volume 7, issue 2, article 66, 2006.
Received 14 October, 2005;
accepted 30 December, 2005.
Communicated by:R.U. Verma
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Journal of Inequalities in Pure and Applied Mathematics
GENERALIZED CO-COMPLEMENTARITY PROBLEMS IN p-UNIFORMLY SMOOTH BANACH SPACES
M. FIRDOSH KHAN AND SALAHUDDIN
Department of Mathematics Aligarh Muslim University Aligarh-202002, India EMail:khan_mfk@yahoo.com
c
2000Victoria University ISSN (electronic): 1443-5756 011-06
Generalized
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M. Firdosh Khan and Salahuddin
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Abstract
The objective of this paper is to study the iterative solutions of a class of gen- eralized co-complementarity problems inp-uniformly smooth Banach spaces, with the devotion of sunny retraction mapping,p-strongly accretive,p-relaxed accretive and Lipschitzian (or more generally uniformly continuous) mappings.
Our results are new and represents a significant improvement of previously known results. Some special cases are also discussed.
2000 Mathematics Subject Classification:49J40, 90C33, 47H10.
Key words: Generalized co-complementarity problems, Iterative algorithm, Sunny retraction, Sunny nonexpansive mapping,p-strongly accretive,p-relaxed accretive mapping, Lipschitzian mapping, Hausdorff metric,p-uniformly smooth Banach spaces.
Contents
1 Introduction. . . 3
2 Background of Problem Formulations . . . 4
2.1 Special Cases . . . 7
3 The Characterization of Problem and Solutions. . . 8
4 Iterative Algorithms and Pertinent Concepts . . . 12
5 Main Results . . . 15 References
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1. Introduction
The theory of complementarity problems initiated by Lemke [19] and Cottle and Dantzing [10] in the early sixties and later developed by other mathematicians see for example [6,9,11,14,17,22] plays an important role and is fundamental in the study of a wide class of problems arising in optimization, game theory, economics and engineering sciences [3,6,8,11,15].
On the other hand, the accretive operators are of interest because several physically resolvent problems can be modeled by nonlinear evolution systems involving operators of the accretive type. Very closely related to the accretive operators is the class of dissipative operators, where an operatorT is said to be dissipative if and only if (−T) is accretive. The concepts of strictly strongly andm-(or sometimes hyper-) dissipativity are similarly defined.
These classes of operators have attracted a lot of interest because of their involvement in evolution systems modeling several real life problems. Con- sequently several authors have studied the existence, uniqueness and iterative approximations of solutions of nonlinear equations involving such operators, see [5,12,18] and the references cited therein.
It is our purpose in this article to establish the strong convergence of the iter- ative algorithm to a solution of the generalized co-complimentarity problems in p−uniformly smooth Banach spaces when the operators are accretive, strictly accretive, strongly accretive, relaxed accretive and Lipschitzian. Our iteration processes are simple and independent of the geometry of E and iteration pa- rameters can be chosen at the start of the iteration process. Consequently, most important results known in this connection will be special cases of our problem.
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2. Background of Problem Formulations
Throughout this article, we assume that E is a real Banach space whose norm is denoted byk · k,E?its topological dual space. CB(E)denotes the family of all nonempty closed and bounded subsets ofE. D(·,·)is the Hausdorff metric onCB(E)defined by
max
sup
x∈A
d(x, B), sup
y∈B
d(A, y)
=D(A, B), where
d(x, B) = inf
y∈Bd(x, y) and d(A, y) = inf
x∈Ad(x, y),
dis the metric onEinduced by the normk · k. As usual,h·,·iis the generalized duality pairing betweenEandE?. For1< p < ∞, the mappingJp :E →2E? defined by
Jp(x) = {f? ∈E? :hx, f?i=kfk · kxkandkfk=kxkp−1} for allx∈E, is called the duality mapping with gauge function φ(t) = tp−1. In particular for p = 2, the duality mapping J2 with gauge function φ(t) = t is called the normalized duality mapping. It is known that Jp(x) = kxkp−2J2(x) for all x 6= 0 and Jp is single valued if E? is strictly convex. IfE = H is a Hilbert space, thenJ2 becomes the identity mapping onH.
Proposition 2.1 ([7]). Let E be a real Banach space. For 1 < p < ∞, the duality mappingJp :E →2E? has the following basic properties:
1. Jp(x)6=∅for allx∈E andD(Jp)(the domain ofJp)=E,
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2. Jp(x) = kxkp−2J2(x)for allx∈E,(x6= 0), 3. Jp(αx) =αp−1Jp(x)for allα∈[0,∞), 4. Jp(−x) = −Jp(x),
5. Jp is bounded i.e., for any bounded subset A ⊂ E, Jp(A) is a bounded subset inE?,
6. Jpcan be equivalently defined as the subdifferential of the functionalϕ(x) = p−1kxkp (Asplund [2]), i.e.,
Jp(x) =∂ϕ(x) ={f ∈E? : ϕ(y)−ϕ(x)≥(f, y−x), for ally∈E}
7. E is a uniformly smooth Banach space (equivalently, E? is a uniformly convex Banach space) if and only if Jp is single valued and uniformly continuous on any bounded subset ofE(Xu and Roach [24]).
Definition 2.1. Let E be a real Banach space andK a nonempty subset ofE.
LetT :K →2E be a multivalued mapping
1. T is said to be accretive if for anyx, y ∈K,u∈T(x)andv ∈T(y)there existsj2 ∈J2(x−y)such that
hu−v, j2i ≥0,
or equivalently, there existsjp ∈Jp(x−y),1< p <∞, such that
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2. T is said to be strongly accretive if for any x, y ∈ K, u ∈ T(x) and v ∈T(y)there existsj2 ∈J2(x−y)such that
hu−v, j2i ≥kkx−yk2,
or equivalently, there existsjp ∈Jp(x−y),1< p <∞such that hu−v, jpi ≥kkx−ykp,
for some constantk >0.
The concept of a single-valued accretive mapping was introduced indepen- dently by Browder [5] and Kato [18] in 1967. An early fundamental result in the theory of accretive mappings which is due to Browder states that the following initial value problem,
du(t)
dt +T u(t) = 0, u(0) =u0, is solvable ifT is locally Lipschitzian and accretive onE.
More precisely, letN :E×E →Eandm, g :E →E be the single-valued mappings and F, G, T : E → CB(E)the multivalued mappings. Let X be a fixed closed convex cone ofE. DefineK :E →2E by
K(z) =m(z) +X for allx∈E, z ∈T(x).
We shall study the following generalized co-complementarity problem (GCCP):
Findx∈E,u∈F(x),v ∈G(x),z ∈T(x)such thatg(x)∈K(z)and (2.1) N(u, v)∈(J(K(z)−g(x)))?,
where(J(K(z)−g(x)))?is the dual cone of the setJ(K(z)−g(x)).
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2.1. Special Cases
(i) IfEis a Hilbert space,F, T are identity mappings andN(u, v) =Bx+Av, whereB, A are single-valued mappings, then Problem (2.1) reduces to a problem of findingx∈E,v ∈G(x)such thatg(x)∈K(z)and
(2.2) B(x) +A(v)∈(K(x)−g(x))? considered by Jou and Yao [16].
(ii) If Gandg are identity mappings, then (2.2) reduces to findingx ∈ K(x) such that
(2.3) B(x) +A(y)∈(K(x)−x)?
which is called a strongly nonlinear quasi complementarity problem, stud- ied by Noor [22].
(iii) Ifmis a zero mapping, then (2.3) is equivalent to findingx∈Esuch that (2.4) Bx+Ax∈E? and hBx+Ax, xi= 0,
which is known as the mildly nonlinear complementarity problem, studied by Noor [21].
(iv) IfAis zero mapping, then (2.4) is equivalent to a problem of findingx∈E such thatBx ∈E?and
(2.5) hBx, xi= 0,
considered by Habetler [14] and Karamardian [17].
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3. The Characterization of Problem and Solutions
In this section, we briefly consider some basic concepts and results, which will be used throughout the paper. The real Banach spaceE is said to be uniformly smooth if its modulus of smoothnessρE(τ)defined by
ρE(τ) = sup
kx+yk+kx−yk
2 −1 : kxk= 1,kyk ≤τ
satisfies ρEτ(τ) → 0 as τ → 0. It follows that E is uniformly smooth if and only ifJp is single-valued and uniformly continuous on any bounded subset of E and there exists a complete duality between uniform convexity and uniform smoothness. E is uniformly convex (smooth) if and only if E? is uniformly smooth (convex). Recall that E is said to have the modulus of smoothness of power type p > 1(and E is said to be p-uniformly smooth) if there exists a constantc >0such that
ρE(τ)≤cτp for0< τ <∞.
Remark 1. It is known that all Hilbert spaces and Banach spaces, Lp, lp and Wmp (1< p <∞)are uniformly smooth and
ρE(τ)<
1
p τp, 1< p <2
(E =Lp, lp orWmp) p−1
2 τ2, p≤2
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thereforeE is ap-uniformly smooth Banach space with modulus of smoothness of power type p < 1 and Jp will always represent the single-valued duality mapping.
Definition 3.1 ([4,13]). Let E be ap-uniformly smooth Banach space and let Ωa nonempty closed convex subset ofE. A mappingQΩ :E →Ωis said to be
(i) retraction onΩifQpΩ =QΩ;
(ii) nonexpansive retraction if it satisfies the inequality
kQΩ(x)−QΩ(y)k ≤ kx−yk, for allx, y ∈E;
(iii) sunny retraction if for allx∈Eand for all−∞< t <∞ QΩ(QΩ(x) +t(x−QΩ(x)) = QΩ(x).
The following characterization of a sunny nonexpansive retraction mapping can be found in [4,13].
Lemma 3.1 ([4,13]). QΩis sunny nonexpansive retraction if and only if for all x, y ∈E,
hx−Q?Ω, J(QΩx−y)i ≥0.
Lemma 3.2. Let E be a real Banach space andJp : E → 2E?,1 < p < ∞a duality mapping. Then, for any givenx, y ∈E, we have
kx+ykp ≤ kxkp +phy, jpi, for alljp ∈Jp(x+y).
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Proof. From Proposition 2.1, it follows thatJp(x) = ∂ϕ(x)(subdifferential of ψ), whereψ(x) = p−1kxkp. Also, it follows from the definition of the subdif- ferential ofψ that
ψ(x)−ψ(x+y)≥ hx−(x+y), jpi, for alljp ∈Jp(x+y). Substitutingψ(x)byp−1kxkp, we have
kx+ykp ≤ kxkp+phy, jpi, for alljp ∈Jp(x+y).
This completes the proof.
Theorem 3.3 ([9]). Let E be a Banach space, Ω a nonempty closed convex subset ofE, andm:E →E. Then for allx, y ∈E, we have
QΩ+m(z)(x) =m(z) +QΩ(x−m(z)).
We mention the following characterization theorem for the solution of a generalized co-complementarity problem which can be easily proved by using Lemma3.1and the argument of [1, Theorem 8.1].
Theorem 3.4. Let E be a real p-uniformly smooth Banach space and X a closed convex cone in E. LetF, G, T : E → CB(E)be the multivalued map- pings,m, g:E →E the two single-valued mappings andN :E×E →Ethe nonlinear mapping. LetK :E → 2E andK(z) =m(z) +X forx ∈E. Then the following statements are equivalent:
(i) x ∈ E, u ∈ F(x), v ∈ G(x)andz ∈ T(x)are solutions of the Problem (2.1), i.e.,g(x)∈K(z)and
N(u, v)∈(J(K(z)−g(x)))?.
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(ii) x∈E,u∈F(x),v ∈G(x)andz ∈T(x)andτ > 0 g(x) = QK(z)[g(x)−τ N(u, v)].
Combining Theorem3.3and3.4, we have the following result.
Theorem 3.5. Let E be a p-uniformly smooth Banach space and X a closed convex cone in B. Let m, g : E → E be the two single-valued mappings, F, G, T : E → CB(E) the multivalued mappings and N : E ×E → E a nonlinear mapping. Then the following statements are equivalent:
(i) x ∈ E, u ∈ F(x), v ∈ G(x)andz ∈ T(x)are solutions of the Problem (2.1),
(ii) x=x−g(x) +m(z) +QX[g(x)−τ N(u, v)−m(z)],for someτ >0.
The following inequality will be used in our main results.
Lemma 3.6. LetE be a real Banach space and jp : E → 2E?, 1 < p <∞a duality mapping. Then, for any givenx, y ∈E, we have
hx−y, jp(x)−jp(y)i ≤2dpρE
4kx−yk d
, where
dp =
kxk2+kyk2 2
.
Proof. The proof of the above inequalities are the generalized form of the proof of Theorem3.3, and hence will be omitted.
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4. Iterative Algorithms and Pertinent Concepts
We now propose the following iterative algorithm for computing the approxi- mate solution of (GCCP).
Algorithm 1. Let g, m: E → Ebe the two single-valued mappings,F, G, T : E → CB(E) the multivalued mappings and N : E ×E → E a nonlinear mapping.
For any givenx0 ∈E,u0 ∈F(x0),v0 ∈G(x0)andz0 ∈T(x0), let x1 =x0−g(x0) +m(z0) +QX[g(x0)−τ N(u0, v0)−m(z0)]
whereτ >0is a constant.
Since u0 ∈ F(x0) ∈ CB(E), v0 ∈ G(x0) ∈ CB(E)and z0 ∈ T(x0) ∈ CB(E), by Nadler’s Theorem [20], there exists u1 ∈ F(x1), v1 ∈ G(x1) and z1 ∈T(x1)such that
ku0−u1k ≤(1 + 1)D(F(x0), F(x1)), kv0−v1k ≤(1 + 1)D(G(x0), G(x1)), kz0 −z1k ≤(1 + 1)D(T(x0), T(x1)), whereDis a Hausdorff metric onCB(E).
Let
x2 =x1−g(x1) +m(z1) +QX[g(x1)−τ N(u1, v1)−m(z1)].
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Since u1 ∈ F(x1) ∈ CB(E), v1 ∈ G(x1) ∈ CB(E) and z1 ∈ T(x1) ∈ CB(E), there existsu2 ∈F(x2),v2 ∈G(x2)andz2 ∈T(x2)such that
ku1−u2k ≤(1 + 2−1)D(F(x1), F(x2)), kv1−v2k ≤(1 + 2−1)D(G(x1), G(x2)), kz1−z2k ≤(1 + 2−1)D(T(x1), T(x2)).
By induction, we can obtain{xn},{un},{vn}and{zn}as
(4.1) xn+1 =xn−g(xn) +m(zn) +QX[g(xn)−τ N(un, vn)−m(zn)].
un∈F(xn);kun−un+1k ≤(1 + (1 +n)−1)D(F(xn), F(xn+1)), vn∈G(xn);kvn−vn+1k ≤(1 + (1 +n)−1)D(G(xn), G(xn+1)), zn ∈T(xn);kzn−zn+1k ≤(1 + (1 +n)−1)D(T(xn), T(xn+1)), n ≥0, whereτ >0is a constant.
These iteration processes have been extensively investigated by various au- thors for approximating either the fixed point of nonlinear mappings or solutions of nonlinear equations in Banach spaces or variational inequalities, variational inclusions, or complementarity problems in Hilbert spaces.
Definition 4.1. A single valued mappingg :E →E is said to be
(i) p-strongly accretive if for allx, y ∈ E there exists jp ∈ Jp(x−y) such that
hg(x)−g(y), jp(x−y)i ≥κkx−ykp for some real constantκ ∈(0,1)and1< p <∞.
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(ii) Lipschitz continuous if for anyx, y ∈E, there exists constantβ >0, such that
kg(x)−g(y)k ≤βkx−yk.
Definition 4.2. A multivalued mapping F : E → CB(E) is said to be D- Lipschitz continuous if for anyx, y ∈E,
D(F(x), F(y))≤µkx−yk forµ >0andD(·,·)is Hausdorff metric defined onCB(E).
Definition 4.3. LetF : E → CB(E)be a multivalued mapping. A nonlinear mappingN :E×E →Eis said to be relaxed accretive with respect to the first argument of mapF, if there exists a constantα >0such that
hN(un,·)−N(un−1,·), jp(xn−xn−1)i ≥ −αkxn−xn−1kp; andN is Lipschitz continuous with respect to the first argument if
kN(u,·)−N(y,·)k ≤σkx−yk, forx, y ∈E, whereσ >0is a constant.
Similarly, we define the Lipschitz continuity of N with respect to second argument.
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5. Main Results
In this section, we show that if E is ap-uniformly smooth Banach space, then the iterative process converges strongly to the given problem (2.1).
Theorem 5.1. LetEbe ap-uniformly smooth real Banach space withρE(τ)≤ cτp for some c > 0, 0 < τ < ∞ and 1 < p < ∞. Let X be a closed convex cone of E. Let m, g : E → E be the two single-valued mappings, F, G, T : E → CB(E)the multivalued mappings. LetK : E →2E such that K(z) = m(z) +X for allx∈E,z ∈T(x)and the following conditions hold.
(i) gandmare Lipschitz continuous;
(ii) gis strongly accretive;
(iii) F, GandT areD-Lipschitz continuous;
(iv) N is Lipschitz continuous with respect to the first as well as the second argument;
(v) N is p-relaxed accretive with respect to the first argument with mapping F :E →CB(E);
(vi)
q+ (1 +pατ +pc22p+1τpσpηp)1/p+τ δξ < 1 and
(5.1) q= 2(1−pκ+c22p+1pβp)1/p+ 2µρ.
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Then for any x0 ∈ E, u0 ∈ F(x0), v0 ∈ G(x0) and z0 ∈ T(x0) the sequencesxn, un, vnand zngenerated by Algorithm 1, converge strongly to some x ∈ E, u ∈ F(x), v ∈ G(x) and z ∈ T(x), which solve the problem (2.1).
Proof. By the iterative schemes (4.1) and Definition3.1, we have kxn+1−xnk
=kxn−g(xn) +m(zn) +QX[g(xn)−τ N(un, vn)−m(zn)]
−xn−1+g(xn−1)−m(zn−1)
−QX[g(xn−1)−τ N(un−1, vn−1)−m(zn−1)]k
≤ kxn−xn−1−(g(xn)−g(xn−1))k+km(zn)−m(zn−1k +kQX[g(xn)−τ N(un, vn)−m(zn)]
−QX[g(xn−1)−τ N(un−1, vn−1)−m(zn−1)]k
≤2kxn−xn−1−(g(xn)−g(xn−1))k+ 2km(zn)−m(zn−1)k +kxn−xn−1−τ(N(un, vn)−N(un−1, vn−1))k
≤2kxn−xn−1−(g(xn)−g(xn−1))k+ 2km(zn)−m(zn−1)k +kxn−xn−1−τ(N(un, vn)−N(un−1, vn))k
(5.2)
+τkN(un−1, vn)−N(un−1, vn−1)k.
By Lemmas 3.2, 3.6, p-strongly accretive, Lipschitz continuity of g and jp ∈ Jp(x+y), we have
kxn−xn−1−(g(xn)−g(xn−1))kp
≤ kxn−xn−1kp+ph−(g(xn)−g(xn−1)), jpi
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≤ kxn−xn−1kp−phg(xn)−g(xn−1), jp(xn−xn−1−(g(xn)−g(xn−1))i
≤ kxn−xn−1kp−phg(xn)−g(xn−1), jp(xn−xn−1)i
−phg(xn)−g(xn−1), jp(xn−xn−1
−(g(xn)−g(xn−1)))−jp(xn−xn−1)i
≤ kxn−xn−1kp−pkkxn−xn−1kp + 2pdpρE
4kg(xn)−g(xn−1)k d
≤ kxn−xn−1kp−pkkxn−xn−1kp + 2pdpc4pkg(xn)−g(xn−1)kp
dp
≤ kxn−xn−1kp−pkkxn−xn−1kp+ 22p+1cpβpkxn−xn−1kp
≤(1−pk+c22p+1pβp)kxn−xn−1kp. (5.3)
By the Lipschitz continuity ofmandD-Lipschitz continuity ofT, we have km(zn)−m(zn−1)k ≤µkzn−zn−1k
≤µ(1 +n−1)D(T(xn), T(xn−1))
≤µ(1 +n−1)ρkxn−xn−1k.
(5.4)
Since F is η-Lipschitz continuous, G is ξ-Lipschitz continuous and N is Lipschitz continuous with respect to the first and second arguments with posi- tive constantsσandδrespectively. Using a similar argument to that of Xiaolin He [23], we have for every un, u0n ∈ F(xn), N(un, v) = N(u0n, v). On the
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other hand un−1 ∈ F(xn−1), and from the definition of Hausdorff metric and compactness ofF(xn), there is au0n∈F(xn)such that
ku0n−un−1k ≤D(F(xn), F(xn−1)).
Hence
kN(un, vn)−N(un−1, vn)k=kN(u0n, vn)−N(un−1, vn)k
≤σku0n−un−1k
≤σ(1 +n−1)D(F(xn), F(xn−1))
≤σ(1 +n−1)ηkxn−xn−1k.
(5.5)
Similarly, we get
(5.6) kN(un−1, vn)−N(un−1, vn−1)k ≤δξ(1 +n−1)kxn−xn−1k.
By using Lemma3.6, thep-relaxed accretive mapping and (5.5), we have kxn−xn−1−τ(N(un, vn)−N(un−1, vn))kp
≤ kxn−xn−1kp
−pτhN(un, vn)−N(un−1, vn),
jp(xn−xn−1−τ(N(un, vn)−N(un−1, vn)))i
≤ kxn−xn−1kp−pτhN(un, vn)−N(un−1, vn), jp(xn−xn−1)i
−phτ(N(un, vn)−N(un−1, vn)),
jp(xn−xn−1−τ(N(un, vn)−N(un−1, vn)))−jp(xn−xn−1)i
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≤ kxn−xn−1kp+pτ αkxn−xn−1kp + 2pdpρE
τ4kN(un, vn)−N(un−1, vn)k d
≤ kxn−xn−1kp+pατkxn−xn−1kp
+ 2pτpc4pkN(un, vn)−N(un−1, vn)kp
≤ kxn−xn−1kp+pατkxn−xn−1kp
+pτpc22p+1(1 +n−1)pσpηpkxn−xn−1kp
≤(1 +pατ +pc22p+1(1 +n−1)pτpσpηp)kxn−xn−1kp. (5.7)
Now from (5.2) – (5.7), we get kxn−xn−1k
≤2(1−pk+c22p+1pβp)1/pkxn−xn−1k + 2µρ(1 +n−1)kxn−xn−1k
+ (1 +pατ +pc22p+1(1 +n−1)pτpσpηp)1/pkxn−xn−1k +τ δξ(1 +n−1)kxn−xn−1k
≤[2(1−pk+c22p+1pβp)1/p+ 2µρ(1 +n−1)
+ (1 +pατ +pc22p+1(1 +n−1)pτpσpηp)1/p+τ δξ(1 +n−1)]
≤[qn+ (1 +pατ +pc22p+1(1 +n−1)pτpσpηp)1/p +τ δξ(1 +n−1)]kxn−xn−1k
≤θnkxn−xn−1k, (5.8)
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where
θn =qn+ (1 +pατ +pc22p+1(1 +n−1)pτpσpηp)1/p+τ δξ(1 +n−1) and
(5.9) qn = 2(1−pk+c22p+1pβp)1/p+ 2µρ 1 +n−1 . Letting
(5.10) θ =q+ (1 +pατ+pc22p+1τpσpηp)1/p+τ δξ and
q = 2(1−pk+c22p+1pβp)1/p+ 2µρ.
We know that θn → θ as n → ∞. From condition (5.1), it follows that θ < 1. Henceθn < 1, fornsufficiently large. Consequently{xn}is a Cauchy sequence and this converges to some x ∈ E. By Algorithm 1 and the D- Lipschitz continuity ofF, GandT, it follows that
kun−un−1k ≤(1 +n−1)D(F(xn), F(xn−1))
≤(1 +n−1)ηkxn−xn−1k, kvn−vn−1k ≤(1 +n−1)D(G(xn), G(xn−1))
≤(1 +n−1)ξkxn−xn−1k, kzn−zn−1k ≤(1 +n−1)D(T(xn), T(xn−1))
≤(1 +n−1)ρkxn−xn−1k,
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which means that {un}, {vn}and{zn}are all Cauchy sequences inE. There- fore there existu∈E,v ∈Eandz ∈Esuch thatun →u,vn→vandzn →z asn→ ∞. Sinceg, m, F, G, T, N andQX are all continuous, we have
x=x−g(x) +QX[g(x)−τ N(u, v)−m(z)].
Finally, we prove thatu∈F(x). In fact, sinceun ∈F(xn)and d(un, F(x))≤max
(
d(un, F(x)), sup
u∈F(x)
d(T(xn), u) )
≤max (
sup
y∈F(xn)
d(y, F(x)), sup
u∈F(x)
d(F(xn), u) )
=D(F(xn), F(x)), We have
d(u, F(x))≤ ku−unk+d(un, F(x))
≤ ku−unk+D(F(xn), F(x))
≤ ku−unk+ηkxn−xk →0 asn→ ∞,
which implies thatd(u, F(x)) = 0. Since F(x) ∈ CB(E), it follows thatu∈ F(x). Similarly, we can prove thatG(x)∈CB(E)i.e.,v ∈ G(x)andT(x)∈ CB(E)i.e.,z ∈T(x). Hence by Theorem3.5, we get the conclusion.
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