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Existence and uniqueness of positive even homoclinic solutions for second order differential equations

Adel Daouas

B

and Monia Boujlida

High School of Sciences and Technology, Sousse University, Hammam Sousse, 4011, Tunisia Received 12 February 2019, appeared 28 June 2019

Communicated by Petru Jebelean

Abstract. This paper is concerned with the existence of positive even homoclinic solu- tions for the p-Laplacian equation

(|u0|p−2u0)0a(t)|u|p−2u+ f(t,u) =0, tR,

where p2 and the functions aand f satisfy some reasonable conditions. Using the Mountain Pass Theorem, we obtain the existence of a positive even homoclinic solution.

In case p = 2, the solution obtained is unique under a condition of monotonicity on the function u 7−→ f(t,u)u . Some known results in the literature are generalized and significantly improved.

Keywords: homoclinic solution, the (PS)-condition, Mountain Pass Theorem, p- Laplacian equation, uniqueness.

2010 Mathematics Subject Classification: 34C37, 35A15, 37J45.

1 Introduction

In this paper, we study the existence of positive even homoclinic solutions for the p-Laplacian equation

(|u0|p2u0)0−a(t)|u|p2u+ f(t,u) =0, t ∈R, (1.1) where p ≥2. We assume that

(H0) a ∈ C1(R,R),f ∈ C(R×R,R) is continuously differentiable with respect to the first variable and there exist constantsa0,Asuch that 0<a0 ≤a(t)≤ A. Moreover,a(−t) = a(t), f(−t,u) = f(t,u)andta0(t)>0,t ft(t,u)<0 fort6=0, u>0.

By a solution of (1.1), we mean a function u ∈ C1(R,R)such that (|u0|p2u0)0 ∈ C(R,R) and equation (1.1) holds for every t ∈ R. We say that a solution u of (1.1) is a nontrivial homoclinic solution (to 0) ifu6≡0,u(t)→0 andu0(t)→0 as|t| →∞.

When p=2, equation (1.1) reduces to the second order differential equation

u00−a(t)u+ f(t,u) =0, t ∈R, (1.2)

BCorresponding author. Email: daouasad@gmail.com

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which is a generalization of

u00−a(t)u+b(t)u2+c(t)u3=0, t ∈R. (1.3) The existence of a nontrivial positive homoclinic solution of equation (1.3) follows from [7], where the coefficients are either even or periodic. In the case of evenness and under the following conditions mainly

0< a<a(t), 0≤b≤b(t)≤B, 0<c≤c(t)≤ C, for allt ∈R, (1.4) witha,b,c,B,Care real constants and

ta0(t)>0, tb0(t)≤0, tc0(t)< 0 for allt 6=0,

the authors proved the existence of a unique nontrivial even positive homoclinic solution by using variational approach. Their result extends the existence theorem established earlier by Korman and Lazer in [10], whereb(t)is identically zero. It is well known that equation (1.3) plays a key role in biomathematics models suggested by Austin [1] and Cronin [3] to describe an aneurysm of the circle of Willis. Also, equation (1.1) was considered, recently in [17], in the special case where f(t,u) = λb(t)|u|q2u, with 2 ≤ p < q,λ >0 and the functions aand bare strictly positive and even.

During the last decades the study of homoclinic solutions for the p-Laplacian equation (1.1) and the more general Hamiltonian system

d

dt(|u˙(t)|p2u˙(t))−a(t)|u|p2u+∇V(t,u(t)) =0, t∈R,

where p > 1,V ∈ C1(R×RN,R), has been investigated by many authors with various non- linearities (see [4,9,12,16,17] and references therein). Whereas, the existence results for even homoclinics are scarce. Moreover, the question of uniqueness is treated only in limited cases (see [2,18]) and frequently remains open.

Motivated by the above works mainly, in this paper, we study the existence of positive even homoclinic solution for thep-Laplacian equation (1.1). This will be done under assump- tions less restrictive than the so-called Ambrosetti–Rabinowitz superquadraticity condition.

In particular, the nonlinearity f may vanish and change sign. Also, the inequalities in (1.4) may be dropped. On the other hand, since our approach is based on critical point theory, more efforts have to be paid to guarantee the uniqueness of the solution. In this direction, we establish some criteria to ensure the uniqueness of the homoclinic solution obtained for (1.2).

To the best knowledge of the authors it is the first time where uniqueness of even homoclinic solutions for second order differential equations with general nonlinearity is considered.

Our main results are the following.

Theorem 1.1. Under the assumptions(H0)and (H1) f(t,u) =o(|u|p1)as|u| →0uniformly in t, (H2) there existsµ> p such that

µF(t,u)≤ f(t,u)u, ∀ t∈R, u≥0, where F(t,u) =Ru

0 f(t,s)ds,

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(H3) F(t0,u0)>0for some t0Rand u0>0,

the equation(1.1)has at least one positive nontrivial homoclinic solution. Moreover this solution is an even function with u0(t)<0for t>0.

Example 1.2. Let

f(t,u) = (et2−1)u2+u3, ∀(t,u)∈R2.

It is easy to see that the function f satisfies all the assumptions of Theorem (1.1) with p = 2 andµ=3 but does not satisfy neither the (AR)-condition nor the condition (1.4) above. Hence Theorem (1.1) extends the results in [7,10,17] mainly.

In case p=2, we have the following result.

Theorem 1.3. Under the assumptions(H0)–(H3)and

(H4) for a.e. t∈ R,the function u 7→ f(t,uu ) is increasing on]0,+[, the homoclinic solution obtained above for equation(1.2)is unique.

2 Preliminary results

We shall obtain a solution of (1.1) as the limit asT→of the solutions of ((|u0|p2u0)0−a(t)|u|p2u+ f(t,u) =0, t ∈(−T,T)

u(−T) =u(T) =0. (2.1)

For each T≥1, we define the Sobolev space

ET =nu∈W1,p((−T,T),R):u(−T) =u(T) =0o , endowed with the norm

kuk= Z T

T

(|u0(t)|p+|u(t)|p)dt 1p

.

To prove our theorems we need the following theorem introduced in [14]:

Theorem 2.1 (Mountain Pass Theorem). Let E be a real Banach space and I ∈ C1(E,R) satisfy (PS)-condition. Suppose that I satisfies the following conditions:

(i) I(0) =0;

(ii) there existsρ, α>0such that I|∂Bρ(0)≥ α;

(iii) there exists e∈ E\Bρ such that I(e)≤0, where Bρ(0)is an open ball in E of radiusρcentered at0;

then I possesses a critical value c ≥α. Moreover, c can be characterized as c= inf

γΓmax

t∈[0,1]I(γ(t)), where

Γ={γ∈ C([0, 1],E):γ(0) =0, γ(1) =e}.

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Proposition 2.2([17]). Let u∈Wloc1,p(R). Then:

(1) If T ≥1, for t∈[T−12,T+12], max

t∈[T12,T+12]

|u(t)| ≤2p

1 p

Z T+12

T12 |u0(s)|p+|u(s)|pds1p

. (2.2)

(2) For every u∈W01,p(−T,T),

kukL(−T,T)≤2kuk. (2.3) Lemma 2.3. Let p≥2, u∈C1(R)and(|u0|p2u0)0 ∈C(R). Then

(|u0(t)|p)0 = p

p−1(|u0(t)|p2u0(t))0u0(t). (2.4) Proof. Let

(|u0(t)|p)0 = p|u0(t)|p2u0(t)u00(t), (2.5) on the other hand, one has

(|u0(t)|p)0 = (|u0(t)|p2u0(t)u0(t))0 = (|u0(t)|p2u0(t))0u0(t) + (|u0(t)|p2u0(t))u00(t). (2.6) Combining (2.5) with (2.6), we establish (2.4).

Let us consider the problem

((|u0|p2u0)0+g(t,u) =0, t∈ (−T,T)

u(−T) =u(T) =0, (2.7)

whereg∈ C1([−T,T]×R+)and satisfies

g(−t,u) =g(t,u), t∈ (−T,T), u>0, g(t, 0) =0, t∈ (−T,T)

tgt(t,u)<0, t∈ (−T,T)\ {0}, u>0.

(2.8)

The following lemma is an extension of Lemma 1 of [11] for p-Laplacian nonlinear equations.

Lemma 2.4([17]). Assume that g ∈ C1([−T,T]×R+)satisfies (2.8). Then any positive solution of (2.7)is an even function such that max{u(t),−T ≤ t ≤ T} = u(0)and u0(t) < 0 for t ∈ (0,T). Moreover, any two positive solutions of (2.7)do not intersect on(−T,T) and hence they are strictly ordered on(−T,T).

Proposition 2.5. Under the assumptions(H0)–(H3), the problem(2.1)possesses a nontrivial positive solution uT for any T≥1. Moreover, there exist constants K,c>0, such that

(i)

Z T

T

(|u0T(t)|p+|uT(t)|p)dt≤K, ∀T ≥1, (2.9) (ii)

uT(0)> c, ∀ T≥1. (2.10)

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Proof. Consider the modified problem

((|u0|p2u0)0−a(t)|u|p2u+ f(t,u+) =0, t ∈(−T,T)

u(−T) =u(T) =0, (2.11)

where u+=max(u, 0). By (H1), we have f(t, 0) =0 for allt∈ R. So, analogously to [5,17], it is easy to see that solutions of (2.11) are positive solutions of (2.1).

To prove the existence of a solution to (2.11), we consider the functional IT defined on ET by IT(u) = 1

p Z T

T

|u0(t)|p+a(t)|u(t)|pdt−

Z T

TF(t,u+(t))dt, (2.12) for allu ∈ ET. It is well known that under the assumptions of Theorem (1.1), IT ∈C1(ET,R) and

IT0(u).v=

Z T

T

|u0(t)|p2u0(t)v0(t) +a(t)|u(t)|p2u(t)v(t)dt−

Z T

T f(t,u+(t))v(t)dt, (2.13) for all u,v∈ ET.

Step 1: The functionalIT satisfies the (PS)-condition.

Let{uj} ⊂ ET be such that IT(uj)is bounded and IT0(uj)→ 0 as j→ +∞. Then, by (H2), (2.12) and (2.13), there exists a constant MT >0 such that

MT+kujk ≥µIT(uj)−IT0(uj)uj

= (µ p−1)

Z T

T

|u0j(t)|p+a(t)|uj(t)|pdt+

Z T

T

f(t,u+j )u+jµF(t,u+j )dt

≥aˆµ−p p kujkp,

where ˆa=min{1,a0}. Sinceµ> p, then the sequence{uj}is bounded inET. By the compact imbedding ET ⊂ C[−T,T], there exists u ∈ ET and a subsequence of {uj}, still denoted by {uj}such that

uj*u in ET, (2.14)

uj→u inC[−T,T]. (2.15)

From equation (2.13), one has (IT0(uj)−IT0(u)).(uj−u) =

Z T

T

|u0j(t)|p2u0j(t)− |u0(t)|p2u0(t)(u0j−u0)dt

+

Z T

Ta(t)|uj(t)|p2uj(t)− |u(t)|p2u(t)(uj−u)dt

Z T

T

f(t,u+j )− f(t,u+)(uj−u)dt.

(2.16)

Since IT0(uj)→0 as j→+∞, we have

j→+lim(I0T(uj)−IT0(u)).(uj−u) =0 (2.17) and by continuity of f and (2.15), we have

j→+lim Z T

T

f(t,u+j )− f(t,u+)(uj−u)dt=0. (2.18)

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For anyξ,ηR; we have the following inequality (see Remark 3.2 in [15]) (|ξ|p2ξ− |η|p2η)(ξη)≥ 2

p

|ξη|p

2p11, p≥2.

By the last inequality, one has

|u0j(t)|p2u0j(t)− |u0(t)|p2u0(t)(u0j(t)−u0(t))

+a(t)|uj(t)|p2uj(t)− |u(t)|p2u(t)(uj(t)−u(t))

2

p(2p1−1)|u0j(t)−u0(t)|p+a 2

p(2p1−1)|uj(t)−u(t)|p

2 ˆa p(2p1−1)

|u0j(t)−u0(t)|p+|uj(t)−u(t)|p. This coupled with (2.16)–(2.18), implies

j→+limkuj−ukp ≤0.

Souj →uin ET.

Step 2:Obviously IT(0) =0. Furthermore, in view of (H1), we see that, F(t,u) =o(|u|p) as|u| →0, uniformly int∈R, that is, there existsδ ∈(0, 1)such that

F(t,u)≤ a0

2p|u|p, for|u| ≤δ. (2.19) Lettingρ := δ2 andu∈ ET, such thatkuk=ρ, then 0<kukδ.

By (2.19), we have IT(u) =

Z T

T

1 p

|u0(t)|p+a(t)|u(t)|pdt−

Z T

TF(t,u+)dt

1 p

Z T

T

|u0(t)|pdt+ a0 2p

Z T

T

|u(t)|pdt

aˆ

2pkukp= aˆ

2pρp=:α>0.

Hence, the functionalIT satisfies the condition (ii) of the Mountain Pass Theorem.

Step 3: Firstly, without loss of generality, we may assume u0 = 1 in (H3). Then, by the continuity ofF, there exist constantsc1 >0,η>0 such that

F(t, 1)≥c1, ∀t ∈[t0η,t0+η]. (2.20) On the other hand, by (H2), it’s easy to check that

F(t,u)≥F(t, 1)uµ, ∀t∈R,u≥1. (2.21) Combining (2.20) and (2.21), one obtains

F(t,u)≥c1uµ−c2, ∀t∈[t0η,t0+η], u≥0, (2.22)

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wherec2 =max{|F(t,u)−c1uµ|; 0≤u≤1,|t−t0| ≤η}. Now, let ˆu∈Ebe given by

uˆ(t) =

(cos[π(t−t0)], ift∈[t0η,t0+η];

0, ift∈[−T,T]\[t0η,t0+η]. (2.23) Then, for alls >0 we have by (2.22),

I(suˆ) = s

p

pkuˆkp

Z t0+η t0η

F(t,suˆ)dt

s

p

pkuˆkp−c1sµ Z t0+η

t0η

ˆ

uµ(t)dt+2c2t0.

Since µ > p then I(suˆ) < 0 = I(0)for some s > 0 such that ksuˆk > ρ, whereρ is defined in Step 2. So, the functional IT satisfies all the conditions of the Mountain Pass Theorem and therefore there exists a solutionuT ∈ ET such that

cT = IT(uT) = inf

wΓTmax

ξ∈[0,1]IT(w(ξ)), IT0(uT) =0, (2.24) where

ΓT ={w∈C([0, 1],ET):w(0) =0, w(1) =suˆ}. Using the variational characterization (2.24), we have

cTaˆ

pρp >0.

Hence,uT is a nontrivial positive solution of (2.1). Moreover, by Lemma (2.4), one gets

maxTtTuT(t) =uT(0) and u0T(t)<0, ∀t ∈(0,T). Step 4: Uniform estimates.

LetT1≥ T≥1. By continuation with zero of a functionu ∈ET to[−T1,T1], we haveET ⊂ ET1 and ΓTΓT1. Using the variational characterization (2.24), we infer that cT1 ≤ cT ≤ c1 and then

Z T

T

1

p(|u0T(t)|p+a(t)|uT(t)|p)−F(t,uT)dt≤c1, therefore, by (H2)

Z T

T

1 p

|u0T(t)|p+a(t)|uT(t)|pdt≤

Z T

TF(t,uT)dt+c1,

1 µ

Z T

T f(t,uT)uTdt+c1.

(2.25)

Multiplying the equation (2.1) byuT and integrating by parts, we get Z T

T

(|u0T(t)|p+a(t)|uT(t)|p)dt=

Z T

T f(t,uT)uTdt. (2.26) Using (2.26) in (2.25), we obtain

c1 ≥ 1

p − 1 µ

Z T

T

(|u0T(t)|p+a(t)|uT(t)|p)dt≥ aˆ(µ−p)

µp kuTkp, (2.27)

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which gives (2.9) withK = c1µp

ˆ a(µp).

Step 5:It remains to show that there is a constantc>0 such that

uT(0)> c uniformly inT. (2.28) With this aim, we introduce the “energy function” fort≥0 (whereuT(t)≥0), by

E(t) = p−1

p |u0T(t)|pa(t)

p |uT(t)|p+F(t,uT(t)). DifferentiatingE(t)and using (2.11), (2.4) and (H0), we obtain

E0(t) =−1

pa0(t)|uT(t)|p+Ft(t,uT(t))≤0 for all 0≤t≤ T.

Hence

E(0)≥E(T) = 1

p|u0T(T)|p≥0.

SinceuT(t)is even,u0T(0) =0, then E(0) =−a(0)

p |uT(0)|p+F(0,uT(0))≥0, which implies

F(0,uT(0))≥ a(0)

p |uT(0)|p, and consequently

F(0,uT(0))

|uT(0)|pa(0)

p . (2.29)

On the other hand, by (H1), one gets F(t,u)

|u|p →0 as|u| →0,uniformly in t. (2.30) Comparing (2.29) with (2.30), we obtain the estimate (2.28).

3 Proof of Theorem 1.1

TakeTnand consider the problem (2.11) on the interval(−Tn,Tn), ((|u0|p2u0)0−a(t)|u|p2u+f(t,u+) =0, t∈ (−Tn,Tn)

u(−Tn) =u(Tn) =0. (3.1)

Let un be the solution of (3.1) given by Proposition 2.5 and extended by zero outside the interval[−Tn,Tn].

Claim 1:Arguing as in [17], we see that the sequence(un)nadmits a subsequence, still denoted by(un)n, that converges to a certain function uinCloc1 (R). Hence, we can pass to the limit in the equation (3.1), and we conclude thatu(t)solves (1.1). Moreover, we have

Z +

(|u0(t)|p+|u(t)|p)dt< ∞. (3.2)

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Since by Lemma2.4 the functions un(t)are even, with the only maximum att = 0, the same is true for their limit u(t). That u0(t) < 0 for t > 0 is easily seen by differentiating (1.1) (a similar argument can be found in [11]).

Claim 2: We will prove thatu(t)is nonzero andu(±) =u0) =0.

Firstly, by (2.28), there is a constantc>0 such that

un(0)>c uniformly inn∈N. (3.3) By passing to the limit as n→in (3.3), we obtain

u(0)≥c>0,

which implies thatuis not identically zero. Moreover, from (3.2) and Proposition2.2, it follows

Tnlim→± max

t∈[Tn12,Tn+12]

|u(t)| ≤ lim

Tn→±2p

1 p

Z Tn+12

Tn12 |u0(t)|p+|u(t)|pdt1p

=0, (3.4) sou(±) =0.

Next we prove that u0(+) = 0 (the arguments for u0(−) = 0 are similar). By the assumptions (H0), (H1) and equation (1.1) there existsM >0 such that

|u0(t)|p2u0(t)0

≤ M, ∀ t∈R.

If u0(+) 6= 0, there exist e1 > 0 and a monotone increasing sequence tk −→ +such that

|u0(tk)| ≥(2e1). Then fort∈ [tk,tk+ Me1], one has

|u0(t)|p1= |u0(tk)|p2u0(tk) +

Z t

tk

|u0(s)|p2u0(s)0ds

≥ |u0(tk)|p1

Z tk+e1

M

tk

|u0(s)|p2u0(s)

0 ds

≥ 2e1e1

MM =e1, which is in contradiction with (3.4).

4 Proof of Theorem 1.3

Letv be another positive solution of (1.2) (which is also an even function with the only maxi- mum att =0). Multiplying both sides of (1.2) byvand integrating by parts onRwe get

Z +

h−u0v0−a(t)uv+ f(t,u)vi

dt=0. (4.1)

Also, we have

Z +

h−u0v0−a(t)uv+ f(t,v)ui

dt=0. (4.2)

Subtracting (4.2) from (4.1), we get Z +

hf(t,u)

u − f(t,v) v

i

uvdt=0.

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It follows from (H4) that u and v cannot be ordered, and so they have to intersect. By the existence-uniqueness theorem for initial value problems, two cases are possible: eitheruand vhave at least two positive points of intersection, or only one positive point of intersection.

Assume first ξ1 > 0 is the smallest positive point of intersection and ξ2 > ξ1 the next one, and u(t) < v(t) on (ξ1,ξ2). Multiply the equation (1.2) by u0 and integrate from ξ1 to ξ2. Denoting byt = t1(u)the inverse function of u(t)on (ξ1,ξ2). Also, denoting by g(t,u) =

−a(t)u+ f(t,u), andu1= u(ξ1) =v(ξ1),u2=u(ξ2) =v(ξ2), we get 1

2u02(ξ2)− 1

2u02(ξ1) +

Z u2

u1

g(t1(u),u)du=0, (4.3) Doing the same forv(t), and denoting its inverse on(ξ1,ξ2)byt= t2(v), we obtain

1

2v02(ξ2)−1

2v02(ξ1) +

Z u2

u1

g(t2(v),v)dv=0, (4.4) Subtracting (4.4) from (4.3), we get

1 2

u02(ξ2)−v02(ξ2)+ 1 2

v02(ξ1)−u02(ξ1)+

Z u1

u2

h

g(t1(u),u)−g(t2(u),u)idu=0, (4.5) Note thatu2<u1andt2(u)>t1(u)for all u∈(u2,u1). Sinceg(t,u)is decreasing int, then

Z u1

u2

h

g(t1(u),u)−g(t2(u),u)idu≤0. (4.6) On the other hand , it is easy to see that

u0(ξ1)≤v0(ξ1)≤0, v0(ξ2)≤u0(ξ2)≤0, which imply

1 2

u02(ξ2)−v02(ξ2)+1 2

v02(ξ1)−u02(ξ1)<0. (4.7) Combining (4.6), (4.7) with (4.5) we obtain a contradiction, which rules out the case of two positive intersection points. If ξ1 is the only intersection point, we integrate from ξ1 to ∞, obtaining a similar contradiction. Uniqueness of the solution follows.

Acknowledgements

The authors are grateful to the anonymous referee for comments that greatly improved the manuscript.

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