volume 5, issue 3, article 58, 2004.
Received 09 January, 2004;
accepted 22 April, 2004.
Communicated by:P.S. Bullen
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Journal of Inequalities in Pure and Applied Mathematics
A DISCRETE EULER IDENTITY
A. AGLI ´C ALJINOVI ´C AND J. PE ˇCARI ´C
Department of Applied Mathematics
Faculty of Electrical Engineering and Computing Unska 3, 10 000 Zagreb, Croatia.
EMail:andrea@zpm.fer.hr Faculty of Textile Technology University of Zagreb Pierottijeva 6, 10000 Zagreb Croatia.
EMail:pecaric@mahazu.hazu.hr
c
2000Victoria University ISSN (electronic): 1443-5756 086-04
A Discrete Euler Identity A. Agli´c Aljinovi´c and J. Peˇcari´c
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Abstract
A discrete analogue of the weighted Montgomery identity (i.e. Euler identity) for finite sequences of vectors in normed linear space is given as well as a discrete analogue of Ostrowski type inequalities and estimates of difference of two arithmetic means.
2000 Mathematics Subject Classification:26D15
Key words: Discrete Montgomery identity, Discrete Ostrowski inequality.
Contents
1 Introduction. . . 3 2 Discrete Weighted Euler Identity. . . 5 3 Discrete Ostrowski Type Inequalities . . . 13 4 Estimates of the Differences Between Two Weighted Arith-
metic Means. . . 24 References
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1. Introduction
The following Ostrowski inequality is well known [10]:
f(x)− 1 b−a
Z b a
f(t)dt
≤
"
1
4+ x− a+b2 2
(b−a)2
#
(b−a)kf0k∞.
It holds for everyx∈[a, b]wheneverf : [a, b]→Ris continuous on[a, b]and differentiable on(a, b)with derivativef0 : (a, b)→Rbounded on(a, b)i.e.
kf0k∞= sup
t∈(a,b)
|f0(t)|<+∞.
Let f : [a, b] → R be differentiable on [a, b], f0 : [a, b] → R integrable on [a, b]andw : [a, b] → [0,∞)some probability density function, i.e. integrable function satisfying Rb
a w(t)dt = 1; defineW(t) = Rt
aw(x)dx for t ∈ [a, b], W(t) = 0fort < aandW(t) = 1fort > b. The following identity, given by Peˇcari´c in [11], is the weighted Montgomery identity
f(x) = Z b
a
w(t)f(t)dt+ Z b
a
Pw(x, t)f0(t)dt, where the weighted Peano kernel is
Pw(x, t) =
( W(t), a≤t≤x, W(t)−1 x < t≤b.
All results in this paper are discrete analogues of results from [1]. The aim of this paper is to prove the discrete analogue of the weighted Euler identity for
A Discrete Euler Identity A. Agli´c Aljinovi´c and J. Peˇcari´c
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finite sequences of vectors in normed linear spaces and to use it to obtain some new discrete Ostrowski type inequalities as well as estimates of differences be- tween two (weighted) arithmetic means. In Section2, a discrete weighted Mont- gomery (i.e. Euler) identity is presented. In Section 3, Ostrowski’s inequality and its generalization are proved. These are the discrete analogues of some re- sults from [6]. In Section4, estimates of differences between two (weighted) arithmetic means are given and these are the discrete analogues of some results from [2], [3], [4], [5] and [12].
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2. Discrete Weighted Euler Identity
Let x1, x2, . . . , xn be a finite sequence of vectors in the normed linear space (X,k·k) and w1, w2, . . . , wn finite sequence of positive real numbers. If, for 1≤k ≤n,
Wk =
k
X
i=1
wi, Wk=
n
X
i=k+1
wi =Wn−Wk,
then we have, see [9],
(2.1)
n
X
i=1
wixi
=xkWn+
k−1
X
i=1
Wi(xi−xi+1) +
n−1
X
i=k
Wi(xi+1−xi), 1≤k ≤n.
The difference operator∆is defined by
(2.2) ∆xi =xi+1−xi.
So using formula (2.1), we get the discrete analogue of weighted Mont- gomery identity
(2.3) xk = 1
Wn
n
X
i=1
wixi+
n−1
X
i=1
Dw(k, i) ∆xi,
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where the discrete Peano kernel is defined by
(2.4) Dw(k, i) = 1 Wn ·
( Wi, 1≤i≤k−1,
−Wi
, k ≤i≤n.
If we takewi = 1, i = 1, . . . , n, thenWi = i andWi = n −i, and (2.3) reduces to the discrete Montgomery identity
(2.5) xk = 1
n
n
X
i=1
xi+
n−1
X
i=1
Dn(k, i) ∆xi,
where
Dn(k, i) = ( i
n, 1≤i≤k−1,
i
n−1, k≤i≤n.
Ifn∈N,∆nis inductively defined by
∆nxi = ∆n−1(∆xi).
It is then easy to prove, by induction or directly using the elementary theory of operators,see [8], that
∆nxi =
n
X
k=0
n k
(−1)n−kxi+k.
In the next theorem we give the generalization of the identity (2.3).
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Theorem 2.1. Let(X,k·k)be a normed linear space,x1, x2, . . . , xna finite se- quence of vectors inX, w1, w2, . . . , wnfinite sequence of positive real numbers.
Then for allm ∈ {2,3, . . . , n−1}andk ∈ {1,2, . . . , n}the following identity is valid:
(2.6) xk= 1 Wn
n
X
i=1
wixi+
m−1
X
r=1
1 n−r
n−r
X
i=1
∆rxi
!
×
n−1
X
i1=1 n−2
X
i2=1
· · ·
n−r
X
ir=1
Dw(k, i1)Dn−1(i1, i2)· · ·Dn−r+1(ir−1, ir)
!
+
n−1
X
i1=1 n−2
X
i2=1
· · ·
n−m
X
im=1
Dw(k, i1)Dn−1(i1, i2)· · ·Dn−m+1(im−1, im) ∆mxim.
Proof. We prove our assertion by induction with respect to m. For m = 2we have to prove the identity
xk = 1 Wn
n
X
i=1
wixi+ 1 n−1
n−1
X
i=1
∆xi
! n−1 X
i=1
Dw(k, i)
!
+
n−1
X
i=1 n−2
X
j=1
Dw(k, i)Dn−1(i, j) ∆2xj.
Applying the identity (2.5) for the finite sequence of vectors∆xi,i= 1,2, . . . , n−
1,we obtain
∆xi = 1 n−1
n−1
X
i=1
∆xi+
n−2
X
j=1
Dn−1(i, j) ∆2xj
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so, again using (2.3), we have
xk = 1 Wn
n
X
i=1
wixi+
n−1
X
i=1
Dw(k, i) 1 n−1
n−1
X
i=1
∆xi+
n−2
X
j=1
Dn−1(i, j) ∆2xj
!
= 1 Wn
n
X
i=1
wixi+ 1 n−1
n−1
X
i=1
∆xi
! n−1 X
i=1
Dw(k, i)
!
+
n−1
X
i=1 n−2
X
j=1
Dw(k, i)Dn−1(i, j) ∆2xj.
Hence the identity (2.6) holds form = 2.
Now, we assume that it holds for a natural number m ∈ {2,3, . . . , n−2}.
Applying the identity (2.5) for the∆mxim
∆mxim = 1 n−m
n−m
X
i=1
∆mxi+
n−m−1
X
im+1=1
Dn−m(im, im+1) ∆m+1xim+1
and using the induction hypothesis, we get
xk = 1 Wn
n
X
i=1
wixi+
m−1
X
r=1
1 n−r
n−r
X
i=1
∆rxi
!
×
n−1
X
i1=1 n−2
X
i2=1
· · ·
n−r
X
ir=1
Dw(k, i1)Dn−1(i1, i2)· · ·Dn−r+1(ir−1, ir)
!
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+
n−1
X
i1=1 n−2
X
i2=1
· · ·
n−m
X
im=1
Dw(k, i1)Dn−1(i1, i2)· · ·Dn−m+1(im−1, im)
×
1 n−m
n−m
X
i=1
∆mxi+
n−m−1
X
im+1=1
Dn−m(im, im+1) ∆m+1xim+1
= 1 Wn
n
X
i=1
wixi+
m
X
r=1
1 n−r
n−r
X
i=1
∆rxi
!
×
n−1
X
i1=1 n−2
X
i2=1
· · ·
n−r
X
ir=1
Dw(k, i1)Dn−1(i1, i2)· · ·Dn−r+1(ir−1, ir)
!
+
n−1
X
i1=1 n−2
X
i2=1
· · ·
n−(m+1)
X
im+1=1
Dw(k, i1)Dn−1(i1, i2)· · ·Dn−m(im, im+1) ∆m+1xim+1.
We see that (2.6) is valid form+ 1and our assertion is proved.
Remark 2.1. Form=n−1(2.6) becomes
xk = 1 Wn
n
X
i=1
wixi+
n−2
X
r=1
1 n−r
n−r
X
i=1
∆rxi
!
×
n−1
X
i1=1 n−2
X
i2=1
· · ·
n−r
X
ir=1
Dw(k, i1)Dn−1(i1, i2)· · ·Dn−r+1(ir−1, ir)
!
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+
n−1
X
i1=1 n−2
X
i2=1
· · ·
1
X
in−1=1
Dw(k, i1)Dn−1(i1, i2)· · ·D2(in−2, in−1) ∆n−1xin−1.
Corollary 2.2. Let(X,k·k)be a normed linear space,x1, x2, . . . , xna finite se- quence of vectors inX. Then for allm∈ {2,3, . . . , n−1}andk ∈ {1,2, . . . , n}
the following identity is valid:
xk = 1 n
n
X
i=1
xi+
m−1
X
r=1
1 n−r
n−r
X
i=1
∆rxi
!
×
n−1
X
i1=1 n−2
X
i2=1
· · ·
n−r
X
ir=1
Dn(k, i1)Dn−1(i1, i2)· · ·Dn−r+1(ir−1, ir)
!
+
n−1
X
i1=1 n−2
X
i2=1
· · ·
n−m
X
im=1
Dn(k, i1)Dn−1(i1, i2)· · ·Dn−m+1(im−1, im) ∆mxim.
Proof. Apply Theorem2.1withwi = 1,i= 1, . . . , n.
Remark 2.2. If we apply (2.6) withn = 2l−1andk =lwe get
xl = 1 W2l−1
2l−1
X
i=1
wixi+
m−1
X
r=1
1 2l−1−r
2l−1−r
X
i=1
∆rxi
!
×
2l−2
X
i1=1 2l−3
X
i2=1
· · ·
2l−1−r
X
ir=1
Dw(l, i1)D2l−2(i1, i2)· · ·D2l−r(ir−1, ir)
!
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+
2l−2
X
i1=1 2l−3
X
i2=1
· · ·
2l−1−m
X
im=1
Dw(l, i1)D2l−2(i1, i2)· · ·D2l−m(im−1, im) ∆mxim.
We may regard this identity as a generalized midpoint identity since for m= 1 it reduces to
(2.7) xl = 1
W2l−1
2l−1
X
i=1
wixi+
2l−2
X
i=1
Dw(l, i) ∆xi
and further forwi = 1, i= 1,2, . . . ,2l−1to
(2.8) xl = 1
2l−1
2l−1
X
i=1
xi+ 1 2l−1
l−1
X
i=1
i(∆xi−∆x2l−1−i).
Similarly, if we apply (2.6) withk = 1and then withk =n, then sum these two equalities and divide them by2, we get
(2.9) x1 +xn
2 = 1
Wn
n
X
i=1
wixi+
m−1
X
r=1
1 n−r
n−r
X
i=1
∆rxi
!
×
n−1
X
i1=1
· · ·
n−r
X
ir=1
Dw(1, i1) +Dw(n, i1)
2 Dn−1(i1, i2)· · ·Dn−r+1(ir−1, ir)
!
+
n−1
X
i1=1
· · ·
n−m
X
im=1
Dw(1, i1) +Dw(n, i1)
2 Dn−1(i1, i2)· · ·Dn−m+1(im−1, im) ∆mxim.
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We may regard this identity as a generalized trapezoid identity since form = 1 it reduces to
(2.10) x1+xn
2 = 1
Wn
n
X
i=1
wixi+
n−1
X
i=1
Dw(1, i) +Dw(n, i) 2 ∆xi, and further forwi = 1, i= 1,2, . . . , nto
(2.11) x1+xn
2 = 1 n
n
X
i=1
xi+ 1 n
n−1
X
i=1
i−n
2
∆xi.
(2.8) and (2.11) were obtained by Dragomir in [7].
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3. Discrete Ostrowski Type Inequalities
The Bernoulli numbersBi,i≥0, are defined by the implicit recurrence relation
m
X
i=0
m+ 1 i
Bi =
( 1, if m = 0, 0, if m 6= 0.
If, forn∈Nandm∈R,we write
Sm(n) = 1m+ 2m+ 3m+· · ·+ (n−1)m, it is well known, see [8], that ifm∈N
Sm(n) = 1 m+ 1
m
X
i=0
m+ 1 i
Bi nm+1−i.
Theorem 3.1. Let(X,k·k)be a normed linear space,x1, x2, . . . , xna finite se- quence of vectors inX, w1, w2, . . . , wnfinite sequence of positive real numbers.
Let also (p, q)be a pair of conjugate exponents1, m ∈ {2,3, . . . , n−1} and k ∈ {1,2, . . . , n}the following inequality holds:
(3.1)
xk− 1 Wn
n
X
i=1
wixi−
m−1
X
r=1
1 n−r
n−r
X
i=1
∆rxi
!
×
n−1
X
i1=1 n−2
X
i2=1
· · ·
n−r
X
ir=1
Dw(k, i1)Dn−1(i1, i2)· · ·Dn−r+1(ir−1, ir)
!
1That is:1< p, q <∞,1p+1q = 1
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≤
n−1
X
i1=1 n−2
X
i2=1
· · ·
n−m+1
X
im−1=1
Dw(k, i1)Dn−1(i1, i2)· · ·Dn−m+1(im−1,·) q
k∆mxkp,
where
k∆mxkp =
n−m
P
i=1
k∆mxikp 1p
, if1≤p < ∞,
1≤i≤n−mmax k∆mxik ifp=∞.
Proof. By using the (2.6) and the Hölder inequality.
Corollary 3.2. Let (X,k·k) be a normed linear space, x1, x2, . . . , xn a finite sequence of vectors in X, w1, w2, . . . , wn a finite sequence of positive real numbers. Let also (p, q) be a pair of conjugate exponents. Then for all k ∈ {1,2, . . . , n}the following inequalities hold:
xk− 1 Wn
n
X
i=1
wixi
≤
1 Wn
n P
i=1
|k−i|wi
· k∆xk∞,
1 Wn
k−1
P
i=1 i
P
j=1
wj
!q
+
n−1
P
i=k n
P
j=i+1
wi
!q!1q
· k∆xkp, 1
Wnmax{Wk−1, Wn−Wk} · k∆xk1.
Proof. By using the discrete analogue of the weighted Montgomery identity
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(2.3) and applying the Hölder inequality we get
xk− 1 Wn
n
X
i=1
wixi
≤ kDw(k,·)kqk∆xkp.
We have
kDw(k,·)k1 = 1 Wn
k−1
X
i=1
|Wi|+
n−1
X
i=k
−Wi
!
= 1 Wn
k−1
X
i=1
(k−i)wi+
n−k
X
i=1
iwk+i
!
= 1 Wn
n
X
i=1
|k−i|wi
and the first inequality is proved.
Since
kDw(k,·)kq = 1 Wn
k−1
X
i=1
|Wi|q+
n−1
X
i=k
−Wi
q
!1q
= 1 Wn
k−1
X
i=1 i
X
j=1
wj
!q
+
n−1
X
i=k n
X
j=i+1
wi
!q!1q
the second inequality is proved.
Finally, for the third
kDw(k,·)k∞= 1
Wn max{Wk−1, Wn−Wk},
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which completes the proof.
The first and the third inequality from Corollary3.2 and also the following corollary was proved by Dragomir in [7].
Corollary 3.3. Let (X,k·k) be a normed linear space, x1, x2, . . . , xn a finite sequence of vectors in X, w1, w2, . . . , wn finite sequence of positive real num- bers, and also let (p, q) be a pair of conjugate exponents. Then for all k ∈ {1,2, . . . , n}the following inequalities hold:
(3.2)
xk− 1 n
n
X
i=1
xi
≤
1 n
n2−1
4 + k− n+12 2
· k∆xk∞,
1
n(Sq(k) +Sq(n−k+ 1))1q · k∆xkp,
1
nmax{k−1, n−k} · k∆xk1.
Proof. If we apply Corollary3.2withwi = 1,i= 1,2, . . . , n, or use the discrete Montgomery identity (2.5), we have
xk− 1 n
n
X
i=1
xi
=
n−1
X
i=1
Dn(k, i) ∆xi
≤
n−1
X
i=1
|Dn(k, i)|q
!1q n−1 X
i=1
k∆xikp
!1p .
Since forq = 1
n−1
X
i=1
|Dn(k, i)|= 1 n
n2−1
4 +
k− n+ 1 2
2! ,
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the first inequality follows.
For the second let1< q <∞
n−1
X
i=1
|Dn(k, i)|q = 1 nq
k−1
X
i=1
iq+
n−1
X
i=k
(n−i)q
!
= 1
nq (Sq(k) +Sq(n−k+ 1)) the second inequality follows.
Finally forq =∞and
1≤i≤n−1max {|D(k, i)|}= 1
n max{k−1, n−k}
implies the last inequality.
Corollary 3.4. Assume that all assumptions from Theorem 3.1hold. Then the following inequality holds
xl− 1 W2l−1
2l−1
X
i=1
wixi−
m−1
X
r=1
1 2l−1−r
2l−1−r
X
i=1
∆rxi
!
×
2l−2
X
i1=1 2l−3
X
i2=1
· · ·
2l−1−r
X
ir=1
Dw(l, i1)D2l−2(i1, i2)· · ·D2l−r(ir−1, ir)
!
≤
2l−2
X
i1=1 2l−3
X
i2=1
· · ·
2l−m
X
im−1=1
Dw(l, i1)D2l−2(i1, i2)· · ·D2l−m(im−1,·) q
k∆mxkp;
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it may be regarded as a generalized midpoint inequality since for m = 1 it reduces to
xl− 1 W2l−1
2l−1
X
i=1
wixi
≤
1 W2l−1
2l−1 P
i=1
|l−i|wi
· k∆xk∞,
1 W2l−1
l−1
P
i=1 i
P
j=1
wj
!q
+
2l−2
P
i=l n
P
j=i+1
wi
!q!1q
· k∆xkp, 1
W2l−1
max{Wl−1, W2l−1−Wl} · k∆xk1; if in additionwi = 1, i= 1,2, . . . ,2l−1it further reduces to
(3.3)
xl− 1 2l−1
2l−1
X
i=1
xi
≤
l(l−1)
2l−1 · k∆xk∞, 1
2l−1(2Sq(l))1q · k∆xkp, l−1
2l−1 · k∆xk1.
Proof. Apply (3.1) withn= 2l−1andk=lto get the first inequality.
For the second, takingm= 1, or applying Hölder’s inequality to (2.7), gives
xl− 1 W2l−1
2l−1
X
i=1
wixi
=
2l−2
X
i=1
Dw(l, i) ∆xi
≤ kDw(l,·)kqk∆xkp.
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Now
kDw(l,·)k1 = 1 W2l−1
l−1
X
i=1
|Wi|+
2l−1
X
i=l
−Wi
!
= 1
W2l−1 2l−1
X
i=1
|l−i|wi
! ,
kDw(l,·)kq= 1 W2l−1
l−1
X
i=1
|Wi|q+
2l−1
X
i=l
−Wi
q
!1q
= 1
W2l−1 l−1
X
i=1 i
X
j=1
wj
!q
+
2l−2
X
i=l n
X
j=i+1
wi
!q!1q ,
kDw(l,·)k∞ = 1
W2l−1 max{Wl−1, W2l−1−Wl} and the second inequality is proved.
Now if we take wi = 1, i = 1,2, . . . ,2l − 1, or apply inequality (3.2) with n = 2l−1andk =l,
kD2l−1(l,·)k1 = 1 2l−1
2l−1
X
i=1
|l−i|= l(l−1) 2l−1 ,
kD2l−1(l,·)kq= 1 2l−1
2l−1
X
i=1
|l−i|q
!1q
= 1
2l−1(2Sq(l))1q , kD2l−1(l,·)k∞ = 1
2l−1max{l−1,2l−1−l}= l−1 2l−1, and thus the third inequality is proved.
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Corollary 3.5. Let all the assumptions from Theorem 3.1 hold. Then the fol- lowing inequality holds:
x1+xn
2 − 1
Wn
n
X
i=1
wixi−
m−1
X
r=1
1 n−r
n−r
X
i=1
∆rxi
!
×
n−1
X
i1=1
· · ·
n−r
X
ir=1
Dw(1, i1) +Dw(n, i1)
2 Dn−1(i1, i2)· · ·Dn−r+1(ir−1, ir)
!
≤
n−1
X
i1=1
· · ·
n−m+1
X
im−1=1
Dw(1, i1) +Dw(n, i1)
2 Dn−1(i1, i2)· · ·Dn−m+1(im−1,·) q
× k∆mxkp; this may regarded as a generalized trapezoid inequality since for m = 1 it reduces to
x1+xn
2 − 1
Wn
n
X
i=1
wixi
≤
Pn−1
i=1
Wi
Wn − 12
· k∆xk∞, Pn−1
i=1
Wi
Wn − 12
q1q
· k∆xkp,
maxn
w1
Wn − 12 ,
wn
Wn − 12
o· k∆xk1.
and if in addition,wi = 1, i= 1,2, . . . , nit further reduces to
(3.4)
x1 +xn 2 − 1
n
n
X
i=1
xi
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≤
1
n n−1−n
2
n
2
· k∆xk∞,
1
n 2Sq n21q
· k∆xkp, ifnis even,
1 n
Sq(n−1)
2q−1 −2Sq n−12 1q
· k∆xkp, ifnis odd,
n−2
2n · k∆xk1.
Proof. To obtain the first inequality take (2.9) and apply Hölder’s inequality.
For the second we takem= 1or apply Hölder’s inequality to (2.10),
x1+xn
2 − 1
Wn
n
X
i=1
wixi
=
n−1
X
i=1
Dw(1, i) +Dw(n, i)
2 ∆xi
≤
Dw(1,·) +Dw(n,·) 2
q
k∆xkp.
Now
Dw(1,·) +Dw(n,·) 2
1
=
n−1
X
i=1
Wi−Wi 2Wn
=
n−1
X
i=1
Wi Wn − 1
2 ,
Dw(1,·) +Dw(n,·) 2
q
=
n−1
X
i=1
Wi
Wn − 1 2
q!1q ,
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Dw(1,·) +Dw(n,·) 2
∞
= max
1≤i≤n−1
Wi Wn −1
2
= max
W1
Wn − 1 2 ,
Wn−1
Wn − 1 2
= max
w1
Wn − 1 2 ,
wn
Wn −1 2
and the second inequality is proved.
Now if we take wi = 1, i = 1,2, . . . , n, or use (2.11) and apply Hölder’s in- equality, we get
x1+xn 2 − 1
n
n
X
i=1
xi
≤ i n − 1
2 q
k∆xkp.
Forq= 1 i n −1
2 1
= 1 n
n−1
X
i=1
i−n
2 = 1
n
n−1−jn 2
k jn 2
k
;
for1< q <∞ i n −1
2 q
= 1 n
n−1
X
i=1
i− n
2
q!1q
=
1
n 2Sq n21q
, ifnis even,
1 n
S
q(n−1)
2q−1 −2Sq n−12 1q
, ifnis odd;
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and forq =∞ i n − 1
2 ∞
= max
1≤i≤n−1
i n −1
2
= n−2 2n .
Remark 3.1. The first inequality from (3.3) was obtained by Dragomir in [7]
and also an incorrect version of the first inequality from (3.4), viz.:
x1+xn 2 − 1
n
n
X
i=1
xi
≤
k−1
2 k∆xk∞, ifn = 2k,
2k2+2k+1
2(2k+1) k∆xk∞, ifn = 2k+ 1.
The second coefficient 2k2(2k+1)2+2k+1 should be 2k+1k2 since
1 2k+ 1
(2k+ 1)−1−
2k+ 1 2
2k+ 1 2
= k2 2k+ 1.
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4. Estimates of the Differences Between Two Weighted Arithmetic Means
In this section we will give the estimates of the differences between two weighted arithmetic means using the discrete weighted Montgomery (Euler) identity. We suppose l, m, n ∈ N. The first method is by subtracting two weighted Mont- gomery identities. The second is by summing the discrete weighted Mont- gomery identity. Both methods are possible for both the case1 ≤l ≤ m ≤n, i.e. [l, m]⊆[1, n]and the case1≤l≤n ≤m, i.e.[1, n]∩[l, m] = [l, n].
Theorem 4.1. Let(X,k·k)be a normed linear space,x1, x2, . . . , xmax{m,n}a fi- nite sequence of vectors inX,l, m, n ∈N,w1, w2, . . . , wnandul, ul+1, . . . , um, two finite sequences of positive real numbers. Let also W = Pn
i=1wi, U = Pm
i=lui and fork∈N
Wk =
k
P
i=1
wi, 1≤k ≤n, W, k > n,
(4.1) Uk =
0, k < l,
k
P
i=l
ui l≤k ≤m, U, k > m.
If[1, n]∩[l, m]6=∅, then, for both cases[l, m]⊆[1, n]and[1, n]∩[l, m] = [l, n],
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the next formula is valid
(4.2) 1
W
n
X
i=1
wixi− 1 U
m
X
i=l
uixi =
max{m,n}
X
i=1
K(i) ∆xi,
where
K(i) = Ui U − Wi
W, 1≤i≤max{m, n}. Proof. Fork ∈([1, n]∩[l, m])∩N, we subtract the identities
xk = 1 W
n
X
i=1
wixi+
n−1
X
i=1
Dw(k, i) ∆xi,
and
xk = 1 U
m
X
i=l
uixi+
m−1
X
i=l
Du(k, i) ∆xi.
Then put
K(k, i) =Du(k, i)−Dw(k, i). AsK(k, i)does not depend onkwe write simplyK(i):
(4.3) K(i) =
−WWi, 1≤i≤l−1,
Ui
U − WWi, l≤i≤m, 1−WWi, m+ 1 ≤i≤n,
if [l, m]⊆[1, n],
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(4.4) K(i) =
−WWi, 1≤i≤l−1,
Ui
U − WWi, l ≤i≤n,
Ui
U −1, n+ 1≤i≤m,
if [1, n]∩[l, m] = [l, n].
Theorem 4.2. Let all assumptions from Theorem4.1 hold and(p, q)be a pair of conjugate exponents. Then we have
1 W
n
X
i=1
wixi− 1 U
m
X
i=l
uixi
≤ kKkqk∆xkp.
The constantkKkq is sharp for1≤p≤ ∞.
Proof. We use the identity (4.2) and apply the Hölder inequality to obtain
1 W
n
X
i=1
wixi− 1 U
m
X
i=l
uixi
=
max{m,n}
X
i=1
K(i) ∆xi
≤ kKkqk∆xkp.
For the proof of the sharpness of the constant kKkq, we will find x, a finite sequence of vectors inX such that
max{m,n}
X
i=1
K(i) ∆xi
=
max{m,n}
X
i=1
|K(i)|q
1 q
k∆xkp.
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For1< p <∞takexto be such that
∆xi = sgnK(i)· |K(i)|p−11 . Forp=∞take
∆xi = sgnK(i).
Forp= 1we will find a finite sequence of vectorsxsuch that
max{m,n}
X
i=1
K(i) ∆xi
= max
1≤i≤max{m,n}|K(i)|
max{m,n}
X
i=1
|∆xi|
.
Suppose that |K(i)|attains its maximum ati0 ∈ ([1, n]∪[l, m])∩N. First we assume thatK(i0)>0. Definexsuch that∆xi0 = 1and∆xi = 0,i6=i0,i.e.
xi =
( 0, 1≤i≤i0,
1, i0+ 1< i≤max{m, n}. Then,
max{m,n}
X
i=1
K(i) ∆xi
=|K(i0)|= max
1≤i≤max{m,n}|K(i)|
max{m,n}
X
i=1
|∆xi|
,
and the statement follows. In the caseK(i0) <0, we takexsuch that∆xi0 =