Matrix Trace Inequalities on the Tsallis Entropies
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MATRIX TRACE INEQUALITIES ON THE TSALLIS ENTROPIES
SHIGERU FURUICHI
Department of Electronics and Computer Science Tokyo University of Science
Yamaguchi, Sanyo-Onoda City Yamaguchi, 756-0884, Japan EMail:furuichi@ed.yama.tus.ac.jp
Received: 28 June, 2007
Accepted: 29 January, 2008
Communicated by: F. Zhang
2000 AMS Sub. Class.: 47A63, 94A17, 15A39.
Key words: Matrix trace inequality, Tsallis entropy, Tsallis relative entropy and maximum entropy principle.
Abstract: Maximum entropy principles in nonextensive statistical physics are revisited as an application of the Tsallis relative entropy defined for non-negative matrices in the framework of matrix analysis. In addition, some matrix trace inequalities related to the Tsallis relative entropy are studied.
Matrix Trace Inequalities on the Tsallis Entropies
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Close Acknowledgements: The author would like to thank the reviewer for providing valuable com-
ments to improve the manuscript. The author would like to thank Professor K.Yanagi and Professor K. Kuriyama for providing valuable comments and constant encouragement. This work was supported by the Japanese Ministry of Education, Science, Sports and Culture, Grant-in-Aid for En- couragement of Young Scientists (B), 17740068. This work was also par- tially supported by the Ministry of Education, Science, Sports and Culture, Grant-in-Aid for Scientific Research (B), 18300003.
Dedicatory: Dedicated to Professor Kunio Oshima on his 60th birthday.
Matrix Trace Inequalities on the Tsallis Entropies
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Contents
1 Introduction 4
2 Maximum Entropy Principle in Nonextensive Statistical Physics 6 3 On Some Trace Inequalities Related to the Tsallis Relative Entropy 10
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1. Introduction
In 1988, Tsallis introduced the one-parameter extended entropy for the analysis of a physical model in statistical physics [10]. In our previous papers, we studied the properties of the Tsallis relative entropy [5, 4] and the Tsallis relative operator en- tropy [17,6]. The problems on the maximum entropy principle in Tsallis statistics have been studied for classical systems and quantum systems [9, 11, 2, 1]. Such problems were solved by the use of the Lagrange multipliers formalism. We give a new approach to such problems, that is, we solve them by applying the non- negativity of the Tsallis relative entropy without using the Lagrange multipliers for- malism. In addition, we show further results on the Tsallis relative entropy.
In the present paper, the set of n× n complex matrices is denoted by Mn(C).
That is, we deal withn×n matrices because of Lemma2.2in Section2. However some results derived in the present paper also hold for the infinite dimensional case.
In the sequel, the set of all density matrices (quantum states) is represented by Dn(C)≡ {X ∈Mn(C) :X ≥0,Tr[X] = 1}.
X ∈ Mn(C)is called by a non-negative matrix and denoted byX ≥ 0, if we have hXx, xi ≥ 0for allx ∈ Cn. That is, for a Hermitian matrixX, X ≥ 0means that all eigenvalues ofXare non-negative. In addition,X ≥Y is defined byX−Y ≥0.
For−I ≤ X ≤ I andλ ∈ (−1,0)∪(0,1), we denote the generalized exponential function byexpλ(X)≡(I+λX)1/λ. As the inverse function ofexpλ(·), forX ≥0 andλ∈(−1,0)∪(0,1), we denote the generalized logarithmic function bylnλX ≡
Xλ−I
λ . Then the Tsallis relative entropy and the Tsallis entropy for non-negative matricesX andY are defined by
Dλ(X|Y)≡Tr
X1−λ(lnλX−lnλY)
, Sλ(X)≡ −Dλ(X|I).
These entropies are generalizations of the von Neumann entropy [16] and of the
Matrix Trace Inequalities on the Tsallis Entropies
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Umegaki relative entropy [14] in the sense that
λ→0limSλ(X) =S0(X)≡ −Tr[XlogX]
and
λ→0limDλ(X|Y) = D0(X|Y)≡Tr[X(logX−logY)].
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2. Maximum Entropy Principle in Nonextensive Statistical Physics
In this section, we study the maximization problem of the Tsallis entropy with a constraint on theλ-expectation value. In quantum systems, the expectation value of an observable (a Hermitian matrix) H in a quantum state (a density matrix) X ∈ Dn(C)is written asTr[XH]. Here, we consider theλ-expectation valueTr[X1−λH]
as a generalization of the usual expectation value. Firstly, we impose the following constraint on the maximization problem of the Tsallis entropy:
Cfλ ≡
X ∈Dn(C) : Tr[X1−λH] = 0 ,
for a givenn×nHermitian matrixH. We denote a usual matrix norm byk·k, namely forA∈Mn(C)andx∈Cn,
kAk ≡ max
kxk=1kAxk. Then we have the following theorem.
Theorem 2.1. Let Y = Zλ−1expλ(−H/kHk), where Zλ ≡ Tr[expλ(−H/kHk)], for an n × n Hermitian matrix H and λ ∈ (−1,0) ∪(0,1). If X ∈ Cfλ, then Sλ(X)≤ −cλlnλZλ−1,wherecλ ≡Tr[X1−λ].
Proof. SinceZλ ≥ 0 and we have lnλ(x−1Y) = lnλY + (lnλx−1)Yλ for a non- negative matrixY and scalarx, we calculate
Tr[X1−λlnλY] = Tr[X1−λlnλ
Zλ−1expλ(−H/kHk) ]
= Tr[X1−λ
−H/kHk+ lnλZλ−1(I−λH/kHk) ]
= Tr[X1−λ
lnλZλ−1I−Zλ−λH/kHk ] =cλlnλZλ−1,
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since lnλZλ−1 = Z
−λ λ −1
λ by the definition of the generalized logarithmic function lnλ(·). By the non-negativity of the Tsallis relative entropy:
(2.1) Tr[X1−λlnλY]≤Tr[X1−λlnλX], we have
Sλ(X) = −Tr[X1−λlnλX]≤ −Tr[X1−λlnλY] =−cλlnλZλ−1.
Next, we consider the slightly changed constraint:
Cλ ≡
X ∈Dn(C) : Tr[X1−λH]≤Tr[Y1−λH] and Tr[X1−λ]≤Tr[Y1−λ] for a givenn×n Hermitian matrixH, as the maximization problem for the Tsallis entropy. To this end, we prepare the following lemma.
Lemma 2.2. For a givenn×nHermitian matrixH, ifnis a sufficiently large integer, then we haveZλ ≥1.
Proof.
(i) For a fixed0< λ <1and a sufficiently largen, we have
(2.2) (1/n)λ ≤1−λ.
From the inequalities− kHkI ≤H ≤ kHkI, we have (2.3) (1−λ)λ1I ≤expλ(−H/kHk)≤(1 +λ)1λI.
By inequality (2.2), we have 1
nI ≤(1−λ)1λI ≤expλ(−H/kHk), which impliesZλ ≥1.
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(ii) For a fixed−1< λ <0and a sufficiently largen, we have
(2.4) (1/n)λ ≥1−λ.
Analogously to (i), we have inequalities (2.3) for−1 < λ < 0. By inequality (2.4), we have
1
nI ≤(1−λ)1λI ≤expλ(−H/kHk), which impliesZλ ≥1.
Then we have the following theorem by the use of Lemma2.2.
Theorem 2.3. Let Y = Zλ−1expλ(−H/kHk), where Zλ ≡ Tr[expλ(−H/kHk)], for λ ∈ (−1,0)∪(0,1) and ann ×n Hermitian matrix H. If X ∈ Cλ andn is sufficiently large, thenSλ(X)≤Sλ(Y).
Proof. Due to Lemma2.2, we havelnλZλ−1 ≤ 0for a sufficiently largen. Thus we havelnλZλ−1Tr[X1−λ] ≥ lnλZλ−1Tr[Y1−λ]forX ∈ Cλ. Similarly to the proof of Theorem2.1, we have
Tr[X1−λlnλY] = Tr[X1−λlnλ
Zλ−1expλ(−H/kHk) ]
= Tr[X1−λ
−H/kHk+ lnλZλ−1(I−λH/kHk) ]
= Tr[X1−λ
lnλZλ−1I−Zλ−λH/kHk ]
≥Tr[Y1−λ
lnλZλ−1I−Zλ−λH/kHk ]
= Tr[Y1−λ
−H/kHk+ lnλZλ−1(I−λH/kHk) ]
= Tr[Y1−λlnλ
Zλ−1expλ(−H/kHk) ]
= Tr[Y1−λlnλY].
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By Eq.(2.1) we have
Sλ(X) =−Tr[X1−λlnλX]≤ −Tr[X1−λlnλY]≤ −Tr[Y1−λlnλY] =Sλ(Y).
Remark 1. Since−x1−λlnλxis a strictly concave function, Sλ is a strictly concave function on the setCλ. This means that the maximizing Y is uniquely determined so that we may regardY as a generalized Gibbs state, since an original Gibbs state e−βH/Tr[e−βH], whereβ ≡1/T andT represents a physical temperature, gives the maximum value of the von Neumann entropy. Thus, we may define a generalized Helmholtz free energy by
Fλ(X, H)≡Tr[X1−λH]− kHkSλ(X).
This can be also represented by the Tsallis relative entropy such as Fλ(X, H) = kHkDλ(X|Y) + lnλZλ−1Tr[X1−λ(kHk −λH)].
The following corollary easily follows by taking the limit asλ→0.
Corollary 2.4 ([12,15]). LetY =Z0−1exp (−H/kHk), whereZ0 ≡Tr[exp (−H/kHk)], for ann×nHermitian matrixH.
(i) IfX ∈fC0, thenS0(X)≤logZ0. (ii) IfX ∈C0, thenS0(X)≤S0(Y).
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3. On Some Trace Inequalities Related to the Tsallis Relative Entropy
In this section, we consider an extension of the following inequality [8]:
(3.1) Tr[X(logX+ logY)]≤ 1
pTr[XlogXp/2YpXp/2] for non-negative matricesX andY, andp >0.
For the proof of the following Theorem3.3, we use the following famous inequal- ities.
Lemma 3.1 ([8]). For any Hermitian matricesAandB,0 ≤λ ≤ 1andp > 0, we have the inequality:
Trh
epA]λepB1/pi
≤Tr
e(1−λ)A+λB ,
where theλ-geometric mean for positive matricesAandB is defined by A]λB ≡A1/2 A−1/2BA−1/2λ
A1/2.
Lemma 3.2 ([7,13]). For any Hermitian matrices GandH, we have the Golden- Thompson inequality:
Tr eG+H
≤Tr eGeH
.
Theorem 3.3. For positive matricesX andY,p≥1and0< λ≤1, we have (3.2) Dλ(X|Y)≤ −Tr[Xlnλ(X−p/2YpX−p/2)1/p].
Proof. First of all, we note that we have the following inequality [3]
(3.3) Tr[(Y1/2XY1/2)rp]≥Tr[(Yr/2XrYr/2)p]
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for non-negative matricesX and Y, and0 ≤ r ≤ 1, p > 0. Similar to the proof of Theorem 2.2 in [5], inequality (3.2) easily follows by setting A = logX and B = logY in Lemma3.1such that
Tr[(Xp]λYp)1/p]≤Tr[elogX1−λ+logYλ]
≤Tr[elogX1−λelogYλ]
= Tr[X1−λYλ], (3.4)
by Lemma3.2. In addtion, we have
(3.5) Tr[XrYr]≤Tr[(Y1/2XY1/2)r], (0≤r ≤1), on takingp= 1of inequality (3.3). By (3.4) and (3.5) we obtain:
Tr[(Xp]λYp)1/p] = Tr h
Xp/2(X−p/2YpX−p/2)λXp/2 1/p i
≥Tr[X(X−p/2YpX−p/2)λ/p].
Thus we have,
Dλ(X|Y) = Tr[X−X1−λYλ] λ
≤ Tr[X−X(X−p/2YpX−p/2)λ/p] λ
=−Tr[X
((X−p/2YpX−p/2)1/p)λ−I ] λ
=−Tr[Xlnλ(X−p/2YpX−p/2)1/p].
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Remark 2. For positive matricesXandY,0< p <1and0< λ≤1, the following inequality does not hold in general:
(3.6) Dλ(X|Y)≤ −Tr[Xlnλ(X−p/2YpX−p/2)1/p].
Indeed, the inequality (3.6) is equivalent to
(3.7) Tr[X(X−p/2YpX−p/2)λ/p]≤Tr[X1−λYλ].
Then we have many counter-examples. If we set p = 0.3, λ = 0.9 and X = 10 3
3 9
, Y =
5 4 4 5
,then inequality (3.7) fails. (R.H.S. minus L.H.S. of (3.7) approximately becomes -0.00309808.) Thus, inequality (3.6) is not true in general.
Corollary 3.4.
(i) For positive matricesX andY, the trace inequality
Dλ(X|Y)≤ −Tr[Xlnλ(X−1/2Y X−1/2)]
holds.
(ii) For positive matricesX andY, andp≥1, we have inequality (3.1).
Proof.
(i) Putp= 1in (1) of Theorem3.3.
(ii) Take the limit asλ→0.
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