Open questions
OQ. 3890. 1). If a1, a2, ..., a9 ∈ {1,2, ...,9}and ai6=aj
(i, j ∈ {1,2,3,4,5,6,7,8,9}) then determine all polynomialsfk(n) =Z →Z (k= 1,2,3,4,5,6,7,8,9) such that
P9 k=1
afkk(n) is divisible bya1a2...a9 for all n∈N.
We have the following 22n+1+ 32n+1 ≡0 (mod 5),2n+2+ 32n+1 ≡0 (mod 7), 28n+3+ 3n+1 ≡0 (mod 11),24n+2+ 3n+2≡0 (mod 13),
26n+2+ 34n+2 ≡0 (mod 17),23n+4+ 32n+1 ≡0 (mod 19), 25n+1+ 3n+3 ≡0 (mod 29),24n+1+ 36n+9≡0 (mod 31)
2). Determine all polynomials fk(n) =Z →Z (k= 1,2,3,4,5,6,7,8,9) for which
P9 k=1
afkk(n) is divisible by 45 for alln∈N.
Mih´aly Bencze OQ. 3891. 1). Solve inQ the equation
(x+ 1) (y+ 1) (z+ 1) = (x−1) (y−1) (z−1).If x= a+ba+b, y= b+cb−c, z= c+ac−a, when a, b, c∈Q, then we obtain infinitely many solutions of the given
equation
2). Solve inZ the given equation 3). Solve inQ the equation
Qn k=1
(xk+ 1) = Qn k=1
(xk−1) 4). Solve inZ the previous equation
Mih´aly Bencze OQ. 3892. Ifxk>0 (k= 1,2, ..., n) such that
Qn k=1
xk= 1,then determine all a, b, c >0 for which
Pn k=1
1
(a+xk)b + 1
1+
Pn k=1
xk
c ≥ (a+1)n b +(n+1)1 c.If a= 1, b= 2,c= 1, then we obtain a solution forn= 3.
Mih´aly Bencze OQ. 3893. 1). Solve inQ the equationxy+yz+zx=−1. Ifx= 1a−b−ab, y= 1b−−bcc, z= 1c−−caa,where a, b, c∈Q, then we obtain an infinitely many solutions for the given equation.
3). Solve inQ the equation P
cyclic
x1x2...xn−1 =−1 4). Solve the previous equation inZ
Mih´aly Bencze OQ. 3894. Ifxk>0 (k= 1,2, ..., n) then
P
cyclic
xn1−1+x2...xn
xn2−1+x3...x1
≤ n2n4−1
Pn
k=1
xk 2n−2
.
Mih´aly Bencze OQ. 3895. Ifxk>0 (k= 1,2, ..., n) then
P
cyclic
x1+x1
2 x2+x1
3
...
xn+x1
1
≥ nn2−3
Pn
k=1
xk+ Pn k=1
1 xk
n−2
.
Mih´aly Bencze OQ. 3896. Ifxk>0 (k= 1,2, ..., n) then
Pn k=1
xnk+n2 Qn k=1
xk≥ n(n+1)
nn−12 ·
P
cyclic
x1x2
!n+1
2
Pn k=1
xk
.
Mih´aly Bencze OQ. 3897. Ifxk>0 (k= 1,2, ..., n) such that
Qn k=1
xk= 1,then determine all λ∈R for which
Qn k=1
1 +xλk
≤ n(n2−n1)λ
Pn
k=1
xk
(n−1)λ
.If n= 3 then λ= 2 is a solution.
Mih´aly Bencze OQ. 3898. Ifxk >0 (k= 1,2, ..., n) such that
Pn k=1
xk =nthen determine all a, b, λ >0 for whicha
Pn k=1
xλk+b Qn k=1
xk≥na+b.The casea=n−1, b=n, λ= 2 is a solution.
Mih´aly Bencze
OQ. 3899. Solve inZ the equation x2+yxy2+tz2 +y2+zyz2+tx2 +z2+xzx2+ty2 = t+23 . Mih´aly Bencze OQ. 3900. Solve in Z the equation 3 x2+y2+z2
=t2+u2+v2+w2.If t=x+y+z, u=x−y, v=y−z, w=z−x, wherex, y, z ∈Z, then the equation have infinitely many solutions inZ.
Mih´aly Bencze OQ. 3901. Solve in Z the equation
x31y1+x32y2+x33y3= 2 z21+z22+z32
+u1t21+u2t22+u3t23.If y1=x2+x3, y2 =x3+x1, y3 =x1+x2, z1 =x1x2, z2=x2x3, z3 =x3x1, u1 =x1x2, u2 =x2x3, u3=x3x1, t1 =x1−x2, t2 =x2−x3, t3=x3−x1, where x1, x2, x3∈Z then the given equation have infinitely many solutions inZ.
Mih´aly Bencze OQ. 3902. Solve in Z the equation
x51y1+x52y2+x53y3=z14t1+z42t2+z34t3+u21v1+u22v2+u23v3.
Ify1 =x2+x3, u2=x3+x1, y3 =x1+x2, z1=x1, z2=x2, z3=x3, t1 =x22+x23, t2=x23+x21, t3 =x21+x22, u1=x1−x2, u2=x2−x3, u3 =x3−x1, v1 =x31x2+x21x22+x1x32, v2=x32x3+x22x23+x2x33,
v3 =x33x1+x23x21+x3x21, wherex1, x2, x3∈Z,then the given equation have infinitely many solutions in Z.
Mih´aly Bencze OQ. 3903. Solve in Z the equation
2 x61+x62+x63
=y15z1+y52z2+y35z3+u21v1+u22v2+u23v3.
Ify1 =x1, y2=x2, y3 =x3, z1 =x2+x3, z2=x3+x1, z3 =x3+x2,
u1 =x1−x2, u2 =x2−x3, u3=x3−x1, v1=x41+x31x2+x21x22+x1x32+x42, v2 =x42+x32x3+x22x23+x2x33+x43, v3=x43+x33x1+x23x21+x3x31+x41 where x1, x2, x3∈Z, then the given equation have infinitely many solutions in Z.
OQ. 3904. Solve in Z the equation 2
xk+21 +xk+22 +xk+23
+ 2 yk1z1+yk2z2+yk3z3
=
= 2
tk+11 u1+tk+12 u2+tk+13 u3
+v21w1+v22w2+v32w3.
Ify1 =x1, y2=x2, y3 =x3, z1 =x2+x3, z2=x3+x1, z3 =x2+x3, t1 =x1, t2 =x2, t3 =x3, u1 =x2x3, u2 =x3x1, u3=x1x2, v1 =x1−x2, v2 =x2−x3, v3=x3−x1, w1 =−xk1 +xk2 +xk3, w2=−xk2+xk3+xk1, w3=−xk3+xk1+xk2,where x1, x2, x3∈Z, then the given equation have infinitely many solutions in Z.
Mih´aly Bencze OQ. 3905. Solve in Z the equationn
Pn k=1
x2k =y2+ P
1≤i<j≤n
zij2.If y=
Pn k=1
xk, zij =xi−xj, i, j∈ {1,2, ..., n} when xi ∈Z (i= 1,2, ..., n),then the given equation have infinitely many solutions inZ.
Mih´aly Bencze OQ. 3906. 1). Solve inQ the equation
Pn k=1
1
x2k = Pnn2 k=1
y2k
+n1 P
1≤i<j≤n
zij2.If yk=xk (k= 1,2, ..., n), zij = xxi
j −xxji, where xi ∈Q (i= 1,2, ..., n) then the given equation have infinitely many solution inQ
2). Solve inZ the given equation
Mih´aly Bencze OQ. 3907. Solve in Z the equation 2
Pn
k=1
x2k−y1y2−...−yny1
= Pn k=1
zk2. Ifyk =xk, zk=xk−xk+1,where xk∈Z (k= 1,2, ..., n), then the equation have infinitely many solutions inZ.
Mih´aly Bencze
OQ. 3908. Solve in Z the equation
x21+x22+...+x2k x1+x2+...+xk +x
2
2+x23+...+x2k+1
x2+x3+...+xk+1 +...+x
2n+x21+...+x2k−1 xn+x1+...+xk−1 =
n Pn i=1
x2i Pn i=1
xi
,when k∈ {1,2, ..., n}.The casex1 =x2=...=xn∈Z offer infinitely many solutions.
Mih´aly Bencze OQ. 3909. Solve in Z the equation
(n−1)xn1−1−x2x3...xn
xn1−1−(x1x2)n−21+xn2−1 +...+ (n−1)xn−1n −x1x2...xn−1
xnn−1−(xnx1)n−21+xn1−1 =n.
The casex1=x2 =...=xn∈N offer infinitely many solutions in Z.
Mih´aly Bencze OQ. 3910. Ifxk>0 (k= 1,2, ..., n) such that
Qn k=1
xk= 1 then determine all a(n), b(n)>0 for which
Pn k=1
x2k−n≥a(n) Pn k=1
xk−b(n) P
1≤i<j≤n
xixj.If n= 3, then a(n) =b(n) = 18.
Mih´aly Bencze OQ. 3911. 1). Solve inQ the following system:
Pn k=1
xk=n (n−1)
Pn k=1
x2k+n Qn k=1
xk=n2 2). Solve inZ the given system.
Mih´aly Bencze
OQ. 3912. Solve in Qthe following equation Qn
k=1
xk+ n sQn
k=1
x+ykn
= n(n2(x+2)−1) P
1≤i<j≤nzizj.
Mih´aly Bencze OQ. 3913. Determine all n, k∈N for which nk+ 1 = aa...a| {z }
m−time
,where a∈ {1,2,3,4,5,6,7,8,9}.An example is 65+ 1 = 7777.
Mih´aly Bencze OQ. 3914. Determine all n, k∈N for which 1k+1k
2k+1k
... nk+k1 is the square of a rational number.
Mih´aly Bencze OQ. 3915. Determine all n, k∈N for which
Φ Φ nk
+ Φ (Φ (kn)) =n+k,where Φ is the Euler‘s totient function.
Mih´aly Bencze OQ. 3916. Ifxk∈(0, π) (k= 1,2, ..., n) and
Pn k=1
xk=π then determine all functions f : (0, π)→(0,+∞) such that
Pn k=1
f(xk) = Pn
k=1 1 f(xk)
Qn
k=1
f(xk).
A solution isf(x) =tgx.
Mih´aly Bencze OQ. 3917. Letf : [a, b]→R be a convex function. Determine all λ∈[0,1]
such that b−1a Rb a
f(x)≤ λ(f(a)+f(b))
2 + (1−λ)f a+b2
. A solution is λ= 12. Mih´aly Bencze OQ. 3918. Let be P(x) =a0xn+a1xn−1+...+an−1x+an.Determine all a0, a1, ..., an∈C for which all positive rational number AB (A, B∈N∗) can be represented in following form: BA =
Qn i=1
(P(i))±1.ForP(x) = x(x+1)2 we have a solution.
OQ. 3919. All positive integers mcan be represented in the following forms:
1). m=±dk(1)±dk(2)±...±dk(n) 2). m=±σk(1)±σk(2)±...±σk(n) 3). m=±Φk(1)±Φk(2)±...±Φk(n) 4). m=±Ψk(1)±Ψk(2)±...±Ψk(n) 5). m=±F1k±F2k±...±Fnk
6). m=±Lk1 ±Lk2 ±...±Lkn 7). m=± n1k
± n2k
±...± nnk
Mih´aly Bencze OQ. 3920. Determine all a1, r∈C,ak=a1+ (k−1)r, and allp∈N for which all positive integers m can be represented in the following form:
m=±ak1±ak2±...±akn.
Mih´aly Bencze OQ. 3921. Determine all b1, q∈C, bk=b1qk−1 and allp for which all positive integersm can be represented in the following form:
m=±bk1±bk2±...±bkn.
Mih´aly Bencze OQ. 3922. Determine all ak>0 (k= 1,2, ..., n) for which P
cyclic a1−a2
a2+a3 ≥0.
Mih´aly Bencze OQ. 3923. Determine all ak>0 (k= 1,2, ..., n) for which
1 +
Qn k=1
ak
P
cyclic 1 a1+a2a3...an
!
≥n.
Mih´aly Bencze OQ. 3924. Determine all ak>0 (k= 1,2, ..., n) such that
Pn k=1
1
ak + 9P 1
a1+a2+a3 + 25P 1
a1+a2+a3+a4+a5 +...≥
≥4P 1
a1+a2 + 16P 1
a1+a2+a3+a4 +...
Mih´aly Bencze
OQ. 3925. Ifxk>0 (k= 1,2, ..., n),then Pn
k=1
xnk+n Qn k=1
xk ≥ n−21 P
cyclic
x1...xn−1(x1+...+xn−1).
Mih´aly Bencze OQ. 3926. Ifxk>0 (k= 1,2, ..., n),then
P
cyclic
x1+x
n−1 2
xn3−2
n−1
≥ n·2
n−1 Pn k=1
x2nk −3 Pn
k=1
xn−2k
.
Mih´aly Bencze OQ. 3927. Ifxk>0 (k= 1,2, ..., n),then determineF(n)>0 such that
Pn k=1
xnk−n Qn k=1
xk ≥F(n) (x1−x2) (x2−x3)...(xn−x1).We haveF(1) = 0, F(3) = 4.
Mih´aly Bencze OQ. 3928. Ifxk>0 (k= 1,2, ..., n),then P
cyclic
xn+11
xn1+...+xnn−1 ≥ n−11 Pn
k=1
xk. Mih´aly Bencze OQ. 3929. Ifxk>0 (k= 1,2, ..., n),then
Pn
k=1
xk Pn k=1
1 xk
≥n+ 2 +
(n−2)(n+1) Pn k=1
xnk−1 P
cyclic
x1...xn−1 .
Mih´aly Bencze OQ. 3930. Ifxk>0 (k= 1,2, ..., n),then P
cyclic
(x2+...+xn)n−1
xn1−1+x2...xn ≥ n(n−21)n−1. Mih´aly Bencze OQ. 3931. Ifxk >0 (k= 1,2, ..., n),then
nn−2 Pn k=1
x(n−1)2k Pn
k=1
xn−1k
n−1 +
P
cyclic
x1...xn−1
Pn k=1
xnk−1 ≥2.
Mih´aly Bencze
OQ. 3932. Ifxk>0 (k= 1,2, ..., n),then P
cyclic
x2+...+xn
(n−1)xn−11 +x2x3...xn ≥ Pn(nn −1)
k=1
xnk−2
.
Mih´aly Bencze OQ. 3933. Ifxk>0 (k= 1,2, ..., n),then
P
cyclic 1
xn−11 +x2...xn ≤
(n−1) Pn
k=1
xk P
cyclic 1 x1+...+xn−1
!
2 P
cyclic
x1...xn−1 .
Mih´aly Bencze OQ. 3935. Ifxk>0 (k= 1,2, ..., n),then
n(n−1) P
cyclic x1
x2+...+xn ≤ Pn
k=1
xk Pn k=1
1 xk
.
Mih´aly Bencze OQ. 3936. Ifxk>0 (k= 1,2, ..., n),then P
cyclic x21 x2 ≥ n+1
s nn
Pn
k=1
xn+1k
.
Mih´aly Bencze OQ. 3937. Ifxk>0 (k= 1,2, ..., n),then
Pn k=1
x2(n−1)k P
cyclic
x1x2...xn−1 +
n Qn k=1
xk
Pn k=1
xk
≥ 2n Pn
k=1
xnk−1.
Mih´aly Bencze OQ. 3938. Ifxk>0 (k= 1,2, ..., n),then determine alla, b >0 such that
a Pn k=1
xnk Pn k=1
xnk−1
+
b P
cyclic
(x1x2)n−1 Pn
k=1
x2nk −3 ≥ a+bn Pn
k=1
xk.
Mih´aly Bencze OQ. 3939. Ifxk>0 (k= 1,2, ..., n),then
Pn k=1
xnk Qn k=1
xk
+
2nn Qn k=1
xk Pn
k=1
xk
n ≥n+ 2.
OQ. 3940. Ifxk>0 (k= 1,2, ..., n),then
Pn
k=1
xk Qn
k=1
xk Pn
k=1
xn+1k
+
(n+1)nn−1 Pn k=1
x
n(n−1) 2
Pn k
k=1
xk Pn
k=1
x2k
...
Pn
k=1
xnk−1
≥n+ 2.
Mih´aly Bencze OQ. 3941.P Ifxk>0 (k= 1,2, ..., n),then
cyclic
1
(x1+x2+...+xn−1)n−1 ≥ (n−1)n−1 Pn2
cyclic
x1x2...xn−1.
Mih´aly Bencze OQ. 3942. Ifak>0 (k= 1,2, ..., n),then
P a1
a2+...+an +
Qn k=1
ak
(n−1) Pn k=1
ank ≥ n(n−1)n2+1 .
Mih´aly Bencze OQ. 3943. Ifxk>0 (k= 1,2, ..., n),then P
cyclic
x21+...x2n−1 x1+...+xn−1 ≤ n
Pn k=1
x2k Pn k=1
xk
.
Mih´aly Bencze OQ. 3944. Ifxk>0 (k= 1,2, ..., n),then
Pn k=1
xnk−1 P
cyclic
x1x2...xn−1 +
(n−1)n Qn
k=1
xk
Q
cyclic
(x1+...+xn−1) ≥2.
Mih´aly Bencze OQ. 3945. Ifpk (k= 1,2, ..., n) are given prime, then solve inN the
equation Qn4n k=1
pk
=
3n
P
k=1 1 xk.
Mih´aly Bencze
OQ. 3946. If 0< xk< π, pk >0,(k= 1,2, ..., n), An=
Pn k=1
pkxk
Pn k=1
pk
,
G= Qn
k=1
xpkk Pn1
k=1pk
,then sinGGPn
k=1
pk
≤ Qn
k=1
sinxk
xk
pk
≤ sinAAPn
k=1
pk
. Mih´aly Bencze OQ. 3947. Solve in Qthe equation 2z4= x3+y3
x3+ 4y3 .
Mih´aly Bencze OQ. 3948. Solve in Qthe equationx3+nx+n+ 1 = (n+ 1)y2 when n∈N is given.
Mih´aly Bencze OQ. 3949. Solve in Z the equationy6 = 2x4−1
3x4−1
5x4−1 . Mih´aly Bencze OQ. 3950. Solve in Z the equationa
Pn k=1
x2k+b P
1≤i<j≤n
xixj =c when a, b, c∈Z are given.
Mih´aly Bencze OQ. 3951. Ifp is a given prime, then solve inZ the equationx2+p=yn.
Mih´aly Bencze OQ. 3952. Solve in Z the equation
x4−2y4
z4−8t4
u3−3uv2−v3
= 1.
Mih´aly Bencze OQ. 3953. Solve in Z the equation x3+x2y+axy2+b=cwhen a, b, c∈Z are given.
Mih´aly Bencze
OQ. 3954. Determine all n∈Z for which the equation x4+y4+nz4 = 1 have infinitely many solutions inQ.
Mih´aly Bencze OQ. 3955. Solve in Qthe equation
Pn k=1
x2pk =pwhen p∈Z is given.
Mih´aly Bencze OQ. 3956. Ifa, b∈Z are given, then solve inZ the equation
Qn k=1
x2k+a2
= ay2+b2n
.
Mih´aly Bencze OQ. 3957. Solve in Qthe equation
Pn k=1
x3k =p,when p is a given prime.
Mih´aly Bencze OQ. 3958. Ifa, b, c, ak, bk, ck∈Z (k= 1,2, ..., n) are given, then solve the equation
Qn k=1
akx2+bky2+ckz2
= ax2+by2+cz2n
.
Mih´aly Bencze OQ. 3959. Ifak∈Z (k= 1,2, ..., n) are given, then solve in Q the equation
Pn k=1
akx2p+1k = 0.
Mih´aly Bencze OQ. 3960. Solve in Z the equation
Pn k=1
x2pk = Pn k=1
yk2p whenp∈Z.
Mih´aly Bencze OQ. 3961. Ifak, bk, ck, dk ∈Z (k= 1,2, ..., n) are given, then solve in Qthe equation xy
Qn k=1
akx2+bky2
=zt Qn k=1
ckz2+dkt2 .
Mih´aly Bencze
OQ. 3962. Ifpk∈Z (k= 1,2, ..., n) are given prime, then solve inZ the equation
Pn k=1
pkx2k=y3.
Mih´aly Bencze OQ. 3963. Solve in Z the equations
1). x2n+y2n=zn 2). x2n−y2n=zn
Mih´aly Bencze OQ. 3964. Solve in Z the equationx2n+y2n=nzn.
Mih´aly Bencze OQ. 3965. Solve in Z the equationx2n− 2nn
xnyn+y2n=zn.
Mih´aly Bencze OQ. 3966. Solve in Z the equationa bx2+cy22
+z2= dt2+eu22
wherea, b, c, d, e∈Z are given.
Mih´aly Bencze OQ. 3967. Ifb, ak ∈Z (k= 1,2, ..., n) are given, then solve in Z the
equation Pn k=1
akx2k =b Qn k=1
xk.
Mih´aly Bencze OQ. 3966. Solve in Z the equation
Pn k=0
ak nk
xn−kyk=zn whereak ∈Z (k= 1,2, ..., n) are given.
Mih´aly Bencze OQ. 3969. Ifp, q are prime, andk∈Z is given, then solve inZ the
equation x2+py2 =k z2+qt2 .
Mih´aly Bencze
OQ. 3970. LetABC (a6=b6=c) be a triangle. Compute St(a, b, c) = minPat+bt
at−bt,when t∈R.We have S1(a, b, c) = 5, S2(a, b, c) = 3.
Mih´aly Bencze OQ. 3971. Compute Sk= P
1≤i<j≤n 1
(ji)(j−i)k.
Mih´aly Bencze OQ. 3972. IfSnp = P
k≥0 n pk
then determine a relation betweenSn1, Sn2, ..., Snp.
Mih´aly Bencze OQ. 3973. IfRpn= P
k≥0 1
(pkn) then determine a relation between Rn1, R2n, ..., Rpn.
Mih´aly Bencze OQ. 3974. Ifak>0 (k= 1,2, ..., n) andλ≥t >0 then determine all tsuch that
Pn k=1
aλ+1k Pn k=1
aλk ≥
Pn k=1
aλ+1k Pn k=1
aλ+1k −t
1 t
. (For t= 2 we have a solution).
Mih´aly Bencze OQ. 3975. Denotean the nearest integer of √k
n (k≥2).Compute 1).
Pn i=1
ai 2).
Pn i=1
1 ai
3). a 1
1a2...ai +a 1
2a3...ai+1 +...+a 1
na1...ai−1 wherei∈ {2,3, ..., n−1}.
Mih´aly Bencze OQ. 3976. Ifxk>0 (k= 1,2, ..., n),then determine alln∈N∗ for which
P
cyclic
xn1−1−x2x3...xn
xn1−1+ (n−1)x2x3...xn
n−11
≥0.