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Multiplicity of solutions for Dirichlet boundary conditions of second-order quasilinear equations with

impulsive effects

Tengfei Shen and Wenbin Liu

B

College of Sciences, China University of Mining and Technology, Xuzhou 221116, China Received 14 July 2015, appeared 30 December 2015

Communicated by Petru Jebelean

Abstract. This paper deals with the multiplicity of solutions for Dirichlet boundary conditions of second-order quasilinear equations with impulsive effects. By using crit- ical point theory, a new result is obtained. An example is given to illustrate the main result.

Keywords: critical point theory, boundary value problems, impulsive effects, quasilin- ear equations.

2010 Mathematics Subject Classification: 34B15, 34B18, 34B37.

1 Introduction

Consider the following problem with impulses





−u00(t) +a(t)u(t)−(|u(t)|2)00u(t) = f(t,u(t)), t ∈ J,

∆(u0(tj)) = Ij(u(tj)), j=1, 2, . . . ,m, u(0) =u(T) =0,

(1.1)

wheret0=0< t1 <t2<· · · <tm <tm+1 =T,J = [0,T]\ {t1,t2, . . . ,tm}, f ∈C([0,T]×R;R), Ij ∈ C(R;R), a(t) ∈ L[0,T], ∆(u0(tj)) = u0(t+j )−u0(tj ) and u0(t±j ) = limtt±

j u0(t), j = 1, 2, . . . ,m.

This problem is derived from a class of quasilinear Schrödinger equation. When we look for the standing wave solution whose form is Ψ(t,x) = eiwtu(x), wR of the following quasilinear Schrödinger equation

i∂tΨ=−Ψ00+W(x)Ψ−(|Ψ|2)00Ψµ|Ψ|q1Ψ, x∈R, (1.2) whereq>1, µ>0, we can obtain the elliptic equation of the form

−u00+ (W(x)−w)u−(|u|2)00u=µ|u|q1u, x∈R, (1.3)

BCorresponding author. Email: cumt_equations@126.com

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which was investigated by some scholars (see [2,4,9,19,22]).

It is generally known that critical point theory is a classical method to deal with the existence and multiplicity of solutions for differential equations (see [3,7,12,16,21,26,30]).

Then a natural question is asked: Can we consider the multiplicity of solutions for second- order quasilinear equations with impulsive effects which are produced by the quasilinear term (|u|2)00uandu00 by using critical point theory?

Impulsive differential equations can be used to describe many evolution processes (see [5,10,11,14,17,27]). Some classical methods and theorems such as fixed point theorems, the method of lower and upper solutions and coincidence degree theory have been widely used to investigate impulsive differential equations (see [1,8,13,15,20]). Recently, critical point theory has been proved to be an effective tool to investigate boundary value problems for impulsive differential equations. Many valuable results have been obtained by some scholars (see [6,18,24,25,28,29]).

In [18], Nieto and O’Regan studied the linear Dirichlet problem with impulses





−u00(t) +λu(t) =σ(t), a.e.t∈ [0,T],

∆(u0(tj)) =dj, j=1, 2, . . . ,p, u(0) =u(T) =0,

(1.4)

and the nonlinear Dirichlet problem with impulses





−u00(t) +λu(t) = f(t,u(t)), a.e.t∈ [0,T],

∆(u0(tj)) =Ij(u(tj)), j=1, 2, . . . ,p, u(0) =u(T) =0.

(1.5)

and got some results by using critical point theory.

In [29], Zhou and Li investigated the nonlinear Dirichlet problem with impulses





−u00(t) +g(t)u(t) = f(t,u(t)), a.e.t ∈[0,T],

∆(u0(tj)) = Ij(u(tj)), j=1, 2, . . . ,p, u(0) =u(T) =0.

(1.6)

and obtained the existence of infinitely many solutions by employing the Symmetric Mountain Pass Theorem.

However, there are few articles which considered the multiplicity of standing wave so- lutions for the impulsive Dirichlet boundary value problem involving the quasilinear term (|u|2)00u. The impulsive effects which brought from the quasilinear term (|u|2)00u are more complicated thanu00.

Motivated by the works mentioned above, in this paper, our purpose is to investigate the multiplicity of solutions for Dirichlet boundary conditions of second-order quasilinear equations with impulsive effects (1.1). Moreover, the nonlinearity f does not need to satisfy the Ambrosetti–Rabinowitz condition (see [3]). Furthermore, the impulsive terms Ij(u) need to satisfy the suplinear condition rather than the sublinear condition as those in [18,23,28,29].

By making use of the variant fountain theory (see [30]), the multiplicity of solutions for the problem (1.1) are obtained.

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2 Preliminaries

In this section, the following theorem will be needed in the proof of our main results. Let E be a Banach space with the norm k·kand E = ⊕j=kXj with dim Xj < for any jN. Set Yk =⊕kj=0Xj, Zk = ⊕j=kXj.

Theorem 2.1 ([30, Theorem 2.2]). The C1-functional Φλ : E → R defined by Φλ(u) = A(u)− λB(u), λ∈ [1, 2],satisfies

(B1) Φλmaps bounded sets to bounded sets uniformly forλ∈ [1, 2]. Moreover, Φλ(−u) =Φλ(u)for all(λ,u)∈[1, 2]×E.

(B2) B(u)≥0; B(u)→+askuk →+on any finite dimensional subspace of E.

(B3) There existρk >rk >0such that ak(λ):= inf

uZk,kuk=ρk

Φλ(u)≥0>bk(λ):= max

uYk,kuk=rkΦλ(u) for allλ∈[1, 2] and

dk(λ):= inf

uZk,kuk≤ρk

Φλ(u)→0as k→+ uniformly forλ∈ [1, 2]. Then there existλn →1, u(λn)∈Ynsuch that

Φ0λn|Yn(u(λn)) =0, Φλn(u(λn))→ck ∈[dk(2), bk(1)] as n →+∞.

Particularly, if {u(λn)}has a convergent subsequence for every k, thenΦ1 has infinitely many non- trivial critical points{uk} ∈E\ {0}satisfyingΦ1(uk)→0as k→+∞.

In the Sobolev spaceH01(0,T), consider the inner product hu,vi=

Z T

0 u(t)v(t)dt+

Z T

0 u0(t)v0(t)dt, ∀u,v∈ H01(0,T), inducing the norm

kukH1

0 =

Z T

0

|u(t)|2+|u0(t)|2dt 12

. By Poincaré’s inequality

Z T

0

|u(t)|2dt≤ √1 λ

Z T

0

|u0(t)|2dt, where λ = π2

T2 is the first eigenvalue of the problem −u00 = λu with Dirichlet boundary conditions, the normkukH1

0(0,T) andku0kL2 are equivalent.

But, in this paper, we define the following inner product inH10(0,T) hu,vi1=

Z T

0

a(t)u(t)v(t)dt+

Z T

0

u0(t)v0(t)dt, ∀u,v∈ H01(0,T), whose norm is

kuk= Z T

0 a(t)|u(t)|2+|u0(t)|2 12

.

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Throughout our paper, we assume that ess inft∈[0,T]a(t)>−λ, which together with Lemma 2.1 in [29] yields that the norm kukH1

0 and kukare equivalent. Thus, by the Sobolev Embedding Theorem, there exists a constantc>0 such thatkuk :=maxt∈[0,T]|u(t)| ≤ckuk.

For each u∈ H10(0,T), uis absolutely continuous andu0 ∈ L2(0,T). In this case,∆u(t) = u0(t+j )−u0(tj ) =0 may not hold for anyt ∈(0,T). It leads to the impulsive effects. Thus,

Z T

0

(|u(t)|2)00u(t)v(t)dt= −

m j=0

Z tj+1

tj

(|u(t)|2)00u(t)v(t)dt

= −(

m j=0

2u0(tj+1)u2(tj+1)v(tj+1)−2u0(t+j )u2(t+j )v(t+j )

Z tj+1

tj

2u02(t)u(t)v(t) +2u2(t)u0(t)v0(t)dt)

=

m j=1

2∆u0(tj)u2(tj)v(tj) +2u0(0)u2(0)v(0)−2u0(T)u2(T)v(T) +

Z T

0 2u02(t)u(t)v(t) +2u2(t)u0(t)v0(t)dt

=

m j=1

2Ij(u(tj))u2(tj)v(tj) +

Z T

0 2u02(t)u(t)v(t) +2u2(t)u0(t)v0(t)dt.

Similarly, we have

Z T

0 u00(t)v(t)dt=

m j=1

Ij(u(tj))v(tj) +

Z T

0 u0(t)v0(t)dt.

Define the functionalΦ: H10(0,T)→Rby Φ(u) = 1

2kuk2+

m j=1

Z u(tj) 0

(2t2+1)Ij(t)dt+

Z T

0 u02(t)u2(t)dt−

Z T

0 F(t,u(t))dt, whereF(t,u) =Ru

0 f(t,s)ds. Clearly,Φ∈C1(H01(0,T),R), hΦ0(u),vi=

Z T

0 u0(t)v0(t) +a(t)u(t)v(t)dt+

Z T

0 2u02(t)u(t)v(t) +2u2(t)u0(t)v0(t)dt +

m j=1

(2u2(tj) +1)Ij(u(tj))v(tj)−

Z T

0 f(t,u(t))v(t)dt.

Definition 2.2. A functionu∈ H01(0,T)is a weak solution of the problem (1.1), if it is a critical point ofΦ.

Next, let

Φλ(u):= A(u)−λB(u), where

A(u):= 1

2kuk2+

m j=1

Z u(tj) 0

(2t2+1)Ij(t)dt+

Z T

0 u02(t)u2(t)dt, B(u):=

Z T

0 F(t,u(t))dt,

λ∈[1, 2]. Clearly, the critical points ofΦ1(u) =Φ(u)correspond to the weak solutions of the problem (1.1). In H01(0,T), we can choose a completely orthonormal basisejand set Xj =Rej. Thus,Zk andYk can be defined.

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3 Main result

Theorem 3.1. Assume that F(t,u)is even about u and the following conditions are satisfied.

(H1) Ij(u)are odd about u and Ij(u)u≥0,(j=1, 2, . . . ,m).

(H2) There exist constants bj >0andγj ∈[1,)such that|Ij(u)| ≤bj|u|γj. (H3) F(t,u) =o(|u|ν)as|u| →0uniformly on[0,T].

(H4) There exist constants l1, L>0such that

|f(t,u)| ≤l1|u|p, |u| ≥L, p ∈[0, 1), t ∈[0,T]. (H5) There exist constants l2, l3>0such that

F(t,u)≥ l2|u|θ+l3|u|ν, θ,ν∈[1, 2), t∈[0,T]. Then the problem(1.1)has infinitely many solutions.

In order to prove Theorem3.1, we need the following lemmas.

Lemma 3.2. Under the assumptions of Theorem3.1, there exists aρk small enough such that ak(λ):= infuZk,kuk=ρkΦλ(u) ≥ 0 and dk(λ) := infuZk,kuk≤ρkΦλ(u) → 0 as k → + uniformly for any λ∈ [1, 2].

Proof. LetΓk :=supuZ

k,kuk=1kuk. ThenΓk →0 ask→+∞. By (H3), for givene1 >0, there exists δ1>0 such that

F(t,u)≤e1|u|ν, |u| ≤δ1, t∈ [0,T]. Based on (H4), we have

F(t,u)≤l1|u|p+1, |u| ≥L, t∈ [0,T].

From the continuity ofF(t,u), for(t,|u|)∈[0,T]×[δ1,L], there exists M>0 such that F(t,u)≤ e1|u|ν+l1|u|p+1+M.

So, we have

F(t,u)≤e1|u|ν+ (Mδ11p+l1)|u|p+1, u∈ R, t ∈[0,T]. (3.1) Based on (H1), for anyu∈ Zk andkuksmall enough, we have

Φλ(u) = 1

2kuk2+

m j=1

Z u(tj) 0

(2t2+1)Ij(t)dt+

Z T

0 u02(t)u2(t)dt−λ Z T

0 F(t,u(t))dt

1

2kuk2λe1 Z T

0

|u|νdt−λ(Mδ11p+l1)

Z T

0

|u|p+1dt

1

2kuk2−2e1νkkukν2TΓkp+1(Mδ11p+l1)kukp+1

1

8ρ2k ≥0,

where kuk=ρk := (16TΓpk+1(Mδ11p+l1) +16e1νk)11p (without loss of generality, assume that v≥ p+1). It is easy to find thatρk →0 as k→ +∞. Thus, we can obtain that ak(λ)≥0 anddk(λ)→0 asn→+uniformly for λ∈ [1, 2].

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Lemma 3.3. Under the assumptions of Theorem3.1, there exists a rk small enough such that bk(λ):= maxuYk,kuk=rkΦλ(u)<0forλ∈[1, 2].

Proof. Let M1 = max{b1,b2,b3, . . .}. For any u ∈ Yk, by the equivalence of the norms on the finite-dimensional spaceYk and (H5), we have

Φλ(u) = 1

2kuk2+

m j=1

Z u(tj)

0

(2t2+1)Ij(t)dt+

Z T

0

u02(t)u2(t)dt−λ Z T

0

F(t,u(t))dt

1

2kuk2+2M1

m j=1

c3+γjkuk3+γj+M1

m j=1

c1+γjkuk1+γj +c2c21kuk4

λl2 Z T

0

|u|θdt−λl3 Z T

0

|u|νdt

1

2kuk2+2M1

m j=1

c3+γjkuk3+γj+M1

m j=1

c1+γjkuk1+γj +c2c21kuk4

λl2c2kukθλl3c3kukν,

which together withθ,ν ∈ [1, 2)yields that Φλ(u)< 0 for kuk:= rk < ρk small enough and λ∈[1, 2].

Lemma 3.4. Under the assumptions of Theorem3.1, there existλn→1, u(λn)∈Ynsuch that Φ0λn|Yn(u(λn)) =0, Φλn(u(λn))→ck ∈[dk(2), bk(1)] as n→+∞.

Proof. Clearly, Φλ maps bounded sets to bounded sets uniformly forλ ∈ [1, 2]. Since F(t,u) is even about u and Ij(u) are odd about u, we have Φλ(−u) = Φλ(u) for all (λ,u) ∈ [1, 2]×H01(0,T). Furthermore, by (H5) and the equivalence of the norms on the finite- dimensional space on H01(0,T), there exist two positive constants c4, c5 such that B(u) ≥ l2c4kukθ+l3c5kukν. So, B(u)≥ 0, B(u) → + as kuk → +∞. Thus, (B1) and (B2) are satis- fied. By Lemma3.2and3.3, (B3) holds. In view of Theorem2.1, we can obtain Lemma3.4.

Next, we show the proof of Theorem3.1.

Proof of Theorem3.1. Let u(λn) := un ∈ Yn. First, we will prove that {un} is bounded on H01(0,T). Based on Lemma 3.4, there exist λn → 1, un ∈ Yn such that Φ0λn|Yn(un) = 0, Φλn(un)→ck ∈[dk(2), bk(1)]as n→+∞. Thus, we have

Φλn(un) = 1

2kunk2+

m j=1

Z un(tj) 0

(2t2+1)Ij(t)dt+

Z T

0 u0n2u2ndt−λn Z T

0 F(t,un)dt

1

2kunk2−2 Z T

0 F(t,un)dt.

By the same way as Lemma3.2, we have Φλn(un)≥ 1

2kunk2−2Tcp+1(Mδ11p+l1)kunkp+1−2e1Tcνkunkν,

which implies that{un}is bounded on H01(0,T). Then there exists a subsequence of{un}(for simplicity denoted again by {un}) such that un * u in H01(0,T) and un → u uniformly in

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C[0,T]. Thus,

hΦ0λ

n(un)−Φ0λ

n(u),un−ui →0, Z T

0

(u0n2(t)un(t)−u02(t)u(t))(un(t)−u(t))dt→0,

m j=1

(Ij(un(tj))−Ij(u(tj)))(un(tj)−u(tj))→0,

m j=1

(Ij(un(tj))u2n(tj)−Ij(u(tj))u2(tj))(un(tj)−u(tj))→0, Z T

0

(f(t,un(t))− f(t,u(t)))(un(t)−u(t))dt→0, asn→+. Moreover,

Z T

0

(u2n(t)u0n(t)−u2(t)u0(t))(u0n(t)−u0(t))dt

=

Z T

0

(u2n(t)−u2(t))u0n(t) +u2(t)(u0n(t)−u0(t))(u0n(t)−u0(t))dt

=

Z T

0 u0n(t)(u0n(t)−u0(t))(u2n(t)−u2(t))dt+

Z T

0 u2(t)|u0n(t)−u0(t)|2dt.

Since

Z T

0 u0n(t)(u0n(t)−u0(t))(u2n(t)−u2(t))dt→0 asn→+∞, we have

hΦ0λn(un)−Φ0λn(u),un−ui

= kun−uk2+2 Z T

0

(u0n2(t)un(t)−u02(t)u(t))(un(t)−u(t))dt +2

Z T

0

(u2n(t)u0n(t)−u2(t)u0(t))(u0n(t)−u0(t))dt +

m j=1

(Ij(un(tj))−Ij(u(tj)))(un(tj)−u(tj)) +2

m j=1

(Ij(un(tj))u2n(tj)−Ij(u(tj))u2(tj))(un(tj)−u(tj))

λn Z T

0

(f(t,un(t))− f(t,u(t)))(un(t)−u(t))dt

= kun−uk2+2 Z T

0 u2(t)|u0n(t)−u0(t)|2dt+o(1),

which implies that un →u in H01(0,T). ThenΦ1 has infinitely many nontrivial critical points {uk} ∈ H01(0,T)\ {0} satisfying Φ1(uk) → 0 as k → +∞. Thus, the problem (1.1) has infinitely many solutions.

Example 3.5.





−u00(t) +a(t)u(t)−(|u(t)|2)00u(t) = f(t,u(t)), t∈ J,

∆(u0(tj)) = Ij(u(tj)), j=1, u(0) =u(1) =0,

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wherea(t) =1,t1= 12,F(t,u) =|u|ln(1+|u|12) +|u|54(sin|u|12 +3),Ij(u) =u3, ν=1. Clearly, the conditions of (H1), (H2), (H3) and (H5) are satisfied. Moreover,

|f(t,u)| ≤ln(1+|u|12) + |u|12

2(1+|u|12)+5|u|14 +1

2|u|34 ≤2|u|45, |u| ≥L,

where L should be large enough. Thus, (H4) holds. Then Example 3.5 has infinitely many solutions.

Acknowledgements

The authors really appreciate the referee’s valuable suggestions and comments, which im- proved the former version of this paper. This research is supported by the National Natural Science Foundation of China (No. 11271364).

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