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volume 7, issue 3, article 79, 2006.

Received 03 March, 2006;

accepted 21 March, 2006.

Communicated by:I. Olkin

Abstract Contents

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Journal of Inequalities in Pure and Applied Mathematics

A VARIANCE ANALOG OF MAJORIZATION AND SOME ASSOCIATED INEQUALITIES

MICHAEL G. NEUBAUER AND WILLIAM WATKINS

Department of Mathematics California State University Northridge Northridge, CA 91330.

EMail:michael.neubauer@csun.edu EMail:bill.watkins@csun.edu URL:http://www.csun.edu/˜vcmth006

c

2000Victoria University ISSN (electronic): 1443-5756 064-06

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A Variance Analog of Majorization and Some Associated Inequalities

Michael G. Neubauer and William Watkins

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Abstract

We introduce a partial order, variance majorization, onRn, which is analogous to the majorization order. A new class of monotonicity inequalities, based on variance majorization and analogous to Schur convexity, is developed.

2000 Mathematics Subject Classification: Primary: 26D05, 26D07; Secondary:

15A42.

Key words: Inequality, Symmetric polynomial, Majorization, Schur convex, Variance.

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A Variance Analog of Majorization and Some Associated Inequalities

Michael G. Neubauer and William Watkins

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Contents

1 Introduction. . . 4

2 Majorization and Variance Majorization. . . 6

2.1 Definitions of Variance Majorization and Majorization 6 2.2 Least and Greatest Sequences with Respect to the Variance Majorization Order . . . 8

3 Variance Monotone Functions and Schur Convex Functions. 10 3.1 The Main Result . . . 10

3.2 Schur Convex Functions. . . 12

4 Some Variance Monotone and Schur Convex Functions. . . 14

4.1 Elementary Symmetric Functions . . . 14

4.2 Moment Functions. . . 15

4.3 Entropy Function. . . 17

4.4 Coordinates ofx . . . 17

5 RestrictingS(m, v)to an Interval. . . 20

6 Proofs . . . 22

6.1 Helmert basis . . . 22

6.2 Proof of Theorem 3.1 and Lemma 4.7. . . 25

6.3 Proof of Corollary 3.2. . . 30

6.4 Proof of Theorem 4.1 . . . 30

6.5 Proof of Lemma 5.1. . . 33

6.6 Proof of Lemma 2.1. . . 41

6.7 Example 5.1. . . 45 References

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A Variance Analog of Majorization and Some Associated Inequalities

Michael G. Neubauer and William Watkins

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1. Introduction

Let (x1, . . . , xn)and (y1, . . . , yn)be two sequences of real numbers in nonin- creasing order. The sequencexmajorizesyif

i

X

k=1

xk

i

X

k=1

yk,

for i = 1, . . . , n with equality for i = n. Majorization is a partial order on the set of nonincreasing sequences having the same sum and it plays a large role in the theory of inequalities dating back to the work of I. Schur [7]. In- deed a function F(x1, . . . , xn) of n real variables is said to be Schur convex if F(x) ≥ F(y) whenever the sequence x majorizes y. Marshall and Olkin [6] catalog many functions and results of this type with particular emphasis on statistical inequalities. As a simple example, take the product function F(x) = Qn

k=1xk. If x, y are n-tuples of nonnegative real numbers and if x majorizes y, then F(x) ≤ F(y). That is, −F is a Schur convex function. In particular, ify = (¯x, . . . ,x)¯ thenxmajorizesy and therefore the product ofn nonnegative numbers with fixed mean is maximized when all of them are equal to the meanx. Another way to state this well-known elementary result is that¯ the product of a sequence x of nonnegative reals with fixed mean x¯ attains a maximum when the variance ofxis zero.

Now suppose that the variance ofxis also fixed. In this paper, we define a partial order (variance majorization) on the set of sequences x having a fixed mean and a fixed variance. We obtain a monotonicity result similar to the one above for sequences in which one is variance-majorized by the other. In partic- ular the maximum value of the product of a sequence of nonnegative reals with

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A Variance Analog of Majorization and Some Associated Inequalities

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fixed mean and fixed variance is attained when the sequence takes on only two values α < β and the multiplicity of β is 1. This simple consequence of the main theorem is known as Cohn’s Inequality [1]: ifx1, . . . , xnare nonnegative reals then

n

Y

k=1

xk ≤αn−1β,

whereαandβare chosen so that the sequencesx= (x1, . . . , xn)and(α, . . . , α, β) have the same means and the same variances.

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A Variance Analog of Majorization and Some Associated Inequalities

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2. Majorization and Variance Majorization

LetI(Ist) be the set of nondecreasing (strictly increasing) sequences inRn: I={x∈Rn :x1 ≤x2 ≤ · · · ≤xn}

Ist ={x∈Rn :x1 < x2 <· · ·< xn}.

The variance majorization order involves the variances of leading subsequences of x ∈ I. So let x[i] = (x1, . . . , xi)be the leading subsequence ofx for i = 1, . . . , n. Note thatx[i]consists of thei smallest components ofx. We denote the mean ofx[i]by

x[i] = (1/i)

i

X

k=1

xk, and the variance ofx[i]by

Var(x[i]) = (1/i)

i

X

k=1

(xk−x[i])2.

2.1. Definitions of Variance Majorization and Majorization

Definition 2.1 (Variance Majorization). Let x = (x1, . . . , xn) and y = (y1, . . . , yn)be sequences of real numbers in Isuch thatx¯ = ¯y and Var(x) = Var(y). We say thatxis variance majorized byy(oryvariance majorizesx), if

Var(x[i])Var(y[i]), fori= 2, . . . n. We writexvm≺ yoryvm x.

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A Variance Analog of Majorization and Some Associated Inequalities

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For fixed mean m and variance v ≥ 0, variance majorization is a partial order on the set

S(m, v) = {x∈I: ¯x=m,Var[x] =v},

which is the intersection of Iwith the sphere in Rn centered atm(1,1, . . . ,1) with radius √

nv, and the hyperplane throughm(1,1, . . . ,1)orthogonal to the vector(1,1, . . . ,1).

By contrast, majorization is a partial order of the set of nonincreasing se- quences

D={z∈R:z1 ≥z2 ≥ · · · ≥zn}.

Definition 2.2 (Majorization). Let x = (x1, . . . , xn)andy = (y1, . . . , yn)be sequences inDsuch thatx¯= ¯y. We say thatxis majorized byy(orymajorizes x), if

x[i]≤y[i], fori= 1, . . . , n. In this case we writexmaj≺ y.

The definition of majorization is usually given in this equivalent form:

i

X

k=1

xk

i

X

k=1

yk, fori= 1, . . . , nwith equality fori=n.

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A Variance Analog of Majorization and Some Associated Inequalities

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2.2. Least and Greatest Sequences with Respect to the Variance Majorization Order

Returning now to the variance majorization order, there is a least element and a greatest element inS(m, v)for eachmandv ≥0.

Lemma 2.1. Letmandv ≥0be real numbers and let xmin = (α1, . . . , α1, β1) xmax= (α2, β2, . . . , β2), where

α1 =m−p

v/(n−1), β1 =m+p

(n−1)v, α2 =m−p

(n−1)v, β2 =m+p

v/(n−1).

Thenxmin, xmax ∈S(m, v)and

xmin vm≺ xvm≺ xmax, for allx∈S(m, v).

Figure1shows the Hasse diagram for the variance majorization partial order for all integral sequences of length six with sum 0 and sum of squares equal to 30. In this case,xmin = (−1,−1,−1,−1,−1,5)andxmax= (−5,1,1,1,1,1).

By contrast, the least and greatest elements inD∩ {x: ¯x=m}with respect to the majorization order are(¯x, . . . ,x)¯ and(n¯x,0, . . . ,0).

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A Variance Analog of Majorization and Some Associated Inequalities

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http://jipam.vu.edu.au

Variance-majorization 5

8-1,-1,-1,-1,-1, 5<

8-2,-2,-1,-1, 2, 4< 8-2,-2,-2, 1, 1, 4<

8-3,-2, 0, 0, 1, 4<

8-2,-2,-2, 0, 3, 3<

8-3,-1,-1,-1, 3, 3<

8-4,-1, 0, 0, 2, 3<

8-3,-3, 1, 1, 1, 3< 8-3,-3, 0, 2, 2, 2<

8-4,-1,-1, 2, 2, 2< 8-4,-2, 1, 1, 2, 2<

8-5, 1, 1, 1, 1, 1<

Figure 1: Variance majorization partial order for integral sequences inS(0,6)

Figure 1: Variance majorization partial order for integral sequences inS(0,30).

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A Variance Analog of Majorization and Some Associated Inequalities

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3. Variance Monotone Functions and Schur Convex Functions

LetI be a closed interval inRand letF(x1, . . . , xn)be a real-valued function defined onI∩In.

Definition 3.1 (Variance Monotone). The function F is variance monotone increasing onI∩Inif

xvm≺ y =⇒ F(x)≤F(y),

for allx, y ∈ I∩In. If−F is variance monotone increasing, we say thatF is variance monotone decreasing.

Definition 3.2 (Schur Convex). The functionF is Schur convex onD∩Inif xmaj≺ y =⇒ F(x)≤F(y),

for allx, y ∈D∩In.

3.1. The Main Result

The next theorem is the main result.

Theorem 3.1. Let I be a closed interval in Rn, and let F(z1, . . . , zn) be a continuous, real-valued function onI∩Inthat is differentiable on the interior ofI∩Inwith gradient∇F(z) = (F1(z), . . . , Fn(z)). Suppose that

(3.1) F2(z)−F1(z)

z2−z1 ≥ F3(z)−F2(z)

z3−z2 ≥ · · · ≥ Fn(z)−Fn−1(z) zn−zn−1

,

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A Variance Analog of Majorization and Some Associated Inequalities

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for allz ∈Ist∩In. ThenF is variance monotone increasing onI∩In, that is xvm≺ y =⇒ F(x)≤F(y).

for allx, y ∈I∩In.

For functions of the formF(z) =φ(x1) +· · ·+φ(xn), Theorem3.1special- izes to the following corollary:

Corollary 3.2. Let φ(t) be a continuous, real-valued function on a closed in- tervalI such thatφis twice-differentiable on the interior ofI andφ00 is nonin- creasing. Then the function

F(x1, . . . , xn) =φ(x1) +· · ·+φ(xn)

is variance monotone increasing on the set of nondecreasing sequences inIn. That is,

xvm≺ y =⇒ φ(x1) +· · ·+φ(xn)≤φ(y1) +· · ·+φ(yn), for allx, y ∈I∩In.

It turns out thatS(m, v)⊂Inwhen the interval I =h

m−p

(n−1)v, m+p

(n−1)v)i

(see Corollary 4.8). Thus the sequences xmax and xmin (described in Lemma 2.1) are in In. So, if F is variance monotone increasing on I∩In, then the maximum and minimum values ofF are attained atxmaxandxmin. This means we can boundF(x)by expressions involving only the mean and variance ofx:

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Corollary 3.3. Letmandv ≥0be real numbers and I =

h

m−p

(n−1)v, m+p

(n−1)v i

. LetF be a variance monotone increasing function onI∩In. Then

F(α1, . . . , α1, β1)≤F(x)≤F(α2, β2, . . . , β2), for allx∈S(m, v), whereα1, β1, α2, β2are defined as in Lemma2.1.

3.2. Schur Convex Functions

By comparison, the following theorem by Schur is the result analogous to The- orem3.1for majorization. It plays the central role in the theory of majorization inequalities:

Theorem 3.4 ([7]). Let F(z) be a continuous, real-valued function onDthat is differentiable on in the interior ofD. Then

xmaj≺ y =⇒ F(x)≤F(y), for allx, y ∈Dif and only if

(3.2) F1(z)≥F2(z)≥ · · · ≥Fn(z), for allz in the interior ofD.

The result analogous to Corollary 3.2 for majorization is known as Kara- mata’s Theorem:

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Corollary 3.5 ([4]). Let φ be a continuous, real-valued function on a closed intervalI such thatφ is twice differentiable on the interior ofI andφ00 is non- negative. Then

xmaj≺ y =⇒ φ(x1) +· · ·+φ(xn)≤φ(y1) +· · ·+φ(yn), for allx, y ∈D∩In.

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4. Some Variance Monotone and Schur Convex Functions

In this section, we give a short list of some common functions that are monotone in both the regular majorization and variance majorization orders. And we give as corollaries some samples of the kinds of inequalities one can obtain from Corollary3.3.

4.1. Elementary Symmetric Functions

Let Ek(z)denote the kth elementary symmetric function of the sequencez = (z1, . . . , zn)∈Rn:

Ek(z) = X

zi1zi2· · ·zik,

where the sum is taken over all sets ofkindices with1≤i1 <· · ·< ik ≤n.

Theorem 4.1. LetEkbe thekth elementary symmetric function. Then xvm≺ y =⇒ Ek(y)≤Ek(x),

xvm≺ y =⇒ Ek+1(x)

Ek(x) ≤ Ek+1(y) Ek(y) , for allx, y ∈I∩[0,∞)n.

The next corollary is obtained from Corollary3.3by evaluating the elemen- tary symmetric functionEkatxminandxmax.

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Corollary 4.2. Letx ∈ I∩[0,∞)n. ThenA(v, m, k) ≤Ek(x)≤ B(v, m, k), where

A(v, m, k) =Ek(xmax) = n

k m+

r v n−1

k−1

m−(k−1) r v

n−1

B(v, m, k) =Ek(xmin) = n

k m−

r v n−1

k−1

m+ (k−1) r v

n−1

The inequality analogous to Theorem4.1for (regular) majorization is given next:

Theorem 4.3 ([6, p. 80]).

xmaj≺ y =⇒ Ek(y)≤Ek(x) xmaj≺ y =⇒ Ek+1(y)

Ek(y) ≤ Ek+1(x) Ek(x) , for allx, y ∈D∩[0,∞)n.

4.2. Moment Functions

Letpbe a positive real number and letφ(t) = tp. Thepth moment function of z ∈[0,∞)nis given by

Mp(z) =z1p+· · ·+zpn.

The following results are applications of Corollaries3.5and3.2:

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Theorem 4.4. LetMp be thepth moment function. Then

xmaj≺ y =⇒ Mp(x)≤Mp(y), forp∈(−∞,0]∪[1,∞) xmaj≺ y =⇒ Mp(y)≤Mp(x), forp∈[0,1],

for allx, y ∈D∩[0,∞)nand

xvm≺ y =⇒ Mp(x)≤Mp(y), forp∈(−∞,0]∪[1,2]

xvm≺ y =⇒ Mp(y)≤Mp(x), forp∈[0,1]∪[2,∞), for allx, y ∈I∩[0,∞)n.

Again we obtain bounds on Mp(x), which depend only on the mean and variance ofx, from Corollary3.3:

Corollary 4.5. Letx∈I∩[0,∞)nwith meanmare variancev. Let A(m, v, p)=Mp(xmin) =(n−1)

m−p v n−1

p

+

m+p

(n−1)vp

B(m, v, p)=Mp(xmax)=

m−p

(n−1)vp

+ (n−1)

m+p v

n−1

p

. Then

A(m, v, p)≤Mp(x)≤B(m, v, p), forp∈(−∞,0)∪[1,2]

and

B(m, v, p)≤Mp(x)≤A(m, v, p), forp∈[0,1]∪[2,∞).

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4.3. Entropy Function

The entropy function is defined forx∈[0,∞)nby

H(x) =−(x1logx1 +· · ·+xnlogxn).

Letting φ(t) = −tlogt, we have φ00(t) = −1/t, which is nonpositive and increasing on [0,∞). Thus −φ satisfies the conditions of Corollaries 3.2 and 3.5. Thus we have the following inequalities:

Theorem 4.6. LetHbe the entropy function. Then xvm≺ y =⇒ H(y)≤H(x), for allx, y ∈I∩[0,∞)n, and

xmaj≺ y =⇒ H(y)≤H(x), for allx, y ∈D∩[0,∞)n.

4.4. Coordinates of x

The smallest and the largest coordinates of a sequence are variance monotone decreasing.

Lemma 4.7. Letx, y ∈I. Then

xvm≺ y =⇒ x1 ≥y1 andxn≥yn.

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We call this result a lemma because it is a part of the proof of Theorem3.1 rather than a consequence of it.

When combined with Corollary3.3, Lemma4.7gives bounds for the small- est and largest coordinates of a sequence inS(m, v)in terms ofmandv:

Corollary 4.8. Letx= (x1, . . . , xn)be a sequence inS(m, v). Then m−p

(n−1)v ≤ x1 ≤ m−p

v/(n−1) m+p

v/(n−1) ≤ xn ≤ m+p

(n−1)v.

Applying Corollary4.8to the eigenvalues of a symmetric matrix, we recover an equivalent form of an inequality of Wolkowicz and Styan [8, Theorem 2.1]

that bounds the maximum and minimum eigenvalues by expressions involving only the trace and Euclidean norm of the matrix:

Corollary 4.9. Let Gbe a symmetric matrix with eigenvaluesλ1 ≤ · · · ≤ λn. Then

tr(G)

n + n1n−1p

n||G||2−(tr(G))2 ≤λn≤ tr(G)

n +

n−1 n

pn||G||2−(tr(G))2 tr(G)

n

n−1 n

pn||G||2−(tr(G))2 ≤λ1 ≤ tr(G)

nn1n−1p

n||G||2−(tr(G))2. Corollary4.9 follows from the fact that the mean m and variance v of the eigenvalues can be expressed in terms of the trace and Euclidean norm||G||of

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Gas follows:

m= tr(G) n v = 1

n X

i

i−m)2

= 1 n

X

i

λ2i −2mλi+m2

!

= 1

n(tr(G2)−nm2)

= 1

n2 n||G||2 −tr(G)2 .

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5. Restricting S(m, v) to an Interval

Lemma 2.1 guarantees that there is a least and a greatest element in S(m, v) with respect to the variance majorization order. Now we restrict the setS(m, v) to an intervalI = [m−δ, m+β], withδ, β ≥0, containingm. From Corollary 4.8, we have

h

m−p

v/(n−1), m+p

v/(n−1)in

⊂S(m, v)⊂h

m−p

(n−1)v, m+p

(n−1)vin

. So if eitherδ, β <p

v/(n−1), thenS(m, v)∩In=∅. However, ifS(m, v)∩ Inis not empty, then it contains a least element, but it may not contain a greatest element.

Lemma 5.1. Let m and v ≥ 0 be real numbers. Let I be the interval I = [m−δ, m+β]such thatS(m, v)∩Inis not empty. Then there exist unique real numbersm−δ≤α≤γ < m+βand an integer1≤j ≤n−1such that the sequence

xmin = (

j

z }| { α, . . . , α, γ,

n−j−1

z }| {

m+β, . . . , m+β)∈S(m, v)∩In. Moreoverxmin vm≺ xfor allx∈S(m, v)∩In.

Example 5.1. Let n = 5. The least element in S(0,1944/5) ∩ [−36,24]5 is (−18,−18,−12,24,24). There is no greatest element in S(0,1944/5)∩ [−36,24]5. See Section6.7.

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The situation for restricting the sequences to a closed interval is a little different for majorization. There is always a least element and a greatest in D∩[m, M]n. The sequence(¯x, . . . ,x)¯ ∈D∩[m, M]nis the least element. The greatest element with respect to majorization takes at most three values for its coordinates, two of which are the end points of the closed interval. That is, the greatest element in for majorization inD∩[m, M]nis of the form

(M, . . . , M, θ, m, . . . , m).

A discussion of restricting the majorization order to an interval is given in [5] and [6, page 132].

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6. Proofs

The main technique used in the proofs is to express the sequences inIas linear combinations of a special basis forRn, the so-called Helmert basis.

6.1. Helmert basis

The purpose of this section is to describe the relationship between the coordi- nates of ann-tuplex∈Rnand the coordinates ofxwith respect to the so-called Helmert basis forRn(see [6, p. 47] for a discussion of the Helmert basis). The Helmert basis forRnis defined as follows:

wT0 = 1

√n(1,1, . . . ,1) wT1 = 1

√2(−1,1,0, . . . ,0) wT2 = 1

√6(−1,−1,2,0, . . . ,0) ...

wTi = 1 pi(i+ 1)(

i

z }| {

−1, . . . ,−1, i,0, . . . ,0) ...

wTn−1 = 1

p(n−1)n(−1, . . . ,−1, n−1).

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J. Ineq. Pure and Appl. Math. 7(3) Art. 79, 2006

It is clear that {w0, w1, . . . , wn−1}is an orthonormal basis forRn. Thus every vectorx∈Rnis a linear combinationx=Pn−1

k=0akwk. The Helmert coefficient a0 is determined by the mean x¯ of the sequence x. Specifically, a0 = √

nx.¯ The other Helmert coefficients, a1, . . . , an−1 are related to the variance, partial variances, and order of the coordinates ofx.

Lemma 6.1. Letxbe a sequence of real numbers withx=Pn−1

k=0akwk. Then Var(x[i]) = 1

i(a21+· · ·+a2i−1), fori= 2, . . . , n. In particular,

Var(x) = 1

n(a21+· · ·+a2n−1).

Proof. Sinceak=x·wk,

i−1

X

k=1

a2k=x

i−1

X

k=1

wTkwk

! xT

=x((Ii−(1/i)Ji)⊕0n−i)xT

=

i

X

k=1

x2k−(1/i)(

i

X

k=1

xk)2

!

=iVar(x[i]).

Thei×iidentity matrix is denoted byIi andJi denotes thei×imatrix all of whose entries are one. The fact thatPi−1

k=1wTkwk =Ii−(1/i)Jifollows from a simple inductive argument.

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A Variance Analog of Majorization and Some Associated Inequalities

Michael G. Neubauer and William Watkins

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J. Ineq. Pure and Appl. Math. 7(3) Art. 79, 2006

Letx = P

aiwi. In the next definition and lemma, we give necessary and sufficient conditions on the sequence (a1, . . . , an−1) for the sequence x to be nondecreasing. (Clearly, the coefficienta0does not influence the relative order- ing of the coordinates ofx.)

Definition 6.1 (Admissible Sequence). Letα= (α1, . . . , αn−1)be a sequence of nonnegative real numbers. Thenαis admissible if

(6.1) (i−1)iαi−1 ≤i(i+ 1)αi, for2≤i≤n−1.

Lemma 6.2. Letx= (x1, . . . , xn)be a vector inRnanda0, . . . , an−1be scalars such thatx=Pn−1

i=0 aiwi. The following conditions are equivalent:

1. xis nondecreasing.

2. ai ≥ 0, for i = 1, . . . , n−1, and the sequence a(2) = (a21, . . . , a2n−1)is admissible.

3. the kth component of ai−1wi −aiwi−1 is nonnegative for allk 6= i and nonpositive fork =i.

Proof. Let1≤i≤n−1. Thenx2−x1 =√

2a1, and xi+1−xi = iai

pi(i+ 1) − (i−1)ai−1

p(i−1)i − ai pi(i+ 1)

!

= (i+ 1)ai

pi(i+ 1) − (i−1)ai−1

p(i−1)i

= 1 i

pi(i+ 1)ai−p

(i−1)iai−1

, (6.2)

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A Variance Analog of Majorization and Some Associated Inequalities

Michael G. Neubauer and William Watkins

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J. Ineq. Pure and Appl. Math. 7(3) Art. 79, 2006

fori ≥ 2. Thusxis nondecreasing if and only ifai ≥ 0, fori = 1, . . . , n−1 anda(2)is admissible. So Conditions1and2are equivalent.

Now let(ai−1wi−aiwi−1)kbe thekcomponent ofai−1wi−aiwi−1. Then

(6.3) (ai−1wi−aiwi−1)k =













−√ai−1

i(i+1) +√ai

(i−1)i , ifk < i,

−√ai−1

i(i+1)(i−1)ai−1

(i−1)i , ifk =i,

iai−1

i(i+1) , ifk =i+ 1,

0 , ifk > i+ 1.

To prove that Condition 2 implies Condition 3, suppose that ai ≥ 0 for i = 1, . . . , n−1and thata(2)is admissible. It is clear from Equation (6.3) that (ai−1wi−aiwi−1)k ≥0for allk 6=iand that(ai−1wi−aiwi−1)i ≤0.

Conversely, suppose that Condition3holds. Withk = 3, i = 2in Equation (6.3), we geta1 ≥ 0. Withk = 1 < iwe get thata(2) is admissible andai ≥ 0 for alli. Thus Condition2holds.

6.2. Proof of Theorem 3.1 and Lemma 4.7

Let F be a differentiable, real-valued function onI∩In satisfying Inequality (3.1). Let x, y be nondecreasing sequences in In such thatx¯ = ¯y, Var(x) = Var(y)andxvm≺ y. Let

x=

n−1

X

k=0

akwk, y=

n−1

X

k=0

bkwk,

(26)

A Variance Analog of Majorization and Some Associated Inequalities

Michael G. Neubauer and William Watkins

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J. Ineq. Pure and Appl. Math. 7(3) Art. 79, 2006

for scalarsak, bk,k = 0, . . . , n−1, and let

a(2) = (a21, . . . , a2n−1), b(2) = (b21, . . . , b2n−1).

Sincex¯= ¯y, we havea0 =b0. By Lemma6.2,ak, bk ≥0fork = 1, . . . , n−1, a(2)andb(2)are admissible, and by Lemma6.1

(6.4)

i

X

k=1

a2k

i

X

k=1

b2k,

for1≤i≤n−1with equality in Inequality (6.4) fori=n−1since Var(x) = Var(y).

Next define a pathc(t) = (c0, c(t)1, . . . , c(t)n−1)fromatob byc0 = a0 = b0, and

c(t)k = q

(1−t)a2k+tb2k,

for t ∈ [0,1]and k = 1, . . . , n−1. Then c(t)(2) = (1 −t)a(2) +tb(2), from which it follows thatc(2)is admissible and that

i

X

k=1

a2k

i

X

k=1

c(t)2k

i

X

k=1

b2k, fori= 1, . . . , n−1.

Now define a pathz(t)fromxtoyby z(t) = a0w0+

n−1

X

k=1

c(t)kwk.

(27)

A Variance Analog of Majorization and Some Associated Inequalities

Michael G. Neubauer and William Watkins

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Sincec(t)k ≥0andc(t)(2) is admissible,z(t)is a nondecreasing sequence.

Letj be the smallest index for whichaj 6= bj. Thenc(t)k = ak fork < j andc(t)j >0fort >0. It is easy to verify thatc0(t)k = (b2k−a2k)/c(t)k(unless c(t)k = 0). Thus the tangent vectorz0(t)is given by

z0(t) =

n−1

X

k=j

b2k−a2k c(t)k wk (6.5)

= (b2j −a2j) wj

cj − wj+1 cj+1

+ (b2j+1+b2j+2−a2j+1−a2j+2)

wj+2 cj+2

−wj+3 cj+3

+· · ·+ b21+b22+· · ·+b2n−1

−a21−a22− · · · −a2n−1

wn−2

cn−2

− wn−1

cn−1

,

for t > 0. It follows from Inequality (6.4) that z0(t) is a nonnegative linear combination of the vectors wci−1

i−1wci

i, fori=j + 1, . . . , n−1.

We now show thatz(t)∈ Infor allt ∈ [0,1]. Indeed, both the first and the last coordinates ofz(t)are nonincreasing functions oft. Thus

y1 =z(1)1 ≤z(t)1 ≤z(t)2 ≤ · · · ≤z(t)n≤z(0)n=xn.

Sincey1, xn ∈I,z(t)∈Inand thusF(z(t))is defined for allt∈[0,1]. To see thatz(t)1andz(t)nare decreasing, we examine the first and last coordinates of

(28)

A Variance Analog of Majorization and Some Associated Inequalities

Michael G. Neubauer and William Watkins

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J. Ineq. Pure and Appl. Math. 7(3) Art. 79, 2006

the vectors wci−1

i−1wci

i. The first coordinate is

−1 p(i−1)ici−1

+ 1

pi(i+ 1)ci,

which is nonpositive sincec(2) is an admissible sequence. Thusz0(t)1 ≤ 0and z(t)1 is nonincreasing int. This proves the first part of Lemma4.7.

The last coordinate of wci−1

i−1wci

i is zero unlessi=n−1and in that case it is

−(n−1) p(n−1)ncn−1

,

which is also nonpositive. Thus z(t)n is nonincreasing. This proves the other part of Lemma4.7.

Finally to prove thatF(z(t))is an increasing function int, we show that dF

dt =∇F ·z0(t)≥0.

In view of Equation (6.5), it suffices to show that

∇F ·

wi−1

ci−1

− wi

ci

≥0, fori=j + 1, . . . , n−1.

Sincewkis orthogonal to the all-ones vectore,

∇F ·

wi−1

ci−1

−wi ci

= (∇F −Fie)·

wi−1

ci−1

− wi ci

.

(29)

A Variance Analog of Majorization and Some Associated Inequalities

Michael G. Neubauer and William Watkins

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For eachi= 1, . . . , n−1define a functionKionIst∩Inby Ki(z) = Fi+1(z)−Fi(z)

zi+1−zi . Now let i < j. Then Fj(z)−Fz i(z)

j−zi is a convex combination of Kk(z) for k = i, . . . , j−1:

Fj(z)−Fi(z) zj −zi =

j−1

X

k=i

zk+1−zk

zj−zi Kk(z).

Thus by Condition (3.1),

Fj(z)−Fi(z)

zj−zi ≤Ki(z) and so

Fj(z)−Fi(z)≤(zj−zi)Ki(z) for alli < j andz ∈Ist∩In.

Sincec(t)(2)is an admissible sequence, Lemma6.2guarantees that all com- ponents of wci−1

i−1wci

i are nonpositive except theith component. Of course the ith component of∇F −Fieis zero. It follows that

(∇F −Fie)·

wi−1

ci−1

− wi ci

≥Ki(z)(z−zke)·

wi−1

ci−1

− wi ci

=Kk(z)z·

wi−1

ci−1

− wi ci

= 0.

(30)

A Variance Analog of Majorization and Some Associated Inequalities

Michael G. Neubauer and William Watkins

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J. Ineq. Pure and Appl. Math. 7(3) Art. 79, 2006

The last equality holds becausez =Pn−1

k=j ckwkis clearly orthogonal to wci−1

i−1

wi

ci.

We have shown that dFdt ≥ 0, forz ∈ Ist∩In andt ∈ (0,1). ThusF(z(t)) is an increasing function oft. SoF(x) =F(z(0))≤F(z(1)) =F(y).

By the continuity ofF,F is variance monotone increasing onI∩In.

6.3. Proof of Corollary 3.2

Let φ(t)be a continuous, real-valued function on a closed interval I such that φ(t)is twice-differentiable on the interior ofI andφ00(t)is nonincreasing onI.

Let z be an increasing sequence inIn. Let ibe an integer satisfyng 1 ≤ i ≤ n−1. By the mean-value theorem, there existsξiin the intervalzi < ξi < zi+1 such that

φ0(zi+1)−φ0(zi)

zi+1−zi00i).

Inequality (3.1) follows sinceξ1 ≤ ξ2 ≤ · · · ≤ ξn−1, φ00 is nonincreasing, and Fi(z) =φ0(zi).

6.4. Proof of Theorem 4.1

Since E2(z)andE1(z)are constant on S(m, v), we assume that k ≥ 3. Leti be an integer satisfying 1 ≤ i ≤ n −1 and let Ek(i,i+1) be the kth elementary symmetric polynomial of then−2variablesz1, z2, . . . , zi−1, zi+2, . . . , zn. Then

Ek(z) =Ek(i,i+1)+ (zi+zi+1)Ek−1(i,i+1)+zizi+1Ek−2(i,i+1).

(31)

A Variance Analog of Majorization and Some Associated Inequalities

Michael G. Neubauer and William Watkins

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Thus ∂Ek(z)

∂zi+1 − ∂Ek(z)

∂zi =−(zi+1−zi)Ek−2(i,i+1), and so

1 zi+1−zi

∂Ek(z)

∂zi+1 − ∂Ek(z)

∂zi

=−Ek−2(i,i+1),

for all z ∈ I∩[0,∞]n. But the sequence z is nondecreasing so Ek−2(i−1,i) ≥ Ek−2(i,i+1) for i = 1, . . . , n − 1. It follows from Theorem 3.1 that −Ek(z) is variance monotone increasing. Thus Ek(z) is variance monotone decreasing.

This proves the first inequality in Theorem4.1.

To prove that the function F(z) = Ek+1(z)/Ek(z) is variance monotone increasing, we must show that Inequality (3.1) holds. It suffices to show that

F2(z)−F1(z)

z2−z1 ≥ F3(z)−F2(z) z3−z2 .

We writeEkfor thekth elementary symmetric function ofz1, . . . , znandEk0 for thekth elementary symmetric function ofz4, . . . , zn. Then

(6.6) Ek=Ek0 + (z1+z2+z3)Ek−10 + (z1z2+z1z3+z2z3)Ek−20 +z1z2z3Ek−30 . It follows that

F1 = ∂

∂z1

Ek+1 Ek

= 1

Ek2[EkEk0 −Ek+1Ek−10 + (z2+z3)(EkEk−10 −Ek+1Ek−20 ) +z2z3(EkEk−20 −Ek+1Ek−30 )].

(32)

A Variance Analog of Majorization and Some Associated Inequalities

Michael G. Neubauer and William Watkins

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J. Ineq. Pure and Appl. Math. 7(3) Art. 79, 2006

Thus

F2−F1

z2−z1 =− 1 Ek2

EkEk−10 −Ek+1Ek−20 +z3(Ek0Ek−20 −Ek+1Ek−30 ) . Similarly,

F3−F2

z3−z2 =− 1 Ek2

EkEk−10 −Ek+1Ek−20 +z1(Ek0Ek−20 −Ek+1Ek−30 ) , so that

F2−F1

z2−z1 − F3−F2

z3−z2 = z3−z1

Ek2 (EkEk−20 −Ek+1Ek−30 ).

Sincez3−z1andEk2are positive, it remains to show thatEkEk−20 −Ek+1Ek−30 is nonnegative, which can be rewritten using Equation (6.6) as

EkEk−20 −Ek+1Ek−30

= (Ek0Ek−20 −Ek+10 Ek−30 ) + (z1+z2+z3)(Ek−10 Ek−20 −Ek0Ek−30 ) + (z1z2+z1z3+z2z2)(Ek−20 Ek−20 −Ek−10 Ek−30 ).

Each of the expressions inEr0 above are nonnegative. These weak inequal- ities follow from a simple counting argument. Or we can use an old result in Hardy, Littlewood and Pólya [3, p. 52]:

z ∈[0,∞)nands > r =⇒ Es−1Er > EsEr−1, withr=k−2ands=k+ 1, k, k−1.

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