F(x,ρ)dx

ρ2 =lim sup

ρ→+

G(ρ)R58

3 8

β(x)dx

ρ2 . (3.12)

Now if we assume that A<τBwhere τ,AandBare given by (3.1), (3.11) and (3.12) respec- tively, then according to Theorem3.1 and Lemma2.6for every

λ

#(max{1,|q|,|s|}) B

86111 1080, 1

2A Cq,s2

"

the problem

u(x)−(q(x)u0(x))0+s(x)u(x) =λ β(x)g(u(x)), a.e. x ∈ R, (3.13) admits a sequence of many non-negative weak solutions which is unbounded inW2,2(R).

Using the conclusion (c) instead of (b) in Theorem 3.1, can be obtained a sequence of pairwise distinct weak solutions to the problem (1.1) which converges uniformly to zero. In this case, by replacing ρ → + with ρ0+, A and B will be converted to the following forms:

A0 :=lim inf

ρ0+

R

Rsup|t|≤ρF(x,t)dx

ρ2 (3.14)

and

B0 :=lim sup

ρ0+

R58

3 8

F(x,ρ)dx

ρ2 . (3.15)

Therefore, we can present the other main result of this section as follows.

Corollary 3.6. Let f :R2Rbe an L1-Carathéodory function, and assume that (i) F(x,t)≥0for every(x,t)∈R×0,38

58, 1 ,

(ii) A0 < τB0, whereτ,A0 and B0 are given by(3.1),(3.14)and(3.15)respectively.

Then for every

λ

#(max{1,|q|,|s|}) B0

86111 1080 , 1

2A0Cq,s2

"

the problem (1.1) admits a sequence of many weak solutions which strongly converges to zero in W2,2(R).

We present the following example to illustrate Corollary3.6.

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Example 3.7. Let α> 86111

π 6

120R58

38

ex2dx

−1≈ 2673 be a real number andF :R2Rbe a function defined by

F(x,t):=

(ex2t2(1+αcos2(1t)), if(x,t)∈R×]0,+[ 0, if(x,t)∈R×]−∞, 0]. FromF(x,t) =Rt

0 f(x,ξ)dξ we have f(x,t):=

(ex2 2t+2αtcos2(1t) +αsin(2t), if(x,t)∈R×]0,+[

0, if(x,t)∈R×]−∞, 0].

It is clear that f :R2Ris anL1-Carathéodory function.

Letq(x) =1+1+1x2 ands(x) =2+tanhx and therefore|q| =2 , q0=1 ,|s| =3 ,s0 =1 andτ= 120

6 86111. Putan= 2n+11

2 π andbn= 1 for every n∈N, one has A0 := lim inf

ρ0+

sup|t|≤ρt2 1+αcos2 1tR

Rex2dx ρ2

≤ lim

n

an2

1+αcos2

1 an

R

Rex2dx

an2 =√

π (3.16)

and

B0 := lim sup

ρ0+

R58

3 8

F(x,ρ)dx

ρ2 ≥ lim

n

bn2

1+αcos2

1 bn

R58

3 8

ex2dx bn2

= (1+a)

Z 5

8 3 8

ex2dx. (3.17)

Now, sinceα> 86111

π 6

120R58

38

ex2dx

−1, we have

A0 ≤√

π< 120

√6

86111(1+a)

Z 5

8 3 8

ex2dx≤ τB0

and so condition (ii) of the Theorem3.1 is satisfied. Now, according to the Theorem 3.1 for every

λ

# 86111

360(1+a)R58

38

ex2dx,1 3

r6 π

"

the problem

(u(x)− (1+1+1x2)u0(x)0+ (2+tanhx)u(x)

=λex2 2u(x) +2αu(x)cos2( 1

u(x)) +αsin( 2

u(x)), a.e. x ∈ R, (3.18) admits a sequence of many weak solutions which is converges uniformly to zero.

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4 Acknowledgments

The second author is sponsored by the National Science Foundation of Iran (INFS). Also the authors are very thankful for the many helpful suggestions and corrections given by the referees who reviewed this paper.

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