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Physical Chemistry of Surfaces

2019-20/Spring

Prof. Krisztina LÁSZLÓ

F I. / 1st floor135 klaszlo@mail.bme.hu

http://oktatas.ch.bme.hu/oktatas/konyvek/fizkem/

PHYSICAL CHEMISTRY OF SURFACES

1

Requirements 3 homeworks

Participation at 67 % of the contact hours Completed homeworks

Optional test in the last week (threshold: 51 %) References

• Compendium

• Thommes et al: IUPAC recommendation

• Rouquerol, J., Rouquerol, J., Sing, K: Adsorption by powders & porous solids - Academic 1999

Teaching assistent:

shereen.farah@mail.bme.hu

(2)

Particle size vs. surface 1 cube 1000 cubes 10

21

cubes

Surface/volume

3

„God created space,

and the devil created surface”

Wolfgang Pauli

Molecules on surface, %

Surface tension

293 K

mJ/m

2

or mN/m interaction He(l) 0,308

2,5 K

dispersion

n-hexane 18 dispersion

water 72 H-bridge

Hg(l) 472 metallic bond

intensive property,

work/surface area; force/route ,

  

   s pT   G

A

Why is surface position distinguished?

(3)

5

High surface area materials Examples1

Small particles

Nanoparticles (particles between 1 and 100 nm in size)

High surface area materials Examples2

(4)

Examples3

7

High surface area materials - small/nano particles

- porous materials

High is relative

Low surface exhibit the same feature, but

the extent is limited

(5)

Characterisation of particles -size

range

distribution -shape (morphology)

In case of nanoparticles:

d/l may be as high 1,5∙10

3

9

Particles, sizes and distributions

aspect ratio: shortest/longest dimension

Relevance of particle size (distribution)

Key factor in several pratical applications

Flow/storage behaviour

Sievability

Rheological properties (viscosity) Adhesion (aggregation)

Sedimentation Dusting

Activity/reaction rate (e.g., efficiency of a catalyst) Solubility , rate of absorption (e.g., drug uptake) Rate of burning (fuel)

Rate and measure of gas uptake Water uptake (hydration) Sensitivity to humidity

Penetration during breathing (lung)

… etc.

(6)

11

The size of the particles in the same batch might be different

Monodisperse:

set of particles of identical size (narrow size distribution)

Bi…

Polydisperse:

set of particles of different size (wide size distribution)

dispersity index: PDI

Calculation of the average size:

size of particles: xi

number of particles with size xi: i

i i N

i

x   x

i i W

i

x x W

  W

WN

PDI x x

i) each particle is equal: average by number

ii) particles have different weight (Wi) and we need the average by weight

iii) particles have different volume (Vi) and we need the average by volume

 

i i

V

i

x x V

V

V

N

PDI x x

 1

PDI

if the system is monodisperse

(7)

3 4 4

3 3 3

1 2 10 1 10002 1 2 10 1 1002 9,98

i

i

i i

i i W

i i

d d N d d W

W d N

  

    

  

  

i i i

x x

  

The diameter of the average ball is 4;

i.e., 3 average ball give the same chain length as our 3 balls of real size

Let’s have a sackful of these balls, all made of the same material. Let’s separate them by size and weigh the small and large balls (Wi). The average diameter by weight is:

13

Example:

4

3

 3

sphere

Vr

W

2.5

N

PDI d d

Differencial Integral

Size distribution

(Relative) number of particles

Particle size Frequency curve

Total

% of particles larger than the given size Particle size

(8)

Methods and sizes

Sieve 25 m-125 mm

wet sieve 10 m -100 m

Sedimentation (H

2

O) above 1 m

Centrifugation below 5 m

Optical microscopy 200 nm – 150 m

Ultramicroscopy 10 nm – 1 m

Electronmicroscopy (scanning – SEM,

transmission - TEM) 1 nm – 1 m

Light scattering 1 nm – a few m

15

The various experimental methods are sensitive to different characteristics of the particles – may provide different results

WHEN REPORT SIZE AND DISTRIBUTION, NAME THE METHOD AS WELL

PARTICLE SIZE but which one?

Ibuprofen crystals (SEM)

(9)

Equivalent sphere (here: by

volume)

- A single characteristic size (r or d) - Easy calculation:

- Simple and easy to use

3

6 1 d

V   S   d

2 3

6 d m  

17

The size of the equivalent sphere also depends on the method

WHEN REPORT SIZE AND DISTRIBUTION,

(10)

micropore

mesopore

Ink-bottle

Particle-particle interaction

Particle size

Interparticle space

Macropore

19

Size:

IUPAC-classification (1984):

o micropore

d < 2 nm

o mesopore

2 nm < d < 50 nm

o macropore

d > 50 nm

o

supermacropore d > 500 nm

Pores

Closed/open/one end open Shape: cylindrical

slit ink-bottle

Porosity

pores matrix apparent

V  

 

  

External and internal surface

(11)

Fabrication of high surface area material 1. Dispersion (top down)

incoherent coherent systems

21

2. Synthesis (bottom up)

 Vapour deposition

 Sol/gel

(12)

Separates and connects Interface

23

1. state of the connecting phases

(solid, liquid, gas/vapour): S/S; S/L; S/G; L/L; L/G

Classification of interfaces

(13)

2. geometry: planar, curved

Step

Single atom terrace

terrace

corner

Adsorption of He atom on solid Xe (100) surface

No flat surface on molecular/atomic level

3. energetics

low and high energy

homogeneous or heterogeneous

energy distribution

(14)

The consequence of the excess surface energy

G = H - TS exothermic mobility: fluid phase

solid phase

27

Spontaneous processes

1. Surface (grain boundary) segregation

S

PONTANEOUS PROCESSES REDUCING EXCESS SURFACE ENERGY

(15)

29

Alloy of A with impurity B

2. (Ad)sorption

(16)

3. Contact wetting

S/G + a drop of liquid  S/L + L/G

SG

=

SL

+

LG

cos

S

-

SG

=  spreading pressure

Complete wetting  = 0°

YOUNG eq.

31

LG

 

LGLG

Desorption: removal of the adsorbed species

Equilibrium process Adsorption : enrichment on the surface

(binding on „active” sites)

Adsorption is brought by the forces acting between the

solid and the molecules of the gas. These forces are of

two kinds: physical (physisorption) and chemical

DYNAMIC EQUILIBRIUM

(17)

G = H - TS exothermic

rate mobility: fluid

solid

33

Spontaneous process

Quantitative description of the adsorption

adsorbed excess

if c

g

is low

Vs= Ast

Vs t

s

s

0 0

n cdV A cdz  s

tg g

0

n A cdz c V

 

s g g

n n c V

g,0 s g

solid solid,0

V  V  V  V  V  V

  g g,0 n n c V

Vg,0=Vg+Vs

  g gg s n n c V c V

s g s

n n c V

n

s

n

adsorbed amount

surface area

mass of solid

A

s

Hivatkozások

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