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Electronic Journal of Qualitative Theory of Differential Equations 2011, No. 30, 1-12;http://www.math.u-szeged.hu/ejqtde/

Existence of almost periodic solution for SICNN with a neutral delay

Zheng Fang1 Yongqing Yang2

School of Science, Jiangnan University, Wuxi, 214122, PR China Abstract

In this paper, a kind of shunting inhibitory cellular neural network with a neutral delay was considered. By using the Banach fixed point theorem, we established a result about the existence and uniqueness of the almost periodic solution for the shunting inhibitory cellular neural network.

Keywords: shunting inhibitory cellular neural network, neutral delay, almost periodic solution, fixed point theorem.

1. Introduction

Shunting inhibitory cellular neural network (SICNN) is a kind of very important model and has been investigated by many authors (see [1, 2, 3, 4] and the reference therein) due to its wide applications in practical fields such as robotics, adaptive pattern recognition and image processing. In [1], Ding studied the following SICNN

xij =−aijxij − X

CklNr(i,j)

Cijklf[xkl(t−τ(t))]xij(t) +Lij(t),

Most of the existing SICNN models are concerns with the delays in the state.

However, it is not enough for it can not describe the phenomenon precisely. It is natural and useful to consider the model with a neutral delay, it means that the system describing the model depends on not only the past information of the state but also the information of the derivative of the state, i.e., the decay rate of the cells. This kind of model is described by a differential equation with a neutral delay. The neutral type differential equations have many applications, for more details we refer to [6]. Some authors have considered the Hopfield neural networks with neutral delays, see [7, 8].

To the best of our knowledge, there is few consideration about the shunting inhibitory cellular neural network with a neutral delay. In this paper, we consider the following

1e-mail: fangzhengjd@126.com, corresponding author

2e-mail: yyq640613@gmail.com

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shunting inhibitory cellular neural network with a neutral delay:

xij =−aij(t)xij − X

Ckl∈Nr(i,j)

Cijkl(t)f[xkl(t−τ(t))]xij(t)

− X

CklNs(i,j)

Dklij(t)g[xkl(t−σ(t))]xij(t) +Iij(t). (1.1) In this model, Cij represents the cell at the (i, j) position of the lattice, the r−neighborhood Nr(i, j) of Cij is defined as follows

Nr(i, j) =n

Ckl : max{|k−i|,|l−j |} ≤r, 1≤k ≤m,1≤l ≤no ,

xij(t) describes the state of the cell Cij, the coefficient aij(t) >0 is the passive decay rate of the cell activity, Cijkl(t), Dijkl(t) are connection weights or coupling strength of postsynaptic activity of the cell Ckl transmitted to the cellCij, and f, gare continuous activity functions, representing the output or firing rate of the cell Ckl , andτ(t), σ(t) correspond to the transmission delays.

In the following, we give some basic knowledge about the almost periodic functions and almost periodic solutions of differential equations, please refer to [9, 10] for more details.

Definition 1.1(See [10]) Letu:R→Rnbe continuous in t. uis said to be almost periodic on R if, for any ǫ > 0, the set T(u, ǫ) = {δ :| u(t+δ)−u(t)|< ǫ,∀ t ∈R} is relatively dense, i.e., for ∀ǫ > 0, it is possible to find a real number l = l(ǫ) > 0, for any interval with length l(ǫ), there exists a number δ=δ(ǫ) in this interval such that

|u(t+δ)−u(t)|< ǫ, for all t∈R.

Definition 1.2 ([9, 10]) If u:R→Rn is continuously differentiable in t, u(t) and u(t) are almost periodic on R, then u(t) is said to be a continuously differentiable almost periodic function.

LetAP(R,Rm×n) andAP1(R,Rm×n) be the set of continuous almost periodic func- tions, and continuously differentiable almost periodic functions from R to Rm×n, re- spectively. For each ϕ ∈AP1(R,Rm×n), define

kϕk0 = sup

tR

maxi,j {|ϕi,j |}, kϕk= max{kϕk0,kϕk0}.

It is easy to check that (AP(R,Rm×n),k · k0) and (AP1(R,Rm×n),k · k) are all Banach spaces.

Definition 1.3 ([9, 10]) Let x ∈ Rn and Q(t) be an n ×n continuous matrix defined on R. The linear system

x(t) =Q(t)x(t) (1.2)

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is said to admit an exponential dichotomy on R if there exist positive constants k, α, projection P and the fundamental solution matrix X(t) of (1.2) satisfying

kX(t)P X1(s)k< keα(ts), t ≥s, kX(t)(I−P)X1(s)k< ke−α(s−t), t≤s.

Lemma 1.1 ([9, 10]) If the linear system (1.2) admits an exponential dichotomy, then almost periodic system

x(t) =Q(t)x(t) +g(t) (1.3) has a unique almost periodic solutionx(t), and

x(t) = Z t

−∞

X(t)P X1(s)ds− Z +

t

X(t)(I −P)X(s)ds. (1.4) Lemma 1.2 ([9, 10]) Let c(t) be an almost periodic function on R and

M[ci] = lim

T+

1 T

Z t+T t

ci(s)ds >0, i= 1,2,· · ·n.

Then the linear system

x(t) =diag(−c1(t),−c2(t),· · ·, cn(t))x(t) admits an exponential dichotomy on R.

2. Main results

Firstly, We give some assumptions.

(H1) aij(t), Cijkl(t), Dklij(t), Iij(t), τ(t), σ(t) are all almost periodic functions, i= 1,2,· · ·, n, j = 1,2,· · ·, m;

(H2) the activity functionsf andg are Lipschtiz functions, i.e., there exist L >0, l >0 such that

|f(x)−f(y)| ≤L|x−y|, ∀x, y ∈R,

|g(x)−g(y)| ≤l|x−y|, ∀x, y ∈R; (H3) sup

t∈R

|Cijkl(t)| = Cijkl < +∞, sup

t∈R

|Dklij(t)| = Dijkl < +∞, sup

t∈R

|aij(t)| = a+ij <

+∞, aij(u)≥aij∗ >0.

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Let

ϕ0 =n

t

Z

−∞

eRstaij(u)duIij(s)dso

, kϕ0k=R0 θ1 = max

i,j

n X

CklNr(i,j)

Cijkl

2LR+|f(0)|

+ X

CklNs(i,j)

Dijkl

2lR+|g(0)|o

; θ2 = max

i,j

n X

Ckl∈Nr(i,j)

Cijkl

4LR+|f(0)|

+ X

Ckl∈Ns(i,j)

Dijkl

4lR+|g(0)|o . where R is a constant with R ≥R0.

Theorem 2.1 If (H1), (H2), (H3) and the following conditions are satisfied (1) R0 ≤R <+∞;

(2) θ1 ·max

i,j

n 1

aij∗,1 + a

+ ij

aij∗

o

12; (3) θ =θ2·max

i,j

n 1

aij∗,1 + a

+ ij

aij∗

o

<1,

then Eq.(1.1) has a unique almost periodic solution.

Proof. For any given ϕ={ϕij} ∈AP1(R,Rm×n), we consider the almost periodic solution of the following differential equation

xij =−aij(t)xij − X

Ckl∈Nr(i,j)

Cijkl(t)f(ϕkl(t−τ(t)))ϕij(t)

− X

CklNs(i,j)

Dklij(t)g(ϕkl(t−σ(t)))ϕij(t) +Iij(t). (2.1) Since ϕij(t), aij(t),Cijkl(t), Dijkl(t),τ(t), σ(t) andIij(t) are all almost periodic func- tions, andM[aij]>0, according to Lemma 1 and lemma 2, we know that Eq.(2.1) has a unique almost periodic solution xϕ ={xϕij}, which can be expressed as follows

xϕij =

t

Z

−∞

eRstaij(u)duh

− X

Ckl∈Nr(i,j)

Cijkl(s)f(ϕkl(s−τ(s)))ϕij(s)

− X

Ckl∈Ns(i,j)

Dklij(s)g(ϕkl(s−σ(s)))ϕij(s) +Iij(s)i ds.

We define a nonlinear operator on AP1(R,Rm×n) as follows T(ϕ)(t) =xϕ(t), ∀ϕ∈AP1(R,Rm×n).

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It is obvious that the fixed point ofT is a solution of Eq.(1.1). In the following we will show thatT is a contract mapping, thus the Banach fixed point theorem assert thatT has a fixed point.

Let E be defined as follows

E ={ϕ∈AP1(R,Rm×n)| kϕ−ϕ0k ≤R}.

Firstly, we show that T(E) ⊆ E. For each ϕ ∈ E, we have kϕ − ϕ0k ≤ R, kϕk ≤ kϕ−ϕ0k+kϕ0k ≤R+R ≤2R. Thus

kT ϕ−ϕ0k0

= sup

t∈R

maxi,j

n

t

Z

−∞

eRstaij(u)duh

− X

Ckl∈Nr(i,j)

Cijkl(s)f(ϕkl(s−τ(s)))ϕij(s)

− X

Ckl∈Ns(i,j)

Dijkl(s)g(ϕkl(s−σ(s)))ϕij(s)i ds

o

≤ sup

t∈R

maxi,j

n

t

Z

−∞

eRstaij(u)du

− X

Ckl∈Nr(i,j)

Cijkl(s)f(ϕkl(s−τ(s)))ϕij(s)

− X

Ckl∈Ns(i,j)

Dijkl(s)g(ϕkl(s−σ(s)))ϕij(s) dso

≤ sup

tR

maxi,j

n

t

Z

−∞

eRstaij(u)duh X

CklNr(i,j)

|Cijkl(s)||f(ϕkl(s−τ(s)))||ϕij(s)|

+ X

Ckl∈Ns(i,j)

|Dklij(s)||g(ϕkl(s−σ(s)))||ϕij(s)|i dso

≤ sup

t∈R

maxi,j

n

t

Z

−∞

eRstaij(u)duh X

Ckl∈Nr(i,j)

Cijkl

|f(ϕkl(s−τ(s)))−f(0)|+|f(0)|

+ X

Ckl∈Ns(i,j)

Dijkl

|g(ϕkl(s−σ(s))−g(0)|+|g(0)|)i dso

2R

≤ sup

tR

maxi,j

n

t

Z

−∞

eRstaij(u)du

h X

CklNr(i,j)

Cijkl(L|ϕkl(s−τ(s))|+|f(0)|)

+ X

Ckl∈Ns(i,j)

Dijkl(l|ϕkl(s−σ(s))|+|g(0)|)i dso

2R

≤ sup

t∈R

maxi,j

n

t

Z

−∞

eRstaij(u)duh X

Ckl∈Nr(i,j)

Cijkl(2LR+|f(0)|)

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+ X

Ckl∈Ns(i,j)

Dklij(2lR+|g(0)|)i dso

2R

≤ sup

t∈R

maxi,j

n

t

Z

−∞

e−aij∗(t−s)dso 2Rθ1

≤ 2Rθ1max

i,j

n 1 aij∗

o

≤ R (2.2)

and

k(T ϕ−ϕ0)k0

= sup

t∈R

maxi,j

Z t

−∞

−aij(t)eRstaij(u)du· h− X

Ckl∈Nr(i,j)

Cijkl(s)f(ϕkl(s−τ(s)))

− X

Ckl∈Ns(i,j)

Dijkl(s)g(ϕkl(s−σ(s)))i

ϕij(s)ds + h

− X

CklNr(i,j)

Cijkl(t)f(ϕkl(t−τ(t)))

− X

Ckl∈Ns(i,j)

Dijkl(t)g(ϕkl(t−σ(t)))i ϕij(t)

= sup

t∈R

maxi,j

Z t

−∞

aij(t)eRstaij(u)du· h X

Ckl∈Nr(i,j)

Cijkl(s)f(ϕkl(s−τ(s)))

+ X

Ckl∈Ns(i,j)

Dijkl(s)g(ϕkl(s−σ(s)))i

ϕij(s)ds

− h X

Ckl∈Nr(i,j)

Cijkl(t)f(ϕkl(t−τ(t)))

+ X

Ckl∈Ns(i,j)

Dklij(t)g(ϕkl(t−σ(t)))i ϕij(t)

≤ sup

tR

maxi,j

Z t

−∞

|aij(t)|eRstaij(u)du· h X

CklNr(i,j)

|Cijkl(s)| |f(ϕkl(s−τ(s)))|

+ X

Ckl∈Ns(i,j)

|Dijkl(s)| |g(ϕkl(s−σ(s)))|i

ij(s)|ds

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+ h X

Ckl∈Nr(i,j)

|Cijkl(t)| |f(ϕkl(t−τ(t)))|

+ X

Ckl∈Ns(i,j)

|Dijkl(t)| |g(ϕkl(t−σ(t)))|i

ij(t)|

≤ sup

tR

maxi,j

Z t

−∞

a+ijeaij∗(ts)ds· h X

Ckl∈Nr(i,j)

Cijkl

2LR+|f(0)|

+ X

Ckl∈Ns(i,j)

Dijkl

2lR+|g(0)|i

+h X

Ckl∈Nr(i,j)

Cijkl

2LR+|f(0)|

+ X

Ckl∈Ns(i,j)

Dijkl

2lR+|g(0)|i

·2R

≤ 2Rθ1max

i,j

n1 + a+ij aij∗

o

≤ R. (2.3)

From (2.2) and (2.3), we have kT ϕ−ϕ0k ≤R, thus T(E)⊆E. Let ϕ, ψ∈E, denote by

I1(s) = X

Ckl∈Nr(i,j)

Cijkl(s)h f

ϕkl(s−τ(s))

ϕij(s)−f

ψkl(s−σ(s))

ψij(s)i ,

I2(s) = X

Ckl∈Ns(i,j)

Dijkl(s)h g

ϕkl(s−σ(s))

ϕij(s)−g

ψkl (s−σ(s))

ψij(s)i .

We have

|I1(s)|

=

X

Ckl∈Nr(i,j)

Cijkl(s)h f

ϕkl(s−τ(s))

ϕij(s)−f

ψkl(s−σ(s))

ψij(s)i

≤ X

Ckl∈Nr(i,j)

Cijklh f

ϕkl(s−τ(s))

ϕij(s)−f

ϕkl(s−τ(s))

ψij(s)

+ f

ϕkl(s−τ(s))

ψij(s)−f

ψkl(s−σ(s)) ψij(s)

i

= X

Ckl∈Nr(i,j)

Cijklh f

ϕkl(s−τ(s)) ·

ϕij(s)−ψij(s)

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+ f

ϕkl(s−τ(s))

−f

ψkl(s−σ(s)) ·

ψij(s)

i

≤ X

CklNr(i,j)

Cijklh f

ϕkl(s−τ(s)) ·

ϕij(s)−ψij(s)

+L·

ϕkl(s−τ(s))−ψkl(s−σ(s)) ·

ψij(s)

i

≤ X

Ckl∈Nr(i,j)

Cijklh f

ϕkl(s−τ(s))

−f(0) +

f(0)

·

ϕij(s)−ψij(s) +L·

ϕkl(s−τ(s))−ψkl(s−σ(s)) ·

ψij(s)

i

≤ X

Ckl∈Nr(i,j)

Cijklh

2LR+|f(0)|

·

ϕij(s)−ψij(s)

+2LR·

ϕkl(s−τ(s))−ψkl(s−σ(s)) i

≤ X

Ckl∈Nr(i,j)

Cijkl

4LR+|f(0)|

· kϕ−ψk Similarly,

|I2(s)|

=

X

Ckl∈Ns(i,j)

Dijkl(s)h g

ϕkl(s−τ(s))

ϕij(s)−g

ψkl (s−σ(s))

ψij(s)i

≤ X

Ckl∈Ns(i,j)

Dijkl

4lR+|g(0)|

· kϕ−ψk

kT ϕ−T ψk0

= sup

t∈R

maxi,j

t

Z

−∞

eRstaij(u)du· h

− X

Ckl∈Nr(i,j)

Cijkl(s)

[f(ϕkl(s−τ(s)))ϕij(s)−f(ψkl(s−σ(s)))ψij(s)

− X

Ckl∈Ns(i,j)

Dijkl(s)

g(ϕkl(s−σ(s)))ϕij(s)−g(ψkl (s−σ(s)))ψij(s)i ds

≤ sup

tR

maxi,j

n

t

Z

−∞

eRstaij(u)du

|I1(s)|+|I2(s)|

dso

≤ sup

t∈R

maxi,j

n

t

Z

−∞

eRstaij(u)dudsh X

Ckl∈Nr(i,j)

Cijkl

4LR+|f(0)|

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+ X

Ckl∈Ns(i,j)

Dklij

4lR+|g(0)|io

· kϕ−ψk

≤ sup

t∈R

maxi,j

n

t

Z

−∞

e−aij∗(t−s)dso

·θ2 · kϕ−ψk

≤ θ2·max

i,j { 1 aij∗

} · kϕ−ψk (2.4)

And

k(T ϕ−T ψ)k0

= sup

t∈R

maxi,j

Z t

−∞

−aij(t)eRstaij(u)du· nh− X

Ckl∈Nr(i,j)

Cijkl(s)f(ϕkl(s−τ(s)))

− X

CklNs(i,j)

Dijkl(s)g(ϕkl(s−σ(s)))i ϕij(s)

+ h X

Ckl∈Nr(i,j)

Cijkl(s)f(ψkl(s−τ(s)))

+ X

Ckl∈Ns(i,j)

Dijkl(s)g(ψkl(s−σ(s)))i

ψij(s)o ds

+nh

− X

Ckl∈Nr(i,j)

Cijkl(t)f(ϕkl(t−τ(t)))

− X

Ckl∈Ns(i,j)

Dijkl(t)g(ϕkl(t−σ(t)))i ϕij(t)

+h X

CklNr(i,j)

Cijkl(t)f(ψkl(t−τ(t)))

+ X

Ckl∈Ns(i,j)

Dijkl(t)g(ψkl (t−σ(t)))i

ψij(t)o

≤ sup

t∈R

maxi,j

nZ t

−∞

|aij(t)|eRstaij(u)du

|I1(s)|+|I2(s)|

ds +

|I1(t)|+|I2(t)|o

≤ sup

tR

maxi,j

nZ t

−∞

|aij(t)|eRstaij(u)duds+ 1o

·θ2· kϕ−ψk

≤ sup

t∈R

maxi,j

nZ t

−∞

a+ije−aij∗(t−s)ds+ 1o

·θ2· kϕ−ψk

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≤ θ2 ·max

i,j

n

1 + a+ij aij

o

· kϕ−ψk (2.5)

From (2.4) and (2.5), we have kT ϕ−T ψk ≤θ2 ·max

i,j

n 1

aij∗, 1 + a

+ ij

aij∗

o· kϕ−ψk= θ· kϕ−ψk. According to the condition of this theorem we know θ < 1, therefore T has a unique fixed point.

Example We consider the following SICCN with neutral a delay:

xij =−aij(t)xij − X

Ckl∈Nr(ij)

Cijkl(t)f[xkl(t−τ(t))]xij(t)

+ X

Ckl∈Ns(i,j)

Dijkl(t)g[xkl(t−σ(t))]xij(t) +Iij(t), (2.6)

where i= 1,2,3, j= 1,2,3, τ(t) = cos2t, σ(t) = sin 2t,f(x) = 45sinx, g(x) = 34|x|,

a11(t) a12(t) a13(t) a21(t) a22(t) a23(t) a31(t) a32(t) a33(t)

=

5 +|sint| 5 +|sin 2t| 9 +|sint|

6 +|cost| 6 +|sint| 7 +|cost|

8 +|cost| 8 +|sint| 5 +|sin 2t|

c11(t) c12(t) c13(t) c21(t) c22(t) c23(t) c31(t) c32(t) c33(t)

=

0.004|sin 3t| 0.002|sin 3t| 0.001|sin 3t|

0.002|sin 3t| 0.001|sin 3t| 0.001|sin 3t|

0.001|sin 3t| 0.002|sin 3t| 0.001|sin 3t|

d11(t) d12(t) d13(t) d21(t) d22(t) d23(t) d31(t) d32(t) d33(t)

=

0.001|cos 2t| 0.001|cos 2t| 0.002|cos 2t|

0.001|cos 2t| 0.002|cos 2t| 0.003|cos 2t|

0.002|cos 2t| 0.002|cos 2t| 0.001|cos 2t|

I11(t) I12(t) I13(t) I21(t) I22(t) I23(t) I31(t) I32(t) I33(t)

=

sint sint cost sint cost cost cost cost cost

In the following, we will check that all assumptions of the theorem are satisfied. By computing,we have

a+11 a+12 a+13 a+21 a+22 a+23 a+31 a+32 a+33

=

6 6 10 7 7 8 9 9 6

,

a11 a12 a13

a21 a22 a23

a31 a32 a33

=

5 5 9 6 6 7 8 8 5

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c11 c12 c13 c21 c22 c23 c31 c32 c33

=

0.004 0.002 0.001 0.002 0.001 0.001 0.001 0.002 0.001

,

d11 d12 d13 d21 d22 d23 d31 d32 d33

=

0.001 0.001 0.002 0.001 0.002 0.003 0.002 0.002 0.001

.

Note that f and g are Lipschtz functions with f(0) = g(0) = 0, the Lipschtz constants of f and g, L, l, are less than 1, we take L=l= 1.

X

ckl∈N1(1,1)

ckl+ X

ckl∈N1(1,1)

dkl = 0.014, P

cklN1(1,2)

ckl+ P

cklN1(1,2)

dkl= 0.021, X

ckl∈N1(1,3)

ckl+ X

ckl∈N1(1,3)

dkl = 0.013, P

ckl∈N1(2,1)

ckl+ P

ckl∈N1(2,1)

dkl= 0.021, X

ckl∈N1(2,2)

ckl+ X

ckl∈N1(2,2)

dkl = 0.030, P

cklN1(2,3)

ckl+ P

cklN1(2,3)

dkl= 0.019, X

ckl∈N1(3,1)

ckl+ X

ckl∈N1(3,1)

dkl = 0.013, P

ckl∈N1(3,2)

ckl+ P

ckl∈N1(3,2)

dkl= 0.019, X

cklN1(3,3)

ckl+ X

cklN1(3,3)

dkl = 0.013,

From computing we know kϕ0k ≤ 115, we choose R = 3. Obviously max

i,j

n 1 aij∗,1 +

a+ij aij∗

o = 115 . θ1 = 0.18, θ2 = 0.36, θ1 ·max

i,j {a1

ij∗,1 + a

+ ij

aij∗} = 0.396 ≤ 12, θ = θ2 · maxi,j

n 1

aij∗,1 + a

+ ij

aij∗

o = 0.792 < 1. So all the conditions of theorem 2.1 are satisfied, hence by the theorem 2.1, Eq.(1.1) has a unique almost periodic solution.

Acknowledgements

The authors would like to thank the referees for their valuable suggestions and comments.

The first author was supported by Fund for Young Teachers of Jiangnan University (2008LQN010) and Program for Innovative Research Team of Jiangnan University.

The second author was supported by the National Natural Science Foundation of China under Grant 60875036, the Key Research Foundation of Science and Technology of the Ministry of Education of China under Grant 108067, and Program for Innovative Research Team of Jiangnan University.

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References

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(Received July 1, 2010)

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