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volume 5, issue 2, article 26, 2004.

Received 08 August, 2003;

accepted 10 December, 2003.

Communicated by:N. Elezovi´c

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Journal of Inequalities in Pure and Applied Mathematics

PRICE AND HAAR TYPE FUNCTIONS AND UNIFORM DISTRIBUTION OF SEQUENCES

V. GROZDANOV AND S. STOILOVA

Department of Mathematics, South West University 66 Ivan Mihailov str.

2700 Blagoevgrad, Bulgaria.

EMail:vassgrozdanov@yahoo.com EMail:stanislavast@yahoo.com

c

2000Victoria University ISSN (electronic): 1443-5756 138-03

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Price and Haar Type Functions and Uniform Distribution of

Sequences V. Grozdanov and S. Stoilova

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Abstract

The Weyl criterion is shown in the terms of Price functions and Haar type func- tions. We define the so-called modified integrals of Price and Haar type func- tions and obtain the analogues of the criterion of Weyl, the inequalities of LeV- eque and Erdös-Turan and the formula of Koksma in the terms of the modified integrals of Price and Haar type functions.

2000 Mathematics Subject Classification:65C05; 11K38; 11K06.

Key words: Uniform distribution of sequences; Price and Haar type functions; Weyl criterion; Inequalities of LeVeque and Erdös-Turan; Formula of Koksma.

Contents

1 Introduction. . . 3

2 Price Functional System, Haar Type Functional System and Analogues of the Criterion of Weyl. . . 6

3 Price and Haar Type Integrals and u.d. of Sequences . . . 9

4 Preliminary Statements. . . 13

5 Proofs of the Main Results. . . 27

6 Conclusion. . . 35 References

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Price and Haar Type Functions and Uniform Distribution of

Sequences V. Grozdanov and S. Stoilova

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1. Introduction

Letξ = (xi)i≥0be a sequence in the unit interval[0,1).We defineA(ξ;J;N) = {i : 0 ≤ i ≤ N −1, xi ∈ J}for an arbitrary integerN ≥ 1and an arbitrary subintervalJ ⊆[0,1).The sequenceξis called uniformly distributed (abbrevi- ated u. d.) if for every subinterval J of [0,1)the equality limN→∞ A(ξ;J;N)

N =

µ(J)holds, and whereµ(J)is the length ofJ.

LetξN = {x0, . . . , xN−1}be an arbitrary net of real numbers in[0,1). The extreme and quadratical discrepanciesD(ξN)andT(ξN)of the netξN are de- fined respectively as

D(ξN) = sup

J⊆[0,1)

|N−1A(ξN;J;N)−µ(J)|,

T(ξN) = Z 1

0

|N−1A(ξN; [0, x);N)−x|2dx 12

.

The discrepancy DN(ξ) of the sequenceξ is defined asDN(ξ) = D(ξN),for each integer N ≥ 1, and ξN is the net, composed of the first N elements of the sequence ξ. It is well-known that the sequence ξ is u. d. if and only if limN→∞DN(ξ) = 0.

According to Kuipers and Niederreiter [8, Corollaries 1.1 and 1.2], the se- quence ξ is u. d. if and only if for each complex-valued and integrable in the sense of Riemann function f, defined on R and periodical with period 1, the following equality

(1.1) lim

N→∞

1 N

N−1

X

i=0

f(xi) = Z 1

0

f(x)dx

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Price and Haar Type Functions and Uniform Distribution of

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holds.

The theory of uniformly distributed sequences is divided into quantitative and qualitative parts. Quantitative theory considers measures, showing the de- viation of the distribution of a concrete sequence from an ideal distribution.

Qualitative theory main idea of uniformly distributed sequences is to find nec- essary and sufficient conditions for uniformity of the distribution of sequences.

Weyl [18] obtains such a condition (the so-called Weyl criterion) which is based on the use of the trigonometric functional system T = {ek(x) = exp(2πikx), k∈Z, x∈R}.The criterion of Weyl is: The sequenceξ = (xi)i≥0

is uniformly distributed if and only if the equalitylimN→∞ 1 N

PN−1

i=0 ek(xi) = 0 holds for each integerk 6= 0.

The Walsh functional system has been recently used as an appropriate means of studying the uniformity of the distribution of sequences. Sloss and Blyth [13] use this system to obtain future necessary and sufficient conditions for a sequence to be u. d.

The link, which is realized for studying sequences in[0,1),constructed in a generalized number system and some orthonormal functional systems on[0,1), constructed in the same system, is quite natural. The purpose of our paper is to reveal the possibility some other classes of orthonormal functional system, as the Price functional system and two systems of Haar type functions to be used as a means of obtaining new necessary and sufficient conditions for uniform distribution of sequences.

In Section2we obtain new necessary and sufficient conditions for uniform distribution of sequences, which are analogues of the classical criterion of Weyl.

These conditions are based on the functions of Price and Haar type functions.

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In Section3we introduce the so-called modified integrals of the Price func- tions and Haar type functions. Integral analogues of the Weyl criterion are ob- tained in terms of these integrals. Analogues of the classical inequalities of LeVeque [9] and Erdös-Turan (see Kuipers and Niederreiter [8]), and the for- mula of Koksma, (see Kuipers [7]) are obtained.

In Section4we prove some preliminary statements, which are used to prove the main results. The proofs of the main results are given in Section5. In Sec- tion 6we give a conclusion, where we announce some open problems, having to do with the problems, solved in our paper.

The results of this paper were announced in Grozdanov and Stoilova [3] and [4]. Here we explain the full proofs of them. The results which are based on the Price functions generalize the ones of Sloss and Blyth [13]. The results which are based on the Haar type functions are new.

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2. Price Functional System, Haar Type Functional System and Analogues of the Criterion of Weyl

Let B = {b1, b2, . . . , bj, . . . : bj ≥ 2, j ≥ 1}be an arbitrary fixed sequence of integer numbers. We defineωj = exp

2πi bj

for each integerj ≥ 1.We define the set of the generalized powers {Bj}j=0 as: B0 = 1 and for each integer j ≥1, Bj =Qj

s=1bs. Definition 2.1.

(i) For realx ∈[0,1)in theB−adic formx=P

i=1xiBi−1,where fori≥ 1 xi ∈ {0,1, . . . , bi − 1} and each integer j ≥ 0, Price [10] defines the functionsχBj(x) =ωj+1xj+1.

(ii) For each integerk ≥0in theB−adic formk = Pn

j=0kj+1Bj,where for 1≤j ≤n+ 1, kj ∈ {0,1, . . . , bj−1}, kn+1 6= 0and realx∈[0,1),the k-th function of Priceχk(x)is defined asχk(x) = Qn

j=0Bj(x))kj+1. The system χ(B) = {χk}k=0 is called the Price functional system. This system is a complete orthonormal system inL2[0,1).

Let bj = b in the sequence B for each j ≥ 1. Then, the system {χ0} ∪ {χbk}k=0 is the Rademacher [11] system{φ(b)k }k=0 of orderb. The system of Chrestenson [2]{ψk(b)}k=0 of orderb is obtained from the system χ(B).If for eachj ≥1bj = 2,then the original system of Walsh [17] is obtained.

In 1947 Vilenkin [15] introduced the systemχ(B)and Price [10] defined it independently of him in 1957. Some names are used about the system χ(B)in special literature: both Price system (see Agaev, Vilenkin, Dzafarly, Rubinstein

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[1]) and Vilenkin system (see Schipp, Wade, Simon [12]). We use the name Price functional system in this paper.

We will consider two kinds of the so-called Haar type functions. Starting from the original Haar [5] system, Vilenkin [16] proposes a new system of func- tions, which is called a Haar type system, (see Schipp, Wide, Simon [12]). This definition is:

Definition 2.2. For x ∈ [0,1)thekth Haar type functionh0k(x), k ≥ 0to the baseBis defined as follows: Ifk = 0,thenh00(x) = 1,∀x∈ [0,1).Ifk ≥ 1is an arbitrary integer and

(2.1) k =Bn+p(bn+1−1) +s−1,

where for some integern≥0,0≤p≤Bn−1ands∈ {1, . . . , bn+1−1},then

h0k(x) =

√Bnωsan+1, if pbBn+1+a

n+1 ≤x < pbn+1B +a+1

n+1 and a= 0,1, . . . , bn+1−1,

0, otherwise.

We will consider another one:

Definition 2.3. For x ∈ [0,1)thekth Haar type functionh00k(x), k ≥ 0to the baseBis defined as follows: Ifk = 0,thenh000(x) = 1,∀x∈ [0,1).Ifk ≥ 1is an arbitrary integer and

(2.2) k =knBn+p,

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where for some integern ≥ 0,0 ≤ p ≤ Bn−1andkn ∈ {1, . . . , bn+1−1}, then

h00k(x) =

√Bnωkn+1na, if pbBn+1+a

n+1 ≤x < pbn+1B +a+1

n+1 and a= 0,1, . . . , bn+1−1,

0, otherwise.

It can be easily seen that the systems {h0k}k=0 and {h00k}k=0 are complete orthonormal systems in L2[0,1). In the case when for eachj ≥ 1bj = 2the original system of Haar is obtained from the systems{h0k}k=0 and{h00k}k=0. Theorem 2.1 (Analogues of the criterion of Weyl). The sequence (xi)i≥0 of [0,1)is u. d. if and only if:

Nlim→∞

1 N

N−1

X

i=0

χk(xi) = 0, for each k ≥1,

N→∞lim 1 N

N−1

X

i=0

h0k(xi) = 0, for each k≥1,

and

N→∞lim 1 N

N−1

X

i=0

h00k(xi) = 0, for each k≥1.

The proof of this theorem is based on the equality (1.1) and the properties of Price and Haar type functional systems.

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Price and Haar Type Functions and Uniform Distribution of

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3. Price and Haar Type Integrals and u.d. of Sequences

We consider the integrals of Price and Haar type functionsJk(x) = Rx

0 χk(t)dt, Ψ0k(x) = Rx

0 h0k(t)dt and Ψ00k(x) = Rx

0 h00k(t)dt for each integer k ≥ 1 and x∈[0,1).

For an arbitrary integerk ≥ 1we define the integern ≥0by the condition Bn≤k < Bn+1.We define the modified integrals of Price function as

(3.1) Jn,q,k(x) = Jk(x) + 1 Bn+1

· 1

ωqn+1−1δq.Bn,k,

for all x ∈ [0,1) and each q = 1,2, . . . , bn+1 −1, and for arbitrary integers i, j ≥0, δi,j is the Kronecker’s symbol.

Ifkis an integer of the kind (2.1), we define (3.2) Ψ0n,s,k(x) = Ψ0k(x) + 1

bn+1B

3

n2

1 ωn+1s −1, for allx∈[0,1)and eachs = 1,2, . . . , bn+1−1.

Ifkis an integer of the kind (2.2), we define (3.3) Ψ00n,kn,k(x) = Ψ00k(x) + 1

bn+1

B

3

n2

1 ωn+1kn −1, for allx∈[0,1)and eachkn= 1,2, . . . , bn+1−1.

We will call the integralsΨ0n,s,k(x)andΨ00n,kn,k(x)modified integrals of Haar type functions. The next theorems hold:

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Theorem 3.1 (Analogues of the inequality of LeVeque). LetξN ={x0, x1. . . , xN−1}be an arbitrary net, composed ofN ≥1points of[0,1). The discrepancy D(ξN)of the netξN satisfies the inequalities:

D(ξN)≤

 12 N2

X

n=0 bn+1−1

X

q=1

(q+1)Bn−1

X

k=qBn

N−1

X

m=0

Jn,q,k(xm)

2

1 3

,

D(ξN)≤

 12 N2

X

n=0 bn+1−1

X

s=1

(s+1)Bn−1

X

k=sBn

N−1

X

m=0

Ψ0n,s,k(xm)

2

1 3

,

D(ξN)≤

 12 N2

X

n=0 bn+1−1

X

kn=1

(kn+1)Bn−1

X

k=knBn

N−1

X

m=0

Ψ00n,k

n,k(xm)

2

1 3

.

Theorem 3.2 (Integral analogues of the criterion of Weyl). Let an absolute constant B exist, such as for each j ≥ 1 bj ≤ B. Let k ≥ 1 be an arbitrary integer andBn ≤ k < Bn+1.The sequenceξ = (xi)i≥0 of[0,1)is u. d. if and only if:

(i)

N→∞lim 1 N

N−1

X

i=0

Jn,q,k(xi) = 0 for each q = 1,2, . . . , bn+1−1,

(ii) Ifk ≥1is of the kind (2.1) then

N→∞lim 1 N

N−1

X

i=0

Ψ0n,s,k(xi) = 0 for each s= 1,2, . . . , bn+1−1,

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(iii) Ifk ≥1is of the kind (2.2) then

N→∞lim 1 N

N−1

X

i=0

Ψ00n,k

n,k(xi) = 0 for each kn= 1,2, . . . , bn+1−1.

Theorem 3.3 (An analogue of the inequality of Erdös-Turan). Let an ab- solute constant B exist, such that bj ≤ B for each j ≥ 1 and we signify b = min{bj : j ≥ 1}. Let ξN = {x0, . . . , xN−1} be an arbitrary net, com- posed ofN ≥ 1points of[0,1).For an arbitrary integerH > 0we define the integers M ≥ 0and q ∈ {1,2, . . . , bM+1−1} asqBM ≤ H < (q+ 1)BM. Then the following inequality holds

D(ξN)≤

12

M−1

X

n=0 bn+1−1

X

s=1

(s+1)Bn−1

X

k=sBn

1 N

N−1

X

m=0

Jn,s,k(xm)

2

+ 12

q−1

X

s=1

(s+1)BM−1

X

k=sBM

1 N

N−1

X

m=0

JM,s,k(xm)

2

+12

H

X

k=qBM

1 N

N−1

X

m=0

JM,q,k(xm)

2

+3B(1 + 2bsinBπ)2 (b−1)bsin2 Bπ

1 BM

1 3

.

Theorem 3.4 (Analogues of the formula of Koksma). Let ξN = {x0, x1. . . , xN−1}be an arbitrary net, composed ofN ≥1points of[0,1).The quadratical

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discrepancyT(ξN)of the netξN satisfies the equalities

(N T(ξN))2 =

N−1

X

m=0

xm−1 2

!2

+

X

n=0 bn+1−1

X

q=1

(q+1).Bn−1

X

k=q.Bn

N−1

X

m=0

Jn,q,k(xm)

2

,

(N T(ξN))2 =

N−1

X

m=0

xm−1 2

!2

+

X

n=0 bn+1−1

X

s=1

(s+1)Bn−1

X

k=sBn

N−1

X

m=0

Ψ0n,s,k(xm)

2

, and

(N T(ξN))2 =

N−1

X

m=0

xm− 1 2

!2

+

X

n=0 bn+1−1

X

kn=1

(kn+1)Bn−1

X

k=knBn

N−1

X

m=0

Ψ00n,kn,k(xm)

2

.

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4. Preliminary Statements

Let x ∈ [0,1) have the B−adic representation x = P

j=0xj+1Bj+1−1 , where for j ≥ 0, xj+1 ∈ {0,1, . . . , bj+1 −1}. For each integerj ≥ 0 we have that xj+1 = bj+1 argχBj(x).Hence, we obtain the representation

(4.1) x= 1

X

j=0

1

Bj argχBj(x).

Lemma 4.1. Let k ≥ 1be an arbitrary integer and k = βn+1Bn +k0,where βn+1 ∈ {1, . . . , bn+1−1}and0≤k0 < Bn.Forx∈[0,1)thekthPrice integral satisfies the following equality

(4.2) Jk(x) = 1 Bn+1

1−ω

βn+1bn+1

argχBn(x) n+1

1−ωβn+1n+1 χk0(x)

+ 1

2πBn

X

r=1

b−rn+1argχBn brn+1x

χk(x).

Proof. Letb≥2be a fixed integer andω= exp 2πib

.For an arbitrary integer β,1≤β ≤b−1and realx∈[0,1)let

Jβ(b)(x) = Z x

0

ψ(b)β (t)dt.

We will prove the following equality (4.3) Jβ(b)(x) = 1

b

1−ωβbargφ(b)0 (x) 1−ωβ + 1

X

r=1

b−rargψb(b)r (x)ψβ(b)(x).

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We puts= [bx],where[bx]denotes the integer part ofbxand we have that Jβ(b)(x) =

Z x 0

(b)0 (t)]βdt (4.4)

=

s−1

X

h=0

Z (h+1)/b h/b

ωdt+ Z x

s/b

(b)0 (t)]βdt

= 1 b

1−ωβ[bx]

1−ωββ(b)(x)

x−[bx]

b

. From (4.1) and (4.4) we obtain (4.3).

If

Jβ(bn+1)

n+1·Bn(x) = Z x

0

χβn+1Bn(t)dt,

then

(4.5) Jk(x) = χk0(x)Jβ(bn+1)

n+1Bn(x).

We have the equalities Jβ(bn+1)

n+1·Bn(x) = Z x

0

χβBn+1

n (t)dt

= Z x

0

h

φ(b0n+1)(Bnt)iβn+1

dt

= 1 Bn

Z Bnx 0

ψβ(bn+1)

n+1 (t)dt= 1 Bn

Jβ(bn+1)

n+1 (Bnx),

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so that

Jβ(bn+1)

n+1·Bn(x) = 1 Bn

Jβ(bn+1)

n+1 (Bnx).

From the last equality and (4.5) we obtain that

(4.6) Jk(x) = 1

Bnχk0(x)·Jβ(bn+1n+1)(Bnx).

From (4.3) we obtain

(4.7) Jβ(bn+1)

n+1 (Bnx) = 1

bn+1 · 1−ωβn+1bn+1 argχBn(x) 1−ωn+1βn+1 + 1

X

r=1

b−rn+1argχBn(brn+1x)χβn+1Bn(x).

From (4.6) and (4.7) we obtain (4.2).

For every integer n ≥ 1we consider the set B(n) = {b1, b2, . . . , bn}. We define the “reverse” set B(n) =e {bn, bn−1, . . . , b1}, so that Be1 = bn, Be2 = bnbn−1, . . . ,Ben = bn· · ·b1.For an arbitrary integer p,0 ≤ p < Bn and for a B-adic rational Bp

n let (p)B(n),(p)

B(n)e ,

p Bn

B(n) and p

Bn

B(n)e be the corre- sponding representations ofpand Bp

n to the systemsB(n)andBe(n).

Lemma 4.2. (Relationships between the Price and the Haar type functions)

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(i) Letk ≥1be an arbitrary integer of the kind (2.1). Then for allx∈[0,1)

h0k(x) = 1 bn+1

Bn

×

Bn+1−1

X

α=0

bn+1−1

X

a=0

ωa.sn+1χ(pbn+1+a)

B(n+1)e

α Bn+1

B(n+1)e

!

χα(x);

Ψ0n,s,k(x) = 1 bn+1

Bn

×

n

X

j=0 bj+1−1

X

t=0

(t+1)Bj−1

X

α=tBj

bn+1−1

X

a=0

ωn+1a.s χ(pbn+1+a)

B(n+1)e

α Bn+1

B(n+1)e

!

Jj,t,α(x).

(ii) Letk ≥1be an arbitrary integer of the kind (2.2). Then for allx∈[0,1)

(4.8) h00k(x) = 1 bn+1

Bn

×

Bn+1−1

X

α=0

bn+1−1

X

a=0

ωa.kn+1nχ(pb

n+1+a)

B(n+1)e

α Bn+1

B(n+1)e

!

χα(x);

(4.9) Ψ00n,kn,k(x) = 1 bn+1

Bn

×

n

X

j=0 bj+1−1

X

t=0

(t+1)Bj−1

X

α=tBj

bn+1−1

X

a=0

ωn+1a.knχ(pbn+1+a)

B(n+1)e

α Bn+1

B(n+1)e

!

Jj,t,α(x).

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Proof. For an arbitrary integerp,0≤p < Bnandx∈[0,1),following Kremer [6] we define the function

q(Bn; (p)

B(n)e ;x) =









1, if x∈

p Bn

B(n),

p+1 Bn

B(n)

0 if x6∈

p Bn

B(n), p+1

Bn

B(n)

.

The equality

q(Bn; (p)B(n)e ;x) = 1 Bn

Bn−1

X

α=0

χ(p)

B(n)e

α Bn

B(n)e

! χα(x)

holds. Let us use the significations: For an arbitrary integer p, 0 ≤ p <

Bn, (p)B(n)e = (˜p12. . .p˜n)B(n)e , for an arbitrary integer α, 0 ≤ α < Bn, α

Bn

B(n)e

= (0·αnαn−1. . . α1)

B(n)e ,for realx∈[0,1), x= (0·x1. . . xn+1. . .)B. Then, we obtain the equalities

(4.10) χ(p)

B(n)e

α Bn

B(n)e

!

αnnp˜nωn−1αn−1p˜n−1. . . ω1α1p˜1

and

(4.11) χα(x) =ω1α1x1ω2α2x2. . . ωnαnxn.

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Price and Haar Type Functions and Uniform Distribution of

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If x ∈

p Bn

B(n)

,

p+1 Bn

B(n)

, then for all j = 1, . . . , n, xj = ˜pj. From (4.10) and (4.11) we obtain

χ(p)

B(n)e

α Bn

B(n)e

!

χα(x) = 1.

If x 6∈

p Bn

B(n), p+1

Bn

B(n)

, then, some δ, 1 ≤ δ ≤ n exists, so that xδ 6= ˜pδ.Then, we have that

bδ−1

X

αδ=0

ωαδδ(xδ−˜pδ) = 0.

From (4.10) and (4.11), we obtain

Bn−1

X

α=0

χ(p)

B(n)e

α Bn

B(n)e

!

χα(x) =

n

Y

j=1 bj−1

X

αj=0

ωαjj(xj−˜pj) = 0.

Now letk ≥ 1be an integer of the kind (2.2). In order to prove (4.8) we note that for allx∈[0,1)

h00k(x) =p Bn

bn+1−1

X

a=0

ωn+1a.knq

Bn+1; (pbn+1+a)B(n+1)e ;x .

(19)

Price and Haar Type Functions and Uniform Distribution of

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We will prove (4.9). Using the proved formula forh00k(x),we have that Ψ00k(x) =

Z x 0

h00k(t)dt (4.12)

= 1

bn+1√ Bn

Bn+1−1

X

α=0

bn+1−1

X

a=0

ωn+1a.kn

×χ(pbn+1+a)

B(n+1)e

α Bn+1

B(n+1)e

!Z x 0

χα(t)dt

= 1

bn+1

√Bn n

X

j=0 bj+1−1

X

t=0

(t+1)Bj−1

X

α=tBj

bn+1−1

X

a=0

ωa.kn+1n

×χ(pbn+1+a)

B(n+1)e

α Bn+1

B(n+1)e

!

×

Jj,t,α(x)− 1 Bj+1

1

ωj+1t −1δtBj

.

It is not difficult to prove that (4.13)

n

X

j=0

1 Bj+1

bj+1−1

X

t=0

1 ωj+1t −1

(t+1)Bj−1

X

α=tBj

bn+1−1

X

a=0

ωn+1a.kn

×χ(pbn+1+a)

B(n+1)e

α Bn+1

B(n+1)e

!

δtBj= Bn−1 ωn+1kn −1. From (4.12) and (4.13), we obtain (4.9).

(20)

Price and Haar Type Functions and Uniform Distribution of

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In the following lemma the relationships in the opposite direction are proved.

Lemma 4.3. Let k ≥ 1 be an arbitrary integer and k = sBn +p, where s ∈ {1, . . . , bn+1 −1} and 0 ≤ p ≤ Bn −1. Then, for all x ∈ [0,1) the equalities

(4.14) χk(x) = 1

√Bn Bn−1

X

j=0

α(n)

p,˜jh00sB

nj(x);

(4.15) Jn,s,k(x) = 1

√Bn

Bn−1

X

j=0

α(n)

p,˜jΨ00n,s,sB

nj(x);

χk(x) = 1

√Bn

Bn−1

X

j=0

α(n)

p,˜jh0B

nj(bn+1−1)+s−1(x)

and

Jn,s,k(x) = 1

√Bn

Bn−1

X

j=0

α(n)

p,˜jΨ0n,s,B

nj(bn+1−1)+s−1(x), hold, whereα(n)p,˜j are complex mumbers, so thatPBn−1

j=0 α(n)p,˜j =Bn·δsBn,k. Proof. Let x ∈ [0,1) be fixed. We define t˜ = (t)B(n)e , 0 ≤ t < B˜ n as ˜

t Bn

B(n)

≤ x < ˜

t+1 Bn

B(n)

. We denote ∆(n)˜t = h ˜

t Bn,˜t+1B

n

. It is obvious

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Price and Haar Type Functions and Uniform Distribution of

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that ∆(n)˜t = Sbn+1−1

a=0(n+1)˜tb

n+1+a. There is some a, 0 ≤ a ≤ bn+1 − 1, so that x∈∆(n+1)˜tb

n+1+a.We have the equalities χk(x) = χp

˜t Bn

B(n)

!

ωn+1a.s and h00s·B

nt(x) =p

Bnωa.sn+1.

Hence, we obtain

χk(x) = 1

√Bnχp

t˜ Bn

B(n)

! h00s·B

nt(x).

Let˜t0 be an arbitrary integer, so that0≤t˜0 < Bn,andt˜0 6= ˜t.Forx∈ ∆(n)t˜ we have thath00s·B

nt0(x) = 0.Hence, we obtain the equality χk(x) = 1

√Bn

Bn−1

X

j=0

χp ˜j

Bn

B(n)

! h00s·B

nj(x).

Let for integers0≤p < Bnand0≤j < Bnwe signifyα(n)

p,˜jp ˜

j Bn

B(n)

. We use the representationsp= (pnpn−1. . . p1)B(n) and

˜j Bn

B(n)

= (0·j1j2. . . jn)B(n),

where for1≤τ ≤n pτ, jτ ∈ {0,1, . . . , bτ−1}.Then, we obtain the equality (4.16)

Bn−1

X

j=0

α(n)

p,˜j =

n

Y

τ=1 bτ−1

X

jτ=0

ωτpτjτ.

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Price and Haar Type Functions and Uniform Distribution of

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Ifp= 0,then, for1≤τ ≤n, pτ = 0and from (4.16) we obtainPBn−1 j=0 α(n)

p,˜j = Bn.Ifp6= 0then, someδ, 1≤ δ ≤ nexists, so thatpδ 6= 0.From (4.16), we obtainPBn−1

j=0 α(n)

p,˜j = 0.

We will prove (4.15). From (4.14) for allx∈[0,1)we have

Jk(x) = 1

√Bn

Bn−1

X

j=0

α(n)

p,˜j

Ψ00sB

nj(x) + 1 bn+1B

3

n2

1 ωsn+1−1

− 1

bn+1Bn−2 1 ωn+1s −1

Bn−1

X

j=0

α(n)p,˜j.

From the last equality and (3.3) we obtain (4.15).

Sobol [14] proved a similar result, giving the relationship between the origi- nal Haar and the Walsh functions.

For an arbitrary net ξN = {x0, . . . , xN−1}, composed ofN ≥ 1 points of [0,1)andx ∈ [0,1)we signifyR(ξN;x) = A(ξN; [0, x);N)−N x.Then, the next lemma holds:

Lemma 4.4.

(i) The Fourier-Price coefficiens ofR(ξN;x)satisfy the equalities:

a(χ)0 =−

N−1

X

m=0

xm− 1 2

;

(23)

Price and Haar Type Functions and Uniform Distribution of

Sequences V. Grozdanov and S. Stoilova

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and for each integerk ≥ 1, k = knBn +p, kn ∈ {1,2, . . . , bn+1 −1}, 0≤p < Bn

a(χ)k =−

N−1

X

m=0

Jn,kn,k(xm).

(ii) The Fourier-Haar type coefficiens ofR(ξN;x)satisfy the equalities:

a(h0 0)=−

N−1

X

m=0

xm−1 2

, a(h0 00)=−

N−1

X

m=0

xm−1 2

;

Letk ≥1be an arbitrary integer of kind (2.1). Then,

a(hk0) =−

N−1

X

m=0

Ψ0n,s,k(xm).

Letk ≥1be an arbitrary integer of kind (2.2). Then,

(4.17) a(hk00) =−

N−1

X

m=0

Ψ00n,kn,k(xm).

Proof. Let for 0 ≤ m ≤ N −1, cm(x) be the characteristic function of the interval(xm,1).Then,

R(ξN;x) =

N−1

X

m=0

cm(x)−N x.

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Price and Haar Type Functions and Uniform Distribution of

Sequences V. Grozdanov and S. Stoilova

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We will prove only (4.17). The proof of the remaining equalities of the lemma is similar. For an arbitrary integerk ≥1of the kind (2.2) we have:

a(hk00) = Z 1

0

R(ξN;x)h00k(x)dx (4.18)

=

N−1

X

m=0

Z 1 0

cm(x)h00k(x)dx−N Z 1

0

xh00k(x)dx.

The equalities

N−1

X

m=0

Z 1 0

cm(x)h00k(x)dx=

N−1

X

m=0

Z 1 0

h00k(x)dx− Z xm

0

h00k(x)dx (4.19)

=−

N−1

X

m=0

Ψ00k(xm)

hold. From (4.1) and (4.8) we obtain Z 1

0

xh00k(x)dx (4.20)

= 1

2πbn+1

√Bn Bn+1−1

X

α=0

bn+1−1

X

a=0

ωn+1a·knχ(pbn+1+a)

B(n+1)e

α Bn+1

B(n+1)e

!

×

X

r=0

1 Br

Z 1 0

argχBr(x)χα(x)dx

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