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Existence of infinitely many solutions for a Steklov problem involving the p ( x ) -Laplace operator

Mostafa Allaoui

B

, Abdel Rachid El Amrouss and Anass Ourraoui

University Mohamed I, Faculty of Sciences, Department of Mathematics, Oujda, Morocco Received 5 January 2013, appeared 16 May 2014

Communicated by Ondˇrej Došlý

Abstract. In this article, we study the nonlinear Steklov boundary-value problem

p(x)u=|u|p(x)−2u inΩ,

|∇u|p(x)−2∂u

∂ν = f(x,u) on∂Ω.

We prove the existence of infinitely many non-negative solutions of the problem by applying a general variational principle due to B. Ricceri and the theory of the variable exponent Sobolev spaces.

Keywords: p(x)-Laplace operator, infinitely many solutions, Ricceri’s variational prin- ciple.

2010 Mathematics Subject Classification: 35J48, 35J60, 35J66.

1 Introduction

Motivated by the developments in elastic mechanics, electrorheological fluids and image restoration [4, 16, 17, 20, 21], the interest in variational problems and differential equations with variable exponent has grown in recent decades; see for example [6,12, 13,15]. We refer the reader to [3,7,8,18,19] for developments in p(x)-Laplacian equations.

The purpose of this article is to study the existence and multiplicity of solutions for the Steklov problem involving the p(x)-Laplacian,

p(x)u= |u|p(x)−2u inΩ,

|∇u|p(x)−2∂u

∂ν = f(x,u) on∂Ω. (1.1)

where Ω⊂RN (N ≥2)is a bounded smooth domain, ∂u∂ν is the outer unit normal derivative on ∂Ω, pis a continuous function on Ωwith N < p :=infxp(x)≤ p+ := supxp(x)<

+ and f: Ω×RRis a continuous function. The main interest in studying such prob- lems arises from the presence of the p(x)-Laplace operator div(|∇u|p(x)−2∇u), which is a

BCorresponding author. Email: allaoui19@hotmail.com

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generalization of the classical p-Laplace operator div(|∇u|p2∇u)obtained in the case when p is a positive constant. Many authors have studied the inhomogeneous Steklov problems involving the p-Laplacian [14]. The authors have studied this class of inhomogeneous Steklov problems in the cases of p(x)≡ p = 2 and of p(x)≡ p > 1, respectively. From now, we put X=W1,p(x)()andw:= N/2

NΓ(N2) the measure of theN-dimensional unit ball.

The main results of this paper are as follows.

Theorem 1.1. We assume that f(x,t) = 0for all t≤ 0, a.e x ∈ ∂Ω, andinfη0F(x,η)≥ 0for a.e.

x ∈ Ω. Moreover, suppose that there exist two sequences {ak}kN and{bk}kN in (0,+) with ak <bk,limk→+bk = +such that

(1) limk→+ b

p k

apk+ +β = +for some non-negative constantβ;

(2) max×[a

k,bk] f ≤0for all k∈ N;

(3) there exists a sequence{ξk}kNRsuch thatlimk→+ξk = + and a constant h0 > ||

p||, such that F(x,ξk)≥h0ξp

+

k for a.e. x∈ ∂Ω;

(4) lim supk→+max∂Ω×[0,ak]F(x,η)

bpk < 1

C0pp+|∂Ω|, where C0=supuX\{0} |kuu|k.

Then problem(1.1)admits an unbounded sequence of non-negative weak solutions in X.

Theorem 1.2. We assume that f(x,t) = 0 for all t ≤ 0, a.e. x ∈ Ω, and infη0F(x,η) ≥ 0 for a.e. x∈∂Ω. Moreover, suppose that there exist two sequences{ak}kNand{bk}kNin(0,+)with ak <bk,limk→+bk =0such that

(1) limk→+ b

p k

apk− −α = +for some non-negative constantα< p; (2) max×[ak,bk] f ≤0for all k∈ N;

(3) there exists a sequence{ξk}kNR such thatlimk→+ξk = 0+ and a constant h0 > p||∂Ω| |, such that F(x,ξk)≥h0ξp

k for a.e. x∈ Ω; (4) lim supk→+max∂Ω×[0,ak]F(x,η)

bpk < 1

C0pp+|∂Ω|, where C0=supuX\{0} |ku|

uk.

Then problem (1.1) admits a sequence of non-zero non-negative weak solutions, which strongly con- verges to0in X.

Example 1.3. An example of functions satisfying the assumptions of Theorem1.1

F(x,t) =

e2z(x)ln 2h(x)atbk

k+1bk

z(x)

ak+1t ak+1bk

z(x)

tq(x), ift∈(bk,ak+1);

0, otherwise,

whereh ∈ C()with minxh(x)≥ h0, z∈ C()with minxz(x) >1 andq∈ C()with p+ ≤q(x)≤ p++βfor all x∈Ω. Note that in this occasion we can chooseξk = ak+12+bk.

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Example 1.4. An example of functions satisfying the assumptions of Theorem1.2

F(x,t) =

e2z(x)ln 2h(x)atbk+1

kbk+1

z(x)

akt akbk+1

z(x)

tq(x), ift ∈(bk+1,ak);

0, otherwise,

where h ∈C()with minxh(x)≥ h0,z ∈ C()with minxz(x)> 1 andq∈ C()with pα≤ q(x)≤ pfor all x∈. Note that in this occasion we can chooseξk = bk+12+ak.

Existence of infinitely many solutions for boundary value problems have received a great deal of interest in recent years, see, for instance, the paper [2, 5] and references therein. In [1] we have considered the existence and multiplicity of solutions for the Steklov problem involving the p(x)-Laplacian of the type

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(∆p(x)u= |u|p(x)−2u inΩ,

|∇u|p(x)−2∂u

∂ν = λf(x,u) on∂Ω.

Under the following assumptions of the function f, (f1) | f(x,s)|≤a(x) +b|s |α(x)−1, ∀(x,s)∈ ∂Ω×R,

where a(x)∈ L

α(x)

α(x)−1(∂Ω)andb≥0 is a constant, α(x)∈ C+(∂Ω). (f2) f(x,t)<0 , when|t| ∈(0, 1),

f(x,t)≥m>0 , whent∈(t0,∞),t0>1,

we have established the existence of at least three solutions of this problem.

This article is organized as follows. First, we will introduce some basic preliminary results and lemmas in Section 2. In Section 3, we will give the proofs of our main results.

2 Preliminaries

For completeness, we first recall some facts on the variable exponent spaces Lp(x)() and Wk,p(x)(). For more details, see [9, 10]. Suppose that Ωis a bounded open domain of RN with smooth boundary ∂Ωand p∈C+()where

C+() =

p∈C() and inf

xp(x)>1

.

Denote by p := infxp(x)and p+ := supxp(x). Define the variable exponent Lebesgue space Lp(x)()by

Lp(x)() =

u:Ω→Ris a measurable and Z

|u|p(x)dx< +

, with the norm

|u|p(x)=inf

τ>0;

Z

u τ

p(x)

dx≤1

. Define the variable exponent Sobolev spaceW1,p(x)()by

W1,p(x)() =nu∈ Lp(x)():|∇u| ∈ Lp(x)()o,

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with the norm

kuk=inf (

τ>0;

Z

∇u τ

p(x)

+u τ

p(x)!

dx≤1 )

, kuk=|∇u|p(x)+|u|p(x).

We refer the reader to [9, 10] for the basic properties of the variable exponent Lebesgue and Sobolev spaces.

Lemma 2.1 ([10]). Both (Lp(x)(),| · |p(x)) and (W1,p(x)(),k · k) are separable and uniformly convex Banach spaces.

Lemma 2.2([10]). Hölder inequality holds, namely Z

|uv|dx≤2|u|p(x)|v|q(x) ∀u∈ Lp(x)(),v∈ Lq(x)(), where p(1x)+ 1

q(x) =1.

Lemma 2.3([10]). Let I(u) =R

|∇u|p(x)+|u|p(x)dx, for u∈W1,p(x)()we have

• kuk<1(=1,>1)⇔ I(u)<1(=1,>1);

• kuk ≤1⇒ kukp+ ≤ I(u)≤ kukp;

• kuk ≥1⇒ kukp ≤ I(u)≤ kukp+.

Lemma 2.4 ([9]). Assume that the boundary of Ω possesses the cone property and p ∈ C()and 1≤q(x)< p(x)for x∈ , then there is a compact embedding W1,p(x)(),→ Lq(x)(), where

p(x) =

( N p(x)

Np(x), if p(x)< N;

+∞, if p(x)≥ N.

Lemma 2.5([9]). The embedding W1,p(x)(),→C()is compact whenever N< p.

Lemma 2.6 ([11]). Let X be a separable and reflexive real Banach space, φ,ψ: X → R be two se- quentially weakly lower semicontinuous and Gâteaux differentiable functionals. Assume also thatφis (strongly) continuous and satisfieslimkuk→+φ(u) = +∞. For eachρ>infXφ, put

ϕ(ρ) = inf

xφ1((−))

ψ(x)−inf

φ1((−∞,ρ))wψ ρφ(x) , whereφ1((−∞,ρ))wis the closure ofφ1((−∞,ρ))win the weak topology.

1. If there exist a sequence{rk} ⊂ (infXφ,+)with rk → + and a sequence{uk} ⊂ X such that for each k∈N,

φ(uk)<rk (2.1)

and

ψ(uk)− inf

φ1((−))w

ψ<rkφ(uk), (2.2) and in addition,

lim inf

kuk→+(φ(u) +ψ(u)) =−∞, (2.3) then there exists a sequence{vk}of local minima ofφ+ψsuch thatφ(vk)→+as k→+.

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2. If there exist a sequence{rk} ⊂ (infXφ,+)with rk → (infXφ)+ and a sequence{uk} ⊂ X such that for each k the conditions(2.1)and(2.2)are satisfied, and in addition, every global mini- mizer ofφis not a local minimizer ofφ+ψ, then there exists a sequence{vk}of pairwise distinct local minimizers ofφ+ψsuch thatlimk→+φ(vk) =infXφ, and{vk}weakly converges to a global minimizer ofφ.

Definition 2.7. We say thatu ∈Xis a weak solution of (1.1) if Z

|∇u|p(x)−2∇u∇v dx+

Z

|u|p(x)−2uv dx=

Z

f(x,u)v dσ for allv ∈X.

For eachu∈X, we define φ(u) =

Z

1 p(x)

|∇u|p(x)+|u|p(x)dx, ψ(u) =−

Z

∂ΩF(x,u)dσ, J(u) =φ(u) +ψ(u), where F(x,t) =Rt

0 f(x,s)ds. Then we have hφ0(u),vi=

Z

|∇u|p(x)−2∇u∇v+|u|p(x)−2uv dx, hψ0(u),vi=−

Z

f(x,u)v dσ, for all v∈X.

Then it is easy to see thatφ,ψ∈C1(X,R)andu∈ Xis a weak solution of (1.1) if and only ifu is a critical point of the functional J.

Notice thatφis convex and continuous functional so it is a weakly lower semi-continuous.

Since the embeddingX,→C()is compact, we can see thatψ: X→Ris sequentially weakly lower semi-continuous.

3 Proof of main results

For the proof of Theorems 1.1 and 1.2, we will use Lemma 2.6. We start with the following lemmas.

Lemma 3.1. φis coercive.

Proof. Whenkuk ≥1, we have φ(u) =

Z

1 p(x)

|∇u|p(x)+|u|p(x)dx ≥ 1

p+kukp, (3.1) thenφis coercive. The proof is completed.

Sinceφ: X→Ris coercive we can defineK(r)as K(r) =infn

τ>0 :φ1((−,r))⊂ BX(0,τ)o, (3.2) forr>infXφ, where

BX(0,τ) ={u∈ X:kuk<τ},

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BX(0,τ)denotes the closure of BX(0,τ) in X. Since φis coercive, we know 0 < K(r)< + for each r > infXφ. From the definition of K(r), we have φ1((−∞,r)) ⊂ BX(0,K(r)) and consequentlyφ1((−∞,r))w ⊂ BX(0,K(r)). Since the embeddingX ,→ C() is compact, so there is a constantC0 >0 such that

C0 = sup

uX\{0}

|u| kuk. Therefore we have

BX(0,K(r))⊂ {u∈C():|u| ≤C0K(r)}. So we have

inf

vφ1((−∞,r))w

ψ(v)≥ inf

kvk≤K(r)ψ(v)≥ inf

|v|C0K(r)ψ(v). (3.3) Lemma 3.2. For r≥ p1+, we have

K(r)≤rp+p1

. (3.4)

Proof. Letr≥ p1+ andu∈Xbe such that φ(u)<r. Whenkuk ≥1, by (3.1), we obtain r >φ(u)≥ 1

p+kukp, thus we havekuk< rp+ 1

p

. Whenkuk<1, it is clear that kuk<1≤rp+, which implies thatkuk< rp+p1

. By the definition ofK(r), (3.4) holds.

Proof of Theorem1.1. We use Lemma2.6(1) to prove Theorem1.1.

Now put rk = p1+

bk C0

p

, then limk→+rk = +∞. Using Lemma 3.2, we haveC0K(rk) ≤ bk. Fixx0and pickγ>0 such thatB(x0,γ)⊆Ω.

By condition (2), we have max∂Ω×[0,ak]F = max∂Ω×[0,bk]F. Now we consider the function uk ∈ Xdefined by

uk =





0, ifx∈ \B(x0,γ); ηk, ifx∈ B(x0,γ2);

k

γ γ− |x−x0|, ifx∈ B(x0,γ)\B(x0,γ2),

(3.5)

withηk ∈ (0,ak]and xk∂Ωsuch that F(xk,ηk) =max×[0,ak]F. Without loss of generality, we may assume thatηk ≥max(γ, 1). In view of condition (1), we choosek1Nsuch that

bkp apk+

> p

+C0pNp+ p2N

h

2p+(2N−1) +2Nγp

+i

, (3.6)

for allk>k1. For eachk>k1, using (3.6), we have

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φ(uk) =

Z

1 p(x)

|∇uk|p(x)+|uk|p(x)dx

1 p

Z

|∇uk|p(x)dx+

Z

|uk|p(x)dx

1 p

k γ

p+h

B x0,γ

B x0,γ 2

i

+

Z

B(x0)

|uk|p(x)dx

2

p+

ηp

+ kN pγp+

1− 1

2N

+ η

p+ kN

p

= η

p+ kN pγp+2N

h 2p+

2N−1

+2Nγp

+i

a

p+ kN pγp+2N

h 2p+

2N−1

+2Nγp

+i

<rk. Then for eachk >k1, we have

φ(uk)<rk. (3.7)

For eachv∈ φ1((−∞,rk)), we can easily see that for each x∈ ∂Ω F(x,v(x))≤ max

∂Ω×[0,C0K(rk)]F(x,v)

≤ max

∂Ω×[0,bk]F(x,v)

= max

∂Ω×[0,ak]F(x,v)

=F(xk,ηk). By condition (4), there exists a k2Nsuch that

max×[0,ak]F(x,η) bkp

= F(xk,ηk) bkp

< 1

C0pp+|∂Ω|, (3.8) for every k>k2. Since limk→+ η

p+ k

bkp =0 and (3.8), for everyk >k2, we have F(xk,ηk) + η

p+ k N

|∂Ω|pγp+2N

h 2p+

2N−1

+2Nγp

+i

bkp

< 1

C0pp+|Ω|. (3.9) Therefore, using (3.9), we obtain

sup

vC(),|v|C0K(rk) Z

∂ΩF(x,v(x))dσ−

Z

∂ΩF(x,uk(x))dσ

≤F(xk,ηk)|Ω|

< b

p k

C0pp+

η

p+ kN pγp+2N

h 2p+

2N−1

+2Nγp

+i

≤rkφ(uk),

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for eachk> k2. Then for everyk> k2, we have sup

vC(),|v|C0K(rk) Z

F(x,v(x))dσ−

Z

F(x,uk(x))dσ<rkφ(uk). (3.10) In view of (3.7) and (3.10), for each k > max{k1,k2}, we have proved (2.1) and (2.2). We need to verify that the functional φ+ψhas no global minimum, i.e. (2.3). By condition (3), we can find a sequence {ξk}kNR such that limk→+ξk = + and F(x,ξk) ≥ h0ξp

+ k for a.e. x ∈ ∂Ω. Now we consider a function wk ∈ X defined by wk(x) = ξk. Without loss of generality, we may assume thatξk ≥1. So we have

φ(wk) +ψ(wk)≤ ξ

p+ k ||

p −h0ξp

+ k |∂Ω|

ξp

+ k |Ω|

||

p|∂Ω|−h0

. Sinceh0> p||∂Ω| |. It forces

k→+limξp

+ k |Ω|

|| p|Ω|−h0

=−.

Therefore, Lemma 2.6(1) assures that there is a sequence {vk}kN of local minima of φ+ψ such thatφ(vk)→+ask→+.

It remains to show that the weak solutions obtained are non-negative.

Define

f+(x,t) =

(f(x,t), if t≥0;

0, otherwise, and consider the following problem

(S+)

(∆p(x)u=|u|p(x)−2u inΩ,

|∇u|p(x)−2∂u

∂ν = f+(x,u) onΩ, ifuis weak solution of the problem(S+), then one has

Z

|∇u|p(x)−2∇u∇v dx+

Z

|u|p(x)−2uv dx−

Z

f+(x,u)v dσ=0, (3.11) for all v ∈ X. Taking v = u in (3.11) shows that kuk = 0, so u = 0. Obviously, u is a non-negative solution of (1.1) in X. This completes the proof.

Proof of Theorem1.2. We use Lemma2.6(2) to prove Theorem1.2.

We putrk = p1+ bk C0

p

, and consider the functionuk ∈ Xdefined by

uk =





0, ifx ∈\B(x0,γ); ηk, ifx ∈B(x0,γ2);

k

γ (γ− |x−x0|), ifx ∈B(x0,γ)\B(x0,γ2).

(3.12)

We can easily get (2.1) and (2.2) using the same method as in the proof of Theorem 1.1. In view of condition (3), we can find a sequence{ξk}kNR such that limk→+ξk = 0+ and

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F(x,ξk) ≥ h0ξp

k for a.e. x ∈ Ω. If we take wk = ξk, of course the sequence {wk} strongly converges to 0 in Xandφ(wk) +ψ(wk)< 0 for allk ∈ N. Since φ(0) +ψ(0) =0, this means that 0 is not a local minimum ofφ+ψ.

So, since 0 is the only global minimum of φ. Lemma 2.6(2) ensures that there exists a sequence {vk} of pairwise distinct local minimizers of φ+ψ such that limk→+φ(vk) = 0.

Using the same method as in the proof of Theorem1.1, we can get that each weak solution of problem (1.1) is non-negative. This completes the proof.

Acknowledgements

The authors thank the referees for their careful reading of the manuscript and insightful comments.

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