Vol. 19 (2018), No. 2, pp. 1047–1061 DOI: 10.18514/MMN.2018.2735
ASYMPTOTIC BEHAVIOR OF SOLUTIONS OF SECOND ORDER DIFFERENCE EQUATIONS WITH DEVIATING ARGUMENT
JANUSZ MIGDA AND MAGDALENA NOCKOWSKA-ROSIAK Received 04 November, 2018
Abstract. We consider nonlinear second order difference equations with deviating argument of the form
.rnxn/Danf .xnC 1; xnC 2; : : : ; xnC m/Cbn:
We present sufficient conditions for the existence of solutions with prescribed asymptotic be- havior. Moreover, we study the asymptotic behavior of solutions. We use o.ns/, for a given nonpositive reals, as a measure of approximation.
2010Mathematics Subject Classification: 39A10; 39A22
Keywords: difference equation, prescribed asymptotic behavior, bounded solution, convergent solution, quasidifference, deviating argument
1. INTRODUCTION
In this paper we consider the nonlinear second order difference equation with de- viating argument of the form
.rnxn/Danf .xnC 1; xnC 2; : : : ; xnC m/Cbn (E) rn; an; bn2R; rn> 0; 2Z; m2N; f WRm!R:
HereN,Z,Rdenote the set of positive integers, the set of all integers, and the set of real numbers, respectively. By a solution of (E) we mean a sequencexWN!R satisfying (E) for largen.
An important issue in the asymptotic theory of ordinary and delay differential equations is constructing sufficient conditions which ensure the existence of solutions with prescribed asymptotic behavior. From this point of view many authors studied second order differential equations with deviating argument of the form
rx00
.t /Da.t /f .x.0.t /// (1.1) or
x00.t /Df .t; x.1.t //; : : : ; x.m.t /// (1.2)
c 2018 Miskolc University Press
whererWR!.0;C1/,i.t /! 1ast! 1foriD0; : : : ; m, see e.g. [1], [2], [3], [11], and the references therein. Since difference equations can be treated as discret- ization of differential equations, the existence of solutions with prescribed asymptotic behavior of difference equations was studied in literature too, see for example, in [4], [12], [13] and the references therein.
In papers [4–9], the first author presented a new theory of the study of asymptotic properties of solutions of difference equations of the form
2xnDanf .x .n//Cbn
in which o.ns/, fors0, is used a measure of approximation. In the paper [10], we extend some of results on difference equations of Sturm-Liouville type of the form
.rnxn/Danf .x .n//Cbn:
This paper is a continuation of these investigations. Our main goal is to present sufficient conditions for the existence of a solutionxof equation (E) such that
xnDc.r11C Crn 11 /CdCo.ns/; (1.3) wherec; d 2Rands2. 1; 0. We give also sufficient conditions for a given solu- tionxof equation (E) to have an asymptotic property (1.3).
The paper is organized as follows. In Section 2, we introduce notation and present some preliminary lemmas. Next, Section 3 is devoted to our first main result Theorem 1, some consequences of it and the example which proves that one of assumptions in main theorem is essential. In Section 4 we prove our second main result and some corollaries from it. Moreover, this section includes the example which proves that one of assumptions of main theorem is not “too” strong.
2. PRELIMINARIES
The space of all sequencesxWN!Rwe denote byRN. Ifx; y inRN, then xy andjxjdenotes the sequences defined by.xy/nDxnynandjxjnD jxnj, respectively.
Moreover,
kxk Dsupfjxnj Wn2Ng:
For any sequencex2RNwe define a sequencexWN!Rmby xnD
(.0; 0; : : : ; 0/ forn < m C1 .xnC 1; xnC 2; : : : ; xnC m/ fornm C1:
We use the symboldmto denote the max-metric onRmdefined by dm.u; v/Dmaxfju1 v1j; : : : ;jum vmjg:
Moreover, B.u; ˛/denotes the closed ball of radius˛centered at a pointu2Rm. We say that a functiongWRm!Ris bounded at infinity if there exists a real number such thatgis bounded on the set
Œ;1/ Œ;1/DŒ;1/m:
In the same way, the boundedness at minus infinity can be defined.
Lemma 1. Ify2RNand.rnyn/D0, then there exist real constantsc; dsuch that
ynDc
n 1
X
jD1
1
rj Cd (2.1)
for anyn. Ifc; d 2Randy2RNis defined by(2.1), then.rnyn/D0.
Proof. We leave an easy proof of this lemma to the reader.
Lemma 2([10, Lemma 3]). Assumes2. 1; 0, t2Œs;1/,rn1DO.nt/,a2 RN, and
1
X
nD1
n1Ct sjanj<1; then
1
X
nD1
1 nsrn
1
X
jDn
jajj<1:
Lemma 3. Assume s2. 1; 0,t 2Œs;1/, rn1DO.nt/,a2RN, and at least one of the following conditions is satisfied
.a/ lim inf
n!1n
janj janC1j 1
> 2Ct s; .b/ lim inf
n!1 nlog janj
janC1j> 2Ct s:
Then
1
X
nD1
1 nsrn
1
X
jDn
jajj<1:
Proof. Using [7, Lemma 6.3] in case (a), or [7, Lemma 6.4] in case (b) we obtain
1
X
nD1
n1Ct sjanj<1:
By Lemma2we get the result.
Lemma 4. Assume2R,rn1DO.n/,a2RN, and at least one of the following conditions is satisfied
.a/ lim sup
n!1
janC1j
janj < 1; .b/ lim sup
n!1
pn
janj< 1:
Then
1
X
nD1
1 nsrn
1
X
jDn
jajj<1
for anys2. 1; 0.
Proof. Lets2. 1; 0. Choose a real numbert such thatt >max.s; /. Then rn1DO.nt/and, using the ratio test in case (a), or the root test in case (b) we get
1
X
nD1
n1Ct sjanj<1:
Hence the assertion is a consequence of Lemma2.
Lemma 5([10, Lemma 5]). If
1
X
kD1
1 rk
1
X
iDk
juij<1;
then
1
X
kD1
jukj
k
X
iD1
1 ri
<1 and
1
X
kDn
1 rk
1
X
iDk
juij
1
X
kDn
jukj
k
X
iD1
1 ri
for anyn2N.
Lemma 6([4, Lemma 4.7]). Assumey; WN!R, and lim
n!1nD0. In the set X D fx2RNW jx yj jjgwe define a metric by the formula
d.x; ´/D kx ´k: (2.2)
Then any continuous mapHWX !X has a fixed point.
3. SOLUTIONS WITH PRESCRIBED ASYMPTOTIC BEHAVIOR
In this section we establish various conditions under which for a given solutiony of the equation.rnyn/D0and a given nonpositive realsthere exists a solution xof (E) such thatxnDynCo.ns/.
Theorem 1. Assumes2. 1; 0,yis a solution of the equation.rnyn/D0,
1
X
kD1
1 ksrk
1
X
jDk
.jajj C jbjj/ <1; q2N; ˛2.0;1/; U D
1
[
nDq
B.yn; ˛/;
andf is continuous and bounded onU. Then there exists a solutionx of (E)such thatxnDynCo.ns/.
Proof. Forn2Nandx2RNlet
F .x/.n/Danf .xn/Cbn: (3.1) There existsL > 0, such that
jf .u/j L (3.2)
for anyu2U. Sinces0we have
1
X
kD1
1 rk
1
X
jDk
.Ljajj C jbjj/ <1: Let
Y D fx2RNW jx yj ˛g; 2RN; nD
1
X
kDn
1 rk
1
X
jDk
.Ljajj C jbjj/:
Ifx2Y, thenxn2U for largen. Hence the sequence.f .xn//is bounded for any x2Y. Define sequencesw; gby
wj DLjajj C jbjj; gnD
1
X
kDn
1 ksrk
1
X
jDk
wj:
Then
n snDn s
1
X
kDn
1 rk
1
X
jDk
wj D
1
X
kDn
1 nsrk
1
X
jDk
wj
1
X
kDn
1 ksrk
1
X
jDk
wj Dgn: (3.3) Using the assumption
1
X
kD1
1 ksrk
1
X
jDk
.jajj C jbjj/ <1
we getgnDo.1/. Hence, by (3.3),
nDnsgnDnso.1/Do.ns/:
Therefore there exists an indexpsuch that
n˛ and nC mq for np:
Let
X D fx2RNW jx yj andxnDynforn < pg; H WY !RN; H.x/.n/D
(yn forn < p
ynCP1
kDn 1 rk
P1
jDkF .x/.j / fornp:
Note thatXY. Ifx2X, then fornpwe have jH.x/.n/ ynj D
ˇ ˇ ˇ ˇ ˇ ˇ
1
X
kDn
1 rk
1
X
jDk
F .x/.j / ˇ ˇ ˇ ˇ ˇ ˇ
1
X
kDn
1 rk
1
X
jDk
jF .x/.j /j n:
ThereforeHXX. Letx2X, and" > 0. By Lemma5, we have
1
X
kD1
jakj
k
X
iD1
1 ri
<1:
Choose an indexqpand a positive constant such that L
1
X
kDq
jakj
k
X
iD1
1 ri
< " and
q
X
kDp
jakj
k
X
iD1
1 ri
< ":
Let
C D
q
[
nD1
B.yn; ˛/:
Since C is a compact subset of Rm, f is uniformly continuous on C. Choose a positiveısuch that ifu1; u22C anddm.u1; u2/ < ı, then
jf .u1/ f .u2/j< : Choose´2X such thatkx ´k< ı. Then
kH x H ´k D sup
np
ˇ ˇ ˇ ˇ ˇ ˇ
1
X
kDn
1 rk
1
X
jDk
.F .x/.j / F .´/.j //
ˇ ˇ ˇ ˇ ˇ ˇ
1
X
kDp
1 rk
1
X
jDk
jF .x/.j / F .´/.j /j
1
X
kDp
1 rk
1
X
jDk
jajjjf .xj/ f .´j/j:
By Lemma5
1
X
kDp
1 rk
1
X
jDk
jajjjf .xj/ f .´j/j
1
X
kDp
jakjjf .xk/ f .´k/j
k
X
iD1
1 ri
:
Hence
kH x H ´k
q
X
kDp
jakj
k
X
iD1
1 ri C2L
1
X
kDq
jakj
k
X
iD1
1 ri
< 3":
Therefore the mapH WX !X is continuous with respect to the metric defined by (2.2). By Lemma6there exists a pointx2X such thatxDH x. Then fornpwe have
xnDynC
1
X
kDn
1 rk
1
X
jDk
F .x/.j /:
Hence
.rnxn/D.rnyn/C 0
@rn 0
@
1
X
kDn
1 rk
1
X
jDk
F .x/.j / 1 A 1 A
fornp. Define a sequenceG by GnD
1
X
kDn
1 rk
1
X
jDk
F .x/.j /:
Then
rnGnDrn
0
@ 1 rn
1
X
jDn
F .x/.j / 1 A;
.rnGn/DF .x/.n/Danf .xn/CbnDanf .xnC 1; xnC 2; : : : ; xnC m/Cbn
for largen. Thereforexis a solution of (E). Sincex2X andnDo.ns/, we have
xnDynCo.ns/.
Corollary 1. Assumef is continuous,s2. 1; 0, and
1
X
kD1
1 ksrk
1
X
jDk
.jajj C jbjj/ <1:
Then for any bounded solutionyof the equation.rnyn/D0there exists a solution xof (E)such thatxnDynCo.ns/.
Proof. Assumeyis a bounded solution of the equation.rnyn/D0. Then the set
U D
1
[
nD1
B.yn; 1/
is bounded. Hencef is continuous and bounded onU. By Theorem1there exists a
solutionxof (E) such thatxnDynCo.ns/.
Corollary 2. Assumef is continuous,s2. 1; 0, and
1
X
kD1
1 ksrk
1
X
jDk
.jajj C jbjj/ <1:
Then for any real constantdthere exists a solutionxof(E)such thatxnDdCo.ns/.
Proof. Any constant sequence is a bounded solution of the equation.rnyn/D 0. Hence the assertion is a consequence of Corollary1.
Corollary 3. Assumef is continuous,s2. 1; 0,
1
X
kD1
1
rk <1; and
1
X
kD1
1 ksrk
1
X
jDk
.jajj C jbjj/ <1:
Then for anyc; d2Rthere exists a solutionxof (E)such that xnDc
n 1
X
jD1
1
rj CdCo.ns/:
Proof. Define a sequenceyby ynDc
n 1
X
jD1
1 rj Cd:
By Lemma1, y is a solution of the equation .rnyn/D0. By assumption, the sequenceyis bounded. Using Corollary1we get the result.
Corollary 4. Assumef is continuous and bounded,s2. 1; 0, and
1
X
kD1
1 ksrk
1
X
jDk
.jajj C jbjj/ <1:
Then for any solutiony of the equation.rnyn/D0 there exists a solutionx of (E)such thatxnDynCo.ns/.
Proof. This corollary is an immediate consequence of Theorem1.
Corollary 5. Assumef is continuous,s2. 1; 0,t2Œs;1/,rn1DO.nt/, and
1
X
nD1
n1Ct s.janj C jbnj/ <1:
Then for any bounded solutionyof the equation.rnyn/D0there exists a solution xof (E)such thatxnDynCo.ns/.
Proof. This corollary is a consequence of Lemma2and Corollary1.
Corollary 6. Assumef is continuous,s2. 1; 0,t2Œs;1/,rn1DO.nt/, and lim inf
n!1n
janj C jbnj janC1j C jbnC1j 1
> 2Ct s:
Then for any bounded solutionyof the equation.rnyn/D0there exists a solution xof (E)such thatxnDynCo.ns/.
Proof. This corollary is a consequence of Lemma3and Corollary5.
Corollary 7. Assumef is continuous and bounded at infinity,2R, 1
rn DO.n/ and lim sup
n!1
janC1j C jbnC1j janj C jbnj < 1:
Then for any positivec, any reald and anys2. 1; 0there exists a solutionxof (E)such that
xnDc
n 1
X
jD1
1
rj CdCo.ns/:
Proof. Letc2.0;1/,d 2R,s2. 1; 0. Define a sequenceyby ynDc
n 1
X
jD1
1 rj Cd:
By Lemma1,yis a solution of the equation.rnyn/D0. By Lemma4,
1
X
kD1
1 ksrk
1
X
jDk
.jajj C jbjj/ <1:
If the series
1
X
nD1
1 rn
(3.4) is convergent then the sequenceyis bounded and, using Corollary1we get the result.
Assume the series (3.4) is divergent. Sincec > 0, we haveyn! 1. There exists a real number˛such thatf is bounded onŒ˛;1/m. There exists an indexqsuch that ynC m> ˛C1for anynq. Let
U D
1
[
nDq
B.yn; 1/:
ThenU Œ˛;1/m. Hencef is continuous and bounded onU. Now, using Theorem
1we obtain the result.
Now we present an example that proves the assumption that the function f is bounded on some “neighborhood” of .yn/ such that .yn/ solves .rnyn/ =0 in Theorem1, is essential.
Example1. AssumemD2,
rnDn 1; anD2 n; bnD0; D0; sD0; f .x; y/Dx3Cexp.2y/:
Then equation (E) takes the form
.n 1xn/D2 n xn 13 Cexp.2xn 2/
: (3.5)
Let
ynD
n 1
X
kD1
1 rk D
n 1
X
kD1
kD n.n 1/
2 :
Thenf is continuous and not bounded on S1 nDq
B.yn; ˛/for any q2Nand˛ > 0.
Moreover,
1
X
kD1
1 ksrk
1
X
jDk
.jajj C jbjj/D
1
X
kD1
k
1
X
jDk
1 2j D2
1
X
kD1
k 2k <1: Assumexis a solution of (3.5) such that
xnDynC´n;
for largenand´nDo.ns/Do.1/. Since.n1yn/D0for largen, we have .1n´n/D.1nxn/D2 n xn 13 Cexp.2xn 2/
> 0
for largen. Therefore, the sequence 1n´nis eventually increasing, and there exists the limit
D lim
n!1 1
n´n> 1:
If <1, then the sequencen1´nis convergent inR. Hence the series
1
X
nD1
.n1xn/D
1
X
nD1
.1n´n/
is convergent. On the other hand for largen
.1nxn/D2 n x3n 1Cexp.2xn 2/
2 nexp.2xn 2/:
Since
xn yn
2 for largen, we get that
.n1´n/ > 2 nexp..n 2/.n 3//:
HenceD 1. Therefore 1n´n> 1for largenand we get
1
X
nD1
´n
1
X
nD1
nD 1:
On the other hand, since´n!0, the seriesP1
nD1´nis convergent.
4. ASYMPTOTIC BEHAVIOR OF SOLUTIONS
In this section we present sufficient conditions for a given solutionxof equation (E) to have an asymptotic propertyxnDynCo.ns/, where y is a solution of the equation.rnyn/D0ands2. 1; 0.
Theorem 2. Assume x is a solution of (E) such that the sequence .f .xn// is bounded,
s2. 1; 0; and
1
X
kD1
1 ksrk
1
X
jDk
.jajj C jbjj/ <1: Then there exists a solutionyof the equation.rnyn/D0such that
xnDynCo.ns/:
Proof. Define a sequenceuby
unD.rnxn/Danf .xn/Cbn: Since the sequence.f .xn//is bounded, we have
1
X
kD1
1 ksrk
1
X
jDk
jujj<1:
Define sequencesw; y; ´by wnD
1
X
kDn
1 rk
1
X
jDk
uj; ynDxn wn; ´nD
1
X
kDn
1 ksrk
1
X
jDk
uj:
Then
n sjwnj n s
1
X
kDn
1 rk
1
X
jDk
jujj D
1
X
kDn
1 nsrk
1
X
jDk
jujj
1
X
kDn
1 ksrk
1
X
jDk
jujj Do.1/:
HencewnDo.ns/. Moreover .rnwn/D
0
@rn 0
@
1
X
kDn
1 rk
1
X
jDk
uj
1 A 1 AD
0
@rn
0
@ 1 rn
1
X
jDn
uj
1 A
1 ADun
and we obtain
.rnyn/D.rnxn/ .rnwn/Dun unD0; xnDynCwnDynCo.ns/:
Corollary 8. Assumef is locally bounded,s2. 1; 0, and
1
X
kD1
1 ksrk
1
X
jDk
.jajj C jbjj/ <1:
Then for any bounded solutionxof (E)there exists a solutiony of the equation .rnyn/D0
such thatxnDynCo.ns/.
Proof. Assume x is a bounded solution of (E). Then the sequence x is also bounded. Sincef is locally bounded, the sequence.f .xn//is bounded. Hence the
result follows from Theorem2.
Corollary 9. Assumef is bounded,s2. 1; 0, and
1
X
kD1
1 ksrk
1
X
jDk
.jajj C jbjj/ <1:
Then for any solutionxof (E)there exists a solutionyof the equation .rnyn/D0
such thatxnDynCo.ns/.
Proof. The assertion is an immediate consequence of Theorem2.
Corollary 10. Assumef is bounded and
1
X
kD1
1
rk C jakj C jbkj
<1: Then any solutionxof (E)is convergent.
Proof. LetsD0and letxbe a solution of (E). By assumption the seriesP1
kD11=rk is convergent and the sequenceudefined byukDP1
jDk.jajj C jbjj/is convergent to zero. Hence
1
X
kD1
1 rk
1
X
jDk
.jajj C jbjj/ <1: (4.1) Therefore, by Corollary9and Lemma1, there exist real constantsc; dsuch that
xnDc
n 1
X
jD1
1
rj CdCo.ns/:
SincesD0andP1
kD11=rk<1, we get limn!1xnDcP1
kD11=rkCd. Corollary 11. Assumef is locally bounded and
1
X
kD1
1
rk C jakj C jbkj
<1: Then any bounded solutionxof (E)is convergent.
Proof. LetsD0and letxbe a bounded solution of (E). As in the proof of Corol- lary10we obtain (4.1). Using Corollary8and Lemma1we get the result.
Corollary 12. Assumef is locally bounded,s2. 1; 0,t2Œs;1/,rn1DO.nt/,
and 1
X
nD1
n1Ct s.janj C jbnj/ <1:
Then for any bounded solution x of (E) there exists a solution y of the equation .rnyn/D0such thatxnDynCo.ns/.
Proof. The assertion is a consequence of Lemma2and Corollary8.
Corollary 13. Assumef is locally bounded,s2. 1; 0,t2Œs;1/,rn1DO.nt/,
1
X
nD1
1
rn D 1; and
1
X
nD1
n1Ct s.janj C jbnj/ <1:
Then for any bounded solutionxof (E)there exists a real constantd such that xnDdCo.ns/:
Proof. Assumex be a bounded solution of (E). By Lemma 2 and Corollary 8, there existc; d2Rsuch that
xnDc
n 1
X
jD1
1
rj CdCo.ns/:
Sincexis bounded andP1
nD11=rnD 1, we havecD0.
Corollary 14. Assumef is locally bounded, 1
rn DO.1/; and
1
X
nD1
n.janj C jbnj/ <1: Then any bounded solution of (E)is convergent.
Proof. Lett DsD0 and letx be a bounded solution of (E). By Corollary 12 there exists a solutiony of the equation.rnyn/D0 such thatxnDynCo.1/.
Thenyis a bounded sequence. By Lemma1any bounded solutionyof the equation
.rnyn/D0is convergent. Hencexis convergent.
Corollary 15. Assumef is bounded at infinity,s2. 1; 0, t2Œs;1/,rn1D O.nt/,
lim inf
n!1nlog janj C jbnj
janC1j C jbnC1j > 2Ct s;
andxis a solution of (E)such thatlimn!1xnD 1. Then there exists a solutiony of the equation.rnyn/D0such thatxnDynCo.ns/.
Proof. Sincef is bounded at infinity and limn!1xnD 1, the sequence.f .xn//
is bounded. Using Lemma3and Theorem2we get the result.
Corollary 16. Assumef is locally bounded,2R,rn1DO.n/, lim sup
n!1
janC1j C jbnC1j janj C jbnj < 1;
andxis a bounded solution of (E). Then for anys2. 1; 0there exists a solution yof the equation.rnyn/D0such thatxnDynCo.ns/.
Proof. This assertion is a consequence of Lemma4and Corollary8.
Now we present an example that proves the assumption
1
X
kD1
1 ksrk
1
X
jDk
jajj<1:
is not enough in Theorem2.
Example2. AssumemD2,sD0,D0, rnDn2; anD 1
n2; bnD2nC1 2
n2; f .x; y/D x
jxj C1C yC3 jyj C2: Then equation (E) takes the form
.n2xn/D 1 n2
xn 1
jxn 1j C1C xn 2C3 jxn 2j C2
C2nC1 2
n2: (4.2) Notice thatf is bounded and
1
X
kD1
1 ksrk
1
X
jDk
jajj D
1
X
kD1
1 k2
1
X
jDk
1 j2 <1:
Moreover, the sequencexnDn, is a solution of (4.2). On the other hand, any solution of the equation.n2yn/D0is of the form
ynDc
n 1
X
kD1
1
rkCd Dc
n 1
X
kD1
1 k2Cd
for somec; d2R. Hence any solution of.n2yn/D0is convergent, which means thatxcannot be approximated by any solution of the equation.n2yn/D0.
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Authors’ addresses
Janusz Migda
Faculty of Mathematics and Computer Science, A. Mickiewicz University, Umultowska 87, 61-614 Pozna´n, Poland
E-mail address:migda@amu.edu.pl
Magdalena Nockowska-Rosiak
Institute of Mathematics, Lodz University of Technology, W´olcza´nska 215, 90-924 Ł´od´z, Poland E-mail address:magdalena.nockowska@p.lodz.pl